automatic insertion of the date

I have numbers (3.6.1) (2566)  I used to set up a cell to insert a DATE every day automatically, but I can't find much. Help

Hi Nick,

Today() will provide the current date. It will update every time the table is modified. If you want to insert today's date, and have even tomorrow, try the Insert menu:

Quinn

Tags: iWork

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    Commit complete.
    
    SQL> ed
    Wrote file afiedt.buf
    
      1  select min(date_from)||' - '||max(date_from)
      2  from
      3        (select date_from
      4              ,sum(leap_yr_switch) over (order by date_from) as leap_yr_switch_cnt
      5        from (
      6              select date_from
      7                    ,case when lag(leap_yr) over (order by date_from) != leap_yr then 1 else 0 end as leap_yr_switch
      8              from (
      9                    select date_from
     10                          ,case when mod(to_number(to_char(date_from,'YYYY')),400) = 0
     11                                 or (    mod(to_number(to_char(date_from,'YYYY')),4) = 0
     12                                     and mod(to_number(to_char(date_from,'YYYY')),100) != 0
     13                                    )
     14                           then 1 else 0 end as leap_yr
     15                    from temp_leap
     16                   )
     17             )
     18       )
     19  group by leap_yr_switch_cnt
     20* order by min(date_from)
    SQL> /
    
    MIN(DATE_FROM)||'-'||MAX(DATE_FROM)
    -------------------------------------------
    01-JAN-2010 00:00:00 - 31-DEC-2011 00:00:00
    01-JAN-2012 00:00:00 - 31-DEC-2012 00:00:00
    01-JAN-2013 00:00:00 - 17-AUG-2013 00:00:00
    

    Published by: BluShadow on March 14, 2013 08:51
    a slight correction in the calculation of the leap year, forgotten 100 years being does not leap.

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