Confirm delete before inserting then have a unique key.

Hello

I have a use case where a database field that is entered by the user must be unique.

In the database, there is already a record for example 'name1 '.

The user inserts a new record and puts his name 'name1' as well. Then, for some reason any decides to delete the first existing record and tries to save the new record 'name1 '.

The previous record validation "Name1" is not yet removed, but the new record with 'name1' seeks to insert.

Then I get the error message: attribute value 'name1' leads to duplicate keys for this type of entity. oracle.jbo.AttrValException...

Is it possible to run delete before insertion on commit or another work around?

JDev Version 11.1.2.3.0

Concerning

Here is the link which suites for your usecase

ADF binary Decompilation: customization of the display order of the changes made to the database

You need to wtite your own custom of the Transactionfactory class.

Let us know if it works for you

Thank you

Tags: Java

Foreign key constraints

Whenever two tables have one or more common columns, Oracle database can apply the relationship between the two tables with a foreign key, also called a referential integrity constraint constraint. The constraint requires that for each value in the column on which the constraint is defined, the value in the other specified that another table and column must match. An example of a referential integrity rule is that an employee may work for only one Department.

Table 5-2 lists the terms associated with referential integrity constraints.

Table 5-2 referential integrity constraint conditions

Term Definition

Foreign key

The column or set of columns included in the constraint definition that refers to a key that is referenced. For example, the department_id column employees is a foreign key that refers to the department_id column of departments .

Foreign keys can be described as several columns. However, a composite foreign key must refer to a primary or unique key with the same number of columns and the same types of data.

Term	Definition
Foreign key	The column or set of columns included in the constraint definition that refers to a key that is referenced. For example, the `department_id` column `employees` is a foreign key that refers to the `department_id` column of `departments` . Foreign keys can be described as several columns. However, a composite foreign key must refer to a primary or unique key with the same number of columns and the same types of data.

The value of the foreign keys can be either the primary or unique key value referenced or be null. If any column of a composite foreign key is null, then the portions not null the key do not match any corresponding part of a parent key.

Referenced key

The unique key or the primary key of the table referenced by a foreign key. For example, the department_id column departments is the key referenced to the department_id column of employees .

Table dependent or child

The table containing the foreign key. This table is based on the values present in the primary or unique key referenced. For example, the employees table is a child of departments .

Referenced or the parents table

The table that is referenced by the foreign key of the child table. It is the key to this table reference that determines whether specific inserts or updates are allowed in the child table. For example, the departments table is a parent of employees .

The first three terms defined in the table EXPLICITLY State references to the 'core' or 'unique' keys to the parent.

The doc also refers to the Application Developer Guide:

Maintaining the integrity of the data in Database Applications

Foreign key references a primary key by default

If the list of columns is not included in the REFERENCES option when you set a FOREIGN KEY constraint (simple or composite column), then Oracle database assumes that you want to reference the primary key of the specified table. You can also explicitly specify the columns to reference the table parent in parentheses. Oracle database checks automatically to check this list of column refers to a primary or unique to the parent table key. If it isn't, an informative error is returned.

That the entire paragraph is as explicitly as it gets.

No list of columns? Oracle then checks for a primary key.

There is a list of columns? Then Oracle 'control to verify this list of column made reference to a primary or unique key'...

Trigger before insert
Hi, I need help to create a trigger before the insertion of the STA_STARTDATE column in the employees table
```
CREATE OR REPLACE TRIGGER trig_start_date
BEFORE INSERT OF STAFF FOR EACH ROW
BEGIN
  IF STA_STARTDATE < '01-JAN-1980'
    THEN
        RAISE_APPLICATION_ERROR(-20900, 'No earlier than 1/1/1980');
  END IF;
END;
```
Note: If the declaration is < 01 - JAN-1980 quotes

When I run the script, it comes up with this error:

Error report:
ORA-04073: invalid column list for this type of trigger
04073 00000 - "list of invalid columns for this type of trigger.
* Cause: A list of columns has been specified for a non updated trigger type.
* Action: Delete the column list.

