Concatenate the initials of last names, first and middle initials of the name of a field.

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• Concatenate the address lines (some fields will be empty)

  Hi people,

  I need to format an address with transport flows properly and no blank lines between the two. I tried to look for a similar thread but did not find anything (I'm sure that). I leave the names in this exercise that my main problem is with formatting the address correctly.

  Assumptions:

  1. city, State and ZIP Code on a single line

  2. Add 2 and Add3 should be on the same line

  My exits address should be the following:

  Student ID 1001

  2070

  The University Avenue

  Berkeley, CA 94704 (city, State and ZIP Code on a single line)

  Student ID 1002

  Department of physics

  2111 Bancroft way Berkeley UC (add 2 and Add3 should be on the same line)

  Berkeley, CA 94720

  Student ID 1003

  100 market Street

  San Francisco, CA 94114

  Student ID 1004

  342 happy Valley Road

  Fremont, CA 94212

  Table scripts and data:

  create table STUDENT_ADDRESS_TB (student_id	VARCHAR2 (4).
  	street_number	VARCHAR2 (20).
  	ADD2	VARCHAR2 (50).
  	Add3	VARCHAR2 (50).
  	City	VARCHAR2 (30),
  	State	VARCHAR2 (2),
  	Zip_code	VARCHAR2 (10));

  insert into student_address_tb (student_id,street_number,add2,add3,city,state,postal_code) values ('1001','2070','University Avenue',null,'Berkeley','CA','94704');
  insert into student_address_tb (student_id,street_number,add2,add3,city,state,postal_code) values ('1002','Physics Department','2111 Bancroft Way','UC Berkeley','Berkeley','CA','94720');
  insert into student_address_tb (student_id,street_number,add2,add3,city,state,postal_code) values ('1003',null,'100 Market Street',null,'San Francisco','CA','94114');
  insert into student_address_tb (student_id,street_number,add2,add3,city,state,postal_code) values ('1004',null,null,'342 Happy Valley Road','Fremont','CA','94212');
  
  

  Any help in this regard would be great!

  Here's what I came up with but it does not work as I want it.

  	SELECT street_number	Ligne_adresse_1,
  	decode (add2, null, add3, add2 |) » '|| Add3)	Ligne_adresse_2,
  	decode (city, null, null, city | ',' |) State | » '|| Zip_code)	address_line_3
  	OF student_address_tb;

  Thanks in advance.

  Post edited by: Roxyrollers

  Hello

  Roxyrollers wrote:

  Hi Frank,.

  I'll leave the separate name and include any in my exercises:

  Looks like his work for the first two, but I get the distribution additional return for 1003 and 1004 students. This is of course due to the first CHR (10) as student 1003 and 1004 have no street number. I tried to change x, but I still land by getting the return transport.

  NVL2 (street_number, NULL, street_number | 10 |)

  Remember how NVL2 works.  The 2nd argument is what you want to return if the 1st argument is not NULL, and the 3rd argument is what you want, if it is NULL.  So you say, ' if street_number is not NULL, then return NULL; otherwise return newline. »

  Reverse 2nd and 3rd arguments, like this:

  NVL2 (street_number

  street_number | CHR (10)

  NULL

  )

  Notice how, in response to #2 above, the 2nd argument of NVL2 was never NULL; It was the 3rd argument which was NULL,

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  Original title: address book

  I want that my address book to view all entries by first or last name and have filled all the information accordingly. However, I have a mixture of the first name and the name of the list alphabetically when I scroll down tom insert name in an e-mail message. My list of contracts is organized by all the names first. How can I sync the address book to match the list of contacts?

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  2 are. what device or software you using Sync?

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• Extract the first name and last names of a string

  Hello people,
  I am trying to extract the last name, first name, first name and initial of some names of students for a report. I have some success with the first name and the first names, but have some difficulty to come with the other two. I use Oracle 9i and would like to come with the SQL.
  
  Script to create the table:
  

  create table grad_student_tb
  (student_id varchar2(3) primary key,
   salutation varchar2(4),
   student_name   varchar2(60));

  Script to insert records into the table:
  

  Insert into GRAD_STUDENT_TB (STUDENT_ID,SALUTATION,STUDENT_NAME) values ('001','Mr','Adams,Robert Murphy');
  Insert into GRAD_STUDENT_TB (STUDENT_ID,SALUTATION,STUDENT_NAME) values ('002','Mr','Green,Eric Craig');
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  Insert into GRAD_STUDENT_TB (STUDENT_ID,SALUTATION,STUDENT_NAME) values ('004','Mr','Adams,Michael William H');
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  Here's what I would like on my report:
  

  Student ID   First Middle Name    Last Name   First Name   Initial
  ==================================================================
  001          Robert Murphy        Adams       Robert       M
  002          Eric Craig           Green       Eric         C
  003          Jennifer William H   Brown       Jennifer     W
  004          Michael William H    Adams       Michael      W
  005          Snow                 White       Snow

  Currently my SQL looks like this:
  

  select student_id,
         SUBSTR(student_name, INSTR(student_name,',')+1, LENGTH(student_name)) first_middle_name,
         SUBSTR(student_name,1, INSTR(student_name,',')-1) last_name
  from   grad_student_tb;

  Output:
  

  STUDENT_ID FIRST_MIDDLE_NAME                                            LAST_NAME                                                    
  ---------- ------------------------------------------------------------ ------------------------------------------------------------ 
  001        Robert Murphy                                                Adams                                                        
  002        Eric Craig                                                   Green                                                        
  003        Jennifer William H                                           Brown                                                        

  I need to come up with the first name and initial of the students.
  
  Any help is greatly appreciated!
  
  Thank you
  
  Published by: Roxyrollers on August 18, 2011 12:53

  Assuming that each name is exactly the same format

  SQL> ed
  Wrote file afiedt.buf
  
    1  select student_id,
    2         SUBSTR(student_name,
    3                INSTR(student_name,',')+1,
    4                LENGTH(student_name)-INSTR(student_name,' ')) first_name,
    5         SUBSTR(student_name,
    6                INSTR(student_name,' ')+1) middle_name,
    7         SUBSTR(student_name,
    8                INSTR(student_name,' ')+1,
    9                1) middle_initial,
   10         SUBSTR(student_name,1, INSTR(student_name,',')-1) last_name
   11* from   grad_student_tb
  SQL> /
  
  STU FIRST_NAME      MIDDLE_NAME          MIDDL LAST_NAME
  --- --------------- -------------------- ----- ---------------
  001 Robert          Murphy               M     Adams
  002 Eric            Craig                C     Green
  003 Jennifer        William H            W     Brown
  

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  Justin

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