XML to the URL of the image element

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• Root element is missing. System.Xml.XmlException: The root element is missing.

  Hello

  I have .NET 3.5 Web service hosted in my machine (Windows XP SP3) DEV .net 3.5 sp1... When I try to access the service form my

  client is the exception as below...

  Root element is missing. System.Xml.XmlException: The root element is missing.
  at System.Xml.XmlTextReaderImpl.Throw (Exception e)
  at System.Xml.XmlTextReaderImpl.ThrowWithoutLineInfo (String res)
  at System.Xml.XmlTextReaderImpl.ParseDocumentContent)
  at System.Xml.XmlTextReaderImpl.Read)
  to System.Xml.XmlTextReader.Read)
  at System.Xml.XmlReader.MoveToContent)
  at System.Web.Services.Protocols.SoapHttpClientProtocol.ReadResponse (SoapClientMessage message, WebResponse response, Stream responseStream, Boolean asyncCall)
  at System.Web.Services.Protocols.SoapHttpClientProtocol.Invoke (String methodName, Object [] parameters)

  Can any one opinion on this issue... Am I missing any software update...

  Thanks in advance...

  Kind regards

  Richard Starck M.

  Hi RAMANSELVA,

  Your question is more complex than what is generally answered in the Microsoft Answers forums. It is better suited for the IT audience Pro on MSDN. Please post your question in the MSDN forum.

  http://social.msdn.Microsoft.com/forums/en-us/netfxsetup/threads

• Forms 11 GR 2 - paste from the Clipboard into the image element

  Hi, how can I paste a picture from the Clipboard to an element of the Image on the form?
  If it cannot be done via the features of standard forms, is there no work around - I want to say can Java Bean do it, or maybe to do drag and drop via area of beans?
  I know it's a strange feature, but no suspicion is much appreciated.
  Thanks in advance. Jack

  Hello
  

  I think that it is not possible. The only ways to fill a part of the Image is to use the Read_Image_File() or to query the database.
  You can use a Java Bean that allows to drag and drop an image file.

  
  François

• resize the image in the Image element

  Hello
  
  I have an element of the Image corresponding to a blob column in my data base. I store image files there, then I retrieve and display images in this point of the Image. the question is how can I resize the Image with respect to the dimensions of the part of the Image? Here is an example [http://img25.imageshack.us/i/photoadx.jpg/]. This image is larger that it is displayed, so I need to see the entire image in this point of the Image.
  How can I resize it?
  
  Thank you!

  There is a Style property "calibration" for the image, set this "Adjust".

• How to use the image element displayed on the page

  APEX 4.0
  Oracle-Application-Server-10g/10.1.2.0.0 Oracle-HTTP-Server
  
  Hi all
  
  I have a table that contains 3 columns, see below:
  primary key ID
  BLOB pic1
  Pic2 blog
  
  There is 1 row in it (id = 1), just to display 2 images.
  
  Downloaded 2 pictures above Blob fields by file browse function. Now, I want to show the 2 photos in a region by using the display image P1_AR, but it did not work.
  

  Based on: BLOB Columns specified in item source
  Alternative Text Column: null
  Filename Column: null
  BLOB last update Column: null

  Source used: Only when current value in session state is null
  Source type: SQL Query(return single value)
  Source value or express: select dbms_lob.getlength(PIC) from cp_pic where id=1

  I got the error below after runing:
  ORA-20999: P1_AR must have a valid BLOB column as a source
  
  Thank you
  
  your help with impatience

  Sorry, this demand is in LAN, I have no right to publish on the internet and it has no external IP address to access as well.

  Do not import your request directly to apex.oracle.com.

  Create a simple application to simulate your question.
  

• Create a table that will have a similar table structure that you have.
  
• Download images in table
  
• Try to use item DISPLAY_IMAGE and see how it goes.

  If it doesn't, then please post workspace/name username/password and request of the details here.

  Kind regards
  Hari

• Set the scale of all the images in a table

  Hi all

  I have a chart 2D photos (say 4 x 4). I want to scale/zoom (all together) by a factor. So I use the zoomfactor property node wired to a digital slider, for any element 1 photo. During execution, only the image element for which I extracted the property node can be seen dynamically scaling, the rest stay where they are.

  Only if I hover over them, or use the increment/decrement button, then the rest of them move to the value on the scale suddenly. Is that how it is supposed to happen? I guess that there must be a way out. I would like to see all visible on the façade to the scale of the whole.

  I don't understand the VI because they have the pictures stored on the path to my computer to load whenever it works.

  Hoping to get a solution by advanced users.

  Thank you.

  Quick and dirty, but it works

  

• Check the point of the Image

  Hello world
  
  I have the point of the image as an element of database into my forms 6i application, how can I check if the image element is null or not? because I have a button to delete the image, and I want to make this active button only if there is an image in the image element.
  
  IF: Image_Item IS NULL THEN... END IF; is not... any idea?
  
