Concepts of partition

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• Reference partitioning concept in Oracle 11 g.

  Hello world

  My version of DB is

  BANNER

  --------------------------------------------------------------------------------

  Oracle Database 11 g Enterprise Edition Release 11.2.0.3.0 - 64 bit Production

  PL/SQL Release 11.2.0.3.0 - Production

  CORE Production 11.2.0.3.0

  AMT for Linux: Version 11.2.0.3.0 - Production

  NLSRTL Version 11.2.0.3.0 - Production

  Thanks to Oracle by adding the concept of partitioning. Please have look at the below examples of tables, when trying to fetch something from the child table with specifying a date range, then it accesses the parent table partitions. But I wonder how about a 2nd child level?

  If I create a table over which will be a child table of ORDER_ITEMS, so how can I implement partitioning of reference for this child to level 2? We have some tables of the order, which is designed like that, it took a huge effort so that the archiving of these documents. Now that we are modernizing our database 11 g R2, then we can have the partitioning for these tables reference. While is it to the next level? Can do us the same for the 2nd child level so or how is it?

  -Parent table

  CREATE TABLE ORDER_MAIN_TBL

  (

  ORDER_ID NUMBER PRIMARY KEY,

  ORDER_DATE DATE NOT NULL ACTIVATE.

  ALLOW CUSTOMER_ID NUMBER NOT NULL,

  NUMBER OF SHIPPER_ID

  )

  PARTITION BY RANGE

  (

  ORDER_DATE

  )

  (

  DEC2014 PARTITION VALUES LESS THAN (TO_DATE (' 2014-11-01 00:00:00 ',' SYYYY-MM-DD HH24:MI:SS ',' NLS_CALENDAR = GREGORIAN ')),

  NOV2014 PARTITION VALUES LESS THAN (TO_DATE (' 2014-12-01 00:00:00 ',' SYYYY-MM-DD HH24:MI:SS ',' NLS_CALENDAR = GREGORIAN ')),

  PARTITION OT_MAXVALUE VALUES LESS THAN (MAXVALUE)

  ) ;

  -Parent child table containing the reference

  CREATE TABLE ORDER_ITEMS_TBL

  (

  ORDER_ITEMS_ID NUMBER PRIMARY KEY,

  ALLOW ORDER_ID NUMBER NOT NULL,

  ACTIVATE THE PRODUCT_ID NUMBER NOT NULL,

  NUMBER OF AWARDS,

  QUANTITY NUMBER,

  CONSTRAINT ORDER_ITEMS_TBL_FK FOREIGN KEY (ORDER_ID) REFERENCES ORDER_TEST (ORDER_ID) ACTIVATE

  )

  PARTITION REFERENCE

  (

  ORDER_ITEMS_TBL_FK

  ) ;

  Kind regards

  BS2012.

  Hi BS2012,

  You almost!, forget not... in the distribution for fks reference all must be a column not null, which is not present in the ORDER_ITEMS_CHILD table.

  --Child table of ORDER_ITEMS
  CREATE TABLE ORDER_ITEMS_CHILD
    (
      ORDER_ITEMS_ID NUMBER NOT NULL,
      COMMENTS      VARCHAR2(100),
      CONSTRAINT ORDER_ITEMS_CHILD_FK FOREIGN KEY (ORDER_ITEMS_ID) REFERENCES ORDER_ITEMS (ORDER_ITEMS_ID) ENABLE
    )
    PARTITION BY REFERENCE
    (
      ORDER_ITEMS_CHILD_FK
    )
    ;
  

  Kind regards

  Juan M

• Partition on the clarification of required list

  Hello gurus

  I need clarification on the partition table
  TABLE
  PART)
  Primary key NUMBER PARTNO,
  NUMBER OF LB/PO2
  MEDIAN NUMBER)

  MEDIAN will have 10 distinct values from 0 to 9

  so I created 10 partition list on PART Table for 1 part01 part02 for 2... so now

  Select partno
  a part

  Watch the plan INDEX (PRIMARY KEY is used with scan limited quick index)

  
  Select partno
  partition part01 - selection '1' median part

  don't watch no clue is scanned... It is in full table scan

  
  Please suggest
  My partno primary key must be local indexed?
  MEDIAN should be indexed at the local level?

