Child relationship form Master Builder - column data gets hidden.

Similar Questions

• How to create the column of the table for long-form Master detail relationship

  Apex 4.1

  Oracle 11g

  I created a form master detail and see the main table hotel_list and table hotel_mapping as detailed below.

  Hotel_list

  ID HOTEL_NAME

  1 Holiday Inn

  Hotel Hilton 2

  Hotel_mapping

  ID HOTEL_NAME MAPPING_NAME

  1 Inn Holiday Inn Select hotel

  2 holiday hotel Holiday Inn Select

  3 hotel Holiday Inn Holiday Inn Hotel

  4 Hilton Hotel Hilton Hotel chain

  Hotel Hilton 5 HiltonHotel

  Table Hotel_name Hotel_list is a linked table Hotel_mapping

  When I add a line to the Hotel_mapping table for the selected row in the hotel_list table, mapping_name of column is null, therefore impossible to create the relationship between the main table and the secondary table.

  I would like to know, how to create the relationship?

  Thank you very much

  Best regards

  Yong Huang,

  simple step see creating a form detailed master with APEX - Assistant Master retail

  and check how to maintain the relationship between two tables,

  simple return the packaged application «Sample of Masters details»

  and try to understand this concept...

  In your example, use Hotel_list.ID as a foreign key in the table Hotel_mapping

  and maintain the relationship with the column ID...

  and choose the display type of the column Hotel_list.ID in table Hotel_mapping as List(Query Based LOV) select.

  otherwise the best way is to create sample on oracle.apex.com

  I hope this helps...

  Leave.

• Relationship need master / detail to post a link Master column to the different retail pass 2

  I have a form with a relationship master detail. The main block is a rec_shipments of table of database with a primary key of the shipment_id and a bunch of other columns. The retail block is a rec_containers table with a container_id as the primary key most column shipment_id, split_shipment_id, weight, volume, etc. The shipment_id and the split_shipment_id are nullable.
  
  When a shipment is received a shipping record is created and container records are created with the populous shipment_id and the split_shipment_id null. Under the shape of what a relationship is created between the block of the expedition and the block container as shipment_id = shipment_id. It works very well. However, they have the ability to spit the original containers in small containers easier to manage for the distribution. For example, if they receive a railroad car full of pallets of printer paper they can take and divide the, 1 tray of rolloff half-and-half into another tray of mitigation. The bins of rolloff will get a unique container_id for follow-up. Registration in the system created in the rec_containers table will be the populous split_shipment_id and the shipment_id null. On the screen, they want to see the (railroad car) original containers and containers of split (ferries rolloff) when the query expedition.
  
  What they want:
  Shipment_id - and additional information
  ID drive to railway and additional information
  Rolloff Bin 1 ID and additional information
  Rolloff Bin 2 ID and additional information
  
  My problem is the attenuation of bins do not arise with the current relationship because the shipment_id is set to null in the 2 files of bin rolloff.
  
  I tried to create a view on the rec_containers table that is all columns in the table plus 1 additional column which is
  NVL (shipment_id, split_shipment_id) comp_ship_id
  
  then assign the relationship shipment_id = comp_shipment_id. I have the comp_shipment_id column value query Yes and insert & update or not because I don't want to not update this column in the view.
  
  The problem is I can't update all the columns, I get a cannot book record to update or delete the error.
  
  Does anyone have any ideas how I can get the block of containers to query all records where the shipment_id or the split_shipment_id is shipping block shipment_id and still be able to update the records?
  
  Thanks for any help.

  Your idea of using a view is the best approach. To perform the update block, you have OHS 'Query' property only for your item derived to 'yes '. Witn, the column will not appear in any other dml. On lock... maybe the forms is no longer able to make a regular blocking when a block is based on a view. In this case, put a LOCK ON trigger on the block and lock the record for yourself to SELECT for NOWAIT UPDATE on registration. Just try if it would work, you use a NULL value in the POCKET ON right to xheck if dml himself operations will work. If your view is based on a single table, you have a good chance that there is nothing to change, if you get an error like 'Unmodifiable view', you need to make some additional adjustments
  -Choose the Mode key for the block to 'uneditable '.
  -Set the 'primary key' property to 'Yes' for the pk-point in your block.

  hope this helps

• Build a relationship of Scripts to load data by using a load rule

  You can build a relationship of Scripts to load data using a rule charge and if so, what would this process

  Please notify

  The requirement is in reality a quest for the Holy Grail (instantaneous aggregation in the planning of the BSO)?  We could have a conversation down to level 1 "when there is 10 000' options without being noticed.

