unique random numbers

Similar Questions

• How can I generate multiple unique random numbers?

  Hello

  I am trying to generate multiple random numbers between a given set of numbers (1-52) and do not have the same number generated twice within this group. I can compare the numbers of last and next with the function to compare, but how would I go about comparison of all numbers generated without using a huge list of shift registers...

  Any help/ideas are welcome and appreciated.

  Jason

  Solved my problem. IM passing the random number through a registry to offset to each case and build a table every time. I then searches the table for the new random number. If the number is not found I get a value of-1, another thing is an index value of 0-everything. If a comparator greater than (-1) indicates that the same number is in the table and then I can raise this matter until the same number is not found.

  Kind regards

  Jason

• Effective unique random numbers

  Hi all

  I'm looking for assign a random number from 1-20 from 20 different variables. I need each variable to have a unique number. Later, I put variables into a list, and because of the randomly generated number that the list is in a different order each time the program is run. What I have works, but I think it's bulky. I was wondering if there was a better way to do this. Thank you:

  Here is an excerpt of how I am the procedure, which shows the process for the first 10 variables, but the last 10 follow the same pattern:

  N1 = Math.floor (Math.random () * 20) + 1;

  questionRandomizer1 ();

  questionRandomizer2 ();

  questionRandomizer3 ();

  questionRandomizer4 ();

  questionRandomizer5 ();

  questionRandomizer6 ();

  questionRandomizer7 ();

  questionRandomizer8 ();

  questionRandomizer9 ();

  questionRandomizer10 ();

  questionRandomizer11 ();

  questionRandomizer12 ();

  questionRandomizer13 ();

  questionRandomizer14 ();

  questionRandomizer15 ();

  questionRandomizer16 ();

  questionRandomizer17 ();

  questionRandomizer18 ();

  questionRandomizer19 ();

  questionRandomizer20 ();

  function questionRandomizer1)

  {

  QuestionOrder [1] = n1;

  }

  function questionRandomizer2)

  {

  QuestionOrder [2] = Math.floor (Math.random () * 20) + 1;

  If (QuestionOrder [2] == QuestionOrder [1]) {questionRandomizer2 ()}

  }

  I'm generates a random number to QuestionOrder [2], then check if it is the same number as QuestionOrder [1], and in this case, I'm re - run the function to generate a random number again, until he gets a unique number. This continues for each next function.

  function questionRandomizer3)

  {

  QuestionOrder [3] = Math.floor (Math.random () * 20) + 1;

  If (QuestionOrder [3] == QuestionOrder [1] |) QuestionOrder [3] == QuestionOrder [2]) {questionRandomizer3 ()}

  }

  function questionRandomizer4)

  {

  QuestionOrder [4] = Math.floor (Math.random () * 20) + 1;

  If (QuestionOrder [4] == QuestionOrder [1] |) QuestionOrder [4] == QuestionOrder [2] | QuestionOrder [4] == QuestionOrder [3]) {questionRandomizer4 ()}

  }

  function questionRandomizer5)

  {

  QuestionOrder [5] = Math.floor (Math.random () * 20) + 1;

  If (QuestionOrder [5] == QuestionOrder [1] |) QuestionOrder [5] == QuestionOrder [2] | QuestionOrder [5] == QuestionOrder [3] | QuestionOrder [5] == QuestionOrder [4]) {questionRandomizer5 ()}

  }

  function questionRandomizer6)

  {

  QuestionOrder [6] = Math.floor (Math.random () * 20) + 1;

  If (QuestionOrder [6] == QuestionOrder [1] |) QuestionOrder [6] == QuestionOrder [2] | QuestionOrder [6] == QuestionOrder [3] | QuestionOrder [6] == QuestionOrder [4]

  || QuestionOrder [6] == QuestionOrder [5]) {questionRandomizer6 ()}

  }

  function questionRandomizer7)

  {

  QuestionOrder [7] = Math.floor (Math.random () * 20) + 1;