* fixed by replacing the OF keyword with, but still have a warning

Published by: 888948 on October 2, 2011 16:48
Hello

to use a column in a trigger, the column must have: new for new values, or: old old values before the name of the column, so your if statement should begin with:
```
IF :NEW.STA_STARTDATE 
```
Herald tiomela
http://htendam.WordPress.com

I come to me on my computer and everything was gone. All my files, shortcuts and backround have simply disappeared. It's like I've never been on my computer before. I have nothing! How to get everything back?

I come to me on my computer and everything was gone. All my files, shortcuts and backround have simply disappeared. It's like I've never been on my computer before. I have nothing! How to get everything back?

You have been discharged into a temporary user account. It may be a glitch, or your user account may be damaged. First try a system restore when things worked. If it suits it, fine. If it is not then your account is damaged and the best thing to do is to create a new user account and copy your data from the old to the new. I would also like to do a Chkdsk and then some hardware diagnostics on the hard drive and RAM to make sure that the material is solid.

CHKDSK - click here to open the computer. Right click on the hard drive you want to check, and then click Properties. Click on the Tools tab and then, under error-checking, click check now. If you are prompted for an administrator password or a confirmation, type the password or provide confirmation.

To automatically repair problems with files and folders that the scan detects, select automatically fix file system errors. Otherwise, the disk check will simply report a problem, but not to fix them.

To perform a full disk check, select search and attempt to recover bad sectors. This scan is trying to find and repair physical errors on the hard drive itself, and it may take much longer to complete.

To check for errors file and the physical errors, select both automatically fix errors in file system and search for and attempt recovery of bad sectors.

Click Start.

Depending on the size of your hard disk, this may take several minutes. For best results, do not use your computer for any other tasks while it checks errors.

Note: If you select automatically errors in file system of fix for a disc that is used (for example, the partition that contains Windows), you will be prompted, see the disk check for the next time you restart your computer.

Hardware tests - http://www.elephantboycomputers.com/page2.html#Hardware_Tshoot

Corrupt user account - if your single administrative user account is damaged (and therefore have what one user account is A Bad Thing), you must log on to the built-in Administrator (disabled by default in Vista) account. From there, you can create a new user account for yourself. In these cases, I prefer not to copy the whole profile to a new way to do not copy the bits corrupt. I prefer a new user account to copy the data (documents, photos, emails, etc.). Here are the instructions to do this. I assumed that you had only an administrative account, then you might want to take a look at the "general recommendations for setting Up user accounts in Vista" at the end of this post.

All this requires a certain level of computer skills. You know better and that take the machine to a competent local computer tech (not a type of BigComputerStore/GeekSquad place) is the best solution for you.

Activation of the built-in administrator.

Method 1. If you have an installation of Vista DVD (not a recovery DVDs), you can start the system with it. Select the default language, then select "repair your computer". Then select "Command Prompt". At the command prompt, type:

NET user administrator / Active: Yes [Enter]

If you do not have a Vista installation DVD, you can either make a bootable DVD of Vista repair in the file at this link:

http://NeoSmart.net/blog/2008/Windows-Vista-recovery-disc-download/

Note: All the Neosmart recovery disk downloads are torrent files. There is a good explanation of the torrent on the site Web of Neosmart files. You will need a torrent as muTorrent client to get the files. Torrent client will download the .iso file with which to create the bootable DVD.

After net user, remove the bootable CD and restart the computer. You will now see an icon for administrator on the Welcome screen. Connect to this account.

Method 2. Or you can use NTpassword to enable the built-in administrator. In both methods, you need third-party burning software such as Nero, Roxio or the free ImgBurn (http://www.imgburn.com ) to burn the .iso image image file, not in the form of data.

http://home.eunet.no/pnordahl/ntpasswd/

B. create a new user account for yourself and by copying data from your damaged to her user account

1. you are now connected to the built-in Administrator account. Go to control panel > user accounts and create a new Standard user for your daily work. Let's call it "Sheldon" for this example. Also create an administrator user, called 'CompAdmin' (or 'Tech' or similar).