• Get the former locations of the data files and Redo logs

  Version: 11.2
  Platform: Solaris 10
  
  When we manage hundreds of DBs, we do not know the locations of all DB files these allows DBs. say a DB goes down and you have all the required RMAN backups.
  
  When you restore the DB in a new location in the path of the new server, you must run the commands for the data files and ORLs below. But how do we know
  
  The former location of the data files.
  
  B. the old location of redo online stores that I can run
  
  run

  alter database rename file 'oldPath_of_OnlineRedoLogs' to 'newPath_of_OnlineRedoLogs' ;  --- Without this command , the restored control file will still reflect the old control file location

  run {
  set newname for datafile 1 to '/u04/oradata/lmnprod/lmnprod_system01.dbf' ;
  set newname for datafile 2 to '/u04/oradata/lmnprod/lmnprod_sysaux01.dbf' ;
  set newname for datafile 3 to '/u04/oradata/lmnprod/lmnprod_undotbs101.dbf' ;
  set newname for datafile 4 to '/u04/oradata/lmnprod/lmnprod_audit_ts01.dbf' ;
  set newname for datafile 5 to '/u04/oradata/lmnprod/lmnprod_quest_ts01.dbf' ;
  set newname for datafile 6 to '/u04/oradata/lmnprod/lmnprod_yelxr_ts01.dbf' ;
  .
  .
  .
  .
  .
  }

  Hello

  With the help of Oracle 11.2, you can use feature 'set newname for database' using OMF.

  SET NEWNAME FOR DATABASE TO '/oradata/%U';
  RESTORE DATABASE;
  SWITCH DATAFILE ALL;
  SWITCH TEMPFILE ALL;
  RECOVER DATABASE;
  

  After the restore and recover databases (i.e. before resetlog open) you can do to rename redolog. Just a query column member from v$ logfile and deliver ' alter database rename file 'oldPath_of_OnlineRedoLogs' to 'newPath_of_OnlineRedoLogs ';

  When we use the DSO is much easier to use OMF because Oracle automatically creates the directory structure.
  But when we use the file system that the OMF does not serve due DBA dislikes system generated on file system names.

  If you don't like OMF file system, you can use the script on thread below to help restore you using readable for datafile names, tempfile, and redo.

  {message: id = 9866752}

  Kind regards
  Levi Pereira

• Form master-detail recording detail does not with ORA-20001

  Hello
  
  I have a master/detail form, the detail record has a timestamp field that I people using systimestamp via the default, it is a single field of view and everthing records very well. But if I change the format of the timestamp field via the DD-MON-YY HH24 attrubutes column, I get the following error on save
  
  Internal error in the routine mru: ORA-20001: error in MRU: line = 1, ORA-20001: find the invalid timestamp value, please check the timestamp format.
  
  Someone knows what's goin?
  
  Thank you...

  Looks like your display only column is based on the database column.
  If this is the case, you have little control for it in ApplyMRU.
  What you need to do is
  a. keep the TimeStamp column hidden with any mask format
  b. Add the form as a table with the format mask you want to display a column of data not

  In a Word, the DB column is in the proper format as required by the ApplyMRU but you display for users of the truncated version of that.

  See you soon,.

• Details of form master maker

  I use Jdev 12.1.3

  Scenario is as follows.

  I have a main table with id maker and column date maker.

  I have a secondary table.

  If I make any changes in the main table column id maker and date maker is updated correctly as I wrote the code below in entityImpl.java

  protected void doDML(int operation, TransactionEvent e) {
          System.out.println("inside dml");
          if(operation==this.DML_UPDATE) {
              System.out.println("Updating Function defn "+ADFContext.getCurrent().getSecurityContext().getUserName());
              setMakerId(ADFContext.getCurrent().getSecurityContext().getUserName());
              setMakerDt(Date.getCurrentDate().timestampValue());
          }
          super.doDML(operation, e);
      }
  

  But if I make a few changes in the secondary table I need to have this Creator id and manufacturer date columns updated. Help on the same.

  If you have the Association between master and detail EO, you can get doDML() EO in detail master record.

