Change the clause where in a datablock

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• How to change the path for the clause "where" with TIPS?

  I tried a loooot of positions and you have not found a solution for my case. I don't even know if it of possible or not. Is it possible to change the sequence of Oracle "Predicate Information"?
  
  Here is the my SQL and Oracle execution plan.
  

    SELECT Max(logId) AS logId FROM online_users_t 
    WHERE online_users_date >= to_date('2011-09-19 10:00:00') - 3.2 AND online_users_date <= to_date('2011-09-19 10:00:00') AND online_users_result in (1, -1)
    GROUP BY online_users_user
  
  ---------------------------------------------------------------------------------------------------
  | Id  | Operation                    | Name               | Rows  | Bytes | Cost (%CPU)| Time     |
  ---------------------------------------------------------------------------------------------------
  |   0 | SELECT STATEMENT             |                    | 24800 |   629K|  1336   (1)| 00:00:17 |
  |   1 |  HASH GROUP BY               |                    | 24800 |   629K|  1336   (1)| 00:00:17 |
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  Predicate Information (identified by operation id):
  ---------------------------------------------------
   
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                hh24:mi:ss') AND "ONLINE_USERS_DATE"<=TO_DATE(' 2011-09-19 10:00:00', 'syyyy-mm-dd 
                hh24:mi:ss'))

  I have 2 terms in my article 'where' one is the date range, and the other is ' online_users_result in (1, -1)'. It seems that the Oracle filter the table using the ' online_users_result in (1, -1)' first of all, then access it by date range.
  
  What I want to do first is the table of filtering by using the range of dates followed by other things. How can I do?
  
  Any ideas or help would be very appreciated.
  
  
  Thanks in advance.

  It seems that the Oracle filter the table using the ' online_users_result in (1, -1)' first of all, then access it by date range.

  No it's not.

  What I want to do first is the table of filtering by using the range of dates followed by other things. How can I do?

  It is precisely what he does now.
  It uses the T_IDX index to quickly find all the lines meet the predicate of beach on the date column.
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• Question about the order of evaluation of the clause WHERE CLAUSE when the Oracle OF the syntax used to join tables

  Hello

  Oracle version: 11.1.0.7.0 - 64 bit

  I read the documentation online at joins. The page is avialable here: joins at

  My question is about the join order of evaluation of the conditions in clause and the conditions of those

  are not the join conditions and are placed in the WHERE clause.

  Consider the following pseudocode

  SELECT

  T1. Col1,

  T2.Col1

  Of

  Table1 t1 LEFT OUTER JOIN table2 t2

  WE

  (condition_expression1)

  WHERE

  (condition_expression2)

  Is it correct to say that if there is no column on the status of join (condition_expression1) in condition_expression2, then condition_expression2 is executed before condition_expression1? In other words, oracle always trying to filter based on the WHERE clause individually each table as much as possible before joining them based on the conditions on the article?

  Thanks in advance,

  Hello

  dariyoosh wrote:

  Hello

  Oracle version: 11.1.0.7.0 - 64 bit

  I read the documentation online at joins. The page is avialable here: joins at

  My question is about the join order of evaluation of the conditions in clause and the conditions of those

  are not the join conditions and are placed in the WHERE clause.

  Consider the following pseudocode

  SELECT

  T1. Col1,

  T2.Col1

  Of

  Table1 t1 LEFT OUTER JOIN table2 t2

  WE

  (condition_expression1)

  WHERE

  (condition_expression2)

  Is it correct to say that if there is no column on the status of join (condition_expression1) in condition_expression2, then condition_expression2 is executed before condition_expression1? In other words, oracle always trying to filter based on the WHERE clause individually each table as much as possible before joining them based on the conditions on the article? ...

  The reverse is actually closer to the truth, but we can't really make general statements like that.

  SQL is not a language of the proceedings.  Looking at the code SQL, we could say that the code does, but we cannot say much about how that code it.  In other words, SQL is a language that describes the results you get, not the way to get them.

  The optimizer will do everything what he thinks is faster if it does not change the results.  If any order in which they are applied (in outer joins or CONNECT BY queries, for example), then think of the join is done first, and the value of the WHERE clause is applied to the result of the join.

  Here is a query looks very much like you posted:

  SELECT d.deptno

  e.ename, e.sal

  OF scott.dept d

  LEFT OUTER JOIN scott.emp e ON e.deptno = d.deptno

  WHERE e.sal > = 3000

  ORDER BY d.deptno

  ;

  Output:

  DEPTNO ENAME SAL

  ---------- ---------- ----------

  10 KING 5000

  20 FORD 3000

  20 3000 SCOTT

  The scott.dept table contains deptnos 30 and 40; Why are they not in the result set?  The query behaves as if the outer join is made first (production 15 rows), then the WHERE clause has been applied.  All lines with deptno = 30 had sals down han 3000 and all single line with deptno = 40 was NULL in the sal column, then these lines are excluded (as well as other lines of deptnos 10 and 20), and only 3 lines above are left.

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  Hello
  With the help of JDev 11.1.1.3.0.
  I have a SQL according to VO following where clause ' WHERE some_nbr IN: inSomeNbrStr'
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