3 display unique and random numbers on 6

Similar Questions

• even and odd numbers with level

  Hi Master,

  I tried to display numbers with level like that...

  Select the level from dual connect by level < = 10;

  1

  2

  3

  4

  5

  6

  7

  8

  9

  10

  How to display odd and even numbers with level. I tried with mod(level,0) but does not work very well.

  Please notify.

  Concerning

  SA

  
  

  Odd:

  Select 2 * level - 1 from dual connect by level<>

  /

  2 * LEVEL 1
  ----------
  1
  3
  5
  7
  9

  Scott@ORCL >

  Still:

  Select 2 * double connection by level<>

  /

  2 * LEVEL
  ----------
  2
  4
  6
  8
  10

  Scott@ORCL >

  SY.

• Choosing random numbers and unique serveral

  Hello
  
  I would select 9 random numbers of a series we'll say 1-20. They cannot repeat and each must be recorded in a different variable P1 - P9.
  
  Any ideas?
  Thank you

  Make a table of numbers 1 to 20.
  Mix the table.
  Remove as many numbers as you need.

  Search the forums for shuffle learn how to mix the table.

• I'm trying to generate a table of random numbers 30. After each 5 readings a new vi must open and indicate to the user than 5 readings were made. and continue with the generation of the table again.

  because I don't have a sensor now, I am currently generating a table of random numbers 30. After each 5 readings a warning should be given to the user 5 readngs are completed. This cycle must be repeated. the size of the table is 30.

  Please help me, waiting for response as soon as possible.

  Once I have the transducer, I'll take 30 analog samples and then after each 5 smaples this wraning will be displayed din a new VI

  Use a while loop with a delay time representing your sampling interval.

  Use is equal to the count Terminal to see if 4, then 4th iteration = 5th sample.

  Use a box structure. The real deal will only run on the 4th iteration.

  In the case of true place a Subvi with your message of your choice in the front panel. Go to the properties of the VI window and set ' open the front panel when it is called.

  The condition to closing of attention is not given to your description.

  Consider that rather than usign a Subvi to do this, you can use the "dialog box one/two/three button" or "display message" live in the palette "user interface and dialogue."

  Please try it out and send your own VI. Do not provide us with a working solution.

  Kind regards

• Select 3 Unique random numbers of a Recordset

  I have a table, a row with 3 columns. I want to put a random item I have a database in each column, but want the 3 to be unique. I have a code that runs and runs, but his does not work exactly perfect.

  The following code generates 3 unique pieces of data, but view the first item is always the same, and sometimes it will generate 2 points instead of 3. The table has 5 elements.

  What should I do to change my code so that it displays 3 ads every time, and that all 3 ads are random, unique and not a copy?

  < CFOUTPUT >

  < name cfquery "ri" = >

  SELECT *.

  Oeitem I have

  LEFT JOIN OEVendorCoupons c

  ON i.itempromocode = c.couponid

  WHERE i.itemsaleprice > 0 AND c.coupon_exp > = GetDate()

  < / cfquery >

  < CFSET itemlist = "" > "".

  < CFSET itemcount = 0 >

  < CFSET displaylist = "" > "".

  < request CFLOOP "ri" = >

  < CFSET itemlist = ListAppend (itemlist, ri.itemid) >

  < / CFLOOP >

  < CFSET ilistcount = ListLen (itemlist) >

  < list CFLOOP = "" #itemlist # "index ="item">"

  < CFSET randomi = RandRange(1,ilistcount) >

  < CFIF NOT ListContains (displaylist, ListGetAt (itemlist, randomi)) >

  < CFSET displaylist = ListAppend(displaylist,item) >

  < CFSET itemcount = itemcount + 1 >

  < / CFIF >

  < / CFLOOP >

  < table width = "650" height = "315" border = "0" cellspacing = "0" cellpadding = "2" >

  < b >

  < CFSET outputcount = 0 >

  < list CFLOOP = "' #displaylist # ' index 'i' = >"

  < CFSET outputcount = outputcount + 1 >

  < CFIF outputcount LT 4 >

  "< cfquery name ="If"datasource =" "#DSN #" username = "#USER #" password = "#PASS #" >

  SELECT *.

