Similar Questions

• Calculate the resources-vCAC 6.0 vSphere Agent question

  Hello

  I have a related question Agent vSphere, vsphere Agent connects only shows the error in the picture, because I'm trying to set up a group of Fabrioc no calculation resources whas shown for the account that I use.

  Thank you!

  -vRay

  After reinstall Agent for the 15 th time and wait for about 10 minutes of frustration, it works, I n believe in miracles, but here's the evidence, what I've done:

  Reinstall the name of different Agent than on complete installation

  Recreate the different name endpoint of that on complete installation

  Check all the newspapers of the time

  Place the account that I use for vCAC as the local administrator in vCenter Server

  Reboot identity SSO the vCAC App

  reload the credentials and to recreate endpoint config I mena on vCAC as infrastructure admin.

  any mode of paranoid way.

• How to calculate the cpu in the resource pool

  How to calculate the cpu in the resource pool

  and don't forget that shares in pools of resources are not inherited by the virtual machines in the pools. the action is related to the pool itself.

• Calculate the hours between 2 business days

  Hi all

  Do a complex calculation on the days I do not know how to achieve this.

  Here is my case:

  I have a week of work with hours of work.

  

  Then there's this delivery time sheet for how long should be set an order ready to be delivered:

  Order1: max 5 hours of work

  Order2: max 8 working hours

  Order3: max 16 hours of work

  When an order is placed, the time of the order is recorded, and when an order has been set in ready to be delivered, this time is also registered.

  How to calculate the time difference between the time where an order has been placed and the time where the order has been on loan. Thereby also taking into account the working days and hours of work.

  Example: type order1 order was placed Tuesday at 15:00.

  Order has been fixed loan Wednesday at 14:00

  This means that to fix this ready order lasts 7 hours, which means that it is 2 hours time.

  CREATE TABLE REF_WORKDAYS
    (
      
      "WERKDAG"       VARCHAR2(15 ) NOT NULL ENABLE,
      "SOORT_WERKDAG" VARCHAR2(15 ) NOT NULL ENABLE,
      "BEGIN_TIJD"    VARCHAR2(10 ) NOT NULL ENABLE,
      "EIND_TIJD"     VARCHAR2(10 B) NOT NULL ENABLE,
      
    )
  

  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Monday','WORKINGDAY','08:00','16:00');
  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Tuesday','WORKINGDAY','08:00','16:00');
  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Wednesday','WORKINGDAY','08:00','16:00');
  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Thursday','WORKINGDAY','08:00','16:00');
  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Friday','WORKINGDAY','08:00','16:00');
  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Satrurday','WORKINGDAY','08:00','14:00');
  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Sunday','NOT-WORKINGDAY','08:00','16:00');
  
  COMMIT;
  

  create table glas_order
  
  (order_id number
  , order_desc varchar2(100) not null
  , order_type varchar2(10) not null
  , order_date date not null
  , order_ready date
  
  );
  

  Insert into GLAS_ORDER (ORDER_ID,ORDER_DESC,ORDER_TYPE,ORDER_DATE,ORDER_READY) values (1,'order bla','Order1',to_date('07-APR-15 09:00','DD-MON-RR HH24:MI'),to_date('08-APR-15 12:00','DD-MON-RR HH24:MI'));
  Insert into GLAS_ORDER (ORDER_ID,ORDER_DESC,ORDER_TYPE,ORDER_DATE,ORDER_READY) values (2,'order nice','Order1',to_date('14-APR-15 10:00','DD-MON-RR HH24:MI'),to_date('16-APR-15 16:00','DD-MON-RR HH24:MI'));
  Insert into GLAS_ORDER (ORDER_ID,ORDER_DESC,ORDER_TYPE,ORDER_DATE,ORDER_READY) values (3,'order ugly','Order2',to_date('18-APR-15 13:00','DD-MON-RR HH24:MI'),to_date('21-APR-15 09:00','DD-MON-RR HH24:MI'));
  
  COMMIT;
  

