Concatenate the integers between a table?

Hi all

I have a table with 4 separate inside numbers, let's say they are: [1, 0, 1, 0]

When you retrieve the table, they appear as follows: 1, 0, 1, 0

But I would like to recover the matrix of a single number: 1010

What would be the best way to do this?

Thank you very much for your time.

Brendan

What Ned said work, but it's simpler to use Array.join:

var a: Array = [1,0,1,0];

trace (a.Join(""));

1010

Tags: Adobe Animate

Similar Questions

  • concatenate the data in 2 tables in a third table as well as in CONCATENATE strings

    Hello. as the title says, I wish to only concatenate the data in 2 tables in a similar third table that concatenate strings don't. All tables should be 1 d. For example, suppose that there is 1 table with the following: 1. 2; 3; 4 and table 2 with:; b; c; d. I would like a table 3 either 1 a, 2 b, 3 c, 4 d. Now this could be done easily with above mentioned concatenate strings, then table construction. but table 1 and 2 have something like 150 items. Rather painful. Any ideas?

    Hold arrays of two strings in a loop for example, concatentate the strings inside the loop and run the result réécrirait array3.

    Autoindexing manages table manipulations.

    MIke...

  • What is the difference between a table and a subform?

    What is the difference between a table and a subform in LC forms? Please post your answers about the merits and demerits of using subforms instead of tables.

    Hello

    a table is simply a set of subforms with a particular role.

    It is easier to handle the tables if they must be dynamic (add or remove lines, show or hide lines when page breaks appear etc..).

    And Designers UI has some dialogue prepared in the object palette to simplify the settings of the tables.

    For subforms, dialog boxes are more frequent, so you have yourself a little more script.

    But at least you can do everything with subforms as you can do with tables.

    The only one who is not very good with tables we work when you wrap arrays in other tables.

  • The most elegant way to get the difference between two tables - not least!

    Hello


    Simplified example of what I'm trying to achieve - I have two tables ORIGINAL and REVISED.


    My aim is to compare the two, such as; -


    When there is data in the two tables I get the difference between the Budget column, and if there is no difference, so I don't want no lines.

    When data exists in the ORIGINAL, but not in review, I want to the inverse of the current value of the Budget column.

    Where the data exist in REVISED I want the REVISED value.

    I can see how I can do this, see below, but is there a more elegant solution?




    Data for the ORIGINAL table
    select '801040' entity, '2186' expense_type, 234000 budget
from dual
union all
select '801040' entity, '3001' expense_type, 1000 budget
from dual
union all
select '801040' entity, 'P132' expense_type, 34000 budget
from dual
union all
select '801040' entity, 'P135' expense_type, 43000 budget
from dual
    Data for the REVISED table
    select '801040' entity, '2186' expense_type, 235000 budget
from dual
union all
select '801040' entity, 'P132' expense_type, 34000 budget
from dual
union all
select '801040' entity, 'P139' expense_type, 56000 budget
from dual
    Desired output



    ENTITY EXPENSE_TYPE DIFFERENCE
    ------ ------------ ----------
    801040 2186 1000
    801040 3001-1000
    801040 P135-43000
    801040 P139 56000

    5 selected lines.



    Code current to achieve this, is there a better way?
    select original.entity
,      original.expense_type
,       (nvl(revised.budget,0) - original.budget) as difference
from   original
,      revised
where  original.entity = revised.entity(+)
and    original.expense_type = revised.expense_type(+)
and   (nvl(revised.budget,0) - original.budget) != 0
union all
select  revised.entity
,       revised.expense_type
,       revised.budget as difference
from   revised
where  not exists
(select 'x'
from   original
where  original.entity = revised.entity
and    original.expense_type = revised.expense_type)
and    revised.budget != 0
    Thanks a lot for your comments,.


    Robert.