  If (QuestionOrder [7] == QuestionOrder [1] |) QuestionOrder [7] == QuestionOrder [2] | QuestionOrder [7] == QuestionOrder [3] | QuestionOrder [7] == QuestionOrder [4]

  || QuestionOrder [7] == QuestionOrder [5] | QuestionOrder [7] == QuestionOrder [6]) {questionRandomizer7 ()}

  }

  function questionRandomizer8)

  {

  QuestionOrder [8] = Math.floor (Math.random () * 20) + 1;

  If (QuestionOrder [8] == QuestionOrder [1] |) QuestionOrder [8] == QuestionOrder [2] | QuestionOrder [8] == QuestionOrder [3] | QuestionOrder [8] == QuestionOrder [4]

  || QuestionOrder [8] == QuestionOrder [5] | QuestionOrder [8] == QuestionOrder [6] | QuestionOrder [8] == QuestionOrder [7]) {questionRandomizer8 ()}

  }

  function questionRandomizer9)

  {

  QuestionOrder [9] = Math.floor (Math.random () * 20) + 1;

  If (QuestionOrder [9] == QuestionOrder [1] |) QuestionOrder [9] == QuestionOrder [2] | QuestionOrder [9] == QuestionOrder [3] | QuestionOrder [9] == QuestionOrder [4]

  || QuestionOrder [9] == QuestionOrder [5] | QuestionOrder [9] == QuestionOrder [6] | QuestionOrder [9] == QuestionOrder [7] | QuestionOrder [9] == QuestionOrder [8]) {questionRandomizer9 ()}

  }

  function questionRandomizer10)

  {

  QuestionOrder [10] = Math.floor (Math.random () * 20) + 1;

  If (QuestionOrder [10] == QuestionOrder [1] |) QuestionOrder [10] == QuestionOrder [2] | QuestionOrder [10] == QuestionOrder [3] | QuestionOrder [10] == QuestionOrder [4]

  || QuestionOrder [10] == QuestionOrder [5] | QuestionOrder [10] == QuestionOrder [6] | QuestionOrder [10] == QuestionOrder [7] | QuestionOrder [10] == QuestionOrder [8]

  || QuestionOrder [10] == QuestionOrder [9]) {questionRandomizer10 ()}

  }

  as you can see the checklist gets progressively longer. I feel that I do a ton of If, Then, Else statements, and usually when this happens I will use a system of records. IM wondering if there is a better way to do it, in the same way a case statement is more effective than a bunch of If, then, Else statements.

  Thank you.

  Just create an array with 20 values in either randomly select them (and then splice), or probably even better, just mix table and retrieve ordered items randomly in the order they come.

  Here is a function for the table of brewing in AS3:

  function shuffle(a:Array) {}
  var p:int;
  var t: *;
  var ivar:int;
  for (ivar =. Length-1; Ivar > = 0; Ivar-) {}
  p = Math.Floor ((Ivar+1) * Math.Random ());
  t = a [ivar];
  a [ivar] = a [p];
  a [p] = t;
  }
  }

  Use:
  Shuffle (anArray);

• Select 3 Unique random numbers of a Recordset

  I have a table, a row with 3 columns. I want to put a random item I have a database in each column, but want the 3 to be unique. I have a code that runs and runs, but his does not work exactly perfect.

  The following code generates 3 unique pieces of data, but view the first item is always the same, and sometimes it will generate 2 points instead of 3. The table has 5 elements.

  What should I do to change my code so that it displays 3 ads every time, and that all 3 ads are random, unique and not a copy?

  < CFOUTPUT >

  < name cfquery "ri" = >

  SELECT *.

  Oeitem I have

  LEFT JOIN OEVendorCoupons c

  ON i.itempromocode = c.couponid

  WHERE i.itemsaleprice > 0 AND c.coupon_exp > = GetDate()

  < / cfquery >

  < CFSET itemlist = "" > "".