  BTW, for data changes, it is best to use EO.prepareForDML () as EO.doDML)

  Dario

• ADF query Panel poster not only any value in form master detail, but the field has a value.

  Hi, I use jdeveloper 12.1.3 1.

  1. I request ADF, master form Panel and secondary table.

  2. by default create insert button is enabled in the secondary table. ( button)

  3. no data is demonstrated at the start and it's ok because the main table of the form and the details is under the Panel request af.

  4. even if no data is shown in the form of af, when we get the value of the field (i.e. product) to support bean, field returns a value.

  5. If I am not able to disable the button.

  I tried to use backing bean to disable this key under certain conditions (example: If there is a value for the product on the screen can turn on this button), even if nothing appears on the screen, if we get the value for the field (i.e. product) it returns a value.

  

  Hello

  Tell me if I'm wrong, but you want to disable the button if there is no data in the form of master?

  Try with this property disabled in your button:

  Disabled = ' #{bindings. " Product.inputValue == null} ".

  change 'Product' for the field in the form that will always return a value when there is a line.

  Kind regards

  Ruben.

• parent/child relationship hirarchy

  Hi everyone, consider the sample data

  SELECT LFROM '1TR1Y6', NULL LTO, MID '11ZFDD', '21XHK7' double UNION ALL TID-

  SELECT '1TR1YF' LFROM, LTO NULL, '11ZFDD' MI '21XHK5' TID FROM dual UNION ALL-

  SELECT '1TR1X1' LFROM, LTO NULL, '11ZFDD' MI '21XHK8' TID FROM dual UNION ALL-

  SELECT '1LSZX1' LFROM, LTO NULL, '11ZFDD' MI '1TR1YD' TID FROM dual UNION ALL-

  SELECT LFROM "1LSZWQ", "21XHK7" LTO, MID '11ZFDD', '1TR1Y6' TID FROM dual UNION ALL-

  SELECT LFROM "1LSZX2", "21XHK5" LTO, MID '11ZFDD', '1TR1YF' TID FROM dual UNION ALL-

  SELECT LFROM "1LSZVG", "21XHK8" LTO, MID '11ZFDD', '1TR1X1' TID FROM dual UNION ALL-

  SELECT LFROM "4LSSVG", "21XHK9" LTO "11AAA' MI '1TR1X1' TID double UNION ALL

  SELECT "AAAAA" LFROM, LTO NULL, '11ABB' e, 'CCCCCC' double UNION ALL TID

  SELECT "BATH" LFROM, 'CCCCCC' LTO, MID '11ABB', 'AAAAA' double UNION ALL TID

  some of them have a parent/child releationship. for example, let take rank with LFROM = 1TR1Y6

  1TR1Y6 (lfrom) corresponds to the fifth line with TID 1TR1Y6.  TID 1TR1Y6 LTO COLUMN value corresponds to the first line TID (21XHK7)

  It before these two LINES are IN a parent/child relationship.

  lets take another example.  LINE two WITH LFROM = 1TR1YF matches sixth RANK WITH TID 1TR1YF.  the sixth LINE LTO COLUMN (21XHK5) corresponds to the SECOND TID of LINE.

  Once again the parent child relationship. There are two lines that do not have the relationship of parent/child (ex.  line 8)

  Im trying to write a query that can partition the data in the middle column and find the parent/child relationship. the output of the above data should be

  LTO LFROM MIDDLE TID FLAG

  1TR1Y6 NULL 11ZFDD 21XHK7 1

  1LSZWQ 21XHK7 11ZFDD 1TR1Y6 1

  1TR1YF NULL 11ZFDD 21XHK5 1

  1LSZX2 21XHK5 11ZFDD 1TR1YF 1

  1TR1X1 NULL 11ZFDD 21XHK8 1

  1LSZVG 21XHK8 11ZFDD 1TR1X1 1

  1LSZX1 NULL 11ZFDD 1TR1YD 0

  4LSSVG 21XHK9 11AAA 1TR1X1 0

  ABDELKÉBIR 11ABB CCCCCC NULL 1

  CCCCCC 11ABB AAAAA BATH 1

  For simplicity, I posted the release with parent/child, side by side in the sequence.  the order does not matter as long as the flag column (pull the column) is set to an appropriate value (1 if parent/child, 0 no parent/child)

  the flag column value is derived from column to indicate the parent/child relationship was found.

