Data to be displayed in the following line
HelloWe have created a report that displays columns as the field name and the comment of the employee. I noticed that after10 character the remaining data is displayed on the next line.
Is it possible to displlay data in the same row?
Any help is greatly appreciated.
Thank you
Poojak
Hello
Use white space without film under CSS custom to the title column and column values in order to have them in a single line.
Reference: http://oraclebi.blog.com/tag/data-text-wrap-in-obiee/
Kind regards
Srikanth
Tags: Business Intelligence
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Presentation of the grid - get two or more fields to display on the same line.
I use version 4.2.
I have a form with a number of elements.
I want to control the display of items so that some fields are next to each other (on the same line or line).
I put the provision of grid as follows:
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Anyone have this working?
Amanda.Hi Amanda,.
I think I discovered the cause of the issue, that you face.
The problem is with the model of region "Region alert" and that there no any view defined points indicated the number of grids that can fit into his body in the region. Without any screen edge, the grid layout system attempts to use all the columns available to its container. However, because the alert region extra internal padding, columns won't work and the next line.
To resolve this problem, you need to change the model of region "Region alert", go to "Points of view" and click Add a line. You will need to enter the following fields:
Name: organ of the region
Substitution model: BODY
Rack support: checked
The maximum fixed grid columns: -1This will fix the problem for you. I logged a bug in our bug for this system follow so we can fix it in a later version of the APEX.
Best,
Lyna -
Hi all
with tbdate as
(
Select 6 March 2013 08:00 ' date1, n1 10 'x 1' oggetto in all double union '.
"Select 6 March 2013 08:10 ', 20 ' x 2' of all the double union
"Select 6 March 2013 08:20 ', 10 ' x 3' of all the double union
"Select 6 March 2013 08:30 ', 20 ' x 4' of all the double union
"Select 6 March 2013 08:40 ', 10 ' x 5' of all the double union
"Select 6 March 2013 08:50 ', 30 ' x 6' of all the double union
"Select 6 March 2013 09:00 ', 10 ' x 7' of all the double union
"Select 6 March 2013 09:10 ', 20 ' x 8' of the double
)
Select a.* tbdate one
How can I remove the lines where the total (date1 + numtodsinterval (n1, "MINUTE")) of the previous line does not match the line or the following lines?
With example maybe I'll be more clear
rank 1 03/06/2013 08:00 10 x 1 Yes
rank 2 03/06/2013 08:10 x 30 2 Yes because more time minutes (n1) of the largest previous = 08:10 equal this line
rank 3 03/06/2013 08:20 10 x 3 not because 08:10 + 30 = 08:40 previous line <>this line
rank 4 03/06/2013 08:30 20 x 4 not because 08:10(rows_2) + 30 = 08:40 of the previous lines (2 lines) <>this line
rank 5 03/06/2013 08:40 10 x 5 Yes
tier 6 03/06/2013 08:50 x 20 6 yes because 08:40 plus 10 = 08:50 from the previous row is this line
tier 7 03/06/2013 09:00 10 x 7 no
tier 8 03/06/2013 09:10 10 x 8 Yes
Thanks in advance
Hello
You build the correct path and connect (and then delete the others):
SQL dts@QUALIF > with tbdate like
() 2
3 select to_date (6 March 2013 08:00 ',' dd/mm/yyyy hh24:mi:ss') date1, n1 10 'x 1' oggetto in all double union '.
4 Select to_date (6 March 2013 08:10 ',' dd/mm/yyyy hh24:mi:ss'), 20, 'x 2' dual union all '.
5 Select to_date (6 March 2013 08:20 ',' dd/mm/yyyy hh24:mi:ss'), 10 'x 3' double union all '.
6 select to_date (6 March 2013 08:30 ',' mm/dd/yyyy hh24:mi:ss'), 20 'x 4' double union all '.
7 select to_date (6 March 2013 08:40 ',' dd/mm/yyyy hh24:mi:ss'), 10 'x 5' double union all '.
8 select to_date (6 March 2013 08:50 ',' dd/mm/yyyy hh24:mi:ss'), 20 'x 6' double union all '.
9 select to_date (6 March 2013 09:00 ',' dd/mm/yyyy hh24:mi:ss'), 10 'x 7' double union all '.
10. Select to_date (6 March 2013 09:10 ',' dd/mm/yyyy hh24:mi:ss'), 20 'x 8' from dual '.
(11), a title)
12. Select b.*, sys_connect_by_path (oggetto, '-') pth, connect_by_root (oggetto) r, prior (oggetto) p
tbdate 13 b
14 connect by date1 = prior date1 + prior n1 / 24 / 60
15 beginning with oggetto = 'x 1') '.
16. Select * from a;
DATE1 N1 OG PTH R P
-------- ---------- -- -------------------------------------------------- -- --
03.06.13 10 x1 -x1 x1
03.06.13 20 x 2 - x 1 - x 2 x 1 x 1
03.06.13 20 x 4 - x 1 - x 2 - x 4 x 1 x 2
03.06.13 20 x 6 - x 1 - x 2 - x 4 - x 6 x 1 x 4
03.06.13 20 x 8 - x 1 - x 2 - x 4 - x 6 - x 8 x 1 x 6
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Hello - I have 3 buttons html:
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query
create
They must be displayed on the same line, in the regions of button. (They're in)
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CarolHi Carol,.