  Thank you

  Diana

  Select

  I like order_id

  such as length d

  order_type

  d decode(order_type,'Order1',5,'Order2',8)

  overtime

  of glas_order o

  model

  Reference r on

  (select

  WERKDAG w

  begin_tijd b

  e eind_tijd

  , (to_date (eind_tijd, 'HH24') - to_date (begin_tijd, 'HH24')) * 24 hard

  of ref_workdays

  where soort_werkdag = "WORKINGDAY")

  dimension (w)

  measures (b, e, hard)

  main m

  partition of (order_id I)

  size of (0 n)

  measures (0d, order_date, order_ready, cast (null as varchar2 (10)) as wday, order_type)

  iterate (1e6) rules until (iteration_number > = trunc(order_ready[0]) - trunc(order_date[0])))

  WDAY [0] = to_char (order_date [0] + iteration_number, 'FMDay', 'NLS_DATE_LANGUAGE = ENGLISH')

  , d [0] = d [0] +.

  case

  When trunc(order_date[0]) = trunc(order_ready[0]) - beginning and ready same day

  then presentv (r.b [wday [0]],)

  less (largest (order_ready [0], to_date (to_char (order_date [0], 'YYYYMMDD') | r.b [WDAY [0]], 'YYYYMMDDHH24:MI')), to_date (to_char (order_date [0], 'YYYYMMDD') | r.e [WDAY [0]],'YYYYMMDDHH24:mi'))))

  -bigger (to_date (to_char (order_date [0], 'YYYYMMDD') | r.b [WDAY [0]], 'YYYYMMDDHH24:MI'), least (order_date [0], to_date (to_char (order_date [0], 'YYYYMMDD') | r.e [WDAY [0]],'YYYYMMDDHH24:mi'))))))

  0) * 24

  When order_date [0] + iteration_number = order_date [0] - first day

  then presentv (r.b [wday [0]],)

  TO_DATE (to_char (order_date [0], 'YYYYMMDD') | r.e [WDAY [0]], 'YYYYMMDDHH24:MI')

  -bigger (order_date [0], to_date (to_char (order_date [0], 'YYYYMMDD') | r.b [WDAY [0]],'YYYYMMDDHH24:mi'))))

  0) * 24

  When trunc(order_date[0]) + iteration_number = trunc(order_ready[0]) - last day

  then presentv (r.b [wday [0]],)

  less (order_ready [0], to_date (to_char (order_ready [0], 'YYYYMMDD') | r.e [WDAY [0]],'YYYYMMDDHH24:mi'))))

  -to_date (to_char (order_ready [0], 'YYYYMMDD') | r.b [WDAY [0]], 'YYYYMMDDHH24:MI')

  0) * 24

  of another nvl (r.dur [wday [0]], 0)

  end

  )

  ORDER_ID	DURATION	ORDER_TYPE	OVERTIME
  1	11	Order1	6
  2	22	Order1	17
  3	10	Order2	2

  Rewrittten party rules for readability purposes (more resources)

  measures (0d, order_date, order_ready, cast (null as varchar2 (10)) as to_date (null), (null) to_date, bd, order_type, wday ed)

  iterate (1e6) rules until (iteration_number > = trunc(order_ready[0]) - trunc(order_date[0])))

  WDAY [0] = to_char (order_date [0] + iteration_number, 'FMDay', 'NLS_DATE_LANGUAGE = ENGLISH')

  , comics [0] = to_date (to_char (order_date [0] + iteration_number, 'YYYYMMDD') | r.b [WDAY [0]], 'YYYYMMDDHH24:MI')

  , ed [0] = to_date (to_char (order_date [0] + iteration_number, 'YYYYMMDD') | r.e [WDAY [0]], 'YYYYMMDDHH24:MI')

  , d [0] = d [0] +.

  case

  When trunc(order_date[0]) = trunc(order_ready[0]) - beginning and ready same day

  then presentv (r.b [wday [0]],)

  less (largest (order_ready [0], [0] bd), ed [0])

  -Greatest (BD [0], least(ORDER_DATE[0],ED[0]))

  0) * 24

  When order_date [0] + iteration_number = order_date [0] - first day

  then presentv (r.b [wday [0]],)

  ED [0]

  -Greatest(ORDER_DATE[0],BD[0])

  0) * 24

  When trunc(order_date[0]) + iteration_number = trunc(order_ready[0]) - last day

  then presentv (r.b [wday [0]],)

  least(order_ready[0],ED[0])

  -bd [0]

  0) * 24

  of another nvl (r.dur [wday [0]], 0)

  end

  )

  Jubilee should be Saturday I guessed.

• Calculate the material database

  Hi all

  I'm new Oracle DBA in the industry, not a lot of experience in the database. I have some confusion. Maybe it's stupid question but this turning point in my mind. Please help to solve these.

