A query takes twice as long for an identical database on two separate systems.

Similar Questions

• query takes too long

  Hello
  
  The following query takes too long (more than 30 minutes), work with 11g.
  The table has three columns RID, ida, geometry and index has been created on all of the columns.
  The table has about 5,40,000 documents of point geometries.
  
  Please help me with your suggestions. I want to select the geometry in double point where ida = STRING.
  
  
  SQL > select a.rid, b.rid from totalrecords, totalrecords b where a.ida = 'CORD' and b.idat = 'CORD' and
  sdo_equal (a.geometry, b.geometry) = 'TRUE' and a.rid! = b.rid order of 1,2;
  
  concerning

  Hello

  Just glad it helped, don't forget to award points ;-).

  The SDO_JOIN will use the spatial index for a spatial comparison.
  First of all, it will use the index to check which geometries MBR interact, it is the primary filter: http://docs.oracle.com/cd/B28359_01/appdev.111/b28400/sdo_intro.htm#g1000087

  Secondly, you should apply a space MASK, pair of geometries that comes out of the primary filter is then compared according to the MASK, MASK for example = EQUAL, will check these pair of geoms are equal.

  Now, because you have points, the members are the points themselves, so that if their MBR interact, points to interact, which means they are equal.
  This means that the result of the SDO_JOIN points, in this case even a self-join, will give you all the points that are equal.

  But as points are also equal in their car, the join join reflexive sdo, will give you: a = b & one = one but also a b.
  To this effect, you set the a.rowid< b.rowid,="" to="" avoid="" a="a" but="" also="" b="">

  I hope this explains it a little, again read and read great literature (early!), will have a better understanding.

  Good luck

  Luke

• My computer takes much longer for the initial start as before?

  Original title: startup

  my computer takes much longer for the initial start as before?

  I suggest to do the following:

  (1) Windows Update and install all updates

  (2) run disk clean up and defragnment

  Check disk run 3)

  Check 4) Add/Remove programs and uninstall programs you want

  (5) run full system scan, with:

  http://www.Microsoft.com/security/scanner/en-us/default.aspx

  You can also take a look at:

  http://www.Microsoft.com/atwork/maintenance/speed.aspx

• Why it takes so long for the BlackBerry vendor to deal with accounts?

  Why it takes so long for the BlackBerry vendor to deal with accounts?

  I put in my request 3 days ago, and it has not yet been verified.

  Hello

  Could you please PM me your name of the seller? Do you get the email that asks you to send the document ID/commercial? If this isn't the case, please try to chcek your spam folder.

  Kind regards

  Satya

• Query takes a long time

  Hi Experts

  I'm using Oracle 11 g, I use under delete query to remove records of staging table.

  under query takes a long time (ranging from 1 hour, even there is no record to delete.

  I created payment_id indexes also did not help.

  delete from siebelwb.stg_p where payment_id not in (select * from siebel.s_src_payment)

  I know NOT of IN is degreding performace, is there another way to write above request so that we can remove them in NOT IN use.

  Try to use NOT EXISTS clause...

  Also you inner query must match the payment_id with query parent then here's the example query...

  removal of siebelwb.stg_p where THERE is NO payment_id (select 1 from siebel.s_src_payment where s_src_payment.payment_id = stg_p.payment_id)

• Query takes too long to run after clone

  Hi all
  
  We have a query that works well in our development environment and take about 15 seconds to run the query. When we run the same query with the same parameters in a recently cloned instance, the query takes 1200 dry run.
  Please help us on this issue.
  
  Thank you
  Rambaud

  Thanks for any response.
  We have solved the problem by using indicators of index.

  Thanks for the update!

• Data dictionary query takes too long.

  Hello
  I'm using ORACLE DATABASE 11 g.
  
  The following query takes too long to run and not give the result. As I've tried a few tricks SQL Oracle but it forces developed.
  

  SELECT 
  distinct B.TABLE_NAME, 'Y' 
    FROM USER_IND_PARTITIONS A, USER_INDEXES B, USER_IND_SUBPARTITIONS C
   WHERE A.INDEX_NAME = B.INDEX_NAME
     AND A.PARTITION_NAME = C.PARTITION_NAME
     AND C.STATUS = 'UNUSABLE'
      OR A.STATUS = 'UNUSABLE'
      OR B.STATUS = 'INVALID';

  Please guide me what to do? to run this query in a fast paced mode...
  
  
  Thanks in advance...

