Calculate date/day between 2 days/dates

Similar Questions

• Calculate business hours between 2 dates with negative numbers

  Hi all

  I use a function to calculate the difference between 2 dates schedules. The function was taken and adapted from this thread:

  Calculate business hours between two dates in a cursor

  CREATE OR REPLACE
  FUNCTION get_bus_minutes_between(
                                   p_start_date DATE,
                                   p_end_date DATE
                                  )
    RETURN NUMBER
    IS
        v_return NUMBER;
    BEGIN
        with t as (
                   select  case level
                             when 1 then greatest(p_start_date,trunc(p_start_date) + 9 / 24)
                             else trunc(p_start_date) + level - 15 / 24
                           end start_dt,
                           case connect_by_isleaf
                             when 1 then least(p_end_date,trunc(p_end_date) + 20 / 24)
                             else trunc(p_start_date) + level - 4 / 24
                           end end_dt
                     from  dual
                     connect by level <= trunc(p_end_date) - trunc(p_start_date) + 1
                  )
        select  sum(greatest(end_dt - start_dt,0)) * 24 * 60 work_minutes
          into  v_return
          from  t
          where trunc(start_dt) - trunc(start_dt,'iw') < 5; -- exclude weekends
        RETURN v_return;
    END;
    /

  I am running into an issue that when the p_end_date is before the p_start_date value the function returns the full time between the dates without regard for business hours. if the end_date is before the start date I get the expected result i.e. difference between the dates in business hours.

  Using example dates of start 19th October 2012 13:00:00 and end 22nd october 2012 13:21:00 the business minutes are 681. However if i reverse the dates I get -4341.

  


  Correct labour code is the following, I've annotated so that he could help someone else looking for a solution like this:

  CREATE OR REPLACE
  FUNCTION get_bus_minutes_between(
                                   p_start_date DATE,  --these are the 2 dates passed into the function
                                   p_end_date DATE     --these are the 2 dates passed into the function
)
RETURN NUMBER
IS
v_return NUMBER;

          l_start  DATE;

          l_end    DATE;

          l_factor NUMBER;
    BEGIN

          IF p_start_date <= p_end_date THEN            --this IF section checks which of the 2 dates is the greatest


             l_start  := p_start_date;                  -- and then assigns the earliest date to p_start_date


             l_end    := p_end_date;

             l_factor := 1;

          ELSE   -- swap the dates around, and multiply the result by -1

             l_start  := p_end_date;

             l_end    := p_start_date;

             l_factor := -1;

          END IF;


          with t as (
                   select  case level
                             when 1 then greatest(l_start,trunc(l_start) + 9 / 24)  -- this sets the start of working hours
                             else trunc(l_start) + level - 15 / 24  --if the start time is adjusted this value must also be adjusted
                           end start_dt,
                           case connect_by_isleaf
                             when 1 then least(l_end,trunc(l_end) + 20 / 24)  -- this sets the end of working hours
                             else trunc(l_start) + level - 4 / 24  -- if the end time is adjusted this value must also be adjusted
                           end end_dt
                     from  dual
                     connect by level <= trunc(l_end) - trunc(l_start) + 1
                  )
        select  sum(end_dt - start_dt) * 24 * 60 work_minutes  -- this subtracts the 2 dates and then multiplies by hours and minutes
          into  v_return
          from  t
          where trunc(start_dt) - trunc(start_dt,'iw') < 5; -- this exclude weekends
        RETURN v_return * l_factor;  -- this gives the negative or positive results so you can see if it was completed before or after the required date.
    END;
    /

• How to calculate the difference between a Date column and the Date yesterday in the analysis (in the formula in the column)

  . For example, I need to calculate the difference between a date column, 'Table_Name '. "' Column_Name ' and (Current_Date-1). I tried different ways to do this. But nothing seems to work.

  Try the below formula.

  Replace "Time". "" Date "with your column.

