Cross-application
Hello
I have this request:
select owner, object_type, count(*) from dba_objects where owner='TOM' group by object_type,owner union all select owner, object_type, count(*) from dba_objects where owner='SAM' group by object_type,owner order by 1,2
I want to write the same query but with the below output:
OWNER_TOM OBJECT_TYPE COUNT(*) OWNER_SAM OBJECT_TYPE COUNT(*) ----------- ------------------- ---------- ----------- ------------------- ---------- TOM FUNCTION 74 SAM FUNCTION 174 TOM TYPE 17 SAM TYPE 16 TOM INDEX 500 SAM INDEX 533 TOM SEQUENCE 149 SAM SEQUENCE 141 TOM TABLE 2111 SAM TABLE 2024 TOM LOB 22 SAM LOB 34 TOM PROCEDURE 222 SAM PROCEDURE 519 TOM PACKAGE 33 SAM PACKAGE 73 TOM SYNONYM 1 SAM SYNONYM 4 TOM DATABASE LINK 2 SAM DATABASE LINK 3
Thanks in advance!
Etbin:
I had this similar request but I wasn't too sure how to get all the lines by "holder." I thought of the individual lines, but shaped PIVOT would suffice. Only to learn PIVOT
SELECT * FROM ( SELECT owner , object_type , COUNT(*) AS obj_cnt FROM all_objects WHERE owner = 'TOM' GROUP BY object_type , owner UNION ALL SELECT owner , object_type , COUNT(*) AS obj_cnt FROM all_objects WHERE owner = 'SAM' GROUP BY object_type , owner ORDER BY owner ASC , object_type ASC ) t1 PIVOT (SUM(t1.obj_cnt) FOR owner IN ('TOM' AS OWNER_TOM, 'SAM' AS OWNER_SAM)) ORDER BY 1 ASC;
Result set (data are disabled, that I use in MY scheme of work users, but he gets to the general notion of what the OP asked)
Tags: Database
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