  I try using lead, the lag function but I have problem of sorting data from parent and child line could come at random order (they are not side by side).

  It is therefore difficult to use lead because you don't know how many lines to carry forward.

  can someone help me write a query that displays the output above

  SELECT T1. LFROM,

  T1. LTO,

  T1. ENVIRONMENT,

  T1. TID,

  (

  SELECT COUNT (*)

  OF TBL T2

  WHERE)

  T2. TID = T1. LFROM

  OR

  T2. LFROM = T1. TID

  )

  AND T2. MI = T1. MID

  ) FLAG

  OF TBL T1

  /

  LTO LFROM MIDDLE TID FLAG
  ------ ------ ------ ------ ----------
  1LSZWQ 21XHK7 11ZFDD 1TR1Y6 1
  1LSZX2 21XHK5 11ZFDD 1TR1YF 1
  1LSZVG 21XHK8 11ZFDD 1TR1X1 1
  CCCCCC 11ABB AAAAA BATH 1
  1TR1X1 11ZFDD 21XHK8 1
  1TR1X1 11ZFDD 21XHK8 1
  1LSZX1 11ZFDD 1TR1YD 0
  1TR1Y6 11ZFDD 21XHK7 1
  ABDELKÉBIR 11ABB CCCCCC 1
  1TR1YF 11ZFDD 21XHK5 1
  4LSSVG 21XHK9 11AAA 1TR1X1 0

  11 selected lines.

  SQL >

  SY.

• Detailed form Master in Apex - creating main records and details at the same time

  I m trying to create a master form / retail.
  The master is a simple standard form and below on the same page there is a tabular presentation containing the details.
  
  I am facing a problem when you try to save a new record from the master at the same time with new details.
  If I create a new record of the master and at the same time create detail records for this master (on the same page), when I submit that the foreign key of the details field is not filled in. So only one master record gets inserted into the table and record line is not inserted.
  
  When I have everything first create a master without a detail and edit this master and then add details so everything's allright (since the primary key field is filled out at the time).
  
  I just need to confirm that whether in the APEX form master detail, can save master and line record at the same time or is it as master must be registered the 1 and then line must be enterd and saved?
  
  Please let me know, if this functionality can be achieved in the APEX.

  Hello

  There was an error in the process of pl/sql, you referenced f01 (F01. COUNT) in the loop condition and which should have been f03, also you have assigned the wrong field to what should have been P3_DEPARTMENT_ID

  I fixed that. Also, I'm not 100% sure but I think in order to use the table in the column must be of type text or something (and not hidden), but I can't check now because of lack of time.

  A few mistakes during the presentation, but they are still due to constraints on the other fields.

  FOR I IN 1.APEX_APPLICATION. G_F03. COUNTY

  LOOP

  APEX_APPLICATION. G_F03 (I): =: P3_DEPARTMENT_ID;

  END LOOP;

  Concerning

  Bottom

• Form master / detail - constraint integrity

  Hello
  I created a form master / single detail. Master block is based on say Table1 with 2 columns and block detail based on the Table2 with 4 columns.
  When I am creating records using this form, I enter data in the main block and then navigate to detail block and then enter data. When I press save button,
  the shape raises the error message ' ORA-02291: integrity constraint (APPS.» "FK_RECORD_IDENTIFIER) violated - key parent not found."
  When I check the query using help-> Diagnostics-> display database error, the insert statement is insert into table2 values (...
  
  I guess that the form tries to insert data into table2 first. Given that no entry in Table1, where the error. What should be done, so that the form inserts block Master data in table1 first before you try to insert data block of retail.
  
  Concerning
  Suresh

  Suresh,

  In the view of The Navigator object , check the block order under the section of data blocks . The master's block should come first, and then only the detail should come. If his is not like that, and then modify the order of the blocks by dragging the main block at the top of the blocks.

  Kind regards

  Manu.

  If my answer or the answer to another person has been useful or appropriate, please mark accordingly

• Oracle Forms - master and detail block (join problem).

  Hi all
  
  I have a form (Oracle forms 6i) with 2 data block (master and a block of retail). I have 4 fields in the main block and of the rating is a Nullable.
  
  The problem here is when I query the records - if the Nullable filed of the master is empty, then all records matching the first 3 fields are displayed. (Regardless of the fields fouth is NULL or Not NULL).
  
