Cells in consecutive sheets may include the following line in a master spreadsheet

Similar Questions

• Remove the following lines

  Hi all

  with tbdate as

  (

  Select 6 March 2013 08:00 ' date1, n1 10 'x 1' oggetto in all double union '.

  "Select 6 March 2013 08:10 ', 20 ' x 2' of all the double union

  "Select 6 March 2013 08:20 ', 10 ' x 3' of all the double union

  "Select 6 March 2013 08:30 ', 20 ' x 4' of all the double union

  "Select 6 March 2013 08:40 ', 10 ' x 5' of all the double union

  "Select 6 March 2013 08:50 ', 30 ' x 6' of all the double union

  "Select 6 March 2013 09:00 ', 10 ' x 7' of all the double union

  "Select 6 March 2013 09:10 ', 20 ' x 8' of the double

  )

  Select a.* tbdate one

  How can I remove the lines where the total (date1 + numtodsinterval (n1, "MINUTE")) of the previous line does not match the line or the following lines?

  With example maybe I'll be more clear

  rank 1 03/06/2013 08:00 10 x 1 Yes

  rank 2 03/06/2013 08:10 x 30 2 Yes because more time minutes (n1) of the largest previous = 08:10 equal this line

  rank 3 03/06/2013 08:20 10 x 3 not because 08:10 + 30 = 08:40 previous line <>this line

  rank 4 03/06/2013 08:30 20 x 4 not because 08:10(rows_2) + 30 = 08:40 of the previous lines (2 lines) <>this line

  rank 5 03/06/2013 08:40 10 x 5 Yes

  tier 6 03/06/2013 08:50 x 20 6 yes because 08:40 plus 10 = 08:50 from the previous row is this line

  tier 7 03/06/2013 09:00 10 x 7 no

  tier 8 03/06/2013 09:10 10 x 8 Yes

  Thanks in advance

  Hello

  You build the correct path and connect (and then delete the others):

  SQL dts@QUALIF > with tbdate like

  () 2

  3 select to_date (6 March 2013 08:00 ',' dd/mm/yyyy hh24:mi:ss') date1, n1 10 'x 1' oggetto in all double union '.

  4 Select to_date (6 March 2013 08:10 ',' dd/mm/yyyy hh24:mi:ss'), 20, 'x 2' dual union all '.

  5 Select to_date (6 March 2013 08:20 ',' dd/mm/yyyy hh24:mi:ss'), 10 'x 3' double union all '.

  6 select to_date (6 March 2013 08:30 ',' mm/dd/yyyy hh24:mi:ss'), 20 'x 4' double union all '.

  7 select to_date (6 March 2013 08:40 ',' dd/mm/yyyy hh24:mi:ss'), 10 'x 5' double union all '.

  8 select to_date (6 March 2013 08:50 ',' dd/mm/yyyy hh24:mi:ss'), 20 'x 6' double union all '.

  9 select to_date (6 March 2013 09:00 ',' dd/mm/yyyy hh24:mi:ss'), 10 'x 7' double union all '.

  10. Select to_date (6 March 2013 09:10 ',' dd/mm/yyyy hh24:mi:ss'), 20 'x 8' from dual '.

  (11), a title)

  12. Select b.*, sys_connect_by_path (oggetto, '-') pth, connect_by_root (oggetto) r, prior (oggetto) p

  tbdate 13 b

  14 connect by date1 = prior date1 + prior n1 / 24 / 60

  15 beginning with oggetto = 'x 1') '.

  16. Select * from a;

  DATE1            N1 OG PTH                                                R  P

  -------- ---------- -- -------------------------------------------------- -- --

  03.06.13         10 x1 -x1                                                x1

  03.06.13 20 x 2 - x 1 - x 2 x 1 x 1

  03.06.13 20 x 4 - x 1 - x 2 - x 4 x 1 x 2

  03.06.13 20 x 6 - x 1 - x 2 - x 4 - x 6 x 1 x 4

  03.06.13 20 x 8 - x 1 - x 2 - x 4 - x 6 - x 8 x 1 x 6

• System Restore cannot be started from any level, including the command line.