  Oeitem I have

  LEFT JOIN oevendor v

  ON v.vendorid = i.vendorid

  LEFT JOIN OEVendorCoupons c

  ON i.itempromocode = c.couponid

  WHERE itemid = "#i #

  < / cfquery >

  < td width = "210" valign = "top" >

  < table width = "200" border = "0" align = "center" cellpadding = "2" cellspacing = "0" >

  < class tr 'f10' = >

  < td align = "center" > < img src = "x.png" height = "8" / > < table > "

  < /tr >

  < CFIF Len (si.itemshortdesc) WG 18 >

  < CFSET sdl = 18 - ListLen (si.itemshortdesc) >

  < CFSET sd = ' #Left (si.itemshortdesc, sdl) #...» ">

  < CFELSE >

  < CFSET si.itemshortdesc = sd >

  < / CFIF >

  < b >

  #si.vendorcompany # < td > < table >

  < /tr >

  < /table >

  < table >

  < / CFIF >

  < / CFLOOP >

  < /tr >

  < /table >

  < / CFOUTPUT >

  Thank you

  Chuck

  == cfSearching ==-a writes:

  Update: I just noticed your date filter, we passed in our pseudocode. They should be added to your subquery so it pulls the correct records. Otherwise it will just get three random records, regardless of the price and date.  Try adding filters back and see if that fixes the problem.  (Test the subquery separately first of course.)

  ....

  WHERE i.itemid IN ((in English only)

  SELECT TOP 3 itemid from oeitem WHERE itemsaleprice > 0 AND coupon_exp > = GetDate() ORDER OF NEWID()

  )

  It's funny you should say that. I was wondering if the best solution would be to get exactly these itemIDs that match the query. In other words, in order to reproduce the original query in the where clause, as follows

  SELECT *.
  Oeitem I have
  LEFT JOIN OEVendorCoupons c
  ON i.itempromocode = c.couponid
  WHERE i.itemsaleprice > 0 AND c.coupon_exp > = GetDate()
  AND i.itemid in

  (SELECT j.itemid
  Of oeitem j
  LEFT JOIN OEVendorCoupons k
  ON j.itempromocode = k.couponid
  WHERE j.itemsaleprice > 0 AND k.coupon_exp > = GetDate()
  ORDER BY NEWID())

• Random numbers and generate funds

  Hello.

  I would like to create a very simple equation random addition.

  I have: 3 boxes of dynamic text (r1_txt, r2_txt, a1_txt)

  I want the first two random numbers and 'a1_txt' to display the sum of the first two random numbers.

  Everything is perfect to the point of adding the two numbers and drop the answer in a1_text. What should I do for my last line of code?

  Thanks for your help!

  random numbers
  1.
  function randomNumbers (min:Number, max: Number) {}
  var Results:Number = Math.floor (Math.random () * max) + min;
  return results;
  }

  2.
  new_mc.addEventListener (MouseEvent.CLICK, showRandomnumber);

  3.
  function showRandomnumber(event:MouseEvent):void {}
  r1_txt. Text = randomNumbers (1,100)
  r2_txt. Text = randomNumbers (1,100)
  a1_txt. Text = Number (r1_txt.text) + Number (r2_txt.text);
  }

  Your showRandomnumber() function has a few problems.  TextFields working with channels, so whatever it is assigned to a textfield must be a string value.  You should actually get errors for the first two lines.

  function showRandomnumber(event:MouseEvent):void {}
  r1_txt. Text = String (randomNumbers (1,100));
  r2_txt. Text = String (randomNumbers (1,100));
  a1_txt. Text = String (Number (r1_txt.text) + Number (r2_txt.text));
  }

  If you change which is not fix things, then look to your textfields to the problem

• Random number generator. Even and odd numbers

  I have a problem.

  I have a generator of random numbers, it goes from 0 to 20, I need to have two indicators, we show you how many numbers are pairs, and how much isn't.

  I tried to table D use the decimated 1, but as these numbers are random, it doesn´t works for me. I m new with LabView and I Don t know if there is another way to make it work, I need help, especially with a few examples.

  Thank you very much.

  
  

• How can I generate multiple unique random numbers?

  Hello

  I am trying to generate multiple random numbers between a given set of numbers (1-52) and do not have the same number generated twice within this group. I can compare the numbers of last and next with the function to compare, but how would I go about comparison of all numbers generated without using a huge list of shift registers...