  
  Help, please

  S

  Select partno

  a part

  Here you select the entire table, then there should be a FULL table scan.

  Select partno

  partition part01 - selection '1' median part

  Here the partition must be ENTIRELY digitized as all lines are being accessed.

  My partno primary key must be local indexed?

  I think he must have the overall index, assuming that the primary key should be used without using the partitioning key column in the WHERE clause.

  MEDIAN should be indexed at the local level?

  Yes.

  Here are the generic guidelines for the creation of global/local index:

  When you decide what type of partitioned index to use, you should consider the following recommendations in order:

  1. If the table partitioning column is a subset of index keys, use a local index. If this is the case, you are finished. If this is not the case, continue to guideline 2.
  2. If the index is unique and does not include the partitioning key columns, use a global index. If this is the case, then you are finished. Otherwise, continue to guideline 3.
  3. If your priority is the ease of management, use a local index. If this is the case, you are finished. If this is not the case, continue to guideline 4.
  4. If the application is an OLTP we and users need fast response time, use a global index. If the application is an a MAS and users more interested in flow, use a local index.

  Concepts of partitioning

• Partitioning in Essbase

  From the expensive

  I am new to the concept of partitioning can you please help me out in the idea of creating a partition in Essbase ASO and the OSB.

  Thank you.

  Please see the link below.

  Creating partitioned ASO reports Cubes into Essbase 11.1.2

  Thank you.

• Partitioned tables

  Hello
  
  I am new to the concept of partitioning the Table. Is it possible to check whether a table is a partitioned table, or not?
  
  Kind regards
  
  007

  007 wrote:
  Hello

  I am new to the concept of partitioning the Table. Is it possible to check whether a table is a partitioned table, or not?

  Kind regards

  007

  select table_name,PARTITIONED from dba_tables where table_name='Table name';
  

  If partitioned = yes, then check what are partitions

  select PARTITION_NAME from dba_tab_partitions where table_name='Table name';
  

• activate functionalty edition as a company on a standard edition

  Hello

  I would like to know if it is possible to activate a feature of Enterprise edition (materialized views) on a standard.

  I know that you can switch between versions, from standard to the enterprise by an upgrade, but I need just a feature of business.

  Best regards

  Joey

  You are right. It's really a difficult question. The number of rows and columns you read this table is quite important.

  It is difficult to deal with a large amount of data in SE. Views materialized, if it works, you will save time to the hash join and not so much for the analysis of full tables.

  (It might a little, because it may contain fewer columns than the table origin.)

  What are your options?

  • You can compress the data. (Alter table move compress). It can take a lot of time and a lot of them space. Best, try it on a test database. There was also the provision at the time of scanning.
  • You can partition the data. Based on the query above organization and read the State would be criteria for the right partition. What about other queries? Partitioning is not supported on itself. You must code using the old concept of "partitioning view" version 7. Pretty hard to do, as little as possible. Can be code examples in the net.

  More simple is definitely o EE crossing.

• [vCenter 5] Partitioned network concept

  Hi all

  I am in trouble: I'm just trying to understand the partitioned network!
  1 cluster, 4 ESXi 5.0, 4 VM, 2 heartbeat data warehouses.
  Everything is OK: 1 master, 3 slave, 4 VM 'protected '.
  (Mon test: sur l'hôte 1 esclave, je suis réseau débranché mgmt: vSphere HA État: «Connected (esclave) ') "to"Partitioned"(I can RTC in the fdm.log on Master, data warehouses Heartbeat works)... but after a few seconds, he changed his State for 'isolated '.
  Why? Host is still alive via Heartbeat data warehouses ("[ClusterDatastore::UpdateSlaveHeartbeats] (VMFS) ' host-121 @ 9 c: 8e:99:28:6f:c0 is ALIVE '")
  The host must not remain in the State "partitioned"?
  (I read the vSphere 5.0 high availability Deep Dive)
  Thanks for your help
  Concerning

  No, a host can really be partitioned in this case, it will stay in "partitioned" State This can happen, for example, if you have a cluster extended - if the network connection between the 2 sites goes down, while there will be 2 sets of the cluster hosts that can communicate with each other, but not with hosts on the other site. No host is isolated, but each site is separated from the other. In this case, each partition will elect its own master and each master will be guests in the other partition as "partitioned". When the network connection is facing upward, a master will be "abdicating" and become a slave to the other.