4 Ouvrezunesession 'Sheldon' once for profile files are created. Now log off 'Sheldon' and 'CompAdmin '. In "CompAdmin", disable the built-in security administrator. Do this from a command prompt:

Start > Search > type: cmd
When cmd appears in the above results, right-click and choose "Run as Administrator". Provide the password/OK to the UAC prompt. Now, you will get the command prompt. Type:

NET user administrator / active: No. [Enter] and exit the command prompt.

5. always in 'CompAdmin', you want to open two windows explore side by side. Open computer and navigate to C:\Users\old-corrupted-account. Now, do that again, but navigate to C:\Users\Sheldon. Copy the data from 'old-corrupted-account' on records in 'Sheldon '. Remember your Favorites, bookmarks (if you use Firefox) and by e-mail if you use an email like Windows Mail client.

6. When you are finished, log in to "Sheldon. All your stuff should be there. When you are sure to have what you need, you can remove the old man-corrupted-account control panel > user accounts.

General C. recommendations for creating users in Vista:

You absolutely don't want to have only one user account. As XP and all the other modern operating systems, Vista is an OS multi-user with system built-in accounts such as administrator, by default, all users and guest. These accounts should be left alone because they are part of the structure of the operating system.

In particular, you do not want one account user with administrative privileges on Vista because the administrator account integrated (normally only used in emergencies) is disabled by default. If you use as an administrator for your daily work, and this account is corrupt, things will be difficult. It is not impossible to activate the built-in administrator to rescue things, but it will take third-party tools and work outside the operating system.

The user account that is for your daily work must be a Standard user, with the extra administrative user (call it something like 'CompAdmin' or 'Tech' or similar) only it for elevation purposes. After you have created "CompAdmin", connect to it and change your normal user account Standard. Then log on to your regular account.

If you want to go directly to the desktop and ignore the Welcome screen with the icons of the user accounts, you can do this:

Start Orb > Search box > type: netplwiz [Enter]
Click continue (or provide an administrator password) when you are prompted by UAC

Uncheck "users must enter a user name and password to use this computer". Select a user account to connect automatically by clicking on the account you want to highlight and press OK. Enter the password for this user account (when it exists) when you are prompted. Leave blank if there is no password (null). MS - MVP - Elephant Boy computers - don't panic!

Error message: Picture.library.ms no longer works. Tried to remove the library as suggested but does not ask for confirmation delete a few deletions without asking for confirmation.

Error message: Picture.library.ms no longer works. Tried to remove the library as suggested but does not ask for confirmation delete a few deletions without asking for confirmation. Also don't undersatnd how then restore you the other context using the trash of the library? Don't understand that your instructions please the ventilation in portions of beginner. Is - this recurring issue is sought in microsoft?

Hello

You solved the problem with the photo library?

You have been informed that the question about the image library is fixed in the next thread.

http://answers.Microsoft.com/en-us/IE/Forum/ie11-iewindows8_1/you-tube-videos-do-not-play-after-updating-to/ce05a70a-3548-44e7-b5ed-2602df641dca

If you are now facing problems with videos from YouTube on Internet Explorer 11, try the steps in the above thread link and check.

Let us know if you need help with Windows related issues. We will be happy to help you.

Helps relaxation that fits into another table before insertion
I have two tables:

TABLE A as follows:
x, y, z
1, 1, 1
1, 1, 2
1, 1, 3

TABLE B as follows
c, d, e, f
1, 1, 1, 8
1, 1, 1, 2
1, 1, 1, 6
1, 1, 2, 5
1, 1, 2, 10
1, 1, 2, 3
1, 1, 3, 12
1, 1, 3, 11
1, 1, 3, 15

I want a trigger, BEFORE insertion in the TABLE B, I want to INSERT into TABLE A as follows:

c = > x
d = > y
e = > z

ONLY IF a (x, y, z) record does not already exist in the TABLE.

