Date of the first and the last of the week

Similar Questions

• the start date of the week formula

  Hi guys,.
  
  I have a report in which I need to display the Start Date of the week for a particular calendar date, for example
  
  Date week Start Date
  ---------- ---------------------------
  July 01, 2010 June 28, 2010
  July 2010 05 05 July, 2010
  11 July, 2010 05 July, 2010
  
  No idea how can achieve us.
  
  Thank you
  Ronnie

  TIMESTAMPADD (SQL_TSI_DAY, 2, TIMESTAMPADD (SQL_TSI_DAY, DAYOFWEEK (CURRENT_DATE) *-1, CURRENT_DATE))

• RPD required Variable: first day/date of the week

  Hi all
  
  As a requirement, I need to create a repository variable that would show the first day of everyweek. In other words, I need to display the date on the Monday of each week.
  
  Could if it you please let me know how this is possible.
  
  
  Thank you
  Ronny

  Hello

  Good to see that you help.
  If you find this helpful please be free to assign some points...

  Concerning
  Nicolae

• wants to get the dates of the week

  Hi guys,.
  
  I want the weeks when I give the nth week number.
  

  Eg: 
  
  SQL>  select to_date(to_char(sysdate,'iw'),'DD'),to_date(to_char(sysdate,'iw')+6,'DD')from dual
    2  where to_char(sysdate,'iw') =21
    3  ;
  
  TO_DATE(T TO_DATE(T
  --------- ---------
  21-MAY-12 27-MAY-12

  But when I give it 1 or 2 inplace 21st I do not get the results.
  OK I can without restricting my sysdate...?
  
  Thans
  
  Published by: san on May 24, 2012 17:04

  Select trunc (sysdate, 'yyyy') + (& week * 7)-6, trunc (sysdate, 'yyyy') + (& week * 7) double

• Restart or read courses at first and not last page

  We have a course with a questionnaire which must be passed.

  If the user does not pass must relaunch the course in order to randomize the quiz questions. We noticed that the course is the reopening last police page.

  \is there a way to force a project to open ONLY on the first page anywhere - off left? I realize that this would be unnecessary if the user also left having to start

  I think this is a job for a table of contents page, but can't think how

  help appreciated

  It is a SCORM file to load on an LMS, you must check the 'Never resume data' option under the Advanced button in the reports dialog box:

  

  If it is not transferred to an LMS, and you use the table of contents and biscuits or local storage for bookmarking, you will need to uncheck learning self-paced option in the parameters of the table of contents. But this option is cancelled by the LMS functionality if you publish a LMS.

• Date of the Monday of the week and year

  Hi gurus,
  
  I have the data for the week (eg.52) and year (eg. 08) and I need to get the date of the Monday of the week (December 21, 2008... IE 52nd week of 2008.)
  
  Pls know me the solution for this sql statement...
  
  
  Thank you
  Shashi...

  Hi, Shashi,

  user588757 wrote:
  Hi gurus,

  I have the data for the week (eg.52) and year (eg. 08) and I need to get the date of the Monday of the week (December 21, 2008... IE 52nd week of 2008.)

  Pls know me the solution for this sql statement...

  Thank you
  Shashi...

  Surely you meant December 22, 2008, No 21.
  Assuming that you are talking about ISO dates, where week 1 starts the Monday closest to January 1:

  TRUNC ( TO_DATE ( :year_txt
                  , 'YYYY'
                  )
        , 'IY'
        ) + (7 * (:week_val - 1))
  

  where: year_txt is a string and: week_val is a number.

  TRUNC (dt, "IY") is attached to the Monday of the week 1.

• change the dates of the new person-

  Hi all

  Someone gave me a m130 and the date of the week begins on Monday, the software on the computer, it begins Sunday (that's what I want on the palm pilot). All of the suggestions.

  Thank you

  Norm

  Hello and welcome to the Community Forums of Palm.

  To change the starting day of the week from Monday to Sunday, go to the prefs application.  Select the Formats in the drop-down list at the top right.  The second to the last item of the list, it's week begins, where you can select either Sunday or Monday.