  Ex: Master
  
  Area 1 area 2 area 3 area 4
  21 Siva MNN PEUT
  John TGB USD
  
  
  
  Now, the block of this detail, all records that may have deposited 1 has NULL also 21 etc.
  
  
  I want to display zone 1 is the NULL records in detail block, if the master has the NULL value in it.
  
  Can someone help me?
  
  Thank you in advance!
  
  Nice day!

  In your post is not clear what the relationship between the tables please post the table structure and their relationship information

• Create the form for enrty of data such as oracle forms tabular block by ADF Table!

  Hi guru and Experts
  
  I need some solutions for Oracle JDeveloper11g which is very essential for me.
  
  + Q1. Is it possible to create a form master detail which block detailed will be a tabular as like oracle forms . If possible I such example? +
  
  Q2. How can I create a preview to the point like oracle forms overview at the point of tables?
  
  Q3. How can I add LOV/list items / check for a table/table column?
  
  Q4. If it is possible to insert a new record in the table of the ADF, so I need to save all your data by pressing a key SAVE event
  
  
  I wish you all already taken I want developed. Please give me a better solution.
  
  
  
  Thank you.
  Zed
  ====

  A correction to the above – if you want the table to be modified/inserted you cannot drag and drop as a master-detail, because the detail will be in read only mode.
  Instead first drag the captain and drop as a form of ADF
  Then, drag the details below and drop it as Table of ADF.

  You can drag since the operations node in the data control the operation createInsert to add a button that will add a new empty row to the table.

• in the query and parent/child relationship

  WITH the data AS

  (

  SELECT '213NY1' lfrom, NULL, '215ZVD' mi lto, "215ZV9 ' id, 1 January 2014' sdate, January 2, 2014' edate, 3 January, 2014 'mdate' January 5, 2014 medate double UNION ALL.

  Lfrom SELECT NULL, '215ZVD' mi, id "213NY1", "215ZV9" lto 4 January 2014 'sdate', 6 January 2014 edate, January 7, 2014 'mdate', 8 January 2014 medate double UNION ALL

  SELECT '216TVZ' lfrom, NULL, "213JW7" e "217LVQ" id lto, 21 January, 2014 'sdate' January 9, 2014 edate, 10 January 2014 'mdate', 11 January 2014 medate double UNION ALL

  SELECT lfrom "215Y71", "217LVQ" lto, mi, "216TVZ" id "213JW7", 22 January, 2014 'sdate' January 23, 2014 edate, 24 January, 2014 'mdate' January 25, 2014 medate double UNION ALL

  SELECT '234IJF' lfrom, NULL, "234YU" e "3IUED" id lto, 26 January 2014 'sdate', 27 January 2014 edate, 28 January 2014 'mdate', 29 January 2014 medate OF double

  )

  some lines have parent/child relationship and some does not. for example, the first two query (data) are link together. online, the value of lto (215ZV9) corresponds to the id value

  in line 1.  the value of lfrom in row1 (213NY1) corresponds to the value of online id.

  the same scenario occurs in rows 3 and 4.  5th doesn't have any line which is a child. tier 5 is a single parent

  I want to WRITE a query that gives the following result.

  Mid id initial_date final_date

  =======================================

  215ZVD 215ZV9 1 January 2014 "January 5, 2014"

  "215ZVD 213NY1 7 January 2014" January 6, 2014 "

  "213JW7 217LVQ 21 January 2014 ' 11 January 2014"

  "213JW7 216TVZ 24 January 2014 ' 23 January 2014"

  "234YU 3IUED 26 January 2014 ' 27 January 2014"

  ONLY WHEN there is a parent/child relationship, initial DATE AND follow the final data WHAT such as

  FIRST date of deadline DATE

  < Mdate > < EDate > - for child

  < SDate > < MEDate > - for parent

  WHEN there is no relationship of parent/child (e.g. ONLY a parent ROW) THEN

  FIRST date of deadline DATE

  < SDate > < EDate-> parent

  can someone help me write a query for the above output

  with tt AS

  (SELECT a.*,

  ROW_NUMBER () ON LV (MIDDLE ORDER BY SDATE PARTITION),

  CASE

  WHEN ID = NVL (ADVANCE (lto, 1) OVER (PARTITION BY Middle ORDER BY sdate), LAG (lfrom) OVER (ORDER BY sdate Middle PARTITION))