    Published by: Robert Angel on January 17, 2012 03:31 to change is not equal to! = - Thanks for the heads up 
    SQL> with original
  2  as
  3  (
  4    select '801040' entity, '2186' expense_type, 234000 budget
  5    from dual
  6    union all
  7    select '801040' entity, '3001' expense_type, 1000 budget
  8    from dual
  9    union all
 10    select '801040' entity, 'P132' expense_type, 34000 budget
 11    from dual
 12    union all
 13    select '801040' entity, 'P135' expense_type, 43000 budget
 14    from dual
 15  )
 16  , revised
 17  as
 18  (
 19    select '801040' entity, '2186' expense_type, 235000 budget
 20    from dual
 21    union all
 22    select '801040' entity, 'P132' expense_type, 34000 budget
 23    from dual
 24    union all
 25    select '801040' entity, 'P139' expense_type, 56000 budget
 26    from dual
 27  )
 28  select *
 29    from (
 30          select nvl(o.entity, r.entity) entity,
 31                 nvl(o.expense_type, r.expense_type) expense_type,
 32                 nvl(r.budget,0) - nvl(o.budget,0) budget
 33            from original o
 34            full join revised r
 35              on o.entity = r.entity
 36             and o.expense_type = r.expense_type
 37         )
 38   where budget <> 0
 39  /

ENTITY EXPE     BUDGET
------ ---- ----------
801040 2186       1000
801040 P135     -43000
801040 3001      -1000
801040 P139      56000

SQL>

  • Please help understand the mappings between PS &amp; tables tables of data warehouse

    Hello
    We have OBIEE 11 g with OLIVIER 7.9.6.3 (HR Analytics) installation with Informatica PowerCenter SE 9.01 HF2. We use PeopleSoft HRMS 9.1 system source.
    Can you please help me how to understand the flow of data from end to end (or data model with relationship) between the PeopleSoft Tables and tables of data warehouse? Y at - it none available who liaises between the PeopleSoft HRMS tables and tables of data warehouse?

    PS We are new to Informatica workflow maps to find it very difficult to understand each mapping for each table.

    You can use the guide to table HR analytics on metalink. Here's the note:

    HR Analytics, Oracle Business Intelligence - Source tables uses [ID 1328607.1]

    This will show you the use of the main table. If you need the full line, you can use the data lineage Guide.

    If it helps, please mark as correct.

  • The spacing between a table and the edge of the page

    For a table, instead she's px or more away from the left edge, can 2 you do it right up against the left edge?

    Under Page Properties, change the left margin 0 pixels. Who must drag your page to the brim.

  • How to find the relationship between the tables

    Hello
    I am working in Oracle R12

    How to find the relationship between these tables INV_MIN_MAX_TEMP, po_requisition_lines_all and Per_all_people_f

    These two tables, I joined with po_requisition_lines_all and Per_all_people_f To_person_id of PO and anyone HR table but I can't able to join this table with other tables INV_MIN_MAX_TEMP

    concerning
    Srikkanth

    solved

  • What is the difference between cached and no cached TT tables

    Hi all

    I have three users in my Timesten

    User Admin 1.TimesTen - cache
    2 - cacheuser user cache manager
    3.cbs_owner user schema (which is the same name as the user of oracle schema)


    I have a few groups of cache in timesten for oracle tables, I created some tables on user schema TTs to compile tables pacakges.these not associted with groups of cache;


    My question is what is the difference between cahed tables (tables associted with cache groups) and not cached (associted with any group of cache) TTs schema user, nice tables want to help me

    example-

    Command > tables;

    CBS_OWNER. ACCOUNT_SUBSCRIBER / / table belongs to the Group of cache
    CBS_OWNER. OFFER_REF / / not belogs to any group of table cache



    Thank you
    -AK

    Published by: AK08 on June 13, 2010 23:30

    I just started to investigate TimesTen... and I think that the cache groups allow you to replicate data to and from Oracle. for example
    -Group of cache Read-Only: spreading tables cached in Oracle to TimesTen.
    -Group of asynchronous/synchronous cache: spreading the Oracle data.
    -User managed group cache: no automatic update or spread.

    No cached tables do not have the features of spread.

  • How to establish the relationship between the tables contact and Global (entity) in Oracle Service Cloud to preconfigure data

    Hello

    We strive to integrate the OPA attributes to the Cloud Service Oracle tables to store session data for the customer portal users.