  Message relates to: None

• get the last day of the week

  Hi friends,
  
  I have the below query that returns me the data as below:
  
  Select 'Label', to_number (to_char (to_date(start_date,'yyyy-mm-dd'), 'IW')) - to_number (to_char (add_months (sysdate,-6), 'IW')) + 1 as a weekly sum, (col1) val yyy_view
  where to_date(start_dt,'yyyy-mm-dd') between trunc (add_months(sysdate,-6)) and trunc (sysdate)
  Group of to_char (to_date(start_date,'yyyy-mm-dd'), 'IW')
  order of to_char (to_date(start_date,'yyyy-mm-dd'), 'IW')
  
  Label weekly val
  1 20 data
  2 24 data
  3 20 data
  4 28 data
  5 20 data
  6 24 data
  
  and so on...
  
  Now the requirement is to get the last date of the week for each week as below
  
  Label weekly val
  given 2011-08-30 20
  given 2011-08-23 24
  given 2011-08-16 20
  given 28 2011-08-09
  given 2011-08-02 20
  
  the weekly column should have the date of the last week. In the example above Wednesday is supposed to be the last date of the week.
  
  Kind regards
  Pradeep

  Missed the part "Wednesday is considered date of last week. The week is Thursday to Wednesday. If so:

  select  'Label',
           trunc(min(start_dt)) as day2,
          sum(col1 ) val
    from  yyy_view
    where start_dt between trunc(add_months(sysdate,-6)) and trunc(sysdate)
    group by trunc(start_date - 3,'IW')
    order by trunc(start_date - 3,'IW')
  /
  

  SY.

• How to get the date of Sunday of the week

  Hello
  I have a column date 'start_date', I need to create a report for all the weeks from Sunday, for example:
  
  I need to get the dates of the week in the form:
  
  mm/dd/aa-23/01/11, 01/16/11, 09/01/11 and so on...
  
  Help, please
  
  Thank you...

  Hello

  To find the last Sunday before or equal to start_date:

  SELECT     TRUNC ( start_date + 1
             , 'IW'
             ) - 1          AS week_start_date
  ...
  

  You can also use an expression like that in a GROUP BY clause.

  It's not you NLS parameters. Always ISO weeks start on Monday. Your week begins 1 day earlier, that is why the above expression is the + 1 and -1.
  (According to the parameters of the NLS)

  SELECT     TRUNC ( start_date
             , 'D'
             )          AS week_start_date
  ...
  

  could do the same thing, but I still have rocommend with "IW"; a few extra touches is not big thing to pay for a guarantee that it will still work.)

  I hope that answers your question.
  If not, post a small example of data (CREATE TABLE and INSERT statements) and the results desired from these data.

• Query for the weekly report

  Hello
  I wrote a query to get a weekly report, which is expected to start a week from Sunday to Saturday typical. for example, the week is 03/04/2011 to 04/09/2011 I run the query or the task on Word to say about any of the week of 10/04/2011, 04.11.2011 etc... Here's my query, but it seems to work of the sysdate to-7 days that does not receive the Sunday to Sam requirement... someone can you please...
  
  Select uid, psn, TO_char(date_in,'mm/dd/yyyy')
  OF THE TEST
  WHERE the uid like '% % ST.
  and date_in > trunc (sysdate)-7
  ORDER BY date_in CSA;
  Thank you.

  If you want that data for the week previous ? In if so then just tweak the settings a bit:

  SELECT uid
       , psn
       , TO_char(date_in,'mm/dd/yyyy')
  FROM   test
  WHERE  uid LIKE '%ST%'
  AND    date_in >= TRUNC(SYSDATE,'IW') - 8
  AND    date_in < TRUNC(SYSDATE,'IW') - 1
  ORDER BY date_in ASC
  ;
  

• selection of the week, month, year in source throgh odi 11g?

  Hello

  I have 3 years of data in a source table (tableatm). data will be added to this table eod.

  

  I applied the filter on the column atm_date below screenshot

  Based on the filter, I want to load the data of the year underway, data of the current month data of the week underway, data from the previous month, data from the previous week, data from the previous year to this table.

  If I want to load data for 2010, then filter applied on TO_CHAR (TABLEATM. ATM_DATE, 'YYYY') = '2010' , I get only the data of 2010.

  If want to download data from 2015, filter applied on TO_CHAR (TABLEATM. ATM_DATE, 'YYYY') = "2015". But it's constant...

  I want to give the filter like that.