  TIMESTAMPDIFF (SQL_TSI_DAY, "Time". "Date", TIMESTAMPADD (SQL_TSI_DAY-1, CURRENT_DATE))

  Thank you!

• Calculate business hours between two dates in a cursor

  Hello, its me again (?).
  
  Yesterday, I got a solution to a problem here where I need to calculate the hours between two dates, excluding Sat/Sun and from 09:00 to 18:00. I'm now putting this login in a PL/SQL block, so I can calculate it for each record in a slider, all by looping.

  with t (start_date
         ,end_date
         )
  as (select  to_date('22-oct-2012 09:00:00','dd-mon-yyyy hh24:mi:ss') start_dt,
                         to_date('23-oct-2012 09:00:00','dd-mon-yyyy hh24:mi:ss') end_dt
      from dual
     )
  , hrs (dt) as
    (select start_date
     from   t
     union all
     select dt +1/24/60
     from   hrs
     where  hrs.dt < (select end_date-1/24/60 from t)
    )
  select count(*)/60
  from hrs
  where to_char(dt,'dy') not in ('sat','sun')
  and  to_number(to_char(dt,'hh24')) not between 18 and 23
  and  to_number(to_char(dt,'hh24')) not between 0 and 8
  /

  The logic above, I'm up here:

  FOR c_record IN c_1 LOOP
  //For each record, check if the two dates meet the criteria and then raise the counters accordingly
  select  to_date(c_record.REPORTADA,'dd-mon-yyyy hh24:mi:ss') INTO vFch1 FROM DUAL;
  SELECT  to_date(c_record.INICIOREAL,'dd-mon-yyyy hh24:mi:ss') INTO vFch2 FROM DUAL;
  
  IF ((vHoras > 2) AND c_record.PRIORIDAD=3) THEN
    vContOk :=vContOk + 0;
    vContBad := vContBad+1;
    vContOt   := vContOt+1;
  ELSE 
    vContOk :=vContOk +1;
    vContBad := vContBad+0;
    vContOt   := vContOt+1;
  END
      IF;
  
  IF ((vHoras > 4) AND c_record.PRIORIDAD=2) THEN
    vContOk :=vContOk + 0;
    vContBad := vContBad+1;
    vContOt   := vContOt+1;
  ELSE
    vContOk :=vContOk +1;
    vContBad := vContBad+0;
    vContOt   := vContOt+1;
  END IF;
  
  IF ((vHoras > 16) AND c_record.PRIORIDAD=1) THEN
    vContOk :=vContOk + 0;
    vContBad := vContBad+1;
    vContOt   := vContOt+1;
  ELSE
    vContOk :=vContOk +1;
    vContBad := vContBad+0;
    vContOt   := vContOt+1;
  END IF;
  
  END LOOP;

  I really don't like if the performance is horrible because it will run once a month and should spend only 40-100 records.
  However, I can't find a way to use this connection even in this case
  
  Could you help me?
  Thank you!
  
  Greetings,
  NACEUR

  N wrote:
  I need to calculate the number of minutes between two dates, only count the hours from 9 to 18hs.

  CREATE OR REPLACE
    FUNCTION get_bus_minutes_between(
                                     p_start_date DATE,
                                     p_end_date DATE
                                    )
      RETURN NUMBER
      IS
          v_return NUMBER;
      BEGIN
          with t as (
                     select  case level
                               when 1 then greatest(p_start_date,trunc(p_start_date) + 9 / 24)
                               else trunc(p_start_date) + level - 15 / 24
                             end start_dt,
                             case connect_by_isleaf
                               when 1 then least(p_end_date,trunc(p_end_date) + 18 / 24)
                               else trunc(p_start_date) + level - 8 / 24
                             end end_dt
                       from  dual
                       connect by level <= trunc(p_end_date) - trunc(p_start_date) + 1
                    )
          select  sum(greatest(end_dt - start_dt,0)) * 24 * 60 work_minutes
            into  v_return
            from  t
            where trunc(start_dt) - trunc(start_dt,'iw') < 5; -- exclude weekends
          RETURN v_return;
  END;
  /
  

  For example:

  SQL> select get_bus_minutes_between(
    2                                 to_date('20-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss'),
    3                                 to_date('22-oct-2012 13:21:00','dd-mon-yyyy hh24:mi:ss')
    4                                ) work_minutes
    5    from dual
    6  /
  
  WORK_MINUTES
  ------------
           261
  
  SQL> 
  

  SY.

