Convert the path of negative to positive

Similar Questions

• convert the data-> layer mask vertex position position

  I have 2 videos (A; (B) whose corresponding value of markers, I need to distort the video so the position of the markers would correspond to the position of the corresponding markers in video B.

  The markers are easy to spot, but I can only request data followed the anchor layer,

  while I can use for the distortion (Reshape, revision deform or Morph) the tools work with masks.

  I need a way to convert the caterpillars position data to control individual mask points.

  Someone knows or can write this script?

  much help appreciated

  Yes, as David said, with local Tracker2Mask mode, you can move individual points mask with track points of the tracker item AE.

  See this tutorial:

  

  Tracker2Mask - advanced functions and local change mask | mamoworld

  My MaskTrackerPlus not help not in this particular case, since he cannot move together masks, but individual vertices not independently.

• Convert a path in the shape of a mask path

  It is a question that has been requested before, but as far as I know, has not received a satisfactory answer.

  So I have a rectangle that I made in a shape layer, and I want to it by using the effect of the race, because I need the form to scale, and I found that the scales from the standard race in a shape layer when you turn the STROKE layer

  But with him being a shape path and a parametric shape path that I can't copy/paste this shape as a mask.

  At this point, @Todd_Kopriva

  usually appears to copy and paste the following text:

  
  

  
  

  "command to convert a path of the parametric form of a Bezier curve layer:

  You can convert a path of a Bézier path after the path has already been created by context-click (right-click or control-click on Mac OS) the Group of properties for the path (for example, the Rectangle drawn 1) and choosing convert Bézier path command in the context menu. If the path is animated (retouching), converted Bézier path is a static path based on the way at the present time; keyframes are lost. »

  Who indeed converts the path, as far as I can see, but unfortunately this does not seem to help me pass this way in a mask layer

  Any ideas?

  
  PS someone else has a really weird problem with this forum where you will write a response and everything suddenly find your cursor/Carat jumped a few lines and you type half an answer at the end of a previous line?

  I went through this dozens of times on this forum. To be successful, you need to set a keyframe. Here goes:

  1. Select your shape (Rectangle 1) and right click and select Convert to Bezier path
  2. Open the Rectangle 1 path and set a keyframe
  3. Copy
  4. Select the layer that you want to add a mask of
  5. Choose the pen tool
  6. Click anywhere on the layer to set the first vertex
  7. If you try to put a mask on a shape layer, you must reset the pen tool to create a mask instead of a new form, before setting the first vertex
  8. Dough

  That's all. Works every time. The only problem is that the layer you add the mask must be posted on the default transformation and the shape layer, that you have copied from must also be to default transformations. That and everything works every time.

• Convert a path in line/STROKE/pencil?

  Need help with the railways... I use the tool pen to create a path, having created and close my path I want to convert the path of line weighted about 6 pixels in green.

  I tried to convert in road fill and draw the path, but these options allow me to set a width in pixels of the path.

  Probably miss me something very simple, but tips are welcome.

  Thank you, Rob.

  Trace the path will use everything you have your current brush or pencil value. Then, choose the color and width before tracing path.

  Keep in mind Photoshop do not caress the paths as an Illustrator.

• Help compare the negative and positive values

  Well guys, I do this example to show you what I mean

  

  With this example, I can get positive and negative numbers in digital

  But for me, the 'negative' mean nothing

  Example:

  If I have "100-200" for me the biggest value is - 200

  But if I compare the values of bouth got 100 as greater value

  I do the same calc for 3 different variables such as A, B, C

  and after that I need to calc whose value is 'more '.

  But my problem is that if I have the values "-350 300-400.

  the largest will be "300", but for me the 'negative' mean nothing

  so I need to the largest value is "-400".

  For all positive values, its works very well!

  I compare A and B, after the highest is on C and have a result!

  but when I have negative and positive values... I had this problem...

  and when I have negative values only I have a problem too.

  '-300-400-500' for me the largest value must be "-500" but labview-watch "300".

  as - 300 is greater than-500 in algebriac.

  And if I use absolute values, I will always have a positive value... but I need to know if the value is positive or negative

  No matter which, can help me with this?

  Thank you

  

  Ben

• How to convert the compound path to simple way barred?

  New animation SVG here and you would appreciate the help.

  I exported an SVG graphic logo to facilitate the animation of lines in the logo. In short, I'm trying to make these lines 'draw' sequentially.