  Elisha

• Partitioning for Windows 7

  Hey guys,.

  I'm new to this whole concept of the original operating system. I have this Windows 7 shipped with the system on a single partition. I am conscious of having a single partition facilitates the recovery of the system from disk hard in case the computer crashes.

  It makes me a disadvantage of having only one partition with all my data into it.

  I wish I could partition my single drive in a couple of discs.

  No idea how you could do...

  Hello

  Normally, if you buy a Toshiba laptop there is already a second partition on the HARD drive with the folder HDDrecovery for example if I m wondering about this, because you wrote also that Windows 7 is shipped with your system.

  Anyway, the creation of new partitions is quite easy. It s the same procedure as in Windows Vista:
  http://APS2.toshiba-tro.de/KB0/TSB7101OB0006R01.htm

  If you have any other questions, please let us know! :)

• Computer laptop touch screen 15: need help - restore Partitions, OS system, start-up and drivers!

  [Need help]

  Device name: laptop touch screen, Energy Star, 15.

  Model number: 15 - f023wm

  Device status:
  [Grandma] "I broke the internet.
  [Me] "No, I have demolished just any chance I had as a computer programmer.
  I'll never do it to heaven now... »

  You want to come: difficulty this laptop!

  -Packing plant (Reset/retrieve)

  -Retrieve/Re-restore boot loader

  Retrieve/recreate/Re-restore all original scores.
  -Retrieve / Re - restore all the Original system & hardware drivers.

  -Retrieve/Re-restore Windows 8.1.

  -Possibly find computer Tech/Geek fellow/Pal.

  -Learn something new! (Not including the common sense).

  Explanation:
  -J' was too high as he tried to become the next Bill Gates and create a calculation method in which the processor completely laws of physics bi-passes.

  Topical issues:

  (1) I have little experience, I'm sure compared to most of the users on this forum; However, in the College computer Programmning.

  ---> Very adept in acquireing newly introduced information & request a great sense of understanding of puzzled, abstract and largely serious concepts. (It will be just a little easier than most to explain a simple fix).

  (2) I deleted all partitions, including the system files, System opperating, some methods of starting, all the drivers, and to add to the mess, the existing partitions are not yet check the size or formatting - I'm sure.

  ---> (Drive C is 400 GB;) Drive D is the main partition with only 20 GB)

  (3) any chance of installation/download are only feasible when my boyfriend does everything it does and 'fixed' the laptop.

  ---> Cell phone MAY start, can use internet and MAY be able to download 5 pictures before the system shuts down and the other requires a few hours to wipe the minimum amount of space on the hard disk before you reinstall Windows.

  (4) Windows 7 is the only OS (so far) that we are able to install; We have no other disks, but Windows 8.1, I think, was the original Opperating system and look forward to this return.

  (5) I don't know yet how I will receive notification here on these forums. I'm drunk at 05:59, so I'll find out tomorrow.

  ---> Assuming that I remember I wrote it.
  
  And I think that's all that I need a little help with if you want messages me or live chat to help solve this problem, I think that Skype is aloud; and in all the uncertainties, it is listed on my profile.

  Thank you, & your best.
  Caleb D. Parker
  @CiDiParks25

  CiDiParks25

  What will work restores your computer to its original factory state using HP recovery media.  It is a DVD and CD set that will erase the hard drive (removing all data, applications and settings, reinstall the original OS, drivers and utilities for HP. In some cases, you will be able to order a USB instead of discs.  You must order at HP; they cannot be downloaded.
  