  Using XP Pro SP3. "System restore is not able to protect your computer. Restart your computer and run the restore of the system again. "Tried Msconfig and the following at the prompt to commande--C:\WINDOWS\System32\restore\rstrui.exe

  Using XP Pro SP3. "System restore is not able to protect your computer. Restart your computer and run the restore of the system again. "Tried Msconfig and the following at the prompt to commande--C:\WINDOWS\System32\restore\rstrui.exe

  Have you checked services to make that system restore is set to start automatically?

  http://support.Microsoft.com/kb/302796

• Get the value of the following line in the game ordered under certain conditions

  Do not know if my best subject line sums up what I do :)

  
  

  Oracle DB 12 c (I think 12.1.2)

  
  

  I have a table with the names of people and DOB with a few keystrokes. It is assumed that this person is the 'same' first_name, last_name, birth_day/month/year are identical

  drop table people;

  create table persons

  (

  first name varchar2 (30),

  VARCHAR2 (30) last_name,.

  birth_month varchar2 (2),

  birth_day varchar2 (2),

  birth_year varchar2 (4).

  keyVal number

  );

  insert into values('JOHN','SMITH','10','10','1974',1) people (first_name, last_name, birth_month, birth_day, birth_year, keyval);

  insert into values('JOHN','SMITH','10','10','1974',2) people (first_name, last_name, birth_month, birth_day, birth_year, keyval);

  insert into values('JANE','SMITH','10','10','1974',3) people (first_name, last_name, birth_month, birth_day, birth_year, keyval);

  insert into values('JANE','DOE','10','10','1974',4) people (first_name, last_name, birth_month, birth_day, birth_year, keyval);

  insert into values('JANE','DOE','10','10','1974',5) people (first_name, last_name, birth_month, birth_day, birth_year, keyval);

  insert into values('ERIC','DOE','11','10','1975',6) people (first_name, last_name, birth_month, birth_day, birth_year, keyval);

  insert into values('ERIC','DOE','11','10','1975',7) people (first_name, last_name, birth_month, birth_day, birth_year, keyval);

  insert into values('ERIC','DOE','11','10','1975',8) people (first_name, last_name, birth_month, birth_day, birth_year, keyval);

  I want to see the following output:

  first_name, last_name, birth_month, birth_day, birth_year, keyval_min, keyval_other

  JOHN	SMITH	10	10	1974	1 2
  JANE	DOE	10	10	1974	4 5
  ERIC	DOE	11	10	1975	6 7
  ERIC	DOE	11	10	1975	6 8

  1. the output will display only those who appear at least twice in the original table

  2. If the person appears twice in the original table, the output will only one result where first keyval will be min two; second keyval will be the other value;

  3. If the person has 3 times or more (n times, for example), each line of output will be keyval_min of all keyvals followed by the other value keyval. Total of n-1 lines

  It's very large 100 + M and the processing time is important.

  Hope I explained it well.

  Hello

  This sounds like a job for analytical functions.

  If the same person has N rows in the table, the output should be N - 1 lines.  You can use the ROW_NUMBER analytic function to assign numbers (1, 2, 3,...) to each line and do not display the lines nuimbered 1.

  On each line, you must prove the keyval lowest for this person.  The analytical MIN function can do this.

  Here's one way:

  WITH got_analytics AS

  (

  SELECT first_name, last_name, birth_month, birth_day, birth_year, keyval

  , ROW_NUMBER () OVER (PARTITION BY first_name, last_name, birth_month, birth_day, birth_year)

  ORDER BY keyval

  ) AS r_num

  , MIN (keyval) OVER (PARTITION BY first_name, last_name, birth_month, birth_day, birth_year)

  ) AS keyval_min

  AMONG the people

  )

  SELECT first_name, last_name, birth_month, birth_day, birth_year

  keyval_min

  keyval AS keyval_other

  OF got_analytics

  WHERE r_num > 1

  ORDER BY first_name, last_name, birth_month, birth_day, birth_year

  r_num

  ;

  Use the data DATE to the date information type.  With the help of 3 columns separate NUMBERS will result in complicated, ineffective, code errors and invalid data.