  Thank you very much
  
  
  
  Best regards
  Damien

  you want to test this field if it is null or not... How can I implement this?

  Ali El - Hal pls try the following...

  ---- if u fetch the image first into a variabel IN WHEN-BUTTON-PRESSED Trigger as follow
  
  SELECT ur_image_item
  
  INTO : XYZ                   -- same data type
  
  FROM ur_tabel_name
  
  WHERE  EMP_ID =:EMP_ID;
  
  -- Then make ur validation
  
  IF  : XYZ IS NULL THEN
  
  DELETE_RECORD;
  
  END IF ;
  

  I hope this helps...

  Kind regards

  Abdetu...

• that means xml, when I try to set up an analysis of the image years ago, I get the message that there are on this scan xml elements and if I save it, elments of xml will be cleared. What is

  When I bring up some old pictures on my computer, it comes like a scan, when I opened the scan he says he has xml elements, which, if I save it, the xml elements will be deleted, what are xml elements

  The normal definition of xml is the Extensible Markup Language and is the most used in the web development. There is no logical reason why scans contain xml in their breast.

  All files have an extension that is used by Windows to identify what program to use to open the file. Word uses .doc or .docx format, Excel .xls or .xlsx, Adobe uses .pdf etc.

  Right-click on one of the files and select Properties, in the general tab, it displays the type of file and its extension.

  You are referring to 'initials pvt' but pvt isn't a common file extension and is used by a couple of applications, but have nothing to do with analysis or graphics.

  Up to what you did what in fact do a copy files (copy the directory as a whole) and let the originals intact.

  Although Word works with graphics files which is not normally the native program to use, can you explain the steps that you use to open the files.

• Multi attribute in xml - in the element schema root

  Hello

  I have several attribute in the xml file. all of them - in the root element.

  I know I have to put the declaration of the attribute in the lower part of the Diagram.

  When I put that one attribute in the schema - everything is OK.

  but I have more than one attribute (I have 8 attributes...), and I get this error:

  ORA-01460: LETTER, DEAD OR UNREASONABLE CONVERSION

  
  

  XML file:

  < MyRootElement Myattribute1 = 'MyValue1 '.

  MyAttribute2 = "MyValue2".

  MyAttribute3 = "MyValue3".

  "xmlns ="http://www.oracle.com/xml/test.xsd"

  xmlns ="http://www.w3.org/2001/xmlSchema-instance at the beginning of this line there should be written:" xmlns: xsi", but it's gone...".

  xsi: schemaLocation =http://www.oracle.com/xml/test.xsd my_schema_file.xsd' > '.

  XSD file:

  "" < schema targetNameSpace = "http://www.oracle.com/xml/test.xsd"

  "xmlns ="http://www.w3.org/2001/xmlSchema"

  xmlns: xdb = "http://xmlns.oracle.com/xdb."

  version = "1.0".

  elementFormDefault = "qualified" >

  < element name = "MyRootElement" >

  < complexType >

  < sequence >

  ----------------

  -the rest of the xsd file.

  ---------------------------------------------

  < / sequence >

  < attribute name = "MyAttribute1" type = "string" use = "required".

  < attribute name = "MyAttribute2" type = "string" use = "required".

  < / complexType >

  < / item >

  < / schema >

  Someone knows what's the problem?

  Thanks in advance,

  Elad

  Thank you.

  Okay... where to start? Almost everything is bad or at least very awkward

  (1) do not use the physical path with UTL_FILE, that has been obsolete for many years now. Use directory objects.

  And in fact, you don't even have UTL_FILE here.

  (2) the XML schema must be saved at once, in a separate script.

  Or do you expect to change them as often you must include the part of the record of the proceedings?

  (3) If your input XML document has an attribute xsi: schemaLocation, make sure that you save the schema using the same URL.

  In your example, there is a mismatch: 'my_schema_file.xsd' vs 'xml_schema.xsd' in the register command.

  So, to summarize:

  Create a directory:

  create or replace directory xml_dir as ' / home/myPath ";

  Save the schema (once):

  () dbms_xmlschema.registerschema

  schemaurl-online "my_schema_file.xsd."

  schemadoc-online xmltype)

  BFILENAME ('XML_DIR', '')

  , nls_charset_id ('AL32UTF8') - use the actual encoding of the file here

  )

  local-online true

  genTypes-online fake

  gentables-online fake

  enableHierarchy-online dbms_xmlschema.enable_hierarchy_none

  );

  So here's how I would rewrite the function:

  create or replace function schema_xml_333 (p_tested_xml in varchar2)

  return varchar2

  is

  doc xmltype: = xmltype (bfilename ('XML_DIR', p_tested_xml), nls_charset_id ('AL32UTF8'));

  Start

  return case when doc.isSchemaValid () = 1

  then "XML is valid.

  otherwise "XML is not valid.

  end;

  end;

  /

  Yet once, this will not work if the XML contains an attribute xsi: schemaLocation whose part URL pattern matches the URL used for recording.

  In this case, you don't need the createSchemaBasedXML method.