  Your query is incorrect. It returns all tables if A.STATUS = "UNUSABLE" or B.STATUS = "INVALID". Most likely, you meant:

  SELECT
  distinct B.TABLE_NAME, 'Y'
    FROM USER_IND_PARTITIONS A, USER_INDEXES B, USER_IND_SUBPARTITIONS C
   WHERE A.INDEX_NAME = B.INDEX_NAME
     AND A.PARTITION_NAME = C.PARTITION_NAME
     AND (C.STATUS = 'UNUSABLE'
      OR A.STATUS = 'UNUSABLE'
      OR B.STATUS = 'INVALID');
  

  But the above will return sous-partitionnee tables not valid/no usable index. He ain't no non-sous-partitioned tables partitioned index/index not valid/not usable with same partitions in the form of tables not partitioned with valid/no unusable indexes. If you want to get any table with indexes not valid/not usable, you outer join that's going to hurt even more performance. I suggest you use the UNION:

  SELECT  DISTINCT TABLE_NAME,
                   'Y'
    FROM  (
            SELECT INDEX_NAME,'Y' FROM USER_INDEXES WHERE STATUS = 'INVALID'
           UNION ALL
            SELECT INDEX_NAME,'Y' FROM USER_IND_PARTITIONS WHERE STATUS = 'UNUSABLE'
           UNION ALL
            SELECT INDEX_NAME,'Y' FROM USER_IND_SUBPARTITIONS WHERE STATUS = 'UNUSABLE'
          ) A,
          USER_INDEXES B
    WHERE A.INDEX_NAME = B.INDEX_NAME
  /
  

  SY.

• Usbarbitrator start running takes TOO long for my taste

  Either at startup or during services.sh restart it takes way more long then I think it should

  Anyone with an idea how to speed it up?

  SEB

  Have you tried 'chkconfig usbarbitrator off' from the command prompt?

• most long time value of service for all registered databases in Oracle enterprise manager

  Hello

  We use the grid control Oracle enterprise manager 11g in our environment.

  I want to capture the long service time values for all the databases that are stored in the grid control.

  Is there any query to get the values of the database of the grid control.

  Please help me.

  Thank you

  Is not a 11g to test, but try mark for the target_name + target_type = "oracle_database' of mgmt$ metric_daily or mgmt$ metric_details, and do a like on metric_column looking for this particular measure... Once you have found the metric_name + metric_column, you can shoot for all the DB.

• Guest operating systems take a VERY long time to start and stop to the bottom/connection

  I have a virtual VSphere version 4.1.0 of the client machine, I have a few top server, when I try to start or to stop them, they can take at least half an hour to do this.

  I really want to get this resolved, because it's way too long for an operating system to start.

  The server I want to talk to is a Windows 2008 64 Bit operating system.

  All the tips are greatly appreciated.

  Thank you

  Then replace the HARD drive.

  My guess is that it's completely unrelated to performance or whatever it is. It's probably a script to shutdown/startup/login or performed during these, making it a matter of the GuestOS. Maybe something trivial like nameserver names insoluble / defective (responses), waiting times of the ICF block or something similar.

  If the system running normal operations are fine, there is no ESX(I) - reason why he should be 'slow' for those own time only. Check the disk latency/throughput/Ops ARE / s when he knows.

• query not using the index for some user

  Hello
  
  I have a query that is running in less than a second for sys, system, or schema owner. However, another user (test_user) take 30 seconds to run the same query.
  
  I certainly dba and privileges identical to test_user as schmea_user, but the result is the same.
  
  I checked
  
  Select * from V$ SYS_OPTIMIZER_ENV;
  
  Both are the same for both users.
  
  I have check the plan to explain to both users. I noticed that for sys/system/schema_owner, the query uses an index, but not the test_user.
  
  All have experience the issue where a user uses an index, but not the other?
  
  Thank you for any assistance.

  Thank you for the display of formatting output, this output is much easier to read.

  One of the first things you notice about the execution plans that is for the owner non-schema "SQL_ID, 0wcs85uywn72m, number of children 1" appears in the output of DBMS_XPLAN, while "SQL_ID 0wcs85uywn72m, child number 0" (the same SQL_ID but a different number of child) appears for the schema owner. "" Whereas the SQL_ID is the same, which indicates that the client requires exactly the same SQL statement, so it's a good start.

  Then, note that in the predicate for the nonschema owner information section the following appears (sometimes with the order of the two conditions switched in position) as a condition placed on each table that is available in the schema:

  filter(("SEAL_FLAG" IS NULL OR "SEAL_FLAG"'Y'))
  

  The above suggests the presence of the virtual private database (or a superset of private database virtual) generated the predicates. You should be able to confirm that this is the case by querying V$ VPD_POLICY using the SQL_ID which was displayed in the DBMS_XPLAN output:

  SELECT
    *
  FROM
    V$VPD_POLICY
  WHERE
    SQL_ID='0wcs85uywn72m';
  