That is to say. If record (1, 1, 3) already exists in the TABLE, we do not try to put it back when you insert in the TABLE B with values containing (1, 1, 3).
You will need
```
CREATE OR REPLACE trig_on_insert
BEFORE INSERT ON B
FOR EACH ROW
IS
   lv_count    NUMBER := 0;
BEGIN
   SELECT COUNT(1)
     INTO lv_count
     FROM a
    WHERE x = :new.c
      AND y = :new.d
      AND z = :new.e ;

   IF ( lv_count = 0 ) THEN
      INSERT INTO A VALUES(:new.c,:new.d ,:new.e);
   END IF;
END;
/
```
Concerning
Arun

Redirect data to another table using before insert trigger.
Dear all,
How can I redirect the data to another table in a before Insert trigger? My database is Oracle10g.
I have a table EMP (EMP_ID, LAST_NAME, SALARY).
I have another EMP_COPY table with the same structure. I also have a before Insert trigger on the EMP table.
Based on a condition that I have to redirect the data in table EMP_COPY. Let's say the condition is EMP_ID = 100.
I fire an insert on EMP table for example INSERT IN EMP(EMP_ID,LAST_NAME,SALARY) VALUES(100,'Dev',500).
On the inside of the front Insert trigger on the EMP table, I have the code
IF EMP_ID = 100 THEN
INSERT INTO EMP_COPY (EMP_ID, LAST_NAME, SALARY)
VALUES(:NEW.) EMP_ID,: NEW. LAST_NAME,: NEW. SALARY);
COMMIT;
ON THE OTHER
NULL;
END IF;
But the problem here is that data goes to EMP table of origin also although I don't want. He should do an Insert into EMP table only if EMP_ID! = 100.

One way has been to raise a user-defined exception inside the If statement and not handle it so that the original insert on table EMP fails but INSERT comes in the EMP_COPY table. But in this solution since the inside the trigger unhandled exception, it propagates to the calling environment. And I can't stand outside relaxation as the calling environment is a form of Oracle Apps standard that cannot be customized.

Any kind of help will be highly appreciated that I am fighting for more than two weeks.

Thanks in advance
Dev
Remove the autonomous transaction pragma... and then try again.

Insert, based on condition (constraint unique key)
Hello
Need help with checing the uniqeness of value before inserting

for example
have two table

Book book_owner years and need to inserting 100 rows in the table, but there are a few unique constraints challenged on the table where need to chek the value existing or not, if the value is exisitn jump insertion otherwise insert the value

Here is an example

Insert in the BOOK (BOOK_ID, CNT, ALT_CNT, ROW_INSERT_TMSTMP, ROW_LAST_UPDT_TMSTMP, BOOK_ID)
Values (SEQ_BOOK_ID.nextval, 50, 500, sysdate, sysdate, ' 123456');
commit;
/
Insert into BOOK_OWNER (BOOK_OWNER_ID, BOOK_ID, USER_ID) Values (SEQ_BOOK_OWNER_ID.nextval, SEQ_BOOK_ID.currval, "456");
commit;
/

Insert in the BOOK (BOOK_ID, CNT, ALT_CNT, ROW_INSERT_TMSTMP, ROW_LAST_UPDT_TMSTMP, BOOK_ID)
Values (SEQ_BOOK_ID.nextval, 50, 500, sysdate, sysdate, ' 678901');
commit;
/
Insert into BOOK_OWNER (BOOK_OWNER_ID, BOOK_ID, USER_ID) Values (SEQ_BOOK_OWNER_ID.nextval, SEQ_BOOK_ID.currval, ' 678');
commit;
/

Insert in the BOOK (BOOK_ID, CNT, ALT_CNT, ROW_INSERT_TMSTMP, ROW_LAST_UPDT_TMSTMP, BOOK_ID)
Values (SEQ_BOOK_ID.nextval, 50, 500, sysdate, sysdate, ' 5123987');
commit;
/
Insert into BOOK_OWNER (BOOK_OWNER_ID, BOOK_ID, USER_ID) Values (SEQ_BOOK_OWNER_ID.nextval, SEQ_BOOK_ID.currval, ' 896');
commit;
/

in the Book table BOOK_ID has the unique constraint and the data type is varchar type
BOOK_OWNER table USER_ID) has the unique constraint and as a varchar data type

I use oracle 10g
Double post!