    We tried mapping the attributes of the OPA with relevant tables of cloud Service Oracle? Is there any installation of additional data to create to retrieve the session data for the particular user / contact?

    We managed to save tha data in arrays of cloud Service for users of ananymous and also well regarding customers portal users but to preconfigure data do we need to do any additional configuration / mapping to the contact table?

    Please help on the establishment of the relationship between the contact and Global (new table created in cloud Service) tables.

    Thank you

    Vivek

    Hi Vivek,

    To load data from the Contact in the the OPA policy template, you must configure the widget of the OPA. For instructions, see the following articles:

    - Incorporate an interview that uses data portals in Oracle Service Cloud Customer Portal

    - Deploy and configure the sample OPA widget

    - Insert the widget to sample in a customer portal page

    Obviously, you need to do the mapping in OPM as well, but even if the mapping is correct, you will not be able to load the Contact data unless the widget of the OPA is implemented.

    See you soon,.

    Jasmine

  • SQL Developer / Data Modeler - lost visual on the relationships between the tables

    11 GR 2 DBMS / SQL Developer 4.0.3

    In SQL Developer, using the Data Modeler I lost the visuals 'lines' (one to several, etc.) which show the PK to FK relationship between different tables from one of my patterns of relationship.  I know they exist - I'm sure it's my fault--put out something that I don't have.

    I looked on the web but without SOAP.  Can anyone tell me if it is a property and (as applicable) how to re - turn on the property.

    Thanks in advance.

    Barry D.

    Sorry - I found it - the relationship lines were VERY clear yellow and I could barely see it.

    Article by Jeff Smith on the model configuration screen has been very useful in this regard.

    http://www.thatjeffsmith.com/archive/2013/01/Configuring-display-of-model-relationships-in-Oracle-SQL-Developer-Data-Modeler/

    Thank you Jeff (again).

    Barry D

  • What is the difference between the type of table and view?

    Hello world.

    What is the difference between the type of view and table that we can set using SQL statement such as: "tab type is table of...» » ?

    A view is a stored query.

    An array type is a construction of PL/SQL.

    Both are documented:

    http://docs.Oracle.com/CD/E11882_01/server.112/e10897/schema.htm#ADMQS0841

    Management of schema objects

  • The differences between CAT and table TAB

    1. What is the difference between cat and TAB?
    2. why TAB does not exist in dict?
    3. that the same situation for cat and TAB?

    Thanks a lot for your answer kindly.

    sys@ORCL > cat desc
    Name Null? Type
    ----------------------------------------------------- -------- ------------------------------------
    TABLE_NAME NOT NULL VARCHAR2 (30)
    TABLE_TYPE VARCHAR2 (11)

    sys@ORCL > tab desc
    Name Null? Type
    ----------------------------------------------------- -------- ------------------------------------
    TNOM NOT NULL VARCHAR2 (30)
    TABTYPE VARCHAR2 (7)
    NUMBER OF CLUSTERID

    sys@ORCL > select * dict where table_name = "CAT";

    TABLE_NAME COMMENTS
    ---------- -----------------------------------
    Synonym of cat for USER_CATALOG


    sys@ORCL > select * dict where table_name = 'USER_CATALOG ';

    TABLE_NAME COMMENTS
    -------------------- -----------------------------------------------------------------
    USER_CATALOG Tables, views, synonyms, and sequences belonged to the user

    You've posted enough to know that, for each position, you will need to provide your version of Oracle 4-digit (SELECT * FROM V$ VERSION)
    >
    1. What is the difference between cat and TAB?
    2. why TAB does not exist in dict?
    3. that the same situation for cat and TAB?
    >
    1, 2, 3 - TAB has been deprecated then don't use it.