• Calculate the days of salary

  Dear friend
  
  
  I want to calculate the days of salary. We pay the salaries of the 21st of the month last to the 20th of the current month.
  
  I want to create a view where it will show of the the Scriptures based on this month wise condition
  
  Select empno, name, daytype, count (empno) days, MAX (TO_CHAR (ADATE, 'MONTH')) in dailyattendence
  When al > =('20-OCT-2010') AND ADATE < =('20-NOV-2010')
  Group by empno, daytype
  order by empno
  
  
  for ex
  
  562 SEUN BÉLANGER AFTERNOON OCTOBER 1
  562 SEUN BÉLANGER MORNING OCTOBER 2
  562 SEUN BÉLANGER NIGHT OCTOBER 2
  562 SEUN OFF BÉLANGER 1 OCTOBER
  
  562 SEUN BÉLANGER AFTERNOON NOVEMBER 1
  562 SEUN BÉLANGER MORNING 2 NOVEMBER
  562 SEUN BÉLANGER NIGHT NOVEMBER 2
  562 SEUN OFF BÉLANGER 1 NOVEMBER
  
  Suggest me how to set the dates so that I can get the report as shown above,
  
  Sandy

  It doesn't really have anything to do with the forms, but here's a solution.
  To get the 21st of the month before you use:

  select to_date('21'||to_char(add_months(sysdate,-1),'mmyyyy'),'ddmmyyyy')
  from dual;
  
  TO_DATE('
  ---------
  21-OCT-10
  

  The same for the 20th of this month. So you get:

  where adate between to_date('21'||to_char(add_months(sysdate,-1),'mmyyyy'),'ddmmyyyy')
     and to_date('20'||to_char(sysdate,'mmyyyy'),'ddmmyyyy')
  

  An addition: If your date includes a time, you must use the use trunc (date).

  Published by: InoL on November 11, 2010 12:10

• Flash Template that follow and calculate data?

  I am interested in creation of this emerging and calculate data and give detailed results based on the answers.  Is it possible to create, follow and make this comment in Flash?  Something like the personality test followed.

  I don't know what you mean... Flash is an aspect of Quiz, but you can also create quizzes using Flash.  You will need to learn a bit of everything that involves Flash.  Your main goal to achieve this feature will learn Actionscript and how to interact with a resource of data such as a database of Flash.  He must also learn to use a scripting language on the server, such as PHP, to handle exchanges between the Flash and the database side.

  If you are a beginner with Flash, you have much to learn before you can expect something like what you say you want to create.  If you are a beginner in programming, even more.

• Calculate the difference between the subtotals

  I'm working on a simple report that looks like this:
  
  EmployeeID EmployeeName Date salary wages
  1234 Tom June 1, 2009 $2000.00
  2345 harry $2400,00 June 1, 2009
  3456 sally $3000.00 June 4, 2009
  Partial total salary: $7400,00
  
  Advances of salary Date EmployeeID EmployeeName
  2345 harry $1000.00 may 15, 2009
  3456 sally $750.00 may 15, 2009
  Advances subtotal: $1750,00
  Total: $5650,00
  
  Is there any function in Discoverer, which calculates the difference between subtotals and the poster as a total. Please advise if you can create a named for this sum calculation?
  
  Published by: user1049091 on August 6, 2009 11:33
  
  Published by: user1049091 on August 6, 2009 12:38

  Hello

  Not really possible. You the best approach is probably to create a named calculation that contains the difference: for example

  Decode (salary_type, 'Pay', 'Progress', - wages)

  Then create a total on this calculation. You can often hide the calculation itself in terms of formatting and white text on white background.