• I would like to include the grid lines when I export an image... Is this possible?

  IM drawing the plans of landscape and architectural details. I want to stay for the scale of the grid. How can I do this?

  Hi Rusty,

  The grid lines are only there as a guide so unless you actually "draw", they will not be exported with the art.

  I will definitely pass your comments along to the sketch team.

  Sue.

• Data to be displayed in the following line

  Hello
  
  We have created a report that displays columns as the field name and the comment of the employee. I noticed that after10 character the remaining data is displayed on the next line.
  Is it possible to displlay data in the same row?
  
  Any help is greatly appreciated.
  
  Thank you
  Poojak

  Hello
  Use white space without film under CSS custom to the title column and column values in order to have them in a single line.
  Reference: http://oraclebi.blog.com/tag/data-text-wrap-in-obiee/

  Kind regards
  Srikanth

• Mark the Date based on the value of the following line... Delivery very Urgent

  Hello guys
  
  I work as a Business Intelligenece Developer and one of my reports, I have a requirement where I have a Date column and the date should be in ascending order IE 1 - JAN - 09
  2-JAN-09
  1 - FEB - 09
  
  If the date is not in ascending order, I need to mark the Date
  
  Here are examples of data
  
  Flag - Here if the Date is not in the order I have to report it Print N, i.e. If the date is growing Null we ignore and check the
  Next Date sequence Vale line
  10215 P02095
  10220 P02095
  P02095 10500 13 March 01
  P02095 10600
  P02095 30-Sep-10610 04
  P02095 10960
  P02095 N 10990 05 - Sep - 01
  P02095 20015 1 May 02 N
  P02095 20020 23 April 01 N
  P02095 20030 23 April 01 N
  P02095 50000
  P02095 63500
  P02095 64000
  P02095 64100 18 December 06
  P02095 64125
  P02095 64400 16 March 07
  P02095 64500 16 April 07
  P02095 64550 17 April 07
  P02095 70000 23 April 07
  P02095 70100 27 April 07
  P02095 80000 April 30 07
  P02095 81050
  P02095 81100
  P02095 83000
  P02095 84000
  P02095 14-Sep-86000 07
  86050 P02095
  86230 P02095
  
  
  Let me know if you have any questions I'll post it, thank you

  You did not post the version of Oracle, so I'll assume that you're at least 10g. Then the MODEL would be the best solution:

  with t as (
             select 'P02095' col1,'10215' seq,null dt from dual union all
             select 'P02095','10220',null from dual union all
             select 'P02095','10500',to_date('13-Mar-01','dd-mon-rr') from dual union all
             select 'P02095','10600',null from dual union all
             select 'P02095','10610',to_date('30-Sep-04','dd-mon-rr') from dual union all
             select 'P02095','10960',null from dual union all
             select 'P02095','10990',to_date('05-Sep-01','dd-mon-rr') from dual union all
             select 'P02095','20015',to_date('01-May-02','dd-mon-rr') from dual union all
             select 'P02095','20020',to_date('23-Apr-01','dd-mon-rr') from dual union all
             select 'P02095','20030',to_date('23-Apr-01','dd-mon-rr') from dual union all
             select 'P02095','63500',null from dual union all
             select 'P02095','64000',null from dual union all
             select 'P02095','64100',to_date('18-Dec-06','dd-mon-rr') from dual union all
             select 'P02095','64125',null from dual union all
             select 'P02095','64400',to_date('16-Mar-07','dd-mon-rr') from dual union all
             select 'P02095','64500',to_date('16-Apr-07','dd-mon-rr') from dual union all
             select 'P02095','64550',to_date('17-Apr-07','dd-mon-rr') from dual union all
             select 'P02095','70000',to_date('23-Apr-07','dd-mon-rr') from dual union all
             select 'P02095','70100',to_date('27-Apr-07','dd-mon-rr') from dual union all
             select 'P02095','80000',to_date('30-Apr-07','dd-mon-rr') from dual union all
             select 'P02095','81050',null from dual union all
             select 'P02095','81100',null from dual union all
             select 'P02095','83000',null from dual union all
             select 'P02095','84000',null from dual union all
             select 'P02095','86000',to_date('14-Sep-07','dd-mon-rr') from dual union all
             select 'P02095','86050',null from dual union all
             select 'P02095','86230',null from dual
            )
  select  col1,
          seq,
          dt,
          indicator
    from  t
    model
    dimension by(col1,row_number() over(partition by col1 order by seq) rn)
    measures(dt,seq,cast(null as varchar2(1)) indicator,min(dt) over(partition by col1) x)
    rules(
          x[any,rn > 1] order by rn = greatest(nvl(dt[cv(),cv()],x[cv(),cv() - 1]),x[cv(),cv() - 1]),
          indicator[any,any] = case when nvl(dt[cv(),cv()],x[cv(),cv()]) != x[cv(),cv()] then 'N' end
         )
  /
  