  < CFSET itemcount = 0 >

  < CFSET displaylist = "" > "".

  < request CFLOOP "ri" = >

  < CFSET itemlist = ListAppend (itemlist, ri.itemid) >

  < / CFLOOP >

  < CFSET ilistcount = ListLen (itemlist) >

  < list CFLOOP = "" #itemlist # "index ="item">"

  < CFSET randomi = RandRange(1,ilistcount) >

  < CFIF NOT ListContains (displaylist, ListGetAt (itemlist, randomi)) >

  < CFSET displaylist = ListAppend(displaylist,item) >

  < CFSET itemcount = itemcount + 1 >

  < / CFIF >

  < / CFLOOP >

  < table width = "650" height = "315" border = "0" cellspacing = "0" cellpadding = "2" >

  < b >

  < CFSET outputcount = 0 >

  < list CFLOOP = "' #displaylist # ' index 'i' = >"

  < CFSET outputcount = outputcount + 1 >

  < CFIF outputcount LT 4 >

  "< cfquery name ="If"datasource =" "#DSN #" username = "#USER #" password = "#PASS #" >

  SELECT *.

  Oeitem I have

  LEFT JOIN oevendor v

  ON v.vendorid = i.vendorid

  LEFT JOIN OEVendorCoupons c

  ON i.itempromocode = c.couponid

  WHERE itemid = "#i #

  < / cfquery >

  < td width = "210" valign = "top" >

  < table width = "200" border = "0" align = "center" cellpadding = "2" cellspacing = "0" >

  < class tr 'f10' = >

  < td align = "center" > < img src = "x.png" height = "8" / > < table > "

  < /tr >

  < CFIF Len (si.itemshortdesc) WG 18 >

  < CFSET sdl = 18 - ListLen (si.itemshortdesc) >

  < CFSET sd = ' #Left (si.itemshortdesc, sdl) #...» ">

  < CFELSE >

  < CFSET si.itemshortdesc = sd >

  < / CFIF >

  < b >

  #si.vendorcompany # < td > < table >

  < /tr >

  < /table >

  < table >

  < / CFIF >

  < / CFLOOP >

  < /tr >

  < /table >

  < / CFOUTPUT >

  Thank you

  Chuck

  == cfSearching ==-a writes:

  Update: I just noticed your date filter, we passed in our pseudocode. They should be added to your subquery so it pulls the correct records. Otherwise it will just get three random records, regardless of the price and date.  Try adding filters back and see if that fixes the problem.  (Test the subquery separately first of course.)

  ....

  WHERE i.itemid IN ((in English only)

  SELECT TOP 3 itemid from oeitem WHERE itemsaleprice > 0 AND coupon_exp > = GetDate() ORDER OF NEWID()

  )

  It's funny you should say that. I was wondering if the best solution would be to get exactly these itemIDs that match the query. In other words, in order to reproduce the original query in the where clause, as follows

  SELECT *.
  Oeitem I have
  LEFT JOIN OEVendorCoupons c
  ON i.itempromocode = c.couponid
  WHERE i.itemsaleprice > 0 AND c.coupon_exp > = GetDate()
  AND i.itemid in

  (SELECT j.itemid
  Of oeitem j
  LEFT JOIN OEVendorCoupons k
  ON j.itempromocode = k.couponid
  WHERE j.itemsaleprice > 0 AND k.coupon_exp > = GetDate()
  ORDER BY NEWID())

• Unique random number

  Hello

  Oracle 11.2.0.1

  Windows

  I have a table something like this:

  create table (ID, number of rnd) rnd;

  I need a process something like this:

  exec genrnd (200,300);

  After executing the procedure, there will be 100 lines in the table of rnd and there will be unique random numbers in the column of rnd.  OK, suppose if I run once again something like this:

  exec genrnd (173,514);

  therefore table will be truncated and (514-173) + 1 = 342 lines will be rnd table and new unique random numbers will be in the column of rnd.