  (1) for new projects comes, I'm confusing all cache/RAM required and CPU. Although I can calculate the capacity of the hard drive.  for example - my Application user say we have total TPS (transactions per second) is 1000 (200 update, delete 300, 100 and 200 insertion selects), so in this case how can I calculate hardware capacity, and how I can answer for them.

  (2) this is the reverse of the first question.  Suppose a database running, and everything works fine. I want to calculate the GST (transactions per second). means how select/update/insert/delete running in the second. How to calculate or identified TPS.

  Thanks in advance...

  Reg,

  Hard

  Thank you all, I got my answer...

  Oracle Capacity Planning

  Introduction - Database management

  The best way to perform the Oracle capacity planning is with planningsof the worksheet of the ability of the Oracle. Database management has increased over the years to the simple management of a few tables and indexes to a complex of interlocking responsibilities ranging from management of objects of database to participate in decisions large enterprise on hardware, software and development tools.

  In order to fully discharge these functions the modern Oracle DBA needs one big together skills. In the last hours, we will discuss the skills needed, and specifically how they apply to an Oracle DBA.

  Capacity planning system

  In a green field operation (the one where you're here in front of the equipment and the database), a DBA will have a critical role to play in planning and configuration of the new system. Even in existing environments the ability to predict new servers, new databases, or improvements to existing databases and systems is crucial.

  Essentially the DBA should be concerned with two main questions:

  1. Get enough server to ensure an adequate return
  2. Sufficient backup and power of recovery for backup and restoration carried out respecting the time constraints required.

  All this is actually under the heading planning resources and capabilities. Resources and capacity planning Oracle is a database intensive resources system. The more CPU, memory and disk resources, you can provide Oracle, better it performs. Planning with Oracle resources becomes more a game of "How can we afford to buy" instead of "what is the minimum configuration. A minimally configured Oracle server won't work effectively. Specification of resource for Oracle In the specification of resources, there are several questions that should be answered.

  1. How many users will use the system today and in the future?
  2. Data will include the system contain both now and in the future, we don't know the growth rate?
  3. What response time are expected?
  4. The availability of this system is planned?

  Why are these issues important?

  1. How many users will use the system today and in the future?

  This issue is important, because it effects how much processing power is going to be necessary. The number of users will determine the number and speed of the processors, memory, the related network configuration size.

  1. Data will include the system contain both now and in the future, we don't know the growth rate?

  This issue is important because it determines the disk needs, how much storage will need to take the data we have today and how it will be necessary for the growth. The answer to this question also allows to determine how much memory will be needed.

  1. What response time are expected?

  This question is important because it pushes the number, type and speed of CPU resources, but also of network problems. He will lead also issues such as the number and speed disk configuration disks, number and speed of the controllers, disk partitioning decisions.

  1. The availability of this system is planned?

  This question is important because the availability of the system grows the type of RAID (1, 0, 0/1, RAID5) configuration, the type of scheduled backup (cold, warm) and parallel server problems. Requirements change if all that is expected is the system to be available during business hours from Monday to Friday, or if the system is supposed to be available 24 X 7 seven days a week. This also leads the type of backup media, be it a single tape drive is all that is necessary or is it a hi-speed, tape-stacker, multichannel, solution based silo?

  To properly perform a capacity planning cooperative efforts should be made between system administrators, database administrators, and network administrators.

  Step 1: Size of the Oracle database

  A starting point for the whole process of capacity planning is to know how many and what size, databases will be based on a given server resource. The physical size of the tables, indexes, clusters, and LOB storage areas will play an essential role in the sizing of the overall database, including areas of shared global memory and disk farm. DBAS and developers must work together in order to properly size the physical files of the database. The design of the database will also lead the placement and the number of storage spaces and other resources of database such as the size and quantity of newspapers of recovery, rollback segments and their associated buffers.

  Typically areas of buffer of data to an LMS database block size out to between 1/20 to 1/100 the physical sum relative to the total number of database file sizes. For example, if the physical size of the database is 20 gigabytes the database block buffers should on about 200 megabytes to 1 gigabyte in size depending on the how the data is used. In most cases the LMS shared pool would be size out to about 20-150 megabytes maximum according to the usage model for the common areas of SQL (see next lesson). For a system of 20 gigabytes the redo logs would most likely run between 20 and 80 megabytes, you want mirrored volumes and probably not less than 5 groups. The pad of paper to support a 50 megabyte redo log file would be a minimum of 5 megabytes may be as large as 10 megabytes. The last major factor for BMG would be the size of the sorting box, for this size of a database, a sort of 10 to 20 megabytes field is on the right (according to the number and size of all kinds). Remember that sort areas can be a part of the shared pool or a part of the large pool, so we'll cover in a future lesson.