  As a test, I made a few minor adjustments to the example on this page:
  http://Antognini.ch/2011/09/optimizer_secure_view_merging-and-VPD/
  I changed the name of T to T12 and TESTUSER table specified for the schema names. I then created the function S of this page as follows:

  CREATE OR REPLACE FUNCTION s (schema IN VARCHAR2, tab IN VARCHAR2) RETURN VARCHAR2 AS
  BEGIN
    RETURN 'ID < 10';
  END;
  /
  

  I then added a couple of lines in the T12 test table:

  INSERT INTO T12 VALUES (1,1,NULL);
  INSERT INTO T12 VALUES (4,1,NULL);
  INSERT INTO T12 VALUES (10,1,NULL);
  INSERT INTO T12 VALUES (12,1,NULL);
  
  COMMIT;
  

  With an active 10053 trace, I executed the following SQL statement:

  SELECT id, pad
    FROM t12
    WHERE
    spy(id, pad) = 1
  

  The SQL_ID (in my case, found in the 10053 trace file) was 6hqw5p9d8g8wf, so I checked V$ VPD_POLICY to this SQL_ID:

  SELECT
    *
  FROM
    V$VPD_POLICY
  WHERE
    SQL_ID='6hqw5p9d8g8wf';
  
  ADDRESS          PARADDR            SQL_HASH SQL_ID        CHILD_NUMBER OBJECT_OWNER OBJECT_NAME                    POLICY_GROUP                   POLICY                 POLICY_FUNCTION_OWNER          PREDICATE
  ---------------- ---------------- ---------- ------------- ------------ ------------ ------------------------------ ------------------------------ ---------------------- ------------------------------ ------------------------------------------------------------------------------------
  000007FFB7701608 000007FFB7743350 1518838670 6hqw5p9d8g8wf            0 TESTUSER     T12                            SYS_DEFAULT                    T_SEC                  TESTUSER                       ID < 10
  

  As noted above, the VPD test function named S added the predicate "ID".< 10"="" to="" the="" sql="">

  There are not many clues in the 10053 trace file in my test VPD generated additional predicates. Trace the following was found shortly after the beginning of the file (this is the SQL statement initially presented):

  ----- Current SQL Statement for this session (sql_id=6hqw5p9d8g8wf) -----
  SELECT id, pad
    FROM t12
    WHERE
    spy(id, pad) = 1
  

  I searched then down in the trace for final after changes query file (to be noted that this sentence could be slightly different in different versions of database Oracle). That's what I found:

  Final query after transformations: ******* UNPARSED QUERY IS *******
  SELECT "T12"."ID" "ID","T12"."PAD" "PAD" FROM "TESTUSER"."T12" "T12" WHERE "TESTUSER"."SPY"("T12"."ID","T12"."PAD")=1 AND "T12"."ID"<10
  kkoqbc: optimizing query block SEL$F5BB74E1 (#0)
  

  Note that the final query after transformation shows how the final version of the query that has been rewritten by the query optimizer before the SQL statement has been executed and this version of the query includes AND "T12". "" IDENTITY CARD ".<10. if="" i="" was="" attempting="" to="" determine="" how="" that=""><10 predicate="" was="" added="" to="" the="" sql="" statement,="" i="" would="" start="" at="" the="" "current="" sql="" statement="" for"="" line="" in="" the="" trace="" file="" and="" search="" down="" the="" trace="" file="" for=""><10* -="" in="" this="" case,="" the="" following="" is="" what="" i="" found="" as="" the="" first="" search="" result,="" very="" close="" to="" the="" "current="" sql="" statement="" for"="" line="" in="" the="" trace="">

  **************************
  Predicate Move-Around (PM)
  **************************
  PM:     PM bypassed: Outer query contains no views.
  PM:     PM bypassed: Outer query contains no views.
  query block SEL$F5BB74E1 (#0) unchanged
  FPD: Considering simple filter push in query block SEL$F5BB74E1 (#0)
  "TESTUSER"."SPY"("T12"."ID","T12"."PAD")=1 AND "T12"."ID"<10
  try to generate transitive predicate from check constraints for query block SEL$F5BB74E1 (#0)
  finally: "TESTUSER"."SPY"("T12"."ID","T12"."PAD")=1 AND "T12"."ID"<10
  

  As can be seen from the above (because the predicate again appeared before and after the line containing the word "Finally: '), the AND"T12 ". "" IDENTITY CARD ".<10 predicate="" was="" already="" added="" to="" the="" original="" sql="" statement="" by="" the="" time="" the="" predicate="" move-around="" section="" of="" the="" trace="" file="" was="" written,="" and="" that="" is="" the="" first="" mention="" of=""><10 in="" the="" trace="" file.="" in="" your="" case,="" you="" would="" search="" the="" 10053="" trace="" file="">