It might be interesting to look at model in your region under the shared components > models > region change the model.
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Do not know if my best subject line sums up what I do :)
Oracle DB 12 c (I think 12.1.2)
I have a table with the names of people and DOB with a few keystrokes. It is assumed that this person is the 'same' first_name, last_name, birth_day/month/year are identical
drop table people;
create table persons
(
first name varchar2 (30),
VARCHAR2 (30) last_name,.
birth_month varchar2 (2),
birth_day varchar2 (2),
birth_year varchar2 (4).
keyVal number
);
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insert into values('JOHN','SMITH','10','10','1974',2) people (first_name, last_name, birth_month, birth_day, birth_year, keyval);
insert into values('JANE','SMITH','10','10','1974',3) people (first_name, last_name, birth_month, birth_day, birth_year, keyval);
insert into values('JANE','DOE','10','10','1974',4) people (first_name, last_name, birth_month, birth_day, birth_year, keyval);
insert into values('JANE','DOE','10','10','1974',5) people (first_name, last_name, birth_month, birth_day, birth_year, keyval);
insert into values('ERIC','DOE','11','10','1975',6) people (first_name, last_name, birth_month, birth_day, birth_year, keyval);
insert into values('ERIC','DOE','11','10','1975',7) people (first_name, last_name, birth_month, birth_day, birth_year, keyval);
insert into values('ERIC','DOE','11','10','1975',8) people (first_name, last_name, birth_month, birth_day, birth_year, keyval);
I want to see the following output:
first_name, last_name, birth_month, birth_day, birth_year, keyval_min, keyval_other
JOHN SMITH 10 10 1974 1 2 JANE DOE 10 10 1974 4 5 ERIC DOE 11 10 1975 6 7 ERIC DOE 11 10 1975 6 8 1. the output will display only those who appear at least twice in the original table
2. If the person appears twice in the original table, the output will only one result where first keyval will be min two; second keyval will be the other value;
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It's very large 100 + M and the processing time is important.
Hope I explained it well.
Hello
This sounds like a job for analytical functions.
If the same person has N rows in the table, the output should be N - 1 lines. You can use the ROW_NUMBER analytic function to assign numbers (1, 2, 3,...) to each line and do not display the lines nuimbered 1.
On each line, you must prove the keyval lowest for this person. The analytical MIN function can do this.
Here's one way:
WITH got_analytics AS
(
SELECT first_name, last_name, birth_month, birth_day, birth_year, keyval
, ROW_NUMBER () OVER (PARTITION BY first_name, last_name, birth_month, birth_day, birth_year)
ORDER BY keyval
) AS r_num
, MIN (keyval) OVER (PARTITION BY first_name, last_name, birth_month, birth_day, birth_year)
) AS keyval_min
AMONG the people
)
SELECT first_name, last_name, birth_month, birth_day, birth_year
keyval_min
keyval AS keyval_other
OF got_analytics
WHERE r_num > 1
ORDER BY first_name, last_name, birth_month, birth_day, birth_year
r_num
;
Use the data DATE to the date information type. With the help of 3 columns separate NUMBERS will result in complicated, ineffective, code errors and invalid data.
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I use the following script to customize the layout of a form e-mail:
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JSONArray json = new JSONArray(result); for (int i = 0; i < json.length(); ++i) { JSONObject moleculevalue = json.getJSONObject(i);//get the json data object String tdescription = moleculevalue.getString("Total Description"); if (tdescription == "") tdescription = "Not Applicable"; _fieldManagerMiddle.add(new SeparatorField()); _fieldManagerMiddle.add(new LabelField("Description: " + tdescription, Field.FIELD_HCENTER)); }
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I have the following table:
Service tag Asset Type code Issued to Region FCH11179 1000 [email protected] EMEA CN-011D3V 1004 [email protected] EMEA GX2 1001 [email protected] EMEA CN-00W6KV 1005 [email protected] EMEA LZ242BK0 1004 [email protected] EMEA 9YLDV 1001 [email protected] EMEA CN-00W6KV 1005 [email protected] EMEA FCH111 1000 [email protected] EMEA My result should be as below
Issued to IP_PHONE MOUSE LAPTOP Adapter [email protected] FCH11179 CN-011D3V GX2 CN-00W6KV [email protected] FCH111 LZ242BK0 9YLDV CN-00W6KV I am using the following code but it is not working:
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MIN (decode (ASSET_TYPE_ID, 1001, SERVICE_TAG, NULL)) laptop.
MIN (decode (ASSET_TYPE_ID, 1004, SERVICE_TAG, NULL)) MOUSE,.
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OF AT_ASSET_TRACKER
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Hello guys
I work as a Business Intelligenece Developer and one of my reports, I have a requirement where I have a Date column and the date should be in ascending order IE 1 - JAN - 09
2-JAN-09
1 - FEB - 09
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Flag - Here if the Date is not in the order I have to report it Print N, i.e. If the date is growing Null we ignore and check the
Next Date sequence Vale line
10215 P02095
10220 P02095
P02095 10500 13 March 01
P02095 10600
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P02095 10960
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P02095 63500
P02095 64000
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P02095 64125
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P02095 83000
P02095 84000
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SY.
Published by: Solomon Yakobson on January 23, 2010 10:31
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