By selecting the difference between two images
Hello
I have two photos exactly the same thing that I took using a tripod, studio lighting and general conditions. However, in the second photo, I inserted a subject - in this case a sculpture complex. Photoshop can merge these two images together AND choose so the difference between the two images - in this case the sculpture complex?
Basically, I need to select the sculpture and do not want to spend time manually selecting due to its complexity. I need to separate the background and the sculpture for editing on their own layers.
Thank you
Stephen-CS3
You posted this in the two forums, its been answered in the mac forum.
Tags: Photoshop
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Posted earlier but I think I wasn't clear.
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If you can click on the picture on the left and then the right picture (in a sequence any), then you will get correct answer layer appears...
This single slide have also several issues like this... like date of birth left and right...
Also note how it says answers from users like 1 / 3 if only one has been found corectly then two, such,.
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Grasshopper... a Word to the wise... You double post this question, that will upset just the masters very "advance" whose wisdom looking so humbly.
I replied to your post in the other thread. Go and apply.
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The first image is of the piece, to be hung on a wall or placed on a table.
The second is a photo of the piece after it has been moved, shaken or vibrated during which time particles were moved.
I tried superimposing the two images and see the difference between the layers. The images never seem to perfectly align along the lines of reference drawn in ink on the piece, and I do not understand the presentation of grayscale of the layer mode of difference. I would like to know if anyone has any photographic photoshopic, or insightful ideas on how to capture this specific detail of change. Another big challenge is now the images themselves to the exact distance and exposure to the room at the before and after photos, especially if they were taken in two different places on different dates.
Best I can think of is to load into Photoshop layers >, select the two layers and go Edit > auto alignment of layers. Then to the blending mode of the layer from the top to the difference.
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I wanted to find the difference between two date and time, but my qury is slightest error "invalid number."
select sql_step_num,proc_name,run_seqno,start_date,end_date,(to_char(start_date,'HH24-MI-SS') - to_char(end_date,'HH24-MI-SS') ) as ed from eval.EVAL_RUNTIME_DETAILS where trunc(start_date) = trunc(sysdate) order by sql_step_num;
You try to get the feel between two char strings.
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Try this:select sql_step_num,proc_name,run_seqno,start_date,end_date,numtodsinterval(end_date-start_date,'DAY') as ed from eval.EVAL_RUNTIME_DETAILS where trunc(start_date) = trunc(sysdate) order by sql_step_num;
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Hi gurus,
Hello to everyone. Today, I came with the new requirement.
I need to know the difference between a date and the current date in the formula column application presentation layer.by.
Thank you and best regards,
PratesHi Navin,
TIMESTAMPDIFF function first determines the timestamp component that corresponds to the specified interval setting. For example, SQL_TSI_DAY corresponds to the day component and SQL_TSI_MONTH corresponds to the component "month".
If you want to display the difference between two dates in days using SQL_TSI_DAY, unlike butterflies SQL_TSI_MONTH and so on...
hope you understand...
Award points and to close the debate, if your question is answered.
See you soon,.
Aravind -
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Hello
I'm trying to calculate the distance between two images (A and F - there are other images between A and F), but I can't seem to understand how to make good sense.
Image A.x is "(stage/2)-(A.width/2)" and the image of F.x is "provable - imgSpace" which is a negative value (all images x is a negative value for image A.x). "
In my view, the calculation is F.x - A.x, and although it could be good I still ned the value to be non-negative.
Does anyone know how to do this?
Thanks in advanse...
I think you can find out the distance with this equation,
var len:Numer = Math.abs (A.x - F.x);
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Hello people,
I have a question:
Is it possible to get the layer style settings when I have 1 picture with the layer style and 1 without him.
Let's say I have an icon that's just a House.
[img] http://S6.PostImage.org/xfpzl5hl9/image.PNG [line]
And I have a House with outer glow.
[img] http://S6.PostImage.org/h6un7v2a5/0_h.PNG [line]
Is it possible to get the parameters used in the outer glow?
hosts Ruud.
You will not get the real digital settings, but if you load the two layers in the same document and change the blending mode of the layer that is greater than the difference, you can see the difference between the two images. So:
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The most elegant way to get the difference between two tables - not least!
Hello
Simplified example of what I'm trying to achieve - I have two tables ORIGINAL and REVISED.
My aim is to compare the two, such as; -
When there is data in the two tables I get the difference between the Budget column, and if there is no difference, so I don't want no lines.
When data exists in the ORIGINAL, but not in review, I want to the inverse of the current value of the Budget column.
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I can see how I can do this, see below, but is there a more elegant solution?
Data for the ORIGINAL table
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ENTITY EXPENSE_TYPE DIFFERENCE
------ ------------ ----------
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5 selected lines.
Code current to achieve this, is there a better way?