    Definitioni of base for those located in the reference database
    http://docs.Oracle.com/CD/B28359_01/server.111/b28320/statviews_2127.htm#sthref1535
    >
    CAT

    CAT is a synonym for USER_CATALOG.
    . . .
    USER_CATALOG

    USER_CATALOG lists all the tables, views, clusters, synonyms, and sequences belonged to the current user. Its columns are the same as those of "ALL_CATALOG".
    . . .
    DICT

    DICT is a DICTIONARY.
    . . .
    DICTIONARY

    DICTIONARY contains descriptions of data dictionary tables and views.
    . . .
    TAB

    TAB is included for compatibility. Oracle recommends that you do not use this view.
    >
    TAB has been deprecated. He looks like the cat because it shows the USER objects, but it does not show the sequences, like the cat.

    If you look at the source code for the views TAB and USER_CATALOG you can see the differences. This code is copyrighted by Oracle Corporation, all rights reserved.

    /* Formatted on 1/1/2013 8:50:07 AM (QP5 v5.115.810.9015) */
CREATE OR REPLACE FORCE VIEW SYS.TAB
(
   TNAME,
   TABTYPE,
   CLUSTERID
)
AS
   SELECT   o.name, DECODE (o.type#,
                            2,
                            'TABLE',
                            3,
                            'CLUSTER',
                            4,
                            'VIEW',
                            5,
                            'SYNONYM'), t.tab#
     FROM   sys.tab$ t, sys."_CURRENT_EDITION_OBJ" o
    WHERE       o.owner# = USERENV ('SCHEMAID')
            AND o.type# >= 2
            AND o.type# <= 5
            AND o.linkname IS NULL
            AND o.obj# = t.obj#(+);
. . .
/* Formatted on 1/1/2013 8:54:45 AM (QP5 v5.115.810.9015) */
CREATE OR REPLACE FORCE VIEW SYS.USER_CATALOG
(
   TABLE_NAME,
   TABLE_TYPE
)
AS
   SELECT   o.name,
            DECODE (o.type#,
                    0, 'NEXT OBJECT',
                    1, 'INDEX',
                    2, 'TABLE',
                    3, 'CLUSTER',
                    4, 'VIEW',
                    5, 'SYNONYM',
                    6, 'SEQUENCE',
                    'UNDEFINED')
     FROM   sys."_CURRENT_EDITION_OBJ" o
    WHERE   o.owner# = USERENV ('SCHEMAID')
            AND ( (o.type# IN (4, 5, 6))
                 OR (o.type# = 2 /* tables, excluding iot - overflow and nested tables */
                     AND NOT EXISTS
                           (SELECT   NULL
                              FROM   sys.tab$ t
                             WHERE   t.obj# = o.obj#
                                     AND (BITAND (t.property, 512) = 512
                                          OR BITAND (t.property, 8192) = 8192))))
            AND o.linkname IS NULL;

  • What is the difference between associative arrays and nested tables?

    Hello
    What is the difference between associative arrays and nested tables?

    nested tables cannot be indexed by other than pls_integer and unlike nested tables table associative cananot be declared at the schema level.

    is there any other difference set apart from the diff above 2?

    user13710379 wrote:
    What is the difference between associative arrays and nested tables?

    Name-value pairs (associative) against a list of values (table standard/nested table).

    nested tables cannot be indexed by other than pls_integer

    They are not "indexed" the way in which an associative array is indexed. A standard table is referenced by the position of the cell in the table. This position is essentially the offset of the memory of the cell from the start address of the table.

    Can not solve a cell in an associative array directly via a memory offset index. You place a cell reference value it by his 'name' (a search in the linked list/hash table).

    The following example shows the difference between the pairs of name / value and a list of core values.

    SQL> declare
  2          --// associative arrays are NAME-VALUE pairs
  3          type TArr1 is table of varchar2(10) index by pls_integer;
  4          type TArr2 is table of varchar2(10) index by varchar2(10);
  5
  6          arr1    TArr1;
  7          arr2    TArr2;
  8  begin
  9          arr1(100) := '1st entry';
 10          arr1(1) := '2nd entry';
 11          arr1(5) := '3rd entry';
 12
 13          arr2('john') := 'New York';
 14          arr2('jane') := 'Paris';
 15          arr2('jack') := 'London';
 16
 17  end;
 18  /

PL/SQL procedure successfully completed.