Splitting words before inserting into the new table

SQL> desc company
 Name                                      Null?    Type
 ----------------------------------------- -------- ----------------------------
 CO_ID                                     NOT NULL NUMBER(9)
 R_DATE                                             TIMESTAMP(0)
 CONAME                                             VARCHAR2(140)
 ESTYR                                              NUMBER(5)
 COUNTRY                                            VARCHAR2(32)
 PRODUCTS                                           VARCHAR2(3900)

SQL> select unique(products) from company where rownum<6;

PRODUCTS
--------------------------------------------------------------------------------
bars,tubes,pre-weld seams,isosceles and un-isosceles angles,special profiles,u-p
rofiles,plates,t-profiles,flanges,tube fittings,round,hollow bars,double-t-profi
les (ipe und ipb),pipe clamps,flat,special designs according to drawings for new
 products,profiles for floor covering,hexagon

carbon steel bright bars,tool steel bright bars,alloy steel bright bars,stainles
s steel bright bars

cold rolled coil,e.g sheet,prepainted sheet,galvalume coil,copper scrap,stainles
s steel sheet,shredded scrap,hms1 and 2,cobalt ore,rail scrap,hot rolled coil,ga
lvanized sheet,iron ore

PRODUCTS
--------------------------------------------------------------------------------

ferro alloy producer
switch technology,special tubes,rails,steel strip,special steel

I created another table:

crate table keywords(
k_id number(14),
keywords varchar2(500) unique
);

create sequence keywords_pk_seq
start with 3484 increment by 1;

create or replace trigger keywords_pk_trig
before insert on keywords
referencing new as new
for each row
begin
select keywords_pk_seq.nextval into :new.k_id
from dual;
end;
/

I want to:
one) to split columns of company.products where is comma (,) for example, bars, tubes, pre-soudures, tubes will became 4 different as words:
bars
tubes
welds
tubes

(b) then I want to insert these words in the table keywords.keywords with condition separated by ignoring the existing keywords.keywords (e.g. tubes came twice, let's get just a tubes) for example
k_id keywords
1 bars
2 tubes
3 before welding

Thank you and best regards

You can use the merge statement:

for example

merge into keywords
using (
with t as (select 'pipes,taps,spanner,spade,tubes' as txt from dual)
-- end of sample data
  select distinct REGEXP_SUBSTR (txt, '[^,]+', 1, level) kw
  from t
  connect by level <= length(regexp_replace(txt,'[^,]*'))+1
  ) x
 on (keywords.keyword = x.kw)
when not matched then insert (id, keyword) values (key_seq.nextval, x.kw)
/

But keep in mind that the sequence in this example will be updated for each line independently to know if she gets inserted or not.
If you set the ID using a sequence triggered when inserting then this will solve this problem.

Before Insert TRIGGER to create partitions problem
Hello

I m having a problem with the following situation in Oracle 8i:

I have a table TEST_TABLE, which is divided by the beach with a DATE column. The idea is to have a partition for each month, so the HIGH_VALUE of partitions is always the first day of the month following that represents the partition.

I created a BEFORE TRIGGER INSERT on the table TEST_TABLE, which tests if the partition for the month of registration which is being inserted exists and, in case it doesn´t, a PROC AUTONOMOUS_TRANSACTION is called to create the TRIGGER.

Running the code below one can see that even if partitions are created as expected, when you try to insert a record with a date greater than the last partition for the first time, this error is returned:
ORA-14400: inserted partition key exceeds plu legal partition key.

Note that if you run the same statement again insert, it s inserted correctly on the partition that was created the first try.

I´ll appreciate any help on this matter.

code
----------------
CREATE TABLE TEST_TABLE)
IDENTIFICATION NUMBER,
DATE OF THE DT
)
TABLESPACE USERS
PARTITION BY RANGE (DT)
(
PART_B42009 PARTITION VALUES LESS THAN (TO_DATE ('2009-01-01 00:00:00 ',' YYYY-MM-DD HH24:MI:SS ',' NLS_CALENDAR = GREGORIAN '))
LOGGING
TABLESPACE USERS
);
/

CREATE OR REPLACE PROCEDURE SP_ADD_PARTITION (TEST_TABLE P_DATE. DT % TYPE)
IS
PRAGMA AUTONOMOUS_TRANSACTION;
V_STR VARCHAR2 (500);
BEGIN