• Connecting the Image with the XML schema field

  I have a requirement that I'm working on which would require me to generate dynamic PDFS so that the text as well as images in the PDF must depend on the input XML I get. So in this respect, my question is how can I link an image with an element field in the example of XML data or with an element in the schema. Because of this feature supported by the tool. Generated PDF can have dynamic images in them.

  Any help in this direction would be greatly appreciated.

  Thanks in advance.

  Srini

  If it is possible can you retrieve the contents of the image of the DB and incorporate them into the data file? You have base64 encode.

  Paul

• What is downloaded the image url?

  I created the script to download the image to the server. After downloading images are located in the directory D:/uploads/logo. What is the url of the image to view it in the browser?
  
  My web.xml:
  
  < context-param >
  < description > fileuploads Parent directory location < / description >
  < param-name > APP. FILE_UPLOADS_DIR < / param-name >
  < param-value >/uploads/logo < / param-value >
  < / context-param >
  
  < filter >
  < filter-name > adfFaces < / filter-name >
  > class filter < oracle.adf.view.rich.webapp.AdfFacesFilter < / class filter >
  < / filter >
  
  < filter mapping >
  < filter-name > adfFaces < / filter-name >
  < name servlet - > Faces Servlet < / servlet-name >
  < / filter-mapping >
  
  < servlet >
  < name servlet - > Faces Servlet < / servlet-name >
  > the servlet class < javax.faces.webapp.FacesServlet < / servlet-class >
  < load-on-startup > 1 < / load-on-startup >
  < / servlet >
  
  < servlet-mapping >
  < name servlet - > Faces Servlet < / servlet-name >
  < url-pattern > /visages / * < / url-pattern >
  < / servlet-mapping >

  Alex,

  There will be no default URL that allows you to view the downloaded images. You will need to do something yourself to make the image visible via a URL; some suggestions would be:

  (1) on the Web/Application Server, create a virtual directory to d:/uploads/logo map
  (2) write your own servlet that can (according to certain parameters you offers in the URL) read the file from the image of the directory and the return flow to the browser

  John

• How to make src of the image of the place holder something xml file

  Hello
  im doing xslt on xml file and I want to store the path to the image on an element of the xml file and display the image on the page how?
  I can write about the CBC textbox like any expression xml xml string how?

  > im doing xslt on xml file and I want to keep the image on an element path
  > XML file and display the image on the page how?
  > can I write on the CBC textbox like any expression xml xml string how?

  I'm a little confused, but if you transform XML via XSLT, then
  You must create the link of the image via the XSLT file:

  Assuming that you store in an XML file name of the image node
  "imageFileName":

  

  -Darrel

• When I click on "Copy picture", when I use the dough, it's to show the image URL

  Hello

  I'm having a problem about the exemplary Image resource. I need to copy and paste a lot of images to work.

  I click on an image, holding control and then press "copy picture". But when I paste, it shows the URL of the image and not the image. I tried on different browsers and apps, but the same error occurs.

  Can someone help me please? How should I do? It has changed from one day to the other.

  Thank you

  It looks like you use context Menus to copy your images. Depending on your machine or software, each user will have different contextual shortcuts.

  You might do better to use an application like SnapnDrag, which is free in its basic mode.

• When I click on the + to open a new window I don't like the images that arise. I tried to change that in all: config; Browser.newtab.URL, but it will not

  When I click on the + to open a new window I don't like the images that arise. I tried several times to change that through words: config; Browser.newtab.URL. I put in the site I want and it won't change. I tried to put in: blank and it don't work. I'm obviously something wrong - can you help please?

  Thank you

  If Firefox is ignorant preference browser.newtab.url, the usual culprit is an extension.

  You can open the page in Firefox Add-ons using either:

  • CTRL + SHIFT + a
  • "3-bar" menu button (or tools) > Add-ons
  • in the Windows "Run" dialog box, type or paste
    firefox.exe "about:addons"

  In the left column, click Extensions. Then, in case of doubt, disable (or delete, if possible) not recognized and unwanted extensions. Do not forget that all extensions are optional, none come with Firefox, and you can learn more about them by checking their reviews on the site of the Add - ons.

  Often, a link will appear above at least an extension disabled to restart Firefox. You can complete your work on the tab and click one of the links in the last step.

  Any improvement?

• Can not view the image url on Firefox I can on Chrome

  I am trying to copy a set of images that have urls such as the following:

  http://www.Halldis.com/resources/apt_resource_1564_1272014118921.1

  These images will display well on Chrome, but not Firefox, where I get a lot of funny characters.

  The site is a third party site, and while they let us copy the pictures, I can't ask them to fix the problem.

  The server sends the file as a text/plain because it has an extension of fichier.1 and not a recognized as .jpg file extension
  
  It is always better to avoid problems like that and rename the file by adding .jpg

  You can paste it into the address bar to see the image in this case

  data:text/html,<img src="http://www.halldis.com/resources/apt_resource_1564_1272014118921.1">