  After you import the SVG object in the browser, I realize the path data to describe complex shapes, rather than a simple path with a vascular accident brain. For example, straight lines appear as a path around the outside edge of the line, a rectangle. See the part of the image below showing the anchor around the edge of the line.

  While I could very well be wrong, it seems that I need to make these lines in the draw of logo is given simple way, with the width of the line determined by a stroke. Does anyone know how I could convert/export what I need to give me what I need?

  Thank you!

  Joseph,

  Simple/no tracks transparent FO, you can do the following:

  1) switch from fill to line in the Toolbox (in you first picture you have completed and no stroke);

  (2) ShiftClick each of the segments of both ends with the direct Selection tool and then tap on delete.

  This will give you two simple traces to the mixture;

  (3) object > mix > blend Options, not specified the value 1, then object > mix > do, then object > mix > Expand, then Ctrl / Cmd + Shift + group to ungroup, and then delete the traces of origin;

  (3) select the new path and him giving the desired weight of stroke (half of the difference in width for traces of origin).

  And Willi comments on using JPEG.

• How to convert containers of Type area in the path of

  Accidentally, I converted a tinted path (custom shape with several anchor points) to a container of type box, and he did not notice until this day. Is there a way to convert this back to plain ole filled way. I tried to reduce the basic look, I tried to have add filled a new filling, but because that HAVE it think it's a container of type all the background and contour attributes are ignored. I even tried the adaptation layer and make a clipping from one path to retrieve the path, but it wouldn't let me. It seems to be very easy to make in the areas of type forms but not the other way around.

  Thank you

  Brad

  If you use the group selection (the white arrow with alt/option key), it will allow you to select only the part of the text container path.  You can then copy and paste in front.

• convert the output of a new effect path?

  Hi all.

  So, I take a square, and then I ask a contraction and inflate it, allowing this form of interesting shamrock. Road access remains the same, as a square, but the output vector is modified by the effect in the said shamrock.

  My question is this - how to do the effect directly to the path. In the example above, the blue path would be under the shamrock pleasure.

  http://I35.Photobucket.com/albums/D188/OphidianShenzi/01.jpg

  Often I will edit a shape with multiple effects, for example. first I'll inflate it, then I'll apply some sort of string. It would be very useful to be able to perform the path directly to all stages of the process of effects, because when you have a shape that is veiled strongly and you try and change the area distorted you get a big surprise.

  Suggestions?

  Thank you

  Shenzi,

  I hope that you do not follow these instructions exactly as shown. If you:

  Copy (edition > copy)

  Hide visibility (object > hide selection)

  Then you will not be able to select the object > decaying appearance, because nothing will be selected.

  For clarity:

  Live vector effects really are the real paths. But while remaining in Illustrator, they are paths that are re-generated on-the-fly each time you change the original path. When the work leaves Illustrator (by exporting or printing), get effects 'nailed' to the paths / objects generated by the live effect raster.

  The object > Expand appearance command is if you can "nail" live effects you have applied to an object to real paths (or raster objects) while remaining inside the Illustrator.

  Simply select the access to which you applied the effect Pucker & bloat path. Select object > decaying appearance. The result will be that the result of the effect of contraction & bloating made as a normal path. It will not effect 'live' more. If you think that you will still need to start more, return to the step in which you always had the live effect (adjustable), you can make a copy of the object with the effect applied before you expand appearance and set aside for future use. But there is no need to do this if you are already satisfied with the effect.

  JET

• Some handles Bezier figure is not in the path (CS6)

  Hello

  I'm animating an object bouncing.

  2 first keyframes for the Position property are OK - Bezier handles are shown on the path. However, since the third bazien keyframe handles no more and I'm unable to smooth the path.

  This problem disappear and reappear since I started using AE and it does not matter if the keyframes are facilitated in/out or not. What is going on?

  

  Select the tool (g) feather and then you move on to the vertex and you will have the opportunity to highlight the Bezier handles on the path. You will see the convert vertex tool and V appear on the side. This is the tool you want. You can also manually select the tool vertex disguised by clicking and now on the tool pen in the toolbar. Alternatively, you can hold the Alt/Option key with vertex tool to convert selected to break them and the handles operate independently. Hold down the Ctrl/Cmnd key will give you a selection tool instead of the tool convert Vertex which will allow you to move the vertex or adjust Bezier handles. If you have a single keyframe selected in the timeline panel, you will see only Bezier handles on the two closest handles. If you want to see all the Bézier handles select all the keyframes in the timeline.