  Rod West

• Need help to calculate the difference between times

  Hi all
  
  I have two fields that stores just the hour in 24-hour ex: 08:00 and 20:00 now I want to calculate the difference between two times
  
  Kindle help me
  
  Thanks for your help
  
  Thank you
  Ravi

  Hello

  diiference in hours

  SQL> WITH T AS (SELECT '08:00' ST_TIME, '20:00' END_TIME FROM DUAL)
    2  SELECT (TO_DATE (END_TIME, 'HH24:MI') - TO_DATE (ST_TIME, 'HH24:MI')) * 24 DIFF_HOURS
    3    FROM T;
  
  DIFF_HOURS
  ----------
          12
  
  SQL> 
  

  G.

• FormCalc - how to calculate the difference between the two fields datetime in hh: mm?

  Hello!

  I am building a form of time sheet in which I need to calculate the difference between the start and end times and present the result.

  I'm trying to do with FormCalc but if it is easier with JS is ok too.

  So that's what I did on the total field, by using the calculate on a NUMERIC field called decimalValue event:

  elapsed = Time2Num (endTime.formattedValue, "HH: mm")-Time2Num (startTime.formattedValue, "HH: mm")

  And then I tried to convert a time field:

  Total = decimalValue.rawValue;

  $.formattedValue = Num2Time (total, "HH: mm")

  Well, it doesn't work, it gives me crazy results in the datetime (total) field. If I type 09:00 and 09:30, the final result is... 22:30. Huh?

  Please, could someone help me understand how this thing works?

  Thanks a lot for the tips!

  Marcos

  Hi Marcos,

  Here are some examples:

  https://Acrobat.com/#d=kCPIgVkd09qrx6h-WRXxbQ

  https://Acrobat.com/#d=EsWqBMBt3sgEXnMSsK5pRA

  Hope that helps,

  Niall

• calculate the days remaining until a given date

  Hello

  I am facing a problem and can not find a good solution.

  I want to calculate how many days there are still up to a certain date.

  It is because I want to build in a callback to the re-kalibrate hardware which is used every year.

  So if it's today 05/11/2012, and the constant is 21/05/2012 labview must calculate there are still 10 days left before the re-kalibration must be finished.

  Someone has any idea how to do this?

  Thanks in advantage!

  of course, don't forget that time stamps are DBL in seconds.

  

  Hope this helps

• calculate data for the last 30 days according to the date of sys

  SELECT DT, ITEMCODE, ITEMNAME, QTY
  FROM   TABLE1

  In above given the query, how do I calculate the details of the amount of the last 30 days, APR, MAY, and JUNE
  
  As the month during JULY, August, the amount of detail is required for the last 30 days (from sysdate), MAY, JUNE, July
  
  Please suggest.
  
  Yogesh
  
  Published by: user12957777 on July 28, 2010 03:16

  Hello

  CASE expressions can filter data in specific columns:

  SELECT     SUM ( CASE
              WHEN dt >= ADD_MONTHS ( TRUNC (SYSDATE, 'MONTH')
                           , -3
                           )
              AND  dt <  ADD_MONTHS ( TRUNC (SYSDATE, 'MONTH')
                           , -2
                           )
              THEN qty
             END
           )          AS third_month
  ,     SUM ( CASE
              WHEN dt >= ADD_MONTHS ( TRUNC (SYSDATE, 'MONTH')
                           , -2
                           )
              AND  dt <  ADD_MONTHS ( TRUNC (SYSDATE, 'MONTH')
                           , -1
                           )
              THEN qty
             END
           )          AS second_month
  ,     SUM ( CASE
              WHEN dt >= ADD_MONTHS ( TRUNC (SYSDATE, 'MONTH')
                           , -1
                           )
              AND  dt <               TRUNC (SYSDATE, 'MONTH')
              THEN qty
             END
           )          AS last_month
  ,     SUM ( CASE
              WHEN dt >= TRUNC (SYSDATE) - 30
              AND  dt <  TRUNC (SYSDATE)
              THEN qty
             END
           )          AS last_30_days
  FROM     table1
  ;
  

  You can do this with GROUP BY, in addition, if you want to separate for each itemname (for example) lines.