  Any help/ideas are welcome and appreciated.

  Jason

  Solved my problem. IM passing the random number through a registry to offset to each case and build a table every time. I then searches the table for the new random number. If the number is not found I get a value of-1, another thing is an index value of 0-everything. If a comparator greater than (-1) indicates that the same number is in the table and then I can raise this matter until the same number is not found.

  Kind regards

  Jason

• I want just a bunch of random numbers (about 120 of them) from the list, select 'all' and get the computer to rearrange in CNC

  I try both notepad and wordpad. I'm in Winows XP 2003.  I want just a bunch of random numbers (about 120 of them) from the list, select "all" and reorganize in order digital computer. I can't understand how I've done it before. Google says select the balls feature, but all that is put a point in front of a certain number. There is no arrow down to select. No A - Z. No 1,2,3. what Miss me? is the Notepad or wordpad not the place to do that?

  Use Excel.

• unique random numbers

  How to get the unique random numbers each time in AS3

  I searched but not able to get satisfactory results

  use:

  var tempArray:Array =]

  for (var i: uint = 0; i<>

  tempArray.push (i);

  }

  Shuffle (tempArray);

  You can now browse tempArray for random integers from 0 to moveXml.movie.length () - 1

  function shuffle(a:Array) {}
  var p:int;
  var t: *;
  var ivar:int;
  for (ivar =. Length-1; Ivar > = 0; Ivar-) {}
  p = Math.Floor ((Ivar+1) * Math.Random ());
  t = a [ivar];
  a [ivar] = a [p];
  a [p] = t;
  }
  }

• Random numbers, not so much to chance

  I use a simple piece of code I found online to create a random number between two numbers

  new Random().nextInt(6-1)+1);
  

  I am trying to create random numbers for dice.

  Everything seems to work fine, but the numbers are not that random. I have a loop configuration to display the code above 50 times and it will make a loop over and over again the same number. Here is an example of the results

  1,1,1,1,1,1,4,4,4,4,2,2,2,2,2,1,1,1,1,1

  Therefore, it is quite difficult to create a type of yahtzee game when you always roll a yahtzee on the first roll lol.

  Is there something I'm missing here?

  I agree that the Random function generates only numbers random nickname and there are interesting ways of the algorithm of seeds, I believe that in this case, the problem is that Random is not used correctly.  I think that random is intended to be used as shown in the following fragment.  I also think that random is perfectly satisfactory for use in this case, so I would not personally recommend looking for another algorithm.

  Random myGenerator = new Random(System.currentTimeMillis());
  String thrown = ""; // Yes, this should be a StringBuffer....
  for ( int i = 0; i < 50; i++ ) {
      thrown = thrown + Integer.toString(myGenerator.nextInt(6)+1) + ", ";
  }
  System.out.println("Thrown: " + thrown);
  

  Here is the result of a few tracks:

  Lift: 5, 6, 2, 3, 1, 5, 3, 5, 4, 1, 5, 6, 3, 3, 6, 6, 5, 5, 3, 5, 1, 6, 6, 2, 1, 5, 5, 1, 6, 5, 5, 2, 5, 3, 6, 6, 5, 3, 5, 1, 2, 5, 1, 6, 2, 3, 1, 3, 2, 6,
  Lift: 4, 1, 4, 1, 5, 3, 5, 3, 2, 4, 3, 2, 5, 3, 4, 4, 3, 4, 2, 3, 2, 3, 1, 2, 2, 4, 5, 1, 5, 6, 2, 6, 6, 1, 1, 4, 5, 3, 4, 5, 6, 6, 6, 5, 6, 6, 2, 4, 5, 4,

  Edit: updated to fix the sample code fragment andgive output.