  COL1   SEQ   DT        I
  ------ ----- --------- -
  P02095 10215
  P02095 10220
  P02095 10500 13-MAR-01
  P02095 10600
  P02095 10610 30-SEP-04
  P02095 10960
  P02095 10990 05-SEP-01 N
  P02095 20015 01-MAY-02 N
  P02095 20020 23-APR-01 N
  P02095 20030 23-APR-01 N
  P02095 63500
  
  COL1   SEQ   DT        I
  ------ ----- --------- -
  P02095 64000
  P02095 64100 18-DEC-06
  P02095 64125
  P02095 64400 16-MAR-07
  P02095 64500 16-APR-07
  P02095 64550 17-APR-07
  P02095 70000 23-APR-07
  P02095 70100 27-APR-07
  P02095 80000 30-APR-07
  P02095 81050
  P02095 81100
  
  COL1   SEQ   DT        I
  ------ ----- --------- -
  P02095 83000
  P02095 84000
  P02095 86000 14-SEP-07
  P02095 86050
  P02095 86230
  
  27 rows selected.
  
  SQL> 
  

  SY.

  Published by: Solomon Yakobson on January 23, 2010 10:31

• Remove the duplicate line based on master e-mail

  Hello

  I have a request below that displays the records in doubles because of the tips white space I like how ignore and get a single record.

  Select

  SEPARATE

  MASTER_EMAIL "E-mail account"

  "Name",

  Last_name "Last Name."

  Decode (company_name, NULL, Domain, company_name) "society."

  JOB_FUNCTION "Title."

  Ligne_adresse_1 "address."

  "CITY."

  "STATE."

  'COUNTRY ', HE SAID.

  "Zip, ZIP

  PHONE_NUMBER "phone."

  FAX_NUMBER "Fax."

  CREATED_DATE "created Date."

  FIELD,

  MASTER_FLAG,

  location_company_name

  of master_email_users

  where

  MASTER_EMAIL AS ' [email protected] % %'

  Thank you

  Sudhir

  What I feel is best to remove the white space in the data itself by refreshing the records where we have and making sure that no future records cannot have white space while getting inserted.

  This helps us to avoid additional functions to use in recovery.

• The installation of Service Pack 2 for Vista failed. I tried several times. Message reads "not successful." "Element not found". I click on the 'Détails' link and it shows the following error: ERROR_NOT_FOUND (0 x 80070490).

  The installation of Service Pack 2 for Vista failed. I tried several times. Message reads "not successful." "Element not found". I click on the 'Détails' link and it shows the following error: ERROR_NOT_FOUND (0 x 80070490). I tried in several ways through the links suggested to solve the problem and nothing has worked.

  
  

  I turned to the forums and I saw that many, many people have the same problem with Vista SP2 Upgrade. Microsoft and several of its Vista customers realized that Vista has a lot of problems, but people who have need of the service. Being able to download and install the SP2 can make Vista more stable, but I get the same message mentioned above, and so I am sure are a lot of other people who are trying to get Service Pack 2 integrated into Vista.

  0 X 80070490 - ERROR_NOT_FOUND
  Corrupted system file; You will need to perform an upgrade on the spot or reinstalling the operating system.

