About JMS transfers the JMS Messages

Similar Questions

• A JMS message is not a property of the unity of the order and a unit of work property

  
  I received this message on my side Client of JMS:

  weblogic.jms.common.JMSException : A JMS message is not a property of the unity of the order and a unit of ownership of the work

  I put only the unit of work properties in what follows.  Don't know why he complains that I put together.

  Joe

  ***************************************************

  message.setStringProperty ("JMS_BEA_UnitOfWork", rMes.getPid ());

  message.setIntProperty ("JMS_BEA_UnitOfWorkSequenceNumber", rMes.getSequence ());

  message.setBooleanProperty ("JMS_BEA_IsUnitOfWorkEnd", rMes.isEnd ());

  } catch (Exception e) {}

  System.out.println ("Unit of work" + e.getMessage ());

  }

  queueSender.send (message, DeliveryMode.PERSISTENT, 7, 0);

  I think I found the answer.  While I was watching Oracle Oracle guru Jeff West of Youtube video, he suddenly appeared to me that I missed the series WL classes JMS.

  Import weblogic.jms.extensions.WLConnection;

  Import weblogic.jms.extensions.WLDestination;

  Import weblogic.jms.extensions.WLQueueSession;

  Import weblogic.jms.extensions.WLMessageFactory;

  Import weblogic.jms.extensions.WLMessageProducer;

  Import weblogic.jms.extensions.WLQueueSession;

  This is the code that actually works!  I changed to PUA, however, based on the characteristics of our company. Now the Weird message of "properties have PUA both UOW" disappeared!

  Joe

  *****************

  package test.viant.edi.translator.messaging.processor.images.impl;

  import java.io.BufferedReader;
  import java.io.FileInputStream;
  import java.io.IOException;
  import java.io.InputStreamReader;
  import java.util.ArrayDeque;
  import java.util.Hashtable;
  to import java.util.Iterator;

  Import javax.jms.DeliveryMode;
  Import javax.jms.JMSException;
  Import javax.jms.Queue;
  Import javax.jms.QueueConnection;
  Import javax.jms.QueueConnectionFactory;
  Import javax.jms.QueueSender;
  Import javax.jms.QueueSession;
  Import javax.jms.Session;
  to import javax.jms.TextMessage;
  to import javax.naming.Context;
  Import javax.naming.InitialContext;
  Import javax.naming.NamingException;

  Import weblogic.jms.extensions.WLConnection;
  Import weblogic.jms.extensions.WLDestination;
  Import weblogic.jms.extensions.WLQueueSession;
  Import weblogic.jms.extensions.WLMessageFactory;
  Import weblogic.jms.extensions.WLMessageProducer;
  Import weblogic.jms.extensions.WLQueueSession;

  public class UOOProducer {}
  private static string = "-1" current group
  private static int currentSeq = 1;

  Public Shared Sub main (String [] args) {}

  Dim queueName = "jms/MsgProcSvc/gisInboundQueue";
  String queueConnectionFactoryName = "jms/MsgProcSvc/jmsMsgProcConnectionFactory";
  Context jndiContext = null;
  Factory Factory = null;
  WLConnection queueConnection = null;
  WLQueueSession queueSession = null;
  Queue queue = null;
  WLMessageProducer queueSender = null;
  TextMessage message = null;
   
  / * Set the environment for a connection to the OC4J instance * /.
  Hashtable env = new Hashtable();
  env.put (Context.INITIAL_CONTEXT_FACTORY,
  "weblogic.jndi.WLInitialContextFactory");
  env.put ("java.naming.rmi.security.manager", "Yes");
  env.put (Context.PROVIDER_URL, "t3: / / localhost:5557, localhost:5558" "");
  /*
  The value of the context object. * Search for the queue connection factory. *
  * Search for the JMS Destination.
  */
  try {}
  jndiContext = new InitialContext (env);
  Factory = jndiContext (Factory)
  . Lookup (queueConnectionFactoryName);
  queue = jndiContext.lookup (queueName) (tail);
  } catch (NamingException e) {}
  System.out.println ("JNDI lookup failed:" + try ());
  System.Exit (1);
  }
  /*
  To create the connection. * Create connection session. * Create
  * sender. To create text message. To send messages. Send some out of text
  the message at the end of the text messages. * Close the connection.
  */