  TO_CHAR (TABLEATM. (ATM_DATE, «YYYY») = double '(sélectionnez (sysdate,-12)) ". When I applied the filter using this formula on this date column. I don't get all the data.

  Please help me...

  

  Please help me,

  Thanks in advance,

  A.Kavya.

  Hello

  I applied the dynamic filter as shown below. now, I get only the data of the year 2015...

  filter condition is

  TO_CHAR (to_number (to_char (TABLEATM. ATM_DATE, "YYYY"))) = (SELECT to_char (to_number (to_char (SYSDATE, 'YYYY'))-1)

  THE DOUBLE)

  

  Thanks & regards,

  A.Kavya.

• Breaking a year in coming weeks of beginning and end Dates (parameters) and first and last day of the month

  Hello people:

  I have currently a query that picks up all the weeks between a date range where my week starts on Thursday and ends on Wednesday. The following query works fine except that I need the week of beginning and end, from beginning and end Dates of months and the beginning and the Dates of end of the values of the settings, I'm passing. In this case, I chose January 1, 2013 to 31 December 2013.

  Any help or pointers would be great!

  Thank you!

  Problem: I am picking up days of December 2012 as the first week began on December 27, 2012. In addition, in December, I'm pretty much lost last week as well (26 December - 31 December).

  The request in hand:

  SELECT first_thursday + (7 * (LEVEL - 1))   AS week_start_date,
                   first_thursday + (7 * LEVEL) - 1    AS  week_end_date
  FROM
  (
    SELECT TRUNC(p_from_date + 4, 'IW') - 4   AS first_thursday, -- Week should start the pre ceeding THURSDAY based on the Start Date
                    TRUNC( p_to_date + 4,  'IW') - 5     AS last_wednesday
    FROM
    (
      SELECT to_date('01-JAN-2013') AS p_from_date,
                      NVL(to_date('31-DEC-2013'), SYSDATE) AS p_to_date
      FROM     dual
    ) parms
  ) end_points
  CONNECT BY LEVEL <= ( last_wednesday + 1 - first_thursday)/7;
  

  Currently, this is the result I get (I'm only including the months of January and December here).

  Week_Start_Date     Week_End_Date
  27-DEC-12                02-JAN-13
  03-JAN-13                 09-JAN-13
  10-JAN-13                 16-JAN-13
  17-JAN-13                 23-JAN-13
  24-JAN-13                 30-JAN-13
  31-JAN-13                 06-FEB-13
  

  December:

  28-NOV-13               04-DEC-13
  05-DEC-13              11-DEC-13
  12-DEC-13              18-DEC-13
  19-DEC-13              25-DEC-13
  

  What I would really like is based on start and end Dates, as well as the first and the last day of the month is similarly try nicely. I have provided and then gently break at the end of the month:

  January:

  01-JAN-13              02-JAN-13
  03-JAN-13              09-JAN-13
  10-JAN-13             16-JAN-13
  17-JAN-13             23-JAN-13
  24-JAN-13             30-JAN-13
  31-JAN-13             31-JAN-13
  

  February:

  01-FEB-13    06-FEB-13
  07-FEB-13    13-FEB-13
  14-FEB-13    20-FEB-13
  21-FEB-13    27-FEB-13
  28-FEB-13    28-FEB-13
  

  November:

  31-OCT-13    06-NOV-13
  07-NOV-13    13-NOV-13
  14-NOV-13    20-NOV-13
  21-NOV-13    27-NOV-13
  28-NOV-13    04-DEC-13
  

  December:

  01-DEC-13           04-DEC-13
  05-DEC-13           11-DEC-13
  12-DEC-13          18-DEC-13
  19-DEC-13          25-DEC-13
  26-DEC-13          31-DEC-13
  

  Hello

  Roxyrollers wrote:

  Hello people:

  I have currently a query that picks up all the weeks between a date range where my week starts on Thursday and ends on Wednesday. The following query works fine except that I need the week of beginning and end, from beginning and end Dates of months and the beginning and the Dates of end of the values of the settings, I'm passing. In this case, I chose January 1, 2013 to 31 December 2013.

  Any help or pointers would be great!

  Thank you!

  Problem: I am picking up days of December 2012 as the first week began on December 27, 2012. In addition, in December, I'm pretty much lost last week as well (26 December - 31 December).

