Application of messaging, calendar and missing persons, using 8.1/Area2.

Tried the community solutions [wsreset.exe takes me to store, my account list of app and allows me to install.  Still does not appear in my applications and the search does not find.  Any other suggestions.

Hi again,

Everything works!  My son (a Microsoft employee) did this: it has implemented a new admin account.  The new account, he has deleted all user accounts and all associated with them and checked the Profile Manager to ensure that nothing was left.  (Prior to his help, I made sure that everything I wanted was registered in the OneDrive.)

Thanks, hope this can help others with the same problem (corrupted Win app Store)

Jean Ward

Tags: Windows

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    TBL ACCOUNT
    ACCOUNT_ID        PAYING_ACCOUNT_ID           PARENT_ACCOUNT_ID
    4571111               4571111                    4571111   
    4571112               4571112                    4571111
    4571113               4571113                    4571111
    3995313               3995313                    3995313
    3996786               3995313                    3995313
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    4571111                Active   
    4571112                Active       
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    3995313                Active     
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    3995313                  3995313             3995313              3995313               0            1               0            1                  0                 1                   0               1
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          4571112            4571112             4571112              4571111               0            0               2            0                  0                 0                   0               0
          4571113            4571113             4571113              4571111               0            0               2            0                  0                 0                   0               0
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    MY_TOTAL_NPR_A          Sum of all child accounts of current account that are NPR (PAYING_ACCOUNT_ID != ACCOUNT_ID)  and in sates considered Active. 
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                                         The TOP account is not included in the sum, only TOP account childs
    
    TOTAL_NPR_A                Sum of all accounts of the structure that are NPR and in sates considered Active. 
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    (
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         ,     a.paying_account_id
      ,  a.account_id
      , a.parent_account_id
         ,     LEVEL                    AS lvl
      , c.customer_status
         FROM     account a inner join customer_status c
      on a.account_id = c.customer_id
         CONNECT BY NOCYCLE     PRIOR a.account_id     = a.parent_account_id
              --AND          account_id          != parent_account_id
    ), DUMMY2 AS
    (
    select g.*  from got_descendants g
    ), DUMMY AS
    (
    SELECT       ancestor_id
    ,       COUNT (CASE WHEN lvl             > 1
                      AND  account_id  = paying_account_id
                And  ancestor_id != account_id
                AND  customer_status = 'A' THEN 1 END)     AS my_total_pr_a
    ,       COUNT (CASE WHEN ancestor_id  = paying_account_id
               AND  customer_status = 'A' THEN 1 END)     AS total_pr_a
    ,       COUNT (CASE WHEN lvl             > 1
                      AND  account_id != paying_account_id
                And  ancestor_id != account_id
                AND  customer_status = 'A' THEN 1 END)     AS my_total_npr_a
    ,       COUNT (CASE WHEN ancestor_id != paying_account_id 
               AND  customer_status = 'A'
               And  ancestor_id != parent_account_id THEN 1 END)     AS total_npr_a
    ,       COUNT (CASE WHEN lvl             > 1
                      AND  account_id  = paying_account_id
                And  ancestor_id != account_id
                AND  customer_status = 'D' THEN 1 END)     AS my_total_pr_d
    ,       COUNT (CASE WHEN ancestor_id  = paying_account_id
               AND  customer_status = 'D' THEN 1 END)     AS total_pr_d
    ,       COUNT (CASE WHEN lvl             > 1
                      AND  account_id != paying_account_id
                And  ancestor_id != account_id
                AND  customer_status = 'D' THEN 1 END)     AS my_total_npr_d
    ,       COUNT (CASE WHEN ancestor_id != paying_account_id 
               AND  customer_status = 'D' THEN 1 END)     AS total_npr_d
    FROM       DUMMY2
    GROUP BY ancestor_id
    )
    SELECT  lpad(' ', 2*level) || ACCOUNT.ACCOUNT_ID AS LEVEL_LABEL, LEVEL, CONNECT_BY_ISCYCLE "Cycle",
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    DUMMY.my_total_pr_a, DUMMY.total_pr_a, DUMMY.my_total_npr_a, DUMMY.total_npr_a,
    DUMMY.my_total_pr_d, DUMMY.total_pr_d, DUMMY.my_total_npr_d, DUMMY.total_npr_d
    from ACCOUNT INNER JOIN DUMMY  ON  ACCOUNT.account_id = DUMMY.ancestor_id
    START WITH ACCOUNT.parent_account_id = ACCOUNT.account_id  
    CONNECT BY NOCYCLE PRIOR ACCOUNT.account_id = ACCOUNT.parent_account_id
    DDL
    CREATE TABLE ACCOUNT
      (
        "CUSTOMER_ID"       NUMBER(20,0) NOT NULL ENABLE,
        "PAYING_ACCOUNT_ID" NUMBER(20,0),
        "PARENT_ACCOUNT_ID" NUMBER(20,0),
        "ACCOUNT_ID"        NUMBER,
        "COMPANY_ID"        NUMBER
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    CREATE TABLE CUSTOMER_STATUS
      (
        "CUSTOMER_ID"     NUMBER(10,0),
        "CUSTOMER_STATUS" VARCHAR2(1 BYTE)
      )
    