  The error you receive occurs if there is corruption in the manifest of component maintenance base.

  Ignore the title: the "Windows features" dialog box is empty in Windows 7 or Windows Vista, or you receive an error message that includes the following code when you try to use Windows Update: "0 x 80073712".
  http://support.Microsoft.com/kb/931712
  "Explains the SFC / Scannow.

  A repair install is the usual solution of SFC/scannow does not work.

  You receive an error code "0 x 80070490" when you use Microsoft Update or Windows Update Web sites to install updates
  http://support.Microsoft.com/kb/958044

  NB: If you have installed SP1 for Vistahttp://support.microsoft.com/kb/948537

  Step 7 (method for Windows Vista), the * UPGRADE option is not available because SP1 has been installed.

  Uninstall SP1

  See also:

  How to overcome error 0 x 80070490 when installing updates in Windows Vista/Server 2008
  http://blogs.msdn.com/andrekl/archive/2008/09/29/how-to-overcome-error-0x80070490-when-installing-updates-in-Windows-Vista-Server-2008.aspx

  TaurArian [MVP] 2005-2010 - Update Services

• When I try to use the Windows updates to and the following error message: Windows update cannot currently check updates, because the service is not running

  have tried to use windows update and get the following error message: Windows update cannot currently check the updates, because the service is not running. You may need to restart you computer. I rebooted several times. Any help would be greatly appreciated as I am not very computer

  Original title: update windows

  Solution 1:

  Try this: http://helpdeskgeek.com/windows-7/cannot-run-windows-update-on-a-windows-7-pc/

  Solution 2:

  You can try to stop and restart the Windows Update Service (wuauserv). Open a command line window (run as administrator) and enter the following lines:

  net stop wuauserv
  regsvr32 %windir%\system32\wups2.dll
  net start wuauserv

  If this does not help, try Microsoft Fix It service to reset your Windows Update components:

  http://support.Microsoft.com/kb/971058/en-us

  I hope this helps.

• How to return to changes saved when the menu of 'come back' does not include the version of the document I'm looking for?

  Hello, I use Pages. I worked on a document for several days, save the changes on the way. I have closed or saved the document and asked a question about saving the changes. I pressed on continue, thinking that I was saving my document. It seems that the computer has erased all changes I made since I finally opened the document. The document says he was created today, and none of the versions of my last week of work are available. I want to restore a version with all my important revisions. The menu 'Browse all' and 'Come back' do not have one of my newer versions. Is it possible to find?

  It is important that you have all the hours of backups Time Machine on an external drive. If open the recent item and return to the menus avail you nothing...

  Open a Finder window. In the search window, type the following line, replacing the date with the one that is relevant to the review date that seek you. The following explains show me all the documents pages that have been modified since the specified date. The same syntax works in the Spotlight window.

  modified: 15/12/15, genre: pages

  Also check iCloud drive.

  If it does not find the file you are looking for and you don't have a Time Machine backup, you've learned an important lesson or two.

• the following code

  
  Hello
  
  When you insert a new record I want to assign the next property-ID in the property.property_id table. The query:
  
  < name cfquery = "GetNewID" datasource = "#application. DSN_Name #">"
  SELECT top 1 property-ID
  PROPERTY
  ORDER BY property-ID desc
  < / cfquery >
  
  When I test it works swell.
  
  However, the error appears on the following line of code:
  < cflocation url = "add_property_confirm.cfm? property_id = #GetNewID.property_id #" >
  
  The error indicates that property-ID is not defined in GetNewID.
  
  The table property-ID is set to automatic and custom numbering and using SQL 2000.
  
  I have no idea where start solve this - as an interesting oddity that this code worked for years, the customer pulled the site down, and then we returned it - nothing has changed in the database or the code... a mystery to me.
  
  Thanks in advance,
  
  Kathy
  

  Hey - I figured it!

  The piece of code:

  Need double quotes:

  He now works as it should. This error message a fraction which created a very large problem.

  Thanks for all your comments - I really appreciate the time and thought that you gave my situation.