  The request in hand:

  1. First_thursday SELECT + (7 * (LEVEL - 1)) AS week_start_date,
  2. first_thursday + (7 * LEVEL)-1 AS week_end_date
  3. Of
  4. (
  5. SELECT TRUNC (p_from_date + 4, 'IW') - 4 AS first_thursday,-week should start to perform the pre-mounted THURSDAY based on the Start Date
  6. TRUNC (p_to_date + 4, 'IW') - 5 AS last_wednesday
  7. Of
  8. (
  9. SELECT to_date('01-JAN-2013') AS p_from_date,
  10. NVL (to_date('31-Dec-2013'), SYSDATE) AS p_to_date
  11. OF the double
  12. ) parms
  13. ) end_points
  14. CONNECT BY LEVEL<= (="" last_wednesday="" +="" 1="" -="">

  Currently, this is the result I get (I'm only including the months of January and December here).

  1. Week_Start_Date Week_End_Date
  2. DECEMBER 27, 12 2 JANUARY 13
  3. JANUARY 3, 13 JANUARY 9, 13
  4. 10 JANUARY 13 JANUARY 16, 13
  5. 17 JANUARY 13 23 JANUARY 13
  6. 24 JANUARY 13 30 JANUARY 13
  7. 31 JANUARY 13 FEBRUARY 6, 13

  December:

  1. NOVEMBER 28, 13 4 DECEMBER 13
  2. 5 DECEMBER 13 DECEMBER 11, 13
  3. 12 DECEMBER 13 18 DECEMBER 13
  4. 19 DECEMBER 13 DECEMBER 25, 13

  What I would really like is based on start and end Dates, as well as the first and the last day of the month is similarly try nicely. I have provided and then gently break at the end of the month:

  January:

  1. JANUARY 1, 13 2 JANUARY 13
  2. JANUARY 3, 13 JANUARY 9, 13
  3. 10 JANUARY 13 JANUARY 16, 13
  4. 17 JANUARY 13 23 JANUARY 13
  5. 24 JANUARY 13 30 JANUARY 13
  6. 31 JANUARY 13 JANUARY 31, 13

  February:

  1. 1ST FEBRUARY 13 FEBRUARY 6, 13
  2. 7 FEBRUARY 13 FEBRUARY 13, 13
  3. 14 FEBRUARY 13 FEBRUARY 20, 13
  4. 21 FEBRUARY 13 FEBRUARY 27, 13
  5. 28 FEBRUARY 13 FEBRUARY 28, 13

  November:

  1. 31 OCTOBER 13 NOVEMBER 6, 13
  2. 7 NOVEMBER 13 NOVEMBER 13, 13
  3. 14 NOVEMBER 13 NOVEMBER 20, 13
  4. 21 NOVEMBER 13 NOVEMBER 27, 13
  5. NOVEMBER 28, 13 4 DECEMBER 13

  December:

  1. 1ST DECEMBER 13 DECEMBER 4, 13
  2. 5 DECEMBER 13 DECEMBER 11, 13
  3. 12 DECEMBER 13 18 DECEMBER 13
  4. 19 DECEMBER 13 DECEMBER 25, 13
  5. 26 DECEMBER 13 DECEMBER 31, 13

  Why the "weeks" in November, have all 7 days, while the "weeks" in the first or the last week in the other month usually have less?  (For example, February 28 is a 'week' alone.)

  The following works for the other months:

  WITH all_days AS

  (

  SELECT DATE "2013-01-01' + LEVEL - AS a_date 1

  OF the double

  CONNECT BY LEVEL<=>

  )

  SELECT DISTINCT

  More GRAND (TRUNC (a_date + 4, 'IW') - 4)

  , TRUNC (a_date, 'MONTH')

  ) AS week_begin

  , The LEAST (TRUNC (a_date + 4, 'IW') + 2

  TRUNC (LAST_DAY (a_date))

  ), Week_end

  Of all_days

  ORDER BY week_begin

  ;

  Output:

  WEEK_BEGIN WEEK_END

  ----------- -----------

  January 1, 2013 January 2, 2013

  January 3, 2013 January 9, 2013

  January 10, 2013 January 16, 2013

  January 17, 2013 January 23, 2013

  January 24, 2013 January 30, 2013

  January 31, 2013 January 31, 2013

  February 1, 2013 February 6, 2013

  February 7, 2013 February 13, 2013

  February 14, 2013 February 20, 2013

  February 21, 2013 February 27, 2013

  February 28, 2013 February 28, 2013

  ...