  THEN 1

  END flg

  DATA one

  )

  SELECT THE MIDDLE,

  ID,

  CASE

  WHEN flg IS NOT NULL

  THEN

  CASE

  WHAT LV = 1

  THEN SDATE

  WHAT LV = 2

  THEN mDATE

  END

  Of ANOTHER sdate

  END INITIALDATE

  CASE

  WHEN flg IS NOT NULL

  THEN

  CASE

  WHAT LV = 1

  THEN mEDATE

  WHAT LV = 2

  THEN EDATE

  END

  Of ANOTHER edate

  END FINALDATE

  TT;

  Output:

  -------------

  MID ID INITIALDATE FINALDATE

  213JW7 217LVQ 21 January 2014 January 11, 2014

  213JW7 216TVZ 24 January 2014 23 January 2014

  215ZVD 215ZV9 January 1, 2014 5 January 2014

  215ZVD 213NY1 January 7, 2014 6 January 2014

  234YU 3IUED 26 January 2014 January 27, 2014

• How to cut the column data

  Gurus in the morning
  
  I have two tables with the data in the corresponding column, BUT I need to cut the columns in a table
  the data is displayed as follows in table xpq_log

  LOG_DATE                     LOG_PTR     LOG_HDR
  01/06/2011 00:00:00     0609pro     0609IN002C_06
  04/06/2011 00:00:00     0609pro     0609IN002C_06
  05/06/2011 00:00:00     0609pro     0609IN002C_06
  06/06/2011 00:00:00     0609pro     0609IN002C_06
  07/06/2011 00:00:00     0609pro     0609IN002C_06
  09/06/2011 00:00:00     0609pro     0609IN002C_06
  10/06/2011 00:00:00     0609pro     0609IN002C_06
  12/06/2011 00:00:00     0609pro     0609IN002C_06
  01/06/2012 00:00:00     0609pro     0609IN002C_06
  02/06/2012 00:00:00     0609pro     0609IN002C_06
  03/06/2012 00:00:00     0609pro     0609IN002C_06
  06/06/2012 00:00:00     0609pro     0609IN002C_06
  07/06/2012 00:00:00     0609pro     0609IN002C_06
  08/06/2012 00:00:00     0609pro     0609IN002C_06
  09/06/2012 00:00:00     0609pro     0609IN002C_06

  In the table of printpdf as follows

  PDF_REPORT     PDF_DESCRIPTION
  IN002C                     STOCK FILE PURGE - PRINT WH CONTROL

  How can I cut the column data (log_hdr) to match column (pdf_report)?
  
  Any help will be much appreciated

  user11978142 wrote:
  Yes the code always starts with an alphabetic character and always ends before the underscore character and the prefix is always digital.

  And Yes to the second comment WRT 1 to many relationship.

  WRT the duplicates I want the info displayed even if there is no matching printpdf

  You talk a LEFT OUTER JOIN, then:

  See the example below (the statement are just to reproduce the paintings, just use the last query):

  WITH xpq_log AS
  (
     SELECT '0499SYS003A_06' log_hdr FROM DUAL UNION ALL
     SELECT '0612PV410W1_06' log_hdr FROM DUAL UNION ALL
     SELECT '0609IN002C_06' log_hdr FROM DUAL UNION ALL
     SELECT '2201PA100D1_30' log_hdr FROM DUAL
  )
  , printpdf AS
  (
     SELECT 'SYS003A' pdf_report, 'STOCK FILE PURGE - PRINT WH CONTROL' description FROM DUAL UNION ALL
     SELECT 'PV410W1' pdf_report, 'Description 2' description FROM DUAL
  )
  SELECT a.log_hdr, REGEXP_SUBSTR (a.log_hdr, '[[:alpha:]][^_]*') AS pdf_report
       , b.description
    FROM xpq_log a LEFT OUTER JOIN printpdf b
         ON pdf_report = REGEXP_SUBSTR (a.log_hdr, '[[:alpha:]][^_]*');
  
  Output:
  LOG_HDR        PDF_REPORT     DESCRIPTION
  -------------- -------------- -----------------------------------
  0499SYS003A_06 SYS003A        STOCK FILE PURGE - PRINT WH CONTROL
  0612PV410W1_06 PV410W1        Description 2
  2201PA100D1_30 PA100D1
  0609IN002C_06  IN002C                                           
  

  Kind regards.
  Al