Date function to push the dates of the year?
is there a built in function to return all dates (regardless of format) between dates?Example:
Select nomfonction (' 2009/06/01 ', ' yyyy/mm/dd), (' 2009/06/05 ', ' yyyy/mm/dd')
of the double
Results sought
02/06/2009
03/06/2009
04/06/2009
select to_char(to_date('2009/06/01', 'yyyy/mm/dd') + level - 1,'yyyy/mm/dd')
from dual connect by level <= to_date('2009/06/05', 'yyyy/mm/dd') - to_date('2009/06/01','yyyy/mm/dd') + 1
/
TO_CHAR(TO
----------
2009/06/01
2009/06/02
2009/06/03
2009/06/04
2009/06/05
SQL>
SY.
Tags: Database
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Finally, just for grins, I created the functions of number two, one number, the other with REAL and even these are allowed - they are compiled. But then, at runtime, it fails. I'm really confused.
Here's the apparently erroneous Oracle documentation on this subject: http://docs.oracle.com/cd/B12037_01/appdev.101/b10807/08_subs.htm (see overload subprogram names) and here are the different types and their families: http://docs.oracle.com/cd/E11882_01/appdev.112/e17126/predefined.htm.
Published by: hot water on 9 January 2013 15:38
Published by: hot water on 9 January 2013 15:46>
So, I added a 2nd function with the arguments to DATE. Then I started to get "too many declarations of is_same exist" error during the passage of time stamps. It makes no sense for me
>
This is because when you pass a TIMESTAMP Oracle cannot determine whether to implicitly convert to VARCHAR2 and use your first function or implicitly convert to DATE and use your second function. Where the "too many declarations" error exist.
>
, even if said Oracle documentation you can not do, so I created a 3rd version of the function to manage the TIMESTAMPS explicitly. Surprisingly, it works fine. But then I noticed that he did not work with TIMESTAMP with time zones.
>
Perhaps due to another error "too many declarations? Because now, there will be THREE possible implicit conversions that might be made.
>
Therefore, the fourth version of the function. Docs of the Oracle say that if your arguments are of the same family, you can't create an overloaded function, but in the example above shows, it's very bad.
>
I think that the documentation, of the family of 'date', is wrong as you suggest. For WHOLE and REAL, the problem is that those are the ANSI data types and are really the same Oracle data type; they are more like "alias" that different data types.See the doc of SQL language
>
ANSI SQL/DS and DB2 data typesThe SQL statements that create tables and clusters allows also ANSI data types and products IBM SQL/DS and DB2 data types. Oracle recognizes the ANSI or IBM data type name that differs from the Oracle database data type name. It converts the data type for the equivalent Oracle data type, stores the Oracle data type under the name of the column data type and stores the data in the column in the data type Oracle based on the conversions listed in the following tables.
INTEGER NUMBER
INT
SMALLINT
NUMBER (38)FLOAT (Note b)
DOUBLE-PRECISION (Note c)
REAL (Note d)
FLOAT (126)FLOAT (126)
FLOAT (63)
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Sarah
Published by: SarahSarahSarah on August 30, 2009 12:49 AMSarah.
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Suggest the Sql query to get the years, months, days of the two dates.
Hi all
SELECT TO_DATE('06-02-2014','DD-MM-YYYY') - TO_DATE('01-04-1998','DD-MM-YYYY') SERVICE_DAYS OF THE DOUBLE
5790 SERVICE_DAYS
POWER REQUIRED:
YEARS MONTHS DAYS
15 10 5OUTPUT DISPLAY:
Select
Floor(5790/ 365.25),
Floor (mod (5790,365.25) / (365.25 / 12)),.
ceil (mod(5790,365.25 / 12))
Double;YEARS MONTHS DAYS
15 10 7 - TWO DAYS MORE
How they calculate manually is as follows:2014 02-06
1998-04-01
---------------
05 - days
2014 02-06
1998-04-01
+ 12
---------------
10 month 02 is lower than 04, so we borrow 12 months of TI (2014) years will be (2013)
2014 02-06
1998-04-01
-(1).
---------------
15. for the years since we-1Kind regards
Afzal.
OK... so try not not to multiply the reminder to add_months with 30 but to solve the 'day-thing' in a different way...
first step (data) is only my implementation testdata.
WITH DATA AS (SELECT TO_DATE('02-03-2014','DD-MM-YYYY') AS Degnide
TO_DATE('07-04-2008','DD-MM-YYYY') AS dayfrom
OF the double
UNION ALL
SELECT TO_DATE('12-04-2014','DD-MM-YYYY') AS Degnide
TO_DATE('11-05-1994','DD-MM-YYYY') AS dayfrom
OF the double
UNION ALL
SELECT TO_DATE('06-02-2014','DD-MM-YYYY') AS Degnide
TO_DATE('01-04-1998','DD-MM-YYYY') AS dayfrom
OF the double
)
calc AS (SELECT months_between (dayto, dayfrom) SERVICE_DAYS
Degnide
dayfrom
DATA)
SELECT Degnide
dayfrom
floor(service_days/12) IN years
floor (mod(service_days,12)) AS month
, BUSINESS sign (EXTRACT (Degnide DAY) - EXTRACT (DAY FROM dayfrom))
WHEN THEN-1 EXTRACT (DAY FROM Degnide) + 30 - EXTRACT (DAY OF THE dayfrom)
WHEN 0 then 0
WHEN 1 THEN EXTRACT (Degnide DAY) - EXTRACT (DAY FROM dayfrom)
0 OTHERWISE
end as days
CALC
HTH
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