V_STR: = 'ALTER TABLE TEST_TABLE ADD.
|| 'PARTITION BIRD | TO_CHAR ("P_DATE, ' YYYYMM")
|| ' VALUES LESS (TO_DATE ("')).
|| TO_CHAR (ADD_MONTHS (P_DATE, 1), "YYYY-MM"). '-01 00:00:00 ','
|| ((' SYYYY-MM-DD HH24:MI:SS "," NLS_CALENDAR = GREGORIAN "))';

EXECUTE IMMEDIATE (V_STR);

END SP_ADD_PARTITION;
/

CREATE OR REPLACE TRIGGER TR_B_I_R_TEST_TABLE
BEFORE INSERTING
ON TEST_TABLE FOR EACH LINE
DECLARE
NUMBER OF V_PARTITION_EXISTS;
BEGIN

IF: NEW. DT > = TO_DATE ('2009-01-01 00:00:00 ',' ' YYYY-MM-DD HH24:MI:SS) THEN

IMMEDIATELY EXECUTE (' SELECT COUNT (1) ")
|| "Of all_tab_partitions atp'."
|| "WHERE atp.table_name ="table_test"'.
|| "AND the atp. Nom_partition =: v1 ')
IN V_PARTITION_EXISTS
WITH THE HELP OF "BIRD" | TO_CHAR(:NEW.) "DT,"YYYYMM";)

IF V_PARTITION_EXISTS = 0 THEN

DBMS_OUTPUT. Put_line ('Partition [' |]) 'BIRD ' | TO_CHAR(:NEW.) "DT,"YYYYMM"). does not exist!') ;
DBMS_OUTPUT. Put_line ('creation..');
SP_ADD_PARTITION (: NEW.) DT);
DBMS_OUTPUT. Put_line ('success.');

IMMEDIATELY EXECUTE (' SELECT COUNT (1) ")
|| "Of all_tab_partitions atp'."
|| "WHERE atp.table_name ="table_test"'.
|| "AND the atp. Nom_partition =: v1 ')
IN V_PARTITION_EXISTS
WITH THE HELP OF "BIRD" | TO_CHAR(:NEW.) "DT,"YYYYMM";)

IF V_PARTITION_EXISTS = 1 THEN
DBMS_OUTPUT. Put_line ("it s visible at this point..");
ON THE OTHER
DBMS_OUTPUT. Put_line ("it s not visible at this point..");
END IF;

ON THE OTHER

DBMS_OUTPUT. Put_line ('Partition [' |]) 'BIRD ' | TO_CHAR(:NEW.) DT, "YYYYMM")
|| already exists! ") ;

END IF;

END IF;

DBMS_OUTPUT. Put_line ('continues with insertion...");

END TR_B_I_R_TEST_TABLE;
/

-Go to the low score
INSERT INTO TABLE_TEST VALUES (1, TO_DATE ('2008-12-31 23:59:59 ',' YYYY-MM-DD HH24:MI:SS'));))

-Returns the error on the first try
INSERT INTO TABLE_TEST VALUES (2, TO_DATE ('2009-01-01 00:00:01 ',' YYYY-MM-DD HH24:MI:SS'));))

----------------
It is the use of the pragma AUTONOMOUS TRANSACTION. Your current transaction cannot see the result of this DOF since it occurs outside of the current transaction. The clue is in the name.

Of course, you cannot run the DDL in a trigger without use of this pragma, so you're pretty much stuck. There is a solution in 11g, but that will not help you. Unfortunately, your only option is to pre-create the partitions required in front of the need. For example, you might have a DBMS JOB to create a partition for the next month, which takes place the last day of each month (or logical date of company).

Cheers, APC

blog: http://radiofreetooting.blogspot.com

Restore the option "confirm deletion".

Hello

I have a LENOVO Thinkpad 03193TG. Someone tweaked the settings on it and removed the need to confirm the deletion by pressing ENTER when you press the DELETE key. I would be very grateful if you could advise me on how to restore this option.

Trash > properties > confirm delete

Confirm delete before inserting then have a unique key.

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n_shah18-

Foreign key constraints

Foreign key references a primary key by default

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