  The link is on the software page and download drivers for your PC: http://support.hp.com/us-en/drivers/selfservice/HP-15-Notebook-PC-series/7137590/model/7484025

  Once there, scroll to the bottom of the page and you will see an entry for the command Recovery Media-CD/DVD/USB. Click on the symbol '+' to expand this entty and click on order to press for more details.
  
  Or, if you prefer, you can do the same by contacting HP Customer Service:
  
  If you live in the United States or the Canada, details are on this page: http://www8.hp.com/us/en/contact-hp/phone-assist.html#section1
  
  If you live elsewhere, contact details are on this page: http://www8.hp.com/us/en/contact-hp/ww-contact-us.html
  
  Note that if HP no longer provides a recovery media for your model, a few other sites, you can check are: http://www.computersurgeons.com/ and http://www.restoredisks.com/
  
  Don't forget to read through the material in the linked thread before attempting the recovery: http://support.hp.com/us-en/document/c00707939
  
  Good luck
  
  I'm a volunteer and I do not work for, or represent, HP.
  ========================================================================
  If you feel that my suggestions helped you, please click on the thumbs-up symbol to say thank you!
  
  If they helped to solve your problem, please click 'Accept as Solution' to help others find similar information.

• Will the concept AD LDAP Referral supports two different forests

  Hello

  I have areas DomainA under ForestA and DomainB in ForestB. I would like to implement the concept of LDAP Referral for these two areas, so I have set up between these two areas and add a crossRef under CN = Partitions for DomainA and trying to search for DomainB users using ldp.exe DomainA.

  But it seems to not work.

  LDAP Referral Concept is supported in my case?

  I read somewhere that ads supports LDAP Referral for domains that are in the same forest, is this true?

  Can someone help me with this? Please let me know if I am missing any configuration.

  Thank you

  Phani

  Hello

  Post your question in the TechNet Server Forums, as your question kindly is beyond the scope of these Forums.

  http://social.technet.Microsoft.com/forums/WindowsServer/en-us/home?category=WindowsServer

  See you soon.

• Move the recovery partition

  I have a new HP Pavilion p6 - 2220t, 4 GB ram, 500 GB hard drive. There the C: partition for the operating system (Windows 7 home premium 64-bit) and the D: partition of data as the recovery partition.

  I want to split the C: partition into two partitions, one for the operating system and one for my data. If I move the recovery partition d: using 3rd party partition software (partition magic) without changing the drive letter, it still operates as a recovery partition?

  Thank you for your help in advance.

  I think that your concepts of misunderstandings. The 'C' partition can be divided into partitions, and the D left alone.

  Here is mine, after the creation of partitions. I've never touched him was 'partition.

  

  

• Installing Windows twice on a separate partition/HARD drive

  De : mdagli1

  I currently have Windows XP pro installed. (I have XP pro OS here too install disc) Is it possible to install again but at an another partition/disk? (So I have XP installed on a partition, then installed again on another partition create 2 places to start from).

  And if I install using twice the same XP install disc, pourrais I update one of them using a Windows Vista ultimate upgrade disc?

  (That leaves me with XP pro on one partition and Windows Vista on another.)

  Am I allowed to do?

  De : [Antonio Feitosa]

  It is possible and perhaps even legal.  As the 2 operating systems are on the same machine, they cannot run at the same time. You have the right to run XP pro on a single machine. You also have the right to run Windows Vista on a machine using Windows Vista AND XP licenses and the license of Windows Vista is an updrage one.

  The legal concept is the "notion of open book" in the sense that you can not open a book in two places or two pages at the same time.

  Since the machine is the same, you can run Windows Vista or XP using the start menu.

  But to get this work may require a boot manager other than BCDEdit, or use a 3rd Setup disk borrowed from someone. Or to play a few rounds with bcdedit and maybe partition software mgmt...

  Another response of the community of Windows Vista discussion groups

• How can I move the folder of my users on a different Partition?

  Hi, I recently bought Windows 7 for my PC.