  I guess some things, like what do you mean by the last 30 days.

  If you wish to post a few 9creation TABLE or INSERT sample data) and the results you want from this data, then I could test this.

• calculate the day of the year using the date.

  Hi all
  Can calculate us the day of the year using the date form? Is this possible? Please help me thanks in advance
  Like this
  30/08/2009-30/08/2010 after calculation - 365
  
  
  Sarah
  
  Published by: SarahSarahSarah on August 30, 2009 12:49 AM

  Sarah.

  : ins1.noday must be a part of number!

  Create a function in forms like this:

  function get_nodays ( f_dtm_start in date,
                        f_dtm_end   in date ) return number is
  begin
  if
    f_dtm_start is null OR
    f_dtm_end is null
  then
    return ( null );
  end if;
  return ( trunc ( f_dtm_start ) - trunc ( f_dtm_end ) );
  exception when others
  then message ( sqlerrm || ' in function get_nodays occured.' );
  return ( null );
  end;
  

  Call this function in the when-validate-point triggers on ins1. INSPERIOD and: ins1.end love

  :ins1.noday := get_nodays ( :ins1.INSPERIOD, :ins1.end );
  

  It is redundant to have the: noday as a cause of part of database
  the value may by calculated every time using the values INSPERIOD and: end.

• How to calculate the days with 2 Date/time fields

  Hello
  I tried to create a workflow to update a numeric field with the following formula, however, I get an error message "value too long for the field 'ZNum_0' (maximum size 16) (SBL-DAT-00235). Can I know what is the problem with my calculation?
  
  dtCloseDate - dtAssignDate
  
  Thank you

  Hi, your formula is correct.

  You could be facing this problem because it will assess the value in decimal and result has no set limit for the decimal point. As digital field accept only 16 characters, the problem is occure.

  You must truncate the result with a defined decimal.

  Hope this will help you
  Dinesh

• How to calculate the difference between 2 dates, but with interruptions and stops between

  Hello

  How can I calculate the difference in minutes between 2 dates but taking into account the existence of a table in the Appendix, so if between start_date and end_date arguments, there is no 'work time' then this part of the time will not be included in the total difference.

  Records of the time table example:

  Time_configuration	start_hour	end_day	end_hour
  2	19:00	3	07:00
  3	19:00	4	07:00

  so for example first record said that on Monday you start at 19:00 and leave the next day at 7:00 and then save the same sort of thing.

  There is an event that I want to track how many minutes lasted. for example, this event began the day 2 at 19:00 and ended the day 3 at 21:00

  Theoretically, this event really lasted: 840 minutes. This 840 minutes are within the limits of the annex.

  Thanks in advance.

  The storage of the dates not as data type DATE in most cases is bad design. In addition, how do you know what day of the date is 2 at 19:00? East - Monday 2 November 2015 or Monday, March 7, 2016? It is the same for the event. In any case, assuming that both calendar and events don't extend over several weeks:

  According to schedule)
  Select time_configuration 2, 19:00 ' start_hour, end_day 3,' 07:00 ' end_hour of all the double union
  Select 3, 19:00 ', 4,' 07:00 ' double
  ),
  event like)
  Select event_id 1, time_configuration 2, 19:00 ' start_hour, end_day 3: 21:00 ' end_hour of the double
  )
  Select e.event_id,
  Sum)
  less (e.end_day + to_date (e.end_hour, 'HH24'), s.end_day + to_date (s.end_hour, 'hh24:mi')).
  greater (e.start_day + to_date (e.start_hour, 'HH24'), s.start_day + to_date (s.start_hour,'hh24:mi'))))
  ) * 24 * 60 minutes
  Appendix s,
  e event
  where e.start_day + to_date(e.start_hour,'hh24:mi')< s.end_day="" +="">
  and e.end_day + to_date(e.end_hour,'hh24:mi') > s.start_day + to_date(s.start_hour,'hh24:mi')
  E.event_id group
  /

  EVENT_ID MINUTES
  ---------- ----------
  1 840

  SQL >

  SY.