  

  In your example of a timeline there is no Bézier handles because the spatial interpretation is linear. You can create these edges by simply clicking on a Summit that has the Bézier handles with the convert vertex tool selected.

• is there a way to get the index of the html text field cursor position

  I'm working on a block of text as MC with 'insert text at position X' and 'Find and replace' can someone tell me how to find the index of an html text field cursor. Selection.getBeginIndex (), Selection.getEndIndex (), Selection.getCaretIndex () as far as I know these methods only work with text and not htmltext.
  What I'm trying to do, it's affecting different parts of the chain to the variables so that I can combine in order to restore my html string.

  ray1872:

  If I understand correctly, you want the corresponding position in the
  another index of the caret htmlText property (who, like you, has no on the)
  position in the plain text of the textfield content version).

  Here's how I'd do. It is perhaps easier or more effective
  way (using objects XML etc.), but I don't know it. You could conduct all
  your search string in plain text and then convert the result of
  the positions of html. I didn't build this to accept negative parameters
  for the parameter pos (for example, end of string towards the back), but the
  function could be adapted to do this also if necessary. The test data is
  not good html from a text field, but it does not really matter what he
  is as long as its formatting correctly. It separates only tags of
  content to allow apples to apples comparison.

  some test data
  var testStringXML = ""Hello I can't tell you hOE happy I mod.'; "
  var undecoratedString = Hello "I can't tell you how happy I am.";

  the conversion function
  function findDecoratedPosition(pos:Number,_xmlString:String,_test:Boolean):Number {}
  anything between '<' and="" '="">' should be excluded from the search in plain text.
  create a table of elements of array (n = 2), consisting of tag and then plain text
  requires xml/html properly put in the form
  var tempArr:Array = xmlString.split (')<>
  for (var aa = 0; aa
  tempArr [aa] is [aa] tempArr,.split(">").;
  }
  remove the first and last elements in the new array (they are empty)
  tempArr.pop ();
  tempArr.shift ();
  find the location of corresponding plaintext and calculate the position "decorated."
  var retPos:Number = 0;
  var posCount:Number = 0;
  for (var aa = 0; aa
  retPos += tempArr [aa] [0] .length + 2 + tempArr [aa] [1] .length;
  + 2 allows you to lack< and="">
  posCount += tempArr [aa] [1] .length;
  If (posCount > pos) {}
  return (retPos + (pos-posCount));
  }
  }
  out of range
  Returns - 1;

  }

  test code:
  for (var aa = 0; aa
  var altPos = findDecoratedPosition (aa, testStringXML);
  trace (undecoratedString.charAt (AA) +"position" + aa + "in clear corresponds to the position" + altPos + "in decorated version [" + testStringXML.charAt (altPos) + "" "]" ");

  }

• ChnLinGenImp do not convert the value of units

  Hello

  I use the ChnLinGenImp command in a creation of such as channel below.

  --> Call ChnLinGenImp(SpecChannelName,length,SpecNumber*1,0,Unit)

  The question that I am running, I run the script for a conversion unit that converts the units if they are incorrect.  However the part convert does not convert the IMP channel, because it is a path of IMP.  Is in any way around that in addition to going to the ChnLinGen command?

  Hello J,

  Only two options I know in tiara 2012 are:

  (1) give and make a meaningful string instead of an implicit string and let conversions of unit of the tiara to manage all

  (2) manage your implicit channels separately and re-create them whenever there is a change of unit - but you have to manage the offset and the conversion factor

  For the linear unit conversions as degC to degF, I could imagine DIAdem running automatically on the offset values and factor of the implicit channel, BUT not all unit conversions are linear, and there must be able to operate on the values of the channels - you can not apply a non-linear conversion to a y = mx + b equation and get another y = I x + b' equation.

  Brad Turpin

  Tiara Product Support Engineer

  National Instruments

• How can I return the path of a test step VI in LabVIEW?

  I would create a VI that will return all of the VI paths that are associated with the test steps in a TestStand sequence.  How can I return the path of the VI associated with a test step?  Here is a starting point that will return the first step of the sequence.