  I want to know how to move my complete record of users (C:\Users) to my D drive partition, that make (D:\Users) and then remove the users from the C drive folder, so that all my files and user data are stored on my D drive partition, since my C drive is for the OS and drivers only. Now, I know that you can move files within your name in the users, by right-click folder and clicking on the location tab, but this option is not available on the users folder itself. If it is not possible to move all of the users folder, find at least one solution where I can move my folder by name (C:\Users\Jord) D drive instead.

  Thanks in advance

  -Jordan

  I answered this question at least three times in the last few days/weeks. Please visit the following links. Some are on the folder C:\Users (work folder to be more general) while others refer to the same concept, but for different folders. I hope this helps.

  Link 1: http://social.answers.microsoft.com/Forums/en-US/w7files/thread/8d15f660-293a-48cc-bfc3-f978ad59d67e
  Link 2: http://social.answers.microsoft.com/Forums/en-US/w7files/thread/924138a5-bdb2-4ab4-870b-57b3a8b8ff44
  Link 3: http://social.answers.microsoft.com/Forums/en-US/w7files/thread/bb84d104-d6d6-43c5-be62-b065ee4fa819
  Link 4: http://social.answers.microsoft.com/Forums/en-US/w7files/thread/6af0cf60-84f6-4e48-b0a1-2780a5fd7b7a if you find my answer was what you are looking for, please don't forget to click on the link "Propose as answer" below.

• Swap partition after the derivation of a field value

  Hello gurus

  There is a table that currently contains records 4billion. In this table, there is an obligation to fill a new column that is currently empty. The logic to fill the column based on the value of another column and using substr/instr, we can calculate the value to be entered in the new column. Meaningful to shoot is not a problem. This existing table in which I want to fill the new field is partitioned. Now, since its seen record 4billion and its partitioned and Yes its compressed as a result, I don't mean to update the table of origin rather go for Exchange of partitioning.

  One would be a pseudo-code or flow for the same. I think so

  1. create a temporary table that held all the records of 4 b of the table in its population and origin derive the logic of the new field.

  2. once the temporary table is populated, use exchange notion of partitioning to transfer the data from the temporary table to the original table.

  Please confirm my understanding and if possible any pseduocode to reproduce this scenario will be very useful.

  Thank you very much

  To use the exchange concept, you do partitioning wise partition (a bit like the pseudocode below):

  create the table exchange_table as

  Select c_1, c_2,... out

  Since the partition of big_table (some_partition)

  where 1 = 2;

  for x in (select nom_partition from user_tab_partitions where table_name = "BIG_TABLE")

  loop

  
  

  run immediately "insert into exchange_table" |

  "Select c_1, c_2,..., c_k,..., substr (c_k, instr (c_k,...),...). René,... out ' |

  «partition big_table (' |)» x.partition_name | ') ';

  
  

  run immediately 'alter partition change table big_table' | x. nom_partition | "with table exchange_table;

  
  

  run immediately 'truncate table exchange_table;

  
  

  end loop;

  Concerning

  Etbin

• Manual partitioning - with a check for pruning constraint

  I have a client who won't pay partitioning for real, but only Monster table on a data warehouse that must be broken into pieces for performance applications.

  What I want to do is manually partition table, create a union all join view which is located on top, then have oracle prune query plans for me to hit only the tables that I need to fill the result set.

  
  

  -Create table
  create the table a_tbl
  (
  col1 varchar2 (20).
  col2 varchar2 (20).
  COL3 varchar2 (20).
  COL4 varchar2 (20)
  )
  tablespace AAA_DATA;

  -Create/recreate check constraints
  ALTER table a_tbl
  Add constraint a_tbl_restrict
  check (col1 = 'aaa');
  
  create the table b_tbl
  (
  col1 varchar2 (20).
  col2 varchar2 (20).
  COL3 varchar2 (20).
  COL4 varchar2 (20)
  )
  tablespace AAA_DATA;

  -Create/recreate check constraints
  ALTER table b_tbl
  Add constraint b_tbl_restrict
  check (col1 = 'bbb');
  
  create the table c_tbl
  (
  col1 varchar2 (20).
  col2 varchar2 (20).
  COL3 varchar2 (20).
  COL4 varchar2 (20)
  )
  tablespace AAA_DATA;