  try {}
  queueConnection (WLConnection) = queueConnectionFactory.createQueueConnection ();
  queueSession (WLQueueSession) = queueConnection.createQueueSession (false,
  Session.AUTO_ACKNOWLEDGE);
  queueSender (WLMessageProducer) = queueSession.createSender (tail);
  message = queueSession.createTextMessage ();
    
    
  try {}
  Open the file
  FileInputStream fstream = new FileInputStream("U:\\114157\\testFile1.txt");
  BufferedReader br is new BufferedReader (new InputStreamReader (fstream));.

  String strLine;
  ArrayDeque messageDeque = null;
     
  Read the file line by line
  While ((strLine = br.readLine ())! = null) {}
  Print content on the console
  System.out.println (strLine);
  String pidOfLine = getpid(2) (strLine);
  EDIMessage em = new EDIMessage();
      
  If (! pidOfLine.Equals (currentGroup)) //If this is a new group or the beginning of the message
  {
       
  If (messageDeque! = null &! messageDeque.isEmpty ()) {}
  EM = (EDIMessage) messageDeque.removeLast ();
  em.setEnd (true);
  messageDeque.addLast (em);
        
  EDIMessage AFFECTS = null;
  The message group is now ready.
  for (Iterator itr = messageDeque.iterator (); itr.hasNext ();)  {
  AFFECTS = (EDIMessage) itr.next ();
  try {}
  message.setText (em.getMessage ());
  message.setStringProperty ("JMS_BEA_UnitOfOrder", rMes.getPid ());
  * message. SetStringProperty ("JMS_BEA_UnitOfWork", rMes.getPid ());
  message.setIntProperty ("JMS_BEA_UnitOfWorkSequenceNumber", rMes.getSequence ());
  message.setBooleanProperty ("JMS_BEA_IsUnitOfWorkEnd", rMes.isEnd ());
  String of PUA = message.getStringProperty ("JMS_BEA_UnitOfOrder");
  String uow = message.getStringProperty ("JMS_BEA_UnitOfWork");
  System.out.println ("PUA:" + PUA);
  System.out.println ("uow:" + uow) ;*/
          
  } catch (Exception e) {}
  System.out.println ("Unit of work" + e.getMessage ());
  }
  System.out.println ("before sending the message:" + AFFECTS + "\n");
  queueSender.send (message);
          
  }

  }
  current group = pidOfLine;
  currentSeq = 1;
  messageDeque = new ArrayDeque();
       
       
  }
      
  What is the new nest or not, fill these values
  em.setPid (pidOfLine);
  em.setSequence (currentSeq);
  em.setEnd (false);
  em.setMessage (strLine);
  messageDeque.addLast (em);
      
         
      
  }

  Close the input stream
  Br. Close();
  } catch (IOException ioe) {}
  System.out.println (ioe.getMessage ());
  }
    
    
  } catch (Throwable e) {}
  e.printStackTrace ();
  System.out.println ("Exception occurred:" + e.getMessage ());
  } {Finally
  If (queueConnection! = null) {}
  try {}
  queueConnection.close ();
  } catch (JMSException e) {}
  System.out.println ("error in closing:" + try ());
  }
  }
  }
  }

  private static String getpid(2) (String sampleString) {}
  int start = nthIndexOf (sampleString, "|", 4);
   
  System.out.println ("start =" + start);
  int end = nthIndexOf (sampleString, "|", 5);
  System.out.println ("end =" + end);
  Return sampleString.substring (start + 1, end);
  }

  public static int nthIndexOf (final String string, final string token
  final int index) {}
  int j = 0;

  for (int i = 0; i)< index;="" i++)="">
  j = string.indexOf (token, j + 1);
  If (j == - 1).
  break;
  }

  return j;
  }

  }

• Reading at the OAG JMS message

  Hello

  I'm trying to read a message of IBM MQ and validate againist a schmea. I am able to read IBM MQ, but I get the error message when posting as below.