  Column ID is just at the end of the order of.  There will be 1,2,3... 100 or 1,2,3,4... numbers 342.

  I get random number in this way:

  Select trunc (dbms_random.value (200,300)) rnd twice;

  Select trunc (dbms_random.value (173,514)) rnd twice;

  but number must be unique within the given range, so I don't get how this is possible, please help me.

  Thank you.

  Insert into rnd

  Select rownum, one of

  (

  Select * from

  (

  Select rownum + start_value - 1A

  Double connect rownum<= end_value="" -="" start_value="" +="">

  )

  order of dbms_random.value

  );

  This query has 4 parts

  (1) generation X Y numbers in order

  (2) randomized data generated

  (3) assign a rownum for each row of data

  (4) Insert the result in the table

  So he adapts to the requirements of the opus and don't know how

  > Order by on the insert does nothing

  available in photo with this code.

• 3 display unique and random numbers on 6

  The following program gives me the results in the Panel out because I used the trace.  The problem is I want these numbers when I click on a button.  The numbers do not again when the button is clicked, for example not "3, 3, 2" but "3, 2, 5".»  Here is the program that selects random numbers (which, incidentally, are not mine): (I'll give gladly $15 to the animal charity of your choice for the one who can give me a hand with this problem, thank you!)

  var mynumbers:Array is ['1', '2', '3', '4', '5', '6'];.

  var mystuff:Array = [];

  var randomCount:Number = 3;

  var r: Number;

  for (var i = 0; i < randomCount; i ++)
  {

  r = Math.floor (Math.random () * mynumbers.length);

  Mystuff [mystuff. Length] = mynumbers.splice (r, 1);

  }

  trace (mystuff);

  and here is my button code
  

  generate_btn.addEventListener (MouseEvent.CLICK, coco);

  //3.;
  function coco(event:MouseEvent):void
  {
  }

  Oops, sorry.

  use:

  var mynumbers:Array is ['1', '2', '3', '4', '5', '6'];.

  var randomCount:Number = 3;

  function shuffle(a:Array) {}
  var p:int;
  var t: *;
  var ivar:int;
  for (ivar =. Length-1; Ivar > = 0; Ivar-) {}
  p = Math.Floor ((Ivar+1) * Math.Random ());
  t = a [ivar];
  a [ivar] = a [p];
  a [p] = t;
  }
  }

  and here is my button code
  

  generate_btn.addEventListener (MouseEvent.CLICK, coco);

  //3.;
  function coco(event:MouseEvent):void
  {

  shuffle(mynumbers);
  

  for (var i: int = 0; i<>

  {if(!this["tf_"+i])}

  This ["tf_" + i] = new TextField();

  }

  This ["tf_" + i] .text = mynumbers [i];

  addChild (this ["tf_" + i]);

  This ["tf_" + i] there = i * 40;

  }

  }

  Thanks for the giveaway.  That's very generous of you.

• Choosing random numbers and unique serveral

  Hello
  
  I would select 9 random numbers of a series we'll say 1-20. They cannot repeat and each must be recorded in a different variable P1 - P9.
  
  Any ideas?
  Thank you

  Make a table of numbers 1 to 20.
  Mix the table.
  Remove as many numbers as you need.

  Search the forums for shuffle learn how to mix the table.

• 5 digit unique random number based on the year

  Hello
  I need 5 digit unique random number based on the year. If the new year then duplicate random number allowed.
  Thank you

  If only 5-digit numbers are needed you can extract some transformation injective (http://en.wikipedia.org/wiki/Injective_function) and you could easily check for uniqueness:
  substr (to_char (ln (sequence_value)), 10, 5)
  substr (to_char (exp(1 / sequence_value)), 20, 5)
  ...

  Concerning

  Etbin

• Random numbers appearing in messages

  I am running Firefox 4.0.1 on 64-bit Windows 7 and every time that I post on a forum or send a Gmail account, it adds random numbers at the end of my entry. I tried using Chrome and it doesn't do this, what's the problem?