• Calculate the hours between 2 business days

  Hi all

  Do a complex calculation on the days I do not know how to achieve this.

  Here is my case:

  I have a week of work with hours of work.

  

  Then there's this delivery time sheet for how long should be set an order ready to be delivered:

  Order1: max 5 hours of work

  Order2: max 8 working hours

  Order3: max 16 hours of work

  When an order is placed, the time of the order is recorded, and when an order has been set in ready to be delivered, this time is also registered.

  How to calculate the time difference between the time where an order has been placed and the time where the order has been on loan. Thereby also taking into account the working days and hours of work.

  Example: type order1 order was placed Tuesday at 15:00.

  Order has been fixed loan Wednesday at 14:00

  This means that to fix this ready order lasts 7 hours, which means that it is 2 hours time.

  CREATE TABLE REF_WORKDAYS
    (
      
      "WERKDAG"       VARCHAR2(15 ) NOT NULL ENABLE,
      "SOORT_WERKDAG" VARCHAR2(15 ) NOT NULL ENABLE,
      "BEGIN_TIJD"    VARCHAR2(10 ) NOT NULL ENABLE,
      "EIND_TIJD"     VARCHAR2(10 B) NOT NULL ENABLE,
      
    )
  

  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Monday','WORKINGDAY','08:00','16:00');
  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Tuesday','WORKINGDAY','08:00','16:00');
  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Wednesday','WORKINGDAY','08:00','16:00');
  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Thursday','WORKINGDAY','08:00','16:00');
  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Friday','WORKINGDAY','08:00','16:00');
  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Satrurday','WORKINGDAY','08:00','14:00');
  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Sunday','NOT-WORKINGDAY','08:00','16:00');
  
  COMMIT;
  

  create table glas_order
  
  (order_id number
  , order_desc varchar2(100) not null
  , order_type varchar2(10) not null
  , order_date date not null
  , order_ready date
  
  );
  

  Insert into GLAS_ORDER (ORDER_ID,ORDER_DESC,ORDER_TYPE,ORDER_DATE,ORDER_READY) values (1,'order bla','Order1',to_date('07-APR-15 09:00','DD-MON-RR HH24:MI'),to_date('08-APR-15 12:00','DD-MON-RR HH24:MI'));
  Insert into GLAS_ORDER (ORDER_ID,ORDER_DESC,ORDER_TYPE,ORDER_DATE,ORDER_READY) values (2,'order nice','Order1',to_date('14-APR-15 10:00','DD-MON-RR HH24:MI'),to_date('16-APR-15 16:00','DD-MON-RR HH24:MI'));
  Insert into GLAS_ORDER (ORDER_ID,ORDER_DESC,ORDER_TYPE,ORDER_DATE,ORDER_READY) values (3,'order ugly','Order2',to_date('18-APR-15 13:00','DD-MON-RR HH24:MI'),to_date('21-APR-15 09:00','DD-MON-RR HH24:MI'));
  
  COMMIT;
  

  Thank you

  Diana

  Select

  I like order_id

  such as length d

  order_type

  d decode(order_type,'Order1',5,'Order2',8)

  overtime

  of glas_order o

  model

  Reference r on

  (select

  WERKDAG w

  begin_tijd b

  e eind_tijd

  , (to_date (eind_tijd, 'HH24') - to_date (begin_tijd, 'HH24')) * 24 hard

  of ref_workdays

  where soort_werkdag = "WORKINGDAY")

  dimension (w)

  measures (b, e, hard)

  main m

  partition of (order_id I)

  size of (0 n)

  measures (0d, order_date, order_ready, cast (null as varchar2 (10)) as wday, order_type)

  iterate (1e6) rules until (iteration_number > = trunc(order_ready[0]) - trunc(order_date[0])))