• 6 random numbers without repetition

  I'm doing a generator of 6 random numbers between 1 and 48. When the user clicks a button randomly 6 numbers appear in 6 different textFeilds. The problem is that I don't want the same number twice. How can I generate 6 different random numbers without using back and out of the service?

  import flash.events.Event;

  Stop();

  btn.addEventListener (MouseEvent.CLICK, random1);

  function random1 {(evt:Event)}

  display1. Text = "";

  Display2.text = "";

  Display3.text = "";

  display4. Text = "";

  display5. Text = "";

  display6. Text = "";

  var r1 = Math.floor (Math.random () *(1+48-1)) + 1;

  var r2 = Math.floor (Math.random () *(1+48-1)) + 1;

  var A3 = Math.floor (Math.random () *(1+48-1)) + 1;

  var r4 = Math.floor (Math.random () *(1+48-1)) + 1;

  var A5 = Math.floor (Math.random () *(1+48-1)) + 1;

  var A6 = Math.floor (Math.random () *(1+48-1)) + 1;

  If (r2 = r1 | r3 == r2 | r4 == r3 | r5 == r4 | r6 = r5) {}

  return;

  }

  var list: Array = new Array();

  Liste.push (R1, R2, R3, R4, R5, R6);

  Liste.sort (Array.Numeric);

  display1. Text = String (list [0]);

  Display2.Text = String (list [1]);

  Display3.Text = String (list [2]);

  display4. Text = String (list [3]);

  display5. Text = String (list [4]);

  display6. Text = String (list [5]);

  }

  Here is the code for the approach mentioned with your included textfields

  btn.addEventListener (MouseEvent.CLICK, random1);

  function random1 {(evt:Event)}

  var nums:Array = new Array();

  Complete the table of numbers

  for (var i: uint = 1; i<=48;>
  Nums.push (i);
  }

  Shuffle (NUMS);

  Take the first six of the mixed table

  var list: Array = nums.splice (0.6);

  assign values to the textfields

  for (var j: uint = 1; j<=6;>
  This ["Display" + String (j)] .text = String (list [j]);
  }
  }

  function shuffle(a:Array) {}
  var p:int;
  var t: *;
  var ivar:int;
  for (ivar =. Length-1; Ivar > = 0; Ivar-) {}
  p = Math.Floor ((Ivar+1) * Math.Random ());
  t = a [ivar];
  a [ivar] = a [p];
  a [p] = t;
  }
  }

• random numbers in a textfield?

  Hi all thx for reading and I hope you can help

  I create a game for children, which shows them how to tell the time

  I need to put two random numbers in a textfield one for hours and one for the minutes

  so that I can get the app to say show me 13:45, for example

  However, I don't want to include the time of 12:00, because that's where the clock will start and defeated the purpose

  the clock is 24 hours, from 1 to 24 hours

  00-60 minutes

  Ive looked everywhere on how to do it but could not find an answer

  at the moment I have a textfield that displays the time as the user adds hours etc that I intend to hide

  while I can tell if this textfield random number is equal to the textfield time then correct display and so on

  How could I go about this?

  any help is appreciated

  Thank you

  fonzio

  Then just replace 0 with 24

  return (hour == 0 ? 24 : hour) + ":" + (minute < 10 ? "0" : "") + minute;
  

  --

  Kenneth Kawamoto

  http://www.materiaprima.co.UK/

• The sum of total revenue for each customer unique and graphic it!

  Sunny greetings from Athens!  I walked for 5 hours for an elegant solution to the following:

  I want to add the total amount of revenue for each customer unique and graphic to view what customers bring in most of the species.

  Example of this in it:

  Customers	Charged €
  A	100
  B	200
  C	250
  A	130
  A	120
  B	100

  Customers	Total €
  A	350
  B	300
  C	250

  How this can be implemented by the numbers? As elegantly as possible?

  Hi menick,.

  SUMIF () will do the job.

  

  the formula in table 2::B2 =.

  SUMIF (table 1::A, A2, table 1::B)

  It is filled down.

  Quinn

• Random numbers appearing in messages

  I am running Firefox 4.0.1 on 64-bit Windows 7 and every time that I post on a forum or send a Gmail account, it adds random numbers at the end of my entry. I tried using Chrome and it doesn't do this, what's the problem?

  You paste content or add a signature?

  Start Firefox in Firefox to solve the issues in Safe Mode to check if one of the extensions of the origin of the problem (switch to the DEFAULT theme: Firefox (Tools) > Add-ons > appearance/themes).

  • Makes no changes on the start safe mode window.
  • https://support.Mozilla.com/kb/safe+mode
  • https://support.Mozilla.com/kb/troubleshooting+extensions+and+themes