  30/Oct/2013:20:46:07.120 [230] fault nested ERROR: no content HTTP in the message:

  java.io.IOException: no content HTTP in the message

  at com.vordel.mime.XMLBody.locate(XMLBody.java:99)

  at com.vordel.mime.XMLBody.getDocument(XMLBody.java:86)

  at com.vordel.circuit.schema.SchemaValidationProcessor.invoke(SchemaValidationProcessor.java:205)

  at com.vordel.circuit.InvocationEngine.invokeFilter(InvocationEngine.java:160)

  at com.vordel.circuit.InvocationEngine.invokeCircuit(InvocationEngine.java:52)

  at com.vordel.circuit.InvocationEngine.processMessage(InvocationEngine.java:241)

  at com.vordel.dwe.jms.JMSConsumer.processMessage(JMSConsumer.java:170)

  at com.vordel.dwe.jms.JMSConsumer.run(JMSConsumer.java:321)

  at java.lang.Thread.run(Thread.java:662)

  Kind regards

  Ganesh

  
  

  Hello Stefen,

  Thanks a lot, with the input data (${jms.message.getText ()} I am able to read XML. JMS now validating schema works fine. reterive the filter element also works very well.)

  you saved my day!

  Kind regards

  Ganesh

• Retrieving ID of the JMS Message using Java

  Hello
  
  I built a sequence flow which is JMS Producer (BPEl)-> Consumer (Bpel) JMS-> composite A Bpel, inserting database. Now, I deliberately blamed the bpel instance. now, I want to enter the instance bpelcomposite faulted consumer id which I was able to do, but also to retrieve the message id jms I have been unsuccessful.
  I imported the javax.jms.Message package and my code is as follows
  / public class FaultHandlingPOC implements IFaultRecoveryJavaClass {}
  
  {} public void handleRetrySuccess (IFaultRecoveryContext ctx)
  
  System.out.println ("this is for the success of the new attempt");
  
  handleFault (ctx);
  
  }
  public String handleFault (IFaultRecoveryContext ctx) {}
  BPELFaultRecoveryContextImpl bpelCtx = (BPELFaultRecoveryContextImpl) ctx;
  Message m = ctx (Message);
  System.out.println ("Instance Composite:" + bpelCtx.getCompositeInstanceId ());
  
  try {}
  System.out.println ("ID of Message JMS" + m.getJMSMessageID ());
  } catch (JMSException e) {}
  System.out.println ("insert failed");
  }
  
  return to "Rise again";
  }
  
  The error generated is class Cast Exception even if I am able to retrieve the Bpel composite instance id
  
  Help, please.

  You can not thrown another IFaultRecoveryContext thing, it's an Interface and it does not do anything:

  public interface IFaultRecoveryContext
  {

  public abstract String getIndex (int i);

  public abstract card getProperties();

  public abstract String getActionId();

  public abstract String getPolicyId();

  public abstract String getActivityType();

  public abstract String getActivityId();

  public abstract String getActivityName();

  public abstract String getWsdlLocation();

  public abstract String getPartnerLinkName();

  public abstract QName getPortType();

  public abstract String getCorrelationId();

  public abstract BPELFault getFault();

  public abstract BPELProcessId getProcessId();

  public abstract String getStatus();

  public abstract void setStatus (String s);

  public abstract String setTitle (String s);

  public abstract String getTitle();

  public abstract int getPriority();

  public abstract setPriority (int i) Sub;

  public abstract getInstanceId() long;

  public abstract Locator getLocator();

  public abstract void addAuditTrailEntry (String s, object obj);

