Conditional region with functions, does not

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• Modulo function does not properly

  
  Hi Experts,

  I use OPM version 10.4.5. I have three "Number 1", "Number2" and 'Number3' attributes and my rule is such that:

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  Now this modulo function does not give the expected results when I take a number less than 1 in the denominator.

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  So when number1 = number2 = 0.4 and 1.6, Number3 = 0, in this case, I'm getting correct output.

  I tried a lot of combinations and I get incorrect results in many scenarios.

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  Kind regards

  Mounia

  Interesting.  Working with fractions is not too common in arithmetic mod and I think that there is a debate on this subject in math.

  That said, I agree the best answer to 1.2 mod.4 is probably 0.

  Just guessing here, but it may be a mistake floating arithmetic precision spread due exactly point your choice of fractions in the heart. 1.2 et.4

  Note that in the OPA: 1.2-.4 * trunk (1.2/.4, 0) = - 2 x 10 ^-16 as opposed to the answer of 0.  It's an indication or a tip, you can have floating point arithmetic accuracy challenges.

  Here's the fun trivia.  Google also provides the same answer for 1.2 mod.4 =.4! https://www.Google.com/#q=%3D+1.2+mod+.4 

  However, my windows calculator provides the answer to 1.2 mod.4 = 0.

  A simple selection of numbers of 0.1-2.0 > OPA No.1 increments shows 1.2 mod.4 is a quirk for which Google and agree OPA.

  In any case, while you and Oracle considers it interesting the result, if you need a work around, my guess is that something like this will do:

  Number3 = number 1 - number (text ((Numéro2 * Trunc (Numéro1/nombre2, 0))))

  This would be a possible workaround to Number3 = Number1 mod number2

  I use an old trick of developer to convert a number to text and back again to clear the registry so to speak.  Something like that might work as a temp band-aid. I would wait for a response from the Oracle, however.  I make too many assumptions about my answer to be used on a production database without talking to the appropriate Oracle.

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