    
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    Insert into ACCOUNT (ACCOUNT_ID,PAYING_ACCOUNT_ID,PARENT_ACCOUNT_ID) values (4571112,4571112,4571111);
    Insert into ACCOUNT (ACCOUNT_ID,PAYING_ACCOUNT_ID,PARENT_ACCOUNT_ID) values (4571113,4571113,4571111);
    Insert into ACCOUNT (ACCOUNT_ID,PAYING_ACCOUNT_ID,PARENT_ACCOUNT_ID) values (3996786,3995313,3995313);
    Insert into ACCOUNT (ACCOUNT_ID,PAYING_ACCOUNT_ID,PARENT_ACCOUNT_ID) values (4008375,3995313,3995313);
    Insert into ACCOUNT (ACCOUNT_ID,PAYING_ACCOUNT_ID,PARENT_ACCOUNT_ID) values (3995313,3995313,3995313);
    
    
    Insert into CUSTOMER_STATUS (CUSTOMER_ID,CUSTOMER_STATUS) values (3996786,'D');
    Insert into CUSTOMER_STATUS (CUSTOMER_ID,CUSTOMER_STATUS) values (4008375,'A');
    Insert into CUSTOMER_STATUS (CUSTOMER_ID,CUSTOMER_STATUS) values (3995313,'A');
    Insert into CUSTOMER_STATUS (CUSTOMER_ID,CUSTOMER_STATUS) values (4571111,'A');
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    Insert into CUSTOMER_STATUS (CUSTOMER_ID,CUSTOMER_STATUS) values (4571113,'A');

    Hello

    user11432758 wrote:
    Hi, this is the error msg

    ORA-00904: "O_NUM": invalid identifier
    00904. 00000 -  "%s: invalid identifier"
    

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    ...
    FROM      dummy
    GROUP BY ancestor_id
    ORDER BY  MIN (o_num)
    

    but the model has no column named o_num.

    I'm still not sure that understand what you want to do.
    He gets the results you want from the data sample:

    WITH     got_customer_status     AS
    (
         SELECT  a.account_id
         ,     a.paying_account_id
           ,     a.parent_account_id
           ,     c.customer_status
         ,     CASE
                  WHEN  a.account_id = a.parent_account_id
                  THEN  1
              END     AS is_root
         FROM          account          a
         INNER JOIN     customer_status c  ON     a.account_id = c.customer_id
    )
    ,     got_descendants          AS
    (
         SELECT     CONNECT_BY_ROOT account_id               AS ancestor_id
         ,     paying_account_id
           ,     account_id
           ,     parent_account_id
         ,     LEVEL                              AS lvl
         ,     (CONNECT_BY_ROOT is_root) * LEVEL          AS rlvl
           ,     customer_status
         ,     is_root
         ,     (CONNECT_BY_ROOT is_root) * ROWNUM          AS rnum
         FROM     got_customer_status
         CONNECT BY      PRIOR account_id     = parent_account_id
              AND     account_id          != parent_account_id
    )
    ,     got_my_totals     AS
    (
         SELECT       ancestor_id
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                                  AND  account_id          = paying_account_id
                                 AND  ancestor_id        != account_id
                                 AND  customer_status      = 'A'
                          THEN 1
                      END
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                                  AND  account_id           != paying_account_id
                                       And  ancestor_id      != account_id
                                       AND  customer_status      = 'A'
                          THEN 1
                      END
                   )     AS my_total_npr_a
         ,       COUNT (CASE WHEN lvl             > 1
                      AND  account_id  = paying_account_id
                           And  ancestor_id != account_id
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                      AND  account_id != paying_account_id
                           And  ancestor_id != account_id
                           AND  customer_status = 'D' THEN 1 END)     AS my_total_npr_d
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    ORDER BY  d.rnum
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    Flash Player [click for support]

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    Volumes to back up:

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    [Network] data

    Total size: TB 3.00

    Total number of backups: 82

    An older backup: 21/08/14, 19:49

    Last backup: 30/12/15, 08:39

    Size of backup drive: Excellent

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    1. the present proceedings is a diagnostic test. It doesn't change anything for the better or worse and therefore, by itself, will not solve the problem. But with the help of the results of the tests, the solution may take a few minutes, instead of hours or days.

    The test works on OS X 10.7 ("Lion") and later versions. I do not recommend running it on older versions of Mac OS X. It will do no harm, but it will not do not much good.

    Do not be put off by the complexity of these instructions. The process is much less complicated than the description. You make the tasks more complicated with the computer all the time.

    2. If you do not already have a current backup, please back up all the data before doing anything else. The backup is needed on the general principle, not because of what anyone in the test procedure. Backup is always a must, and when you encounter any kind of problems with the computer, you can be more than the usual loss of data, if you follow these instructions or risk not.

    There are ways to back up a computer that is not fully functional. Ask if you need advice.

    3 here is instructions to run a UNIX shell script, a type of program. As I wrote above, it doesn't change anything. It does not send or receive data over the network. There is no to generate a report on the State of the computer human readable. This report goes nowhere unless you choose to share it. If you prefer, you can act on it yourself without disclosing the contents for me or someone else.

    You should ask yourself if you can believe me, and if it is safe to run a program at the request of a foreign national. In general, no, he's not sure, and I encourage it.

    In this case, however, there are ways for you to decide if the program is safe without having to trust me. First of all, you can read it. Unlike an application that download you and click to start, it is transparent, so any person with the required competence can check what it does.

    You may not be able to understand the script yourself. But variations of it have been posted on this site of thousands of times over a period of years. The site is hosted by Apple, which does not allow it to be used to distribute harmful software. One of the million registered users to have read the script and set off the alarm if it was dangerous. Then I wouldn't be here now, and you would not be reading this message. See, e.g., this discussion.

    Another indication that the test is safe in this threadand this onecan be found, for example, where the comment in which I suggested it was recommended by one of the specialists of the communityApple, as explained here.

    However, if you cannot satisfy yourself that these instructions are safe, do not follow them. Ask other solutions.

    4. here is a general summary of what you need to do, if you decide to go forward:

    ☞ Copy a particular line of text to the Clipboard.

    ☞ Paste into the window to another application.

    ☞ Wait for the test to run. It usually takes a few minutes.

    ☞ Stick the results, which will be copied automatically, in a response on this page.

    These are not specific instructions; just a glimpse. The details are in parts 7 and 8 of this comment. The sequence is: copy, paste, wait and paste it again. You don't need to copy a second time.

    5. try to test in conditions that replicate the problem, to the extent possible. For example, if the computer is slow intermittently, run the test during a downturn.

    You may have started up in safe mode. If the system is now in safe mode and works pretty well in normal mode to test run, restart as usual before running it. If you can test only in safe mode, this.