Thanks a lot for your comments,.select original.entity , original.expense_type , (nvl(revised.budget,0) - original.budget) as difference from original , revised where original.entity = revised.entity(+) and original.expense_type = revised.expense_type(+) and (nvl(revised.budget,0) - original.budget) != 0 union all select revised.entity , revised.expense_type , revised.budget as difference from revised where not exists (select 'x' from original where original.entity = revised.entity and original.expense_type = revised.expense_type) and revised.budget != 0
Robert.
Published by: Robert Angel on January 17, 2012 03:31 to change is not equal to! = - Thanks for the heads upSQL> with original 2 as 3 ( 4 select '801040' entity, '2186' expense_type, 234000 budget 5 from dual 6 union all 7 select '801040' entity, '3001' expense_type, 1000 budget 8 from dual 9 union all 10 select '801040' entity, 'P132' expense_type, 34000 budget 11 from dual 12 union all 13 select '801040' entity, 'P135' expense_type, 43000 budget 14 from dual 15 ) 16 , revised 17 as 18 ( 19 select '801040' entity, '2186' expense_type, 235000 budget 20 from dual 21 union all 22 select '801040' entity, 'P132' expense_type, 34000 budget 23 from dual 24 union all 25 select '801040' entity, 'P139' expense_type, 56000 budget 26 from dual 27 ) 28 select * 29 from ( 30 select nvl(o.entity, r.entity) entity, 31 nvl(o.expense_type, r.expense_type) expense_type, 32 nvl(r.budget,0) - nvl(o.budget,0) budget 33 from original o 34 full join revised r 35 on o.entity = r.entity 36 and o.expense_type = r.expense_type 37 ) 38 where budget <> 0 39 / ENTITY EXPE BUDGET ------ ---- ---------- 801040 2186 1000 801040 P135 -43000 801040 3001 -1000 801040 P139 56000 SQL>
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I have a major problem. I was working on special effects for a film. In After Effects, when I change siggificant, I often have to register under and create a new name so I can go back to the old work if necessary. It comes in a case, I have come back from earlier works. If I use these two files After Effects allows you to create multiple clips of effects. And I do not remember just where you look at it, it is better. Does anyone know a good way to compare the differences between the files?
One thing to keep this conversation on the right way: I know that I did a stupid thing. I've never done this before so can we please not spend a lot of time on how to avoid this problem and stick to how we solve this problem?
If you encounter difficulties to identify differences in the old and new versions, you can use this procedure:
To avoid confusion, I'll call your former company and your most recent compositions CompB comps.
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Place the top layer (CompB) difference.
Now, when you play through the comp, you'll see differences in color at a time where the comparison and CompB are not identical.
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Find the difference between two numbers (DBL)
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Hello
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Rate if this is useful!
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HelloI have a laptop (TotalTime1) which refers to two other cells in the updated hour-shaped (Start1 and 1 to finish).
The formula below is intended to make the difference between the time of departure and of arrival if they are populated.
I had to work unconditionally HasValue, but the formula was calculated when there is no value in the Start1 and Finish1 (due to the time format).
This is the code I have, it is said that there is an error of almost the last line; I'm sorry if I'm posting this in the wrong way, I haven't posted on this forum before but this is:
If (HasValue (Finish1) and HasValue (Start1)) then if (Time2Num (Start1.formattedValue, "HH: mm") < Time2Num (Finish1.formattedValue, "Hh: mm")) then Abs (Time2Num (Start1.formattedValue, "HH: mm")-Time2Num (Finish1.formattedValue, "HH: mm")) / (60 * 60 * 1000) another 24 - ABS (Time2Num (Finish1.formattedValue, "HH: mm")-Time2Num (Start1.formattedValue, "HH: mm")) / (60 * 60 * 1000) endif
Any help would be appreciated.
Cordially Fetachini
you need an another endif at the end (you have nested statement and only 1 endif)
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How to find the difference between two dates in time except Sunday
Hi all
I have a table, as shown below.
I would like to know the difference between same tr_ids create_time, which should give out in hours except Sunday.SQL> select * from test; TR_ID CREATE_TIME CODE -------------------------------------------------- --------------------------------------------------------------------------- ---------- S12341 05-JUN-12 12.20.52.403000 AM 1003 S12342 11-JUN-12 11.15.33.182000 AM 1003 S12342 07-JUN-12 12.00.36.573000 PM 1002 S12343 20-JUN-12 12.34.37.102000 AM 1003 S12343 15-JUN-12 11.34.27.141000 PM 1002 S12344 01-JUL-12 10.01.06.657000 PM 1002 S12344 06-JUL-12 12.01.04.188000 AM 1003 S12341 31-MAY-12 11.20.38.529000 PM 1002
For example:
TR_ID: S12344
1002_Create_time: July 1, 12 PM 10.01.06.657000 (i.e. Sunday)
1003_Create_time: 12.01.04.188000 AM 6 July 12
1002 create time is 22:00 Sunday.
If the query must exclude only the hours of Sunday which is 10 p.m. to Monday 00 h which is 2 Hrs.
I tried the sub query after doing a search on this forum but I am not getting the desired output.