  Take care

  Kathy

• Offset of the vertical lines

  A couple of weeks ago, I bought a Photosmart 7520 to replace my HP D110. I posted a problem here and received a quick solution. I hope that this happen.

  My problem is with vertical lines. The first file that contained a small table is a downloaded pdf file. When I printed this some vertical lines shifted just a little bit - small but noticeable. In fact, I did not notice it until I returned to it after printing an Excel spreadsheet and the problem of the vertical line noticing.

  At this point, I opened HP printer Assistant, to maintain the printer and lined up the printing and print heads cleaning heads. Clean print heads print page showed several vertical line for verification and they were very good: no earthquake. I still once printed the pdf and again once there are sections that were slightly off. Then, I created a small table in Word and do print. Same result: small shift.

  I made another clean and align another and another test print. Vertical lines have always shifted.

  The move was in line. I mean, when I looked at two different prints of the table of the word, the movement was in the same places; identical.

  The spreadsheet has multiple lines. As I scan down the vertical border between adjacent cells, I see a slight shift to the left on the bottom of the third cell. Sweeping down more of three cells the border comes to new right there where it was originally. That displacement, then back left again to the right, seems to repeat on all three rows.

  That describes my problem.

  Any ideas?

  Thank you.

  (My system is Windows7 64 bit running on a Dell StudioXPS computer).

  I must admit that I forgot to update my request.

  After a few days don't get any suggestion, I called the store where I bought the printer asking if I could come and exchange it for the same model. I was told that, because it was more than two weeks after the purchase, there will be an additional cost. Until I reluctantly paid the extra money, I called HP support.

  Basically, what the tech support person is to uninstall the printer driver and install the latest version. Which corrects the problem. The process took time, but the result is that the printer works fine now, including the vertical lines.

• Links out to the new line?

  I am currently working on a new site based on CSS on a test server.
  
  I came up against a problem that makes no sense. Links included in the text to other pages or the destinations which have a CSS hover effect sometimes appear on a single line (correct), but at other times the line of text break on the following line when either before I hover over the link or after. This then breaks the flow of the page instead of the background color showing just behind the link. because of the lines of fracture to the other line shows effect hover on the full range?
  
  It is not systematically; It comes and goes; I don't see where it comes from; two lines that contain links will appear exactly the same in construction, but react differently with the mouse?
  
  Any help with this problem would be greatly appreciated. 2 links behave differently on the same page?

  > [b} #column a: link, a: visited {I thought would cover the rules]
  > for
  > the right column.

  Not quite.

  This is known as grouping the descendant selectors in a list separated by commas.

  However, each item in the list (between commas) is treated independently.

  "#column a: link, a: visited" is the same as #column a: link {;} rules more
  a: visited {rules ;}

  After the comma, he must again specify the id selector "#column" then
  Display: block applies only to one: went inside the '#column '.

  In other words, "#column a: link, a: visited" should be "#column a: link,
  "#column a: visited.

  As it is written currently, all States visited the tag is set to
  Display: block, which causes the break on lines after having clicked on everything
  link in the body of the text.

  --
  Concerning

  John Waller

• How can I change the color of the plots (lines, points) in the collection Scattergraph plot

  For example, I go through a foreach loop and draw two points. How to distinguish this set of plots of the yet to come? How can I change the style, color and have separate lines (instead of on the line connecting everything) for each of my plots? I don't know how to set everything up, but it still does what he wants to do. TIA.

  Hello

  The problem you see occurs because of the following lines of code:

  The _data and _data2 scatterPlot3 value

  _data = scatterPlot3

  _data2 = scatterPlot3

  When you do this, you define _data as _data2 to reference an object of the simple concession - scatterPlot3.  Yes, even if you have (from the code you have posted at least) three slots in your collection, they are all pointing to the same object of point cloud.  So when you change the color for one, it changes the color for them all.  However, I think that you have fallen on the right solution in your last sentence.  If you want to have multiple locations on your ScatterGraph, each with its own color and style, they should each be separate and unique plots in the collection plot of your ScatterGraph.  Based on the code you posted, you'll see this if you comment just the two lines shown above.

  Please let me know if something is still uncertain.

  NickB

  National Instruments