  -Create/recreate check constraints
  ALTER table c_tbl
  Add constraint c_tbl_restrict
  check (col1 = 'ccc');
  
  ALTER table A_TBL
  Add primary key constraint a_tbl_pk (COL1, COL2)
  using index
  tablespace AAA_INDEX;

  ALTER table B_TBL
  Add primary key constraint b_tbl_pk (COL1, COL2)
  using index
  tablespace AAA_INDEX;

  ALTER table C_TBL
  Add primary key constraint c_tbl_pk (COL1, COL2)
  using index
  tablespace AAA_INDEX;
  
  Create view abc_v as
  Select * from a_tbl
  Union of all the
  Select * from b_tbl
  Union of all the
  Select * from c_tbl;

  When I run a query against the view that would eliminate two of the tables, I don't see the size that passes.

  Select * from abc_v

  where col1 = 'aaa' and col2 < '100'

  order by col2

  SELECT STATEMENT, GOAL = 3 1 48 ALL_ROWS

  SORT ORDER BY 3 1 48

  DISCOVERED A LOT OF 2-1-48 ABC_V

  UNION-ALL

  TABLE ACCESS BY INDEX ROWID BUNCH 4 2 96 A_TBL

  INDEX RANGE SCAN BUNCH 3 2 A_TBL_PK

  FILTER

  TABLE ACCESS BY INDEX ROWID HEAP 2 1 48 B_TBL

  INDEX RANGE SCAN HEAP 2 1 B_TBL_PK

  FILTER

  TABLE ACCESS BY INDEX ROWID HEAP 2 1 48 C_TBL

  INDEX RANGE SCAN HEAP 2 1 C_TBL_PK

  I do something that is not possible without partitioning "true"?  Or I put in place without a certain way?

  Thank you!

  Cory Aston

  Cory,

  the concept of the partition views is very old - among the best results in google, I get a link for the setting to version 7.3.3 guide: view of Partition Management - I didn't know that these pages still exist. 7.3 was released in 1996.

  Since then, Oracle has frequently said that views of partition are desupported - but they seem to work yet. If I use your example I get the following execution plan:

  --------------------------------------------------------------------------------------------

  | ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time |

  --------------------------------------------------------------------------------------------

  |   0 | SELECT STATEMENT |          |     1.    48.     1 (100) | 00:00:01 |

  |   1.  SORT ORDER BY |          |     1.    48.     1 (100) | 00:00:01 |

  |   2.   VIEW                          | ABC_V |     1.    48.     0 (0) | 00:00:01 |

  |   3.    UNION-ALL |          |       |       |            |          |

  |   4.     TABLE ACCESS BY INDEX ROWID | A_TBL |     1.    48.     1 (0) | 00:00:01 |

  |*  5 |      INDEX RANGE SCAN | A_TBL_PK |     1.       |     1 (0) | 00:00:01 |

  |*  6 |     FILTER |          |       |       |            |          |

  |   7.      TABLE ACCESS BY INDEX ROWID | B_TBL |     1.    48.     1 (0) | 00:00:01 |

  |*  8 |       INDEX RANGE SCAN | B_TBL_PK |     1.       |     1 (0) | 00:00:01 |

  |*  9 |     FILTER |          |       |       |            |          |

  |  10.      TABLE ACCESS BY INDEX ROWID | C_TBL |     1.    48.     1 (0) | 00:00:01 |

  | * 11 |       INDEX RANGE SCAN | C_TBL_PK |     1.       |     1 (0) | 00:00:01 |

  --------------------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  5 - access ("COL1" = 'aaa' AND "COL2"<>

  6 - filter (NULL IS NOT NULL)

  8 - access ("COL1" = 'aaa' AND "COL2"<>

  9 - filter (NULL IS NOT NULL)

  11 - access ("COL1" = 'aaa' AND "COL2"<>

  The most important part is (once again) the section predicate containing filter NULL IS NOT NULL predicates that should always evaluate to false. So I would say: works as advertised (once upon a time...)

  Concerning

  Martin