    6. If you have more than one user and a user is affected by the problem, and the user is not an administrator, and then run the test twice: once under the affected user and one administrator. The results can be different. The user that is created automatically on a new computer, when you start it for the first time is an administrator. If you are unable to log in as an administrator, verify that the user concerned. More personal Mac have only one user, and in this case this section does not apply. Don't log in as root.

    7 load the linked web page (the site "Pastebin.") Press the combination of keys command + A to select all the text, then copy it to the Clipboard by pressing command-C.

    8. start the Terminal application integrated in one of the following ways:

    ☞ Enter the first letters of his name in a Spotlight search. Select from the results (it should be at the top).

    ☞ In the Finder, select go utilities ▹ of menu bar or press the combination of keys shift-command-U. The application is in the folder that opens.

    ☞ Open LaunchPad and start typing the name.

    Click anywhere in the Terminal window to activate it. Paste from the Clipboard into the window by pressing Command + V, then press return. The text that you pasted should disappear immediately.

    9. If you logged in as an administrator, you will be prompted for your login password. Nothing displayed when you type. You won't see the usual points instead of the characters typed. Make sure that caps lock is turned off. Type carefully, and then press return. You can get a warning to be careful. If you make three unsuccessful attempts to enter the password, the test is still running, but it will produce less information. If you do not know the password, or if you prefer not to enter, just press back three times at the password prompt. Yet once again, the script will run.

    If the test takes much longer that usual to run because the computer is very slow, you can be prompted for your password a second time. The permission you grant by entering it will expire automatically after five minutes.

    If you are not logged as an administrator, you will be prompted for a password. The test will run. It just will not do anything that requires administrator privileges.

    10. the test may take a few minutes to run, depending on the number of files you have and the speed of the computer. A computer that is abnormally slow may take more time to run the test. During execution, a series of lines is displayed in the Terminal window like this:

        Test started
            Part 1 of 4 done at: … sec        …        Part 4 of 4 done at: … sec
        The test results are on the Clipboard.
        Please close this window.

    The intervals between the parties will not be exactly the same, but they give an approximate indication of progress.

    Wait for the final message "Please close this window" appears. If you don't see it in about 15 minutes, the test probably won't be all within a reasonable time. In this case, press the Ctrl + C key combination or the point command to stop it. Then go to the next step. You will have incomplete results, but still something. If you close the window of the Terminal, while the test is still running, the partial results will not be saved and you have to start over.

    11. when the test is completed, or if you have stopped it because it was taking too long, leaving the Terminal. The results have been saved to the Clipboard automatically. They do not appear in the Terminal window. Please do not copy from there. All you have to do is start a response to this comment and then paste it again by pressing Command-V.

    At the top of the results, there will be a line that begins with the words «Start time.» If you do not see that, but rather to see a mass of gibberish, you wait for the message "close this window". Please wait and try again.

    If personal information, such as your name or e-mail address, appear in the results, make anonymous before posting. Usually it will be not necessary.

    12. in the validation of the results, you see an error message on the web page: "you have included content in your post that is not allowed", or "the message contains invalid characters." It's a bug in the software which manages this website. Thanks for posting the results of the tests on Pastebin, then post here a link to the page you created.

    If you have an account on Pastebin, please do not select private in exposure menu to paste on the page, because no one else that you will be able to see it.

    13. This is a public forum and others can give you advice based on the results of the test. They speak for themselves, not for me. The test itself is harmless, but what're told you to do maybe not. For others who choose to run it, I do not recommend that you view the results of test on this Web site unless I ask.

    14. the related UNIX shell script is a notice of copyright. ASC readers can copy for their personal use. The whole nor any part can be redistributed.

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    Hi and welcome to the Forums!

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    So I developed an application. It's good enough for my own personal use, and I want to use it all the time. Problem is the debugging token is annoying and I need to renew it every month. How to deploy the application on my device at all times without the need for debugging token?

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    You can also check this link below where SpiritX (community organizer) discussed how to fix the Boot Manager for Windows 7.

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