  public abstract void addAuditTrailEntry (String s);

  public abstract void addAuditTrailEntry (Throwable throwable);

  public abstract Object getVariableData (String s)
  throw BPELFault;

  public abstract Object getVariableData (String s, String s1)
  throw BPELFault;

  public abstract Object getVariableData (String s, String s1, String s2)
  throw BPELFault;

  public abstract void setVariableData (String s, Object obj)
  throw BPELFault;

  public abstract void setVariableData (String s, String s1, Object obj)
  throw BPELFault;

  public abstract void setVariableData (String s, String s1, String s2, object obj)
  throw BPELFault;
  }

• JMS Messages, refusing to participate in JTA transactions

  I worked on this issue for several days, and I can't find a path.
  
  I have a situation where I have to write in the database and also to send a JMS message. I want both to work, or nothing works, so it's a simple application of JTA, so I think.
  
  The used JMS connection factory is located to participate in XA transactions (I checked that 10 times).
  
  I originally had a UserTransaction started and committed around these statements, but since that doesn't seem to work, I put all the code in an EJB with transaction required.
  
  Whatever it is, it does not the way I expected.
  
  I have a breakpoint in the MDB which receives the message, but also a breakpoint on the Publisher code, and the code immediately after him. I find whenever as soon as I didn't have the JMS publish, the breakpoint in stops MDB then, indicating that the JMS message has been sent, even if the transaction publishers is certainly not over - finally the debugger will return back to the line after the publication.
  
  I am sure that we have made repeatedly in the past, and it worked as I expect with transaction code works.
  
  Someone has ideas about obvious things to check to determine why the JMS message is outside the transaction? Or not so obvious...
  
  Thanks in advance,
  Ken clark

  Hi Ken,

  You reason - the use case is common, but there are has some pitfalls new users sometimes face.

  The results of tracing of breakpoint you are expected. Message from a sender goes to the JMS server while sending message is called. If the message is involved in the transaction, it is always sent, but it became visible to consumers until the transaction is subsequently committed.

  To ensure that a sent message is involved in a transaction:

  1. ensure that the connection factory is «activé XA»

  2. ensure that there is a transaction on the thread. For example: System.out.println ("MY TX" + weblogic.transaction.TransactionHelper.getTransactionHelper () .getTransaction ());

  3 - ensure that your connection.createSession () invoking past 'false' for the first parameter - not true! If true and that you do not use a resource ref, the session would then become a "transactional" session, and JMS messages will take part in an independent local transaction rather than the overall XA transaction

  4. If not using a WebLogic JMS to send, then you must make sure that WebLogic automatically entered the foreign seller send call in the WL TX. All that is needed is to use a standard JEE 'refers to a resource"to get him CF. rather than directly raising the CF foreign in the foreign JNDI provider. This enables WebLogic detect and wrap calls foreign seller of the application, which in turn allows the automatic registration. See the JMS WebLogic Interop FAQ for more information.

  4 b - If you use AQ - JMS to send, more work is required, since QA - JMS are quite unique among the JMS implementations. WL 10.3.1 and later provides features to simplify this work.

  See for a related FAQ [integrating remote JMS providers | http://download.oracle.com/docs/cd/E15523_01/web.1111/e13727/interop.htm#JMSPG553], and for resources info Ref see [support strengthened using WebLogic JMS with EJB and servlet | http://download.oracle.com/docs/cd/E15523_01/web.1111/e13727/j2ee.htm#g1329180] (especially the 9-5 example).

  Hope this helps,

  Tom

• JMS message filtering

  Hello

  can we filter JMS message form

  
  

  
  

  Thank you

  I could not understand the question, but according to my knowledge, selector of JMS messages is static configuration and must have the exact value at the time of the design itself which is the way it currently works. What you're looking for is "way to assess the selection criteria based on the expression at the time of execution". I don't think that he is currently supported.