  

  You must convert the Module to a LabVIEWModule (use the variant to the data node), then you can use LabVIEWModule.VIPath.  If you use TestStand 2010, you can call LabVIEWModule.GetVIAbsolutePath to find the VI in the case you are calling with a project.

• Installed application behaves differently by the path of the file

  Hi all! I have a problem regarding my application installed on another pc from "My Installer", that I have built my original labview project.

  I wanted to set up a file open/create operation, get the path of the current file of my vi, create the new folder 'report' and the new report file, whose name is composed of the date and time when it is created. With 'Get string date/time', I got the date as '25/05/2015' string and time string like '14:24:20 ', and 'find and replace the string' I have them is converted into '25052015' and "142420" everything simply by replacing "/"and":" with nothing.

  It works fine with the original vi in my pc, but with the application installed on another pc, I got error in the path, that instead of 'C:\...\report\transducer_25052015_142420.txt', I got "C:\...\report\transducer_25052015_14.24.20.txt"!  The colomns are replaced by dots!

  I have no idea why my installed application would give such error. Someone has an idea?

  PS. I tested on the difference between 'Run application path of time' and the file path by default, you can see on the image below.

  

  You can provide a format if you use the Format Date/time string.  You don't need to replace the then you do not have to worry about getting to be in the way in which the system settings.

  

• Convert the database to 10 v to v11

  Hello

  I'm unable to convert and merge a v10.1 v11 user database.  I made a backup of Usrcomp_S.usr to another folder in Windows then used the merger of Multisim and Ultiboard and conversion tools. Here are the steps I followed:

  1 tools > Database > convert database...

  2. Select Source in the dialog context database names.

  3. navigate to the database using the Windows dialog box. Select my copy of database using "All Files." Curiously he is not using the default filter. Select OK and then the following error:

  The path of the database: "database\UsrComp_S.usr" was not found or not set.
  You want to select the path where the database of component?

  4. Select Yes then select my now visible database of the dialog Windows.

  5. press start to convert my database to aid auto rename. Briefly, something happens that seems to be the conversion and the window convert watch Done

  6. close the convert and open tools > database > merge a database...

  7. Select a name of the component database

  8. Repeat step 3 above. The allegedly converted database is still not visible but this time there is no option to "All Files." In the file name drop-down box I choose the path previously used for the database copy. Select open and receive the following error message:

  The path of the database: "database\UsrComp_S.usr" was not found or not set.
  You want to select the path where the database of component?

  9. Select Yes then select my now visible database of the dialog Windows.

  10. press on open and receive the following error message:

  Error: Could not open the database [user data].
  The file format/version does not, and cannot be merged.
  If the database is from a previous version, use convert the database.

  Help, please. This should be a simple process of a button to import parts of the user of a previous version.

  Richard

  Hi Richard,

  I think you are trying to convert the incorrect database. From the name you specified (Usrcomp_S.usr), it's just a CDS model uses to create a user database, it is not your user database.

  On Windows XP, the user database is located in C:\Documents and Settings\\Application Data\National Instruments\Circuit Design Suite\11.0\database\

  On Windows Vista/7, the user database is located in C:\Users\\AppData\Roaming\National Instruments\11.0\database\

• Tension running from negative to positive to a negative value again using a structure case

  Hello

  I a VI that takes place (not shown) DAQ hardware and want to do the following with it:

  By feeding the starting value (the maximum negative value of voltage), increase (positive) and the end value (maximum positive) voltage for the DAQ hardware TRADERS (should be

  shown in the digital display) should go to gradually change from negative to positive maxima and do the reverse process of return to the starting value

  which is the maximum negative value.

  for example

  If I put - 3V to the starting value, 0.5 as increment, + 3 V to the end value, I should get the following:

  -3, -2,5, 2,...,.0,..., 2.5, 3 and then 2.5, 2..., 0,...,-2, 2.5-3, then stops.

  I managed to get the first which is negative to positive Maxima but he never do otherwise. Can anyone help with this.

  Thank you very much

  Alain

  Study the attached example.  Instead of having just a graph showing each DC voltage at each iteration, I made a graph that will update to show all the steps as they occur.  The waveform that is the scale of things is to properly size the chart so you can see each stage without having the graph resize with each iteration of the loop.  You can pass values to your DAQ hardware to get the real exit.

  I used a second shift for such direction suggested by Altenbach register.  It is to go to the best (maybe the only way).