  WDAY [0] = to_char (order_date [0] + iteration_number, 'FMDay', 'NLS_DATE_LANGUAGE = ENGLISH')

  , d [0] = d [0] +.

  case

  When trunc(order_date[0]) = trunc(order_ready[0]) - beginning and ready same day

  then presentv (r.b [wday [0]],)

  less (largest (order_ready [0], to_date (to_char (order_date [0], 'YYYYMMDD') | r.b [WDAY [0]], 'YYYYMMDDHH24:MI')), to_date (to_char (order_date [0], 'YYYYMMDD') | r.e [WDAY [0]],'YYYYMMDDHH24:mi'))))

  -bigger (to_date (to_char (order_date [0], 'YYYYMMDD') | r.b [WDAY [0]], 'YYYYMMDDHH24:MI'), least (order_date [0], to_date (to_char (order_date [0], 'YYYYMMDD') | r.e [WDAY [0]],'YYYYMMDDHH24:mi'))))))

  0) * 24

  When order_date [0] + iteration_number = order_date [0] - first day

  then presentv (r.b [wday [0]],)

  TO_DATE (to_char (order_date [0], 'YYYYMMDD') | r.e [WDAY [0]], 'YYYYMMDDHH24:MI')

  -bigger (order_date [0], to_date (to_char (order_date [0], 'YYYYMMDD') | r.b [WDAY [0]],'YYYYMMDDHH24:mi'))))

  0) * 24

  When trunc(order_date[0]) + iteration_number = trunc(order_ready[0]) - last day

  then presentv (r.b [wday [0]],)

  less (order_ready [0], to_date (to_char (order_ready [0], 'YYYYMMDD') | r.e [WDAY [0]],'YYYYMMDDHH24:mi'))))

  -to_date (to_char (order_ready [0], 'YYYYMMDD') | r.b [WDAY [0]], 'YYYYMMDDHH24:MI')

  0) * 24

  of another nvl (r.dur [wday [0]], 0)

  end

  )

  ORDER_ID	DURATION	ORDER_TYPE	OVERTIME
  1	11	Order1	6
  2	22	Order1	17
  3	10	Order2	2

  Rewrittten party rules for readability purposes (more resources)

  measures (0d, order_date, order_ready, cast (null as varchar2 (10)) as to_date (null), (null) to_date, bd, order_type, wday ed)

  iterate (1e6) rules until (iteration_number > = trunc(order_ready[0]) - trunc(order_date[0])))

  WDAY [0] = to_char (order_date [0] + iteration_number, 'FMDay', 'NLS_DATE_LANGUAGE = ENGLISH')

  , comics [0] = to_date (to_char (order_date [0] + iteration_number, 'YYYYMMDD') | r.b [WDAY [0]], 'YYYYMMDDHH24:MI')

  , ed [0] = to_date (to_char (order_date [0] + iteration_number, 'YYYYMMDD') | r.e [WDAY [0]], 'YYYYMMDDHH24:MI')

  , d [0] = d [0] +.

  case

  When trunc(order_date[0]) = trunc(order_ready[0]) - beginning and ready same day

  then presentv (r.b [wday [0]],)

  less (largest (order_ready [0], [0] bd), ed [0])

  -Greatest (BD [0], least(ORDER_DATE[0],ED[0]))

  0) * 24

  When order_date [0] + iteration_number = order_date [0] - first day

  then presentv (r.b [wday [0]],)

  ED [0]

  -Greatest(ORDER_DATE[0],BD[0])

  0) * 24

  When trunc(order_date[0]) + iteration_number = trunc(order_ready[0]) - last day

  then presentv (r.b [wday [0]],)

  least(order_ready[0],ED[0])

  -bd [0]

  0) * 24

  of another nvl (r.dur [wday [0]], 0)

  end

  )

  Jubilee should be Saturday I guessed.