Need help to get the desired o/pSELECT count(*) FROM (SELECT ROWNUM RNUM,tr_id,create_time CT_1002 FROM test c WHERE c.tr_id='S12344' and ROWNUM <= (select (cast(a.create_time as date)-cast((select create_time from test b where a.tr_id=b.tr_id and code=1002) as date)) from test a where a.code=1003 and a.tr_id=c.tr_id) + 1) d WHERE to_char(cast((select create_time from test e where e.tr_id=d.tr_id and code=1002) as date) + RNUM - 1, 'DY') NOT IN('SUN');
Hello
If I unederstand the problem correctly, that's what you want:
WITH got_extrema AS ( SELECT tr_id , CAST (MIN (create_time) AS DATE) AS start_date , CAST (MAX (create_time) AS DATE) AS end_date FROM test GROUP BY tr_id ) SELECT tr_id , start_date, end_date -- If wanted , 24 * ( ( ( TRUNC (end_date, 'IW') -- Count -1 day for every full week - TRUNC (start_date, 'IW') ) / -7 ) + LEAST ( end_date -- If end_date is a Sunday , TRUNC (end_date, 'IW') + 6 -- consider it 00:00:00 on Sunday ) - CASE WHEN start_date >= TRUNC (start_date, 'IW') + 6 -- If start_date is a Sunday THEN TRUNC (start_date, 'IW') + 6 -- consider it 00:00:00 Sunday ELSE start_date END ) AS total_hours FROM got_extrema ;
I guess that you don't need to worry about fractions of a second. As you did in the code you have posted, I am to convert the TIMESTAMP to date values, because of DATE arithmetic and functions are so much better than what is available for timestamps.
Basically, it's just to find the number of days between start_date and end_date and multiplying by 24, with these twists:
(a) 1 day is deducted for each week between start_date and end_date
(b) if End_date is a Sunday, none of the end_date himself hours are counted
(c) If start_date is a Sunday, then all the start_date himself hours are counted. Why these hours should be counted? Because 1 day is already being deducted for the week which includes start_date, which contains only this Sunday.TRUNC (dt, 'IW') is the beginning of the ISO week containing dt; in other words, 00:00:00 the or before the dt last Monday. This is not the NLS parameters.
Of course, I can't test without some sample data and the exact results you want from these data. You may need a little something more If start_date and end_date are both on the same Sunday.
Whenever you have a problem, please post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) of all of the tables involved.
Also post the results you want from this data, as well as an explanation of how you get these results from these data, with specific examples.
Always tell what version of Oracle you are using.
See the FAQ forum {message identifier: = 9360002} -
Dynamic action - Get the difference between two dates + times
I have problems a little dynamic to work action. I'm trying to get the time between two dates with the time difference.
Here is what I got (this is apex 4.0):
Two date pickers + two numbers fields (date/start/end times)
I created a dynamic action on the page who fires on the point lose focus (above points).
The real action for the DA is the body of the PL/SQL function:
When I change the values on the page, I get the following error:declare end_date DATE; start_date DATE; Begin start_date := to_char(:P1_START_DATE || ' ' || :P1_START_TIME, 'DD-MON-YYYY HH:MIAM'); end_date := to_char(:P1_END_DATE || ' ' || :P1_END_TIME, 'DD-MON-YYYY HH:MIAM'); :P1_HOURS := end_date-start_date; End;
AJAX call back Server error ORA-06502: PL/SQL: digital or value error: character number conversion error to set the value.
I'm guessing that there is a problem with the date formatting, but I can't make it work. Thanks in advance!Hi djston,
because you chose the dynamic action of 'Set value' with the "Body of the PL/SQL function" type you need to return the value. Try the following code
declare end_date DATE; start_date DATE; Begin start_date := to_date(:P1_START_DATE || ' ' || :P1_START_TIME, 'DD-MM-YYYY HH:MIAM'); end_date := to_date(:P1_END_DATE || ' ' || :P1_END_TIME, 'DD-MM-YYYY HH:MIAM'); RETURN (end_date-start_date)*24; End;
and P1_REQUESTED_HOURS like 'item affected. "
Concerning
Patrick
-----------
My Blog: http://www.inside-oracle-apex.com
APEX 4.0 Plug-Ins: http://apex.oracle.com/plugins
Twitter: http://www.twitter.com/patrickwolfPublished by: Patrick Wolf on January 17, 2011 10:54
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How to tell the difference between two dates
Hello:
I have a question on how to get the difference in quantities for two dates in the replies and dashboard.
This is the scenario. I have two guests date and three columns. The first column must be the sum of the amounts for the first quick date. The second column should be the sum of the amounts for the second fast date. And the third column is the difference between the first two columns.
Basically, I'm trying to do something similar to a function of sum of two lines but trying to get the difference between the two rows. Any help to solve this problem would be appreciated.Use the COLUMN FILTERS level...
the first column with the first variable of date quick presentation of the filter
Similarly, the second column in the second variable of quick overview of date filter
Kind regards
Rambeau
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