  "SEAL_FLAG" IS NULL
  

  If V$ VPD_POLICY revealed that there are virtual private database (VPD) generated predicates applied to the SQL statement, take a look at the following article in the Oracle documentation library:
  http://docs.Oracle.com/CD/B28359_01/network.111/B28531/VPD.htm

  This article lists the different points of view, who can be interviewed to learn more about the VPD rules which are in force in the schema. For example, with my SPV test:

  SELECT
    *
  FROM
    ALL_POLICIES;
  
  OBJECT_OWNER                   OBJECT_NAME                    POLICY_GROUP                  POLICY_NAME                    PF_OWNER                       PACKAGE                       FUNCTION                       SEL INS UPD DEL IDX CHK ENA STA POLICY_TYPE              LON
  ------------------------------ ------------------------------ ----------------------------- ------------------------------ ------------------------------ ----------------------------- ------------------------------ --- --- --- --- --- --- --- --- ------------------------ ---
  TESTUSER                       T12                            SYS_DEFAULT                   T_SEC                          TESTUSER                       S                                                            YES YES YES YES NO  NO  YES NO  DYNAMIC                  NO
  

  He knows performance issues related to the use of VPD, some of which are Oracle Database version-dependent, and some have been fixed in recent versions. Take a look at the following articles if you have access to My Oracle Support:
  MetaLink (MOS) Doc ID 728292.1 ' known performance problems when you use transparent encryption data and indexes on the encrypted columns.
  MetaLink (MOS) Doc ID 967042.1 "How to investigate Query Performance regressions Caused by VPD (FGAC) predicates?"

  You might find working through the second of the above that the problem is caused by a bug in database Oracle.

  On a side note. Execution plans you have published include the 0 value in the column starts many of the operations in the execution plan. 0 indicates that the operation never actually executed. A 0 is included in the column starts on the line that includes the FULL ACCESS of TABLE of PEOPLE_TRANSACTIONS at least to the OPC. Value 123, a full table of PEOPLE_TRANSACTIONS table scan PROPERTY_CONTAINER_ID was not actually performed.

  Charles Hooper
  http://hoopercharles.WordPress.com/
  IT Manager/Oracle DBA
  K & M-making Machine, Inc.

• Application of THEME - MAPVIEWER - 05517 JDBC string is too long for Oracle cards-

  Hello
  
  If I need a fairly complex query to add the dynamic JDBC theme I get this error:
  
  [MAPVIEWER-05517] Ask the string is too long for no AJAX of Oracle remote access cards.
  
  -Why? I use Oracle Maps API JS isn't remote AJAX or not?
  -What is the limit of a definition of the JDBC theme?
  
  Kind regards
  Brano

  Put this code after creating object mapviewer.

  MVMapView.enableXMLHTTP (true);

• How long for an application appears in iTunes store?

  Hello

  Already had my approval of Apple and I wanted to start my app in the store.

  Can choose us as the launch date for the day? Otherwise and I choose tomorrow will be time table US?

  How long does take to appear in the store?

  I hope that it is not "within 24 hours"... If if what did U experience? How long for your

  Thank you

  Minia,

  usually, if you do not select a later date for the launch, your application appears in some stores within 1-4 hours.

  See you soon,.

  Tomek

• use marker iff section is too long for the header

  Hello everyone,

  I wonder: is it possible to implement FrameMaker using a marker iff there is one on this page?

  Here's the problem: I have a book with several chapters of different authors. Some of them used topics that are too long for the headers. For those I want to use markers.

  I know how to display markers, which I don't want, because then I have to create a benchmark for each unique position in the book (using this master page). And I know how to view the different titles for example < $paratext [H1, H2, H3] >.

  Now I'm looking for is something like this < [marker, line] $paratext >. In plain language: 'check if there is a certain marker. If there is one, show the marker, otherwise display the heading."

  Then I would be able to use the same master page and would need to use markers only where a title is too long.

  Thanks in advance

  Dennis

  Dennis,

  Take a look at http://forums.adobe.com/message/3503638#3503638

  You could create an alternative heading tag (for example InvisibleH1) with an invisible color in a framework anchored to it and can then use the building block <$paratext[InvisibleH1,H1,H2... etc.]="">. Just toggle the views appropriate to hide text in anchored frames.

• I get charged 2.99 twice a month for 2 applications that I had but deleted a year ago because I was doing charged each month. I'm still get charged the 2.99, applications are removed, how do stop this accusation does not happen?

  I get charged 2.99 twice a month for 2 apps I had, but was removed a year ago because I was doing charged each month. I'm still get charged the 2.99, applications are deleted then, how can I stop this accusation occur and how I get my money back?

  Deleting the application's not cancel subscriptions.

  View, change or cancel your subscription - Apple Support