Consider a source of datablock, error FRM-40501

I had a vision, my form is based on this point of view

I query data in the form, based on a list box
(The list box is based on a field in the fom), works very well

Based on a value in the list box, a few columns in the form.

Now I want to add some text in one of the columns, and this should be saved in a
Output table (for example, OUTPUT_VIEW).
It's the 5th column displayed in the form

It is an improvement... The previous part, I did like this:
The other columns in the form (which is the result of the query by the list box) getting stored in the OUTPUT_VIEW table
no problem...
There is no need to update the values in the first 3 columns manually via the form... I'm just doing these
values, they are based on the value in column 4 (which is a box and created a point no DB)
By the value of column 4th change, I have inserts, updates, deletes the table output_view
(Sur-mise to update triggers etc..)
All these nice work

Now is the case of a new column 5.
The value of this need to be registered via the form (free text)
The output_view table contains this column
The requirement is that this column must be in the same datablock with 4 columns above...
So I recreated the join between the first 2 view more tables this single column of the OUTPUT_VIEW table

Now my problem is that when I try to enter text in this field to column 5, he says:
FRM-40501: not able to book record to update or delete

But this error disappears if I put this item property to database element: no
But it is of no use because when you query the view once again, this value does not appear...


I searched on the internet.
attempted to set primary key values and set the block of key_mode for "may".
FRM-40501 appears always

The underlying table doesn't have a primary key
Also the grant on insert, update, delete on all the tables and the view is granted to the user current performs the operation of forms...

I'm confused what to do now... PLS HELP!
Other methods to meet this requirement?

My opinion is as below.
The column in the form, I want to insert data is 'comments '.
I coded to insert this data into the OUTPUT_VIEW table (tested this with the "remarks" field not an element of database and it allows me to enter)
given in the 'comments' field and when I save the form, inserts also in the table of OUTPUT_VIEW... but when I ask next time, the value of this field is missing, because
That is something no DB... This isn't what I want... I want to be an element of database and must still be editable...
Isn't this possible?)
CREATE OR REPLACE FORCE VIEW AUTO_USER.DEFAULT_SKS_LOCALITIES
(
   DELIVERY_OFFICE_ID,
   DELIVERY_OFFICE_NAME,
   LOCALITY_NAME,
   ROUTE_ID,
   ROUTE_NAME,
   POST_TOWN_NAME,
   COUNTY_NAME,
   LOCALITY_DEFAULT_CODE,
   COMMENTS
)
AS
   SELECT   t1.delivery_office_id,
            t1.delivery_office_name,
            t1.locality_name,
            t1.route_id,
            t1.route_name,
            t1.post_town_name,
            t1.county_name,
            t1.locality_default_code,
            t2.comments
     FROM   (SELECT   *
               FROM   GL1    WHERE   route_name IS NOT NULL
             UNION
             SELECT   *
               FROM   GL2
              WHERE   route_name IS NOT NULL) t1,
            (SELECT   NULL,
                      locality_name,
                      delivery_office_name,
                      NULL,
                      NULL,
                      post_town_name,
                      NULL,
                      locality_default_code,
                      comments
               FROM   OUTPUT_VIEW) t2
    WHERE       t1.delivery_office_name = t2.delivery_office_name(+)
            AND t1.locality_name = t2.locality_name(+)
            AND t1.post_town_name = t2.post_town_name(+);
Also, I really need to base the form on the view itself, such as changes in data dynamically

most of our forms is based on views.

Try this

create a trigger-LOCK at the block level and put NULL; inside

Choose your key block-level mode peut
Ask all records on Yes

as for PK, there must be a combination in your recordset that makes each unique, you must set those Yes on primary key item-level.

Hope this helps you

Tags: Oracle Development

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