  So on that basis we've determined? Gives a choice of 400 megabytes for our size memory buffer of data block, 70 megabytes for the shared pool, buffers of the newspaper of 4 to 10 MB (40 MB) and a size of 10 megabytes sort field. We look at a megabyte of 500-600 LMS with the important factors of non - DBA added in. Since you are not supposed to use more than 60% of the physical memory (according to the interviewee) it means w will need at least a gigabyte of RAM. With this size of database a single UC probably won? t give enough performance so we are probably looking at least a 4-processor machine. If we have more than one instance installed on the server, the memory requirements will increase.

  Step 2: Determine the number and Type of users:

  Of course, a database of a user will require fewer resources than the user database of a thousand. Generally, you will need to take a LOOT at how many memory resources and drive each user will need. An example would be to assume that a user installed 1,000 users base, only 10 percent of them at the same time will use the database. That leaves 100 concurrent users, those who perhaps a second 10 percent will do the activity requiring sorting areas, this brings the number up to 10 users each use (in our previous example) 10 megabytes of memory each (100 MB). In addition each of the 100 users simultaneous need about 200 k of space (depending on the activity, BONE, and other factors) process so there is an additional charge of 20 megabytes just for the user process space. Finally, each of these users will require probably some amount of disk resource (or less if they are client-server or web-based) let? s give them 5 meg of disk to start each, which adds up to 5 gigabytes of disk (give or take a meg or two.)

  Step 3: Determine the hardware requirements for the required response time meet and support of user Support:

  This step is the system administrator and maybe the seller of equipment. Given our mix of 1000:100:10 users and any required response time numbers, they should be able to configure a server that will obtain good results. Usually, this will require several, interfaces multi-lane disks and several separate physically the drive bays.

  Step 4: Determine the material backup to support the requirements of availability required:

  Here again the admin system and hardware vendor will have a helping hand in the decision. Based on the size of the disks and the speed of the maximum recovery time backup solution should be developed. If there is no way to meet your requirements of availability required using backup schemas simple more esoteric architectures can be specified as strips of multiple channels, hot databases in standby or even Oracle Parallel Server. Let? s say we need a requirement of availability 24 X 7 with instant failover (no recovery time because of the critical nature of the mission of the system). This type of specification would require Oracle Parallel Server in a configuration of automated failover. We also use either a double or triple mirror on disk so that we could divide the mirror to perform backups without losing the protection of mirroring.

  Let? s compile what we have determined so far:

  Material: 2-4 CPU (for higher-speed CPU we can) with at least 1 gigabyte (preferably 2) of RAM shared, at least 2 disk controllers each with many channels, 90 gigabytes of disk resource using a three way mirror to give us a matrix to mirror a triple 30 concert. The systems themselves should have a sufficient internal disk subsystem to support the operating system and the swap and the requirements of pagination. Systems must be able to share the disk resources so should support clustering. High-speed tape backup to minimize the folding times mirror.

  Software: Oracle Parallel Server, Cluster, the network management software, software backup management software to support backup material.

  Capacity and resource planning is not an exact science. Basically, look for a moving target. Dual Pentium II 200 NT Server with 10 GB of 2 GB SCSI disks for $5 k, I bought 2 years ago has a modern equivalent in the Pentium III 400 with the builtin 14 concert my father-in-law just bought for $1 k. At the time where we specify and purchase of a system, it is already replaced. You should insist on power substitute options more effective, more inexpensive they are available during the phases of specification and procurement.

  Reg,

  Hard...

• Calculate the price based on the field

  Hello

  My apologies, I know it's a very basic question, but I can't understand the correct syntax for the custom calculation Script necessary to produce the total cost in my form (I just received Acrobat Pro today).

  I have the user fill in the quantity field and then I try to set the TOTAL field to calculate the cost by multiplying the quantity by the price of $29. I thought it was simple, like writing a formula in Excel, but it doesn't seem to work that way and I can not find all resources on Adobe.com or online who point me in the right direction. Any help anyone can offer would be greatly appreciated.