  You paste content or add a signature?

  Start Firefox in Firefox to solve the issues in Safe Mode to check if one of the extensions of the origin of the problem (switch to the DEFAULT theme: Firefox (Tools) > Add-ons > appearance/themes).

  • Makes no changes on the start safe mode window.
  • https://support.Mozilla.com/kb/safe+mode
  • https://support.Mozilla.com/kb/troubleshooting+extensions+and+themes

• The value of the seed of the generator of random numbers in Matlab node

  Hi all

  I need to use random variables inside a Matlab Labview Commsuite node. I generate with the randn() function. Is it possible to put the seed of the random number generator such as the random numbers are reproducible?

  Hi Steve,.

  You can use randn ('seed', seeds) to initialize the random number generator. The seed must be a positive integer value. For example, randn ('seed', 3). In addition, this seed is global within the entire application. This means that if the randn() function is called MathScript multi-node that could run in parallel, random results are not guaranteed to be the same after you change any part of your code. But you should always get the same results for repeated passages of the same code.

• Medium-sized random numbers

  So what I need to do, is to generate a series of random numbers. I've got that.

  However, the tricky part is that I need to average the random number and the previous 3 numbers random and exit on a waveform graph.

  Any help or pointers would be great. Thank you

  Simple as pie. He called a VI means Pt by PT. set your buffer to 4 and it will be an average intensity absorbed with the last 3.

  

• How to generate random numbers from 1 to 5

  How to generate random numbers from 1 to 5

  -1110340081

  Thank you I ended up

• How the random numbers will be generated

  The "dice" in LabVIEW function is ised to generate random numbers between 0 and 1. If I create a [100000] array with random numbers between 0 and 100, the appearance of 1 to 100 is the same (about 1000 times each), but the appearance of the 0 is only 500.

  So my question is, on the basis of which will be generated random numbers?

  Mitu salvation,

  It is not a problem of the RNG, it's a problem of your function rounded!

  "To U8" allows you to convert the entire random DBL. ToU8 rounds up to the next integer. So all the number of 0-0.5 will get rounded to 0, but all the numbers from 0.5 to 1.5 will get rounded to 1. If you have twice the range of a number rounded to 1 at the beach of rounding to zero - the same goes for your "end of range" with rounding to 100. 100 should be also less likelihood (in your VI) to appear...

  To get the same probability, you should (explicitly) roundpupils before converting in U8!

  BTW. You can also search the forum to get the same answer by searching for "random"...

• I'm trying to generate a table of random numbers 30. After each 5 readings a new vi must open and indicate to the user than 5 readings were made. and continue with the generation of the table again.

  because I don't have a sensor now, I am currently generating a table of random numbers 30. After each 5 readings a warning should be given to the user 5 readngs are completed. This cycle must be repeated. the size of the table is 30.

  Please help me, waiting for response as soon as possible.

  Once I have the transducer, I'll take 30 analog samples and then after each 5 smaples this wraning will be displayed din a new VI

  Use a while loop with a delay time representing your sampling interval.

  Use is equal to the count Terminal to see if 4, then 4th iteration = 5th sample.

  Use a box structure. The real deal will only run on the 4th iteration.

  In the case of true place a Subvi with your message of your choice in the front panel. Go to the properties of the VI window and set ' open the front panel when it is called.

  The condition to closing of attention is not given to your description.

  Consider that rather than usign a Subvi to do this, you can use the "dialog box one/two/three button" or "display message" live in the palette "user interface and dialogue."

  Please try it out and send your own VI. Do not provide us with a working solution.

  Kind regards

• Division of random numbers, see if the result is an integer.

  Simple and yet impossible to find an easy way around it.

  I have 2 RANDOM numbers, I'm dividing them, and I want to see if the result is an integer or not. Basically, I need to know if the divison of random numbers 2 is an integer.

  Who wants KUDOS?

  /SPAW

  Use Quotient and remains, check if the remainder is 0.