  If we descend into thinking more than why this behavior, then we can say that if we want to execute logic, so we have to instantiate who hold the variables and evaluate expressions of a thread, but Message selector is nothing, but subscription so property whenever a Subscriber is stored in the JMS server he hears message based on it and when something specific Vienna then only he initiated a thread for subscriber process further.

  What will be needed in your case, it's this Subscriber subscribe all messages and will initiate the thread and then reject the message based on the logic of the selector within the scope of the processing thread. I don't think it will be good idea because it will instantiate many unnecessary wires in a business solution. This will be equivalent to an if-else in the pipeline early condition to reject unwanted messages. The whole idea of having Message selector must give this responsibility to the subscription instead of the Subscriber. I don't think that selector messages JMS should work this way.

  I hope that I have understood the question correctly and especially the help of details mentioned.

  Kind regards

  Ankit

• Treatment of JMS messages in order one after another

  It's my use case that I wan to implement in OSB.
  
  1. I have a queue that will receive the messages in the huge number of a single sender.
  2. I have a proxy that will read each message and process the message and send it out.
  
  In step 1, I want each message to be read in order and at step 2 end run, then I want to read the next message in the queue.
  
  I need to give an acknowledgement to JMS message processing is complete and it can make the next available message to the proxy.
  
  What is the best option to implement this use case?
  
  Concerning

  The WebLogic jms to order unit is the best approach for this.
  http://download.Oracle.com/docs/CD/E12840_01/WLS/docs103/JMS/uoo.html

• How to send a JMS Message to a process of BPM

  Hi all
  
  I have small question regarding the sending of JMS Message of a bpm process. Is it possible to send a bpm process JMS messages to another bpm process.
  
  I have a scenario in which I need to send a JMS message to a queue, where another process is listening on this queue, and upon receipt of the message in the queue that is created for the process instance.
  
  I know how to listen to the JMS message on the queue, but I did not how to send a message to a process JMS.
  
  Also can I create processes by sending Notification to the process instead of a JMS message. But the creative process isn't a subprocess i.e. a declaration can be addressed through different processes.
  
  
  Any information or the example in this respect would be useful.
  
  Thanks in advance
  
  Published by: user9945154 on April 22, 2009 19:46

  Hello
  Daniel already told you how to send a JMS message.

  To send messages between different processes, you can use the Notification component:
  http://download.Oracle.com/docs/CD/E13154_01/BPM/docs65/standard_components/Fuego/lib/notification/Notification_component.html

  To create an instance of another process, you can use the ProcessInstance:
  http://download.Oracle.com/docs/CD/E13154_01/BPM/docs65/standard_components/Fuego/lib/ProcessInstance/ProcessInstance_component.html

  If you want to create an instance of another process, I recommend you ProcessInstance component because the creation is done in the same transaction. That has advantages:
  1 - is much faster!
  2. it is performed in the same transaction. Thus, you will be sure that the instance has been created.
  3. you don't have to wait until the arrival of the notification. (Sometimes, this reduces the interprocess synchronization)

  Hope this helps,
  Ariel

• o my iphone 6 has been stolen about 3 months ago, lately I ' ve been reciving imessages from someone claiming to be apple with the following message

  My iphone 6 has been stolen about 3 months ago, lately I ' ve been reciving imessages from someone claiming to be apple with the following message

  [Find my iPhone]

  Your identifier Apple was signed to iCloud on iPhone of Berkley Lyon.

  Mac os: ios 9.3.2

  If you think that an unauthorized person accessed your account, please sign in and manage your account by going to. www.Apple.find. *-GPS.me

  [Apple support]

  ------------------------------------

  is it a scam?

  < link published by host >

  Yes. Look at the web address. This isn't an area of Apple.

• In the mail the bar at the bottom of the Inbox window won't slide up to allow the contents of the selected message appear without double click to open it in a separate window. A thinking about it?

  In the mail the bar at the bottom of the Inbox window won't slide up to allow the contents of the selected message appear without double click to open it in a separate window. A thinking about it? I can't find anything in the preferences that relates. The ability to drag the bar just seems jammed.