  It might be easier to use the option of simplified field notation, in which case you must enter:

  29 * QTY

  If you want to use a custom calculation script, it could be something like:

  Custom calculation for a field text script

  (function () {}

  Get the value of the quantity, as number

  var qty = + getField("QTY").value;

  Calculate the value of this field if the quantity is greater than 0

  If (Qty > 0) {}

  Event.Value = util.printf ("%.2f", 29 * qty);  round to the nearest hundred

  } else {}

  Event.Value = "";   This field blank

  }

  })();

  If this option gives you more flexibility. you to round off and empty the field. You can also perform additional checks to ensure that the amount of sense (for example, a positive integer within a certain range) you can find more information in the Acrobat JavaScript reference, and here is a link to a tutorial introduction on how to set up calculations in PDF forms: https://acrobatusers.com/tutorials/how-to-do-not-so-simple-form-calculations

  Be sure to set the computed fields read-only so that the user does not try to interact with them.

• Calculate the disk space required for the INDEX

  Hello
  
  How to calculate the disk space required to create an INDEX? Please tell me where I can get the details of resources.
  
  For example:
  I need to create a non-UNIQUE INDEX on the columns, an approximate size would do.
  
  < PRE >
  NOT NULL DATE EVENT_DATE
  APPT_DATE_SLOT VARCHAR2 (15)
  EVENT_STATUS VARCHAR2 (4)
  < / PRE >
  
  The table has some 7 300 000 rows. I would like to know how to calculate too.
  
  All AIDS are very much appreciated.

  A rough estimate of the index space will need is possible by

  adding the actual length expected from each column, plus 6 for the rowid, 2 for the number of the X-header of the rows in the table that will be so an entry

  Date are 7 bytes internal + 15 + 4 + 2 + 6 = 34 X 7.3 M = 248200000 X General fresh for the block header, initrans, etc...

  We will use 20% overhead block or 1.2 X 248200000 = 297840000, which is about 285 M

  The actual distribution will vary according to your method of range tablespace.

  HTH - Mark D Powell.

• Calculate the date of the first or last in a quarter

  Hello
  
  I have data of project with a start date and end date I need to calculate the number of days per quarter
  
  project x: 15/03/06 - 15/05/06
  15 days Q1 = Q2 = 45 days
  
  I'm then going to calculate the percentages of resource. I can get the bt of the watch with a hack of a time to identify the first or the last day of a given quarter. Any help win my sincere admiration.
  
  

  Sorry, misread the question. The district will rely on the company that you work for. If the end of his is the same as an end of year calendar (31 December), then the example below will be accurate. Change the dates according to the needs of the company.
  You can hardcode the variables in your application.cfm page.
  quarter1start = "01 - jan -";
  quarter2start = '01 - apr -';
  quarter3start = "01 - jul -";
  quarter4start = '01 - oct -';

  Programatically, the end of each quarter is always the day before the start of the next quarter.
  I would add "year" to the equation dynamically, to keep in it before compatible.

• Calculate the average per slot?

  Hi Chaps,

  I am a beginner on numbers (almost everything on Mac I would say) and I need help to calculate average values.

  These are calculated values (column 2) taken on a specific time of the day (column 1).
  I managed to create a third using a built-in function to get the time slot (column 3).

  14:58:42	235	14
  14:59:42	274	14
  15:00:50	7937	15
  15:01:55	5157	15
  16:02:57	1822	16
  16:03:57	207	16

  Can please somebody see me step by step how to calculate the average by time slot as below?

  14	254,5
  15	6547
  16	1014,5

  Kind regards

  Stone

  This can help you

  

  Assuming you data in a table named 'Data' and the information is summarised in another table (right) named "Summary".