SQL>
SQL>
SQL> declare
  2          --// standard arrays are lists
  3          type TArr3 is table of varchar2(10);
  4          type TArr4 is table of number;
  5
  6          arr3    TArr3;
  7          arr4    TArr4;
  8  begin
  9          arr3 := new TArr3( '1st entry', '2nd entry', '3rd entry' );
 10
 11          arr4 := new TArr4( 100, 1, 5 );
 12  end;
 13  /

PL/SQL procedure successfully completed.

SQL>

  • How to find the Union between the column in the table

    Hello

    I have the followin table and I want to find the union between the lines as below,
    create table test5 (tidset varchar2(200));

insert into test5 values('1;2;3;4;5;6;7;8;9;10;11;12;13;15;16;17;18;19;20');
insert into test5 values('1;2;3;4;5;6;7;8;9;10;11;12;13;14;15;16;17;18;19;20');
insert into test5 values('1;2;3;4;6;7;8;9;11;12;13;15;16;19;20');
insert into test5 values('1;4;6;10;6;11;12;13;14;15;16;17;18;19;20');
    I need the result to be as below.
    1;4;6;11;12;13;15;16;19;20
    any help please,.

    Published by: user11309581 on November 17, 2011 21:32

    Always mention what version of oracle you are using.

    The following query will give you the desired result oracle version 11g release 2.

    Connected to Oracle Database 11g Release 11.2.0.2.0 

SQL>
SQL> with test5 as
  2  (
  3  select '1;2;3;4;5;6;7;8;9;10;11;12;13;15;16;17;18;19;20' tidset from dual union all
  4  select '1;2;3;4;5;6;7;8;9;10;11;12;13;14;15;16;17;18;19;20' from dual union all
  5  select '1;2;3;4;6;7;8;9;11;12;13;15;16;19;20' from dual union all
  6  select '1;4;6;10;6;11;12;13;14;15;16;17;18;19;20' from dual
-- "END OF SAMPLE DATA"
  7  ), all_items as
  8  (
  9    SELECT regexp_substr(t.tidset, '[^;]+', 1, column_value) item
 10          ,t.tidset
 11      FROM test5 t
 12          ,TABLE(CAST(MULTISET
 13                      (SELECT LEVEL
 14                         FROM dual
 15                       CONNECT BY LEVEL <=
 16                                  length(regexp_replace(t.tidset, '[^;]')) + 1) AS
 17                      sys.odcinumberlist))
 18  ),item_counts as
 19  (
 20    SELECT DISTINCT a.item
 21                   ,COUNT(DISTINCT a.tidset) over() total_tidset
 22                   ,COUNT(a.item) over(PARTITION BY a.item) item_occurance_count
 23      FROM (SELECT DISTINCT item
 24                           ,tidset
 25              FROM all_items) a
 26  )
 27  SELECT listagg(item, ';') within GROUP(ORDER BY to_number(item)) common_items
 28    FROM item_counts
 29   WHERE total_tidset = item_occurance_count
 30  ;

COMMON_ITEMS
--------------------------------------------------------------------------------
1;4;6;11;12;13;15;16;19;20

SQL>

    OR if you have any version of oracle less than 11g release 2 then replace below mentioned line

    SELECT listagg(item, ';') within GROUP(ORDER BY to_number(item)) common_items

    with this one

    select xmlagg(xmlelement(c,item||';').extract('//text()') order by (to_number(item))) common_items

    It is because the listagg function used in above query is not supported in versions of oracle 11.2 below.

    I hope this helps.

    -Gregory

    Published by: Mohamed Diarra on November 18, 2011 01:05
    Extra line to be changed for the oracle version lower than 11.2

  • I need to implement Drag N Drop between two tables that saves the two records

    I need to implement Drag N Drop between two tables that saves the two records on a third page, using drag 'n drop.

    Check out this video http://baigsorcl.blogspot.com/2011/01/drag-and-drop-collection-in-oracle-adf.html

Maybe you are looking for