  Using El Capitan? If so, in Mail, go to preferences-> look at one and activate the option "use the classic setup."

  

• use hotmail, when I go to send a message of the current message Inbox is not transferred to the new message, any ideas

  If you use hotmail, when I go to transfer a message from Inbox the current message is not transferred to the new message, any ideas

  If you would like help with hotmail, please go here:

  http://windowslivehelp.com/product.aspx?ProductID=1

• Get the error message about the file cCNColms.dll missing at startup.

  I get the missing file from cCNColms to C:\windows\when dll I start and after connection as I administer. Can't find any help on the internet. I did a fixboot and have done several analyses. A fixmbr command showed that corruption but a fix can damage the disk partitions. Anyone have any suggestions? Thank you

  Using a Google search, I do not met that DLL and it has a special name, and is in the c:\windows folder so it sounds suspicious to me.  I would say that your system is perhaps currently or has been infected by malware.

  Because the MS Answers forum asks you to zero information on your system when a new question is asked, we know absolutely nothing about your system - and I would skip trying things.

  Read these instructions carefully and see what you can find:

  It is sometimes easy to get rid of the error message by doing something like disable the startup item in msconfig (if you can still find), but I suggest you fix the problem and difficulty not only the symptom of the problem by simply deleting the startup message.

  I would also not recommend you start digging in the registry to try to find the startup item and remove it unless you have a backup of your system or at least a backup of your registry, because there is no 'Cancel' or 'quit without saving changes' option in regedit.  If you make a mistake, that's all.

  These ideas relieve 'rapid' and sometimes risky of the symptom if they not even work at all, but they can't actually solve the problem.  Also, I'd be suspicious of ideas that begin with the words "try."  You don't need to try things, you need to fix things.  You don't need to try ideas that might work, you must do something that will always work all the time.

  Here are the detailed instructions that protect you and solve your problem in the 'right' way.

  There is very little. DLL files that should be loaded from the C:\WINDOWS folder and is not one of them.
  A "Cannot find...". ', ' Failed to start..., "Could not load..." ». "Might not work... "" Cannot run ""error loading... ". "or"specific module could not be found"message at startup is usually related to the malware that has been configured to run at startup, but the referenced file has been removed after a malware scan, leaving behind him a startup item or the registry entry pointing to a file that does not exist.
  It might be a removal of malicious software or an application not installed.  The entry may have a curious looking name since it was probably generated at random when the malware was installed. If you search your system for the referenced file, you may not find.
  Windows attempts to load this file but cannot locate because the file has been deleted for most probably during an analysis of the malware. However, an orphaned associate of remainders of startup parameter or registry entry and tells Windows to load the file when you start or connection.
  So you should delete the referenced entry Windows stop trying to load or run the file. It may or may not be included in the registry, but you can find it.  Autoruns (see below) you get the elements no matter where it is.
  If you just locate and uncheck the item in msconfig, which disables the element but does not remove the reference to the element of false starting your computer.   The msconfig program is not a Startup Manager, that's a troubleshooting tool.  Disabling things in msconfig to put an end to the messages and think that your problem is solved is short-sighted and leave behind him a sloppy XP configuration.  Just disable the display of a start-up error message should not count as a 'solution' to the problem.
  If you are comfortable editing the registry, you can find and remove the reference directly from there or remove it using a popular third-party tool called Autoruns.  The problem can always be found in the registry well.
  Before making any changes to your registry by hand or with third-party tools, don't forget to first make a backup of the registry. There is no cancellation or exit without saving the option in regedit.
  Here is a link to a popular registry backup tool:
  http://www.SnapFiles.com/get/ERUNT.html
  You can also use the Autoruns to find the element of start remains little matter where he's hiding
  .  Autoruns does not install anything on your computer.  It will display all startup locations where the reference may be then you can turn it off or remove it completely.  Here is the download link for Autoruns:
  http://TechNet.Microsoft.com/en-us/sysinternals/bb963902.aspx
  Run Autoruns.exe and wait that he at the end of the filling of the list of entries.
  When the Autoruns is finished scanning your system, it will say "Ready" in the lower left corner.  Autoruns can be a little intimidating to first if you have never seen it before because it displays a lot of information
  .  You are really interested only a few sections.
  The problem is usually to start the system or the user startup entries, then click the connection tab and see if the startup item is there.
  Scroll through the list and look for a boot entry associated files in the error message.
  If you can't find on the connection tab, look in any tab.
  You can also click file, search to search for logon, or any tab for all or part of the name of the element.
  Right-click on the offending entry and choose Remove.  If you are not sure what it is, you can simply disable, restart and if the problem is resolved and then remove the offending entry.  If you don't see it in Autoruns, you may edit the registry and remove the item from your startup folder it.  Autoruns shall display the same information however.
  Given that you had or have an infection, followed with this:
  Perform scans for malware, and then fix any problems:
  Download, install, update and do a full scan with these free malware detection programs:
  Malwarebytes (MMFA): http://malwarebytes.org/
  SUPERAntiSpyware: (SAS): http://www.superantispyware.com/
  They can be uninstalled later if you wish.
  Restart your computer and solve the outstanding issues.