  Select cell B1 in the summary table and then type (or copy and paste from here):

  = SUMIF(Data::C,a1,Data::B) ÷COUNTIF (Data::C, a1)

  shortcut for this is:

  B1 = SUMIF(Data::C,a1,Data::B) ÷COUNTIF (Data::C, a1)

  Select cell B1, copy

  Select column B, paste

• I want you to help because the phone asking me to become a frequent and annoying enter a password to calculate the icloud

  Hello

  I want you to help because the phone ask me for becoming a frequent and annoying password to calculate the icloud, and I do not know because I bought a phone from someone else is not new Hama is on the phone (*) No. account. IMEI (*) Please help me soon thank you

  < post branched out by host >

  < personal information under the direction of the host >

  Robert Odamat says:

  Hello

  I want you to help because the phone ask me for becoming a frequent and annoying password to calculate the icloud, and I do not know because I bought a phone from someone else is not new Hama is on the phone (*) No. account. IMEI (*) Please help me soon thank you

  < post branched out by host >

  < personal information under the direction of the host >

  Find my iPhone Activation Lock - Apple Support

  There is nothing you can do to get around activation icloud blocking without recovering the former owners information.

  Communicate with the person that you bought the phone.

• Will the 'flights climbed' work and calculate the altitude of an aircraft?

  I'm going on vacation soon and everything I just want to know my iPhone 6s will calculate the flights climbed when the plane is in the Air?

  You will be on a plane with steps?

• How to calculate the hours between two dates by the numbers

  If I update 09:00 start time 17:00 end time of shift in C3 and B3, how to use a D3 formula to calculate the number of hours between the two?  Then I can just copy down the lines for nth years...

  It is a spreadsheet of the part-time staff payroll.

  I'm sure that a lot of people out there have done that.

  Help, please.

  Thank you.

  Eddie

  What program of worksheet that you are using? Since you have a newer iMac running El Capitan, I can safely assume that you use NOT AppleWorks, which is a Power PC application that can run on any OS newer than the snow leopard, OS X 10.6.8.

  If you use numbers, try to repost your question in numbers for Mac forum. If you use Microsoft Excel, try posting in the Microsoft forums. LibreOffice also has community support.

• How to calculate the difference between two times by the NUMBERS

  I'm so bothered by the fact that I can't understand that.

  Cell B2 - 08:00

  Cell C2 - 10:50

  (How can cell D2 - I get this cell to calculate the difference and say 02:50?)

  I know it's probably one of the most basic operations, but for the life of me I can't understand it. The cells B2 and C2 are formatted for a 24-hour clock. But if I tell the system to just subtract the two, I get "0,118. Everything I find on the forum search goes beyond what I need. Can someone help me?

  Thank you

  Hi sapirs,

  Departure and arrival of the cells are in Date and time with Date format: no and time: 24-hour clock.

  

  Formula in D2 (fill down)

  = C2−B2

  

  The results become a duration format, but under automatic (numbers automatically worth this format)

  

  If you wish, you can change the cells of lasting results.

  What Data Format have your result cells?

  Kind regards

  Ian.

• CPU goes to 100% svchost State takes all the resources on the Qosmio F10

  CPU goes to 100% svchost State takes all the resources. Norton can not find any illegal software. Have tried to list the processes (run... etc.). I get a long list, don't know what to do about this. Anyone out there have some help?

  Hey Buddy

  The same problem here. :( A universal solution is unknown to me but what I do is from the Task Manager. When svchost shows more than 90% of its use I simply stop this stupid process. After having done that, I can use my laptop without any problem and it will not happen again.

  After restarting the laptop, the same thing happens again. I checked some other forums but never found no reasonable explanation how manage this stupid question.

  If someone knows more please let us know.

• VISA: Is denied access to the resource or to the remote machine.

  Hello.

  I use a cRIO-9076 to communicate with a Keithley 2400 via port RS-232 on the cRIO. I have a vi test which is built using the Keithley 2400 drivers and it works perfectly fine with the vi is located under 'My Computer' in my project. If I'm moving that vi on the potion of distance OR cRIO9076 of the project and try to run the vi I get a

  VISA: (Hex 0xBFFF00A8 to the resource or the remote machine access is denied...

  I realized I need to add something to the list of remote access on the cRIO that I find a little confusing. I want to use the serial port on the cRIO by VISA to communicate to the Keithley, so I need to give permission to cRIO on the cRIO? I'm obviously confused.

  I tried to add a simple * (wildcard) to the list of access as a temporary solution but I still get the same error.

  I would like some advice.

  Thank you

  Roth

  cRIO 9076

  Lab View 2013

  Keithley 2400

  NI-VISA 5.4.0

  If you want to move the vi to the CRIO, you can change the name of the resource.

  my example is based on the cRIO-9068. When running at MAX on my local host, it can show as below.

  The resource for the cRIO-9068 should like 'ASRLx:INSTR '.

  

  Good luck!