• How can I get rid of the large message on my screen of e-mail about Thunderbirdd birthday?

  The large message covers the bottom of my screen. Thanks for your help!

  The easy answer is to click on one of your messages, and the message text will replace the Start Page in the messages pane.

  If you want that he spread ever to go to the Menu bar and select Tools-Options-general and uncheck the option to display the Start Page.

  No menu bar display? Press the ALT key.

• Why do I get the error message about wmsncs.exe when I start windows?

  When I start my computer, I get an error message asking if I want to report the windows message.  I learned that there is a problem with wmsncs.exe.  I think it is a real question and perhaps malware.  I have Microsoft security are. but running it delivers not report it as security.  I notice that MsMpEng.exe takes up to 100% of the PC resources and I am curious to know if these two issues are linked.

  If you think that maybe it's malware, check out this site for some great instructions.

  http://www.selectrealsecurity.com/malware-removal-Guide/

  I hope this helps.

• Why do I get a message asking about to cancel the Microsoft Safety Scanner when I haven't touched my machine?

  I downloaded the Scanner Microsoft, ran, and as he ran, he came twice to the top with a message box read, "If you cancel the analysis, the tool doesn't scan and clean your computer. Malicious or unwanted software that the tool can help to eliminate can be left on your computer. Are you sure you want to cancel? "I don't understand why it would come once and even twice, because I didn't click anything while the scan is running.  I stopped the scan and disconnected my cable modem and then ran the scan, get the same message twice again.  A reflection as to why it appeared?  XP Home Edition / 32-bit.

  Hello
  Your computer is probably infected by malicious software. Try the sequence of steps 1 and 2 in this virus/malware removal guide: http://www.selectrealsecurity.com/malware-removal-guide
  It contains instructions which will remove the malware more. If you have any questions, just ask me. I hope this helps you.
  Brian

• To remove the error message about the network drive

  I have W7 Home and recently restructured.   I had this problem of reformatting finally a long time ago and it is solved but do not remember how.  Whenever I boot, I get the message "connection impossible network drives.  When I click it, I see the Epson printer has a red X on it and says Epson memory card.  The printer has always shown in my computer, but it works very well.  All I need is to get rid of the error message.  I tried to go into the center of the Action and unclicking on error messages of network firewall but that did not help. I'll print on any solution this time for the next restructuring!  Thanks for any advice.

  Epson support says that since the printer connecting wireless much later that opens Windows, Windows is not see when it starts.  They say that it is a Windows problem, not them.

  To get rid of the error message, I disconnect a right-click on my computer and clicked on the network drive.  I find the error message disappeared and the printer works fine.  I don't know if there's a problem with that.