  November 1, 2013 November 6, 2013

  November 7, 2013 November 13, 2013

  November 14, 2013 November 20, 2013

  November 21, 2013 November 27, 2013

  November 28, 2013 November 30, 2013

  December 1, 2013 December 4, 2013

  December 5, 2013 December 11, 2013

  December 12, 2013 December 18, 2013

  December 19, 2013 December 25, 2013

  26 December 2013 31 December 2013

• To display the first and last date of one month

  I have the date format in 10 Mar 10.
  My requirement is when ever I select the date in the dashboard for all the month it should show results of all the months.
  I had the request for obiee101.blogspot.com.but if I use that sometimes it is not the latest results of the day. Any body please give me the query to display the results for the first day and lastday?
  I select any day from the drop-down menu of the guest, it must display the month of ex: if results
  If I select either 1 mar mar 10.2 10,30 mar 10...
  It should give results for the month of March.
  Can you please provide me the query for the last month also?
  If I select March date date print want to display the results of March together in a single column, results of the previous months in the other column
  
  Someone help me to achieve this?

  Yes, you are right. Jean SQL for the last day of the month, if the "last day of the previous month" ends on June 30, that "adding a month" will result in the 30th of the following month. But if the next month has 31 days, you don't miss this day here.

  Use it for the last day of the current month.

  TIMESTAMPADD (SQL_TSI_DAY-1, TIMESTAMPADD (SQL_TSI_MONTH, 1, TIMESTAMPADD (SQL_TSI_DAY, 1, TIMESTAMPADD (SQL_TSI_DAY, DAYOFMONTH (CURRENT_DATE) *-1, CURRENT_DATE))))

  The SQL above will ensure that you will get always the last day of the month "current" no matter how many days during the previous or current month.

• Extract the first and the last Date of the previous month

  This seems to be a delicate but again it is perhaps easy for some of you people.
  
  Here is how I find the previous month
  
  Any ideas on how to get the first and last date of the previous month?
  
  Thanks in advance.

  Hello!

  SQL>
  SQL> select last_day(add_months(sysdate,-1)) from dual;
  
  LAST_DAY
  --------
  28.02.10
  
  SQL> select trunc(add_months(sysdate,-1),'MM') from dual
  
  TRUNC(AD
  --------
  01.02.10
  
  SQL> 
  

  T

• Need a query to return the first and last date for a rowset.

  Hello
  
  I have a query which can be simplified to the following data, if
  Assume that it is my dataset, with THE_VALUE of
  Sign (Anum) therefore,-1, 0 or 1.
  
  * (Sorry for crushed registration. "I can't understand this website's rich text formatting.) *
  
  THE_VALUE THE_DATE THE_MEMBER
  1 0 1 January 2007
  1 0 1 February 2007
  1 0 1 March 2007
  1. 1 April 1, 2007
  1 1 1 May 2007
  1 0 1 June 2007
  1. 1 July 1, 2007
  1. 1 August 1, 2007
  1 0 01 - sep - 2007
  2 0 1 January 2007
  2 1 February 1, 2007
  2 0 1 March 2007
  2. 1 April 1, 2007
  2 1 1 May 2007
  2 0 1 June 2007
  -2 1 1 July 2007
  2. 1 August 1, 2007
  2. 1 01-sep-2007
  3 0 1 January 2007
  3. 1 February 1, 2007
  3 0 1 March 2007
  3 0 1 April 2007
  3. 1 May 1, 2007
  3 0 1 June 2007
  3. 1 July 1, 2007
  3. 1 August 1, 2007
  3 0 01 - sep - 2007
  
  I need to get the lines with the THE_MEMBER, the values of the first and the last
  THE_DATE, where the value is - 1, and the date range is the last
  set of lines to the Member, with the same value of THE_VALUE.
  
  I tried the following to get the dates of first and last for a set
  consecutive months with the same value for the Member.
  
  SELECT the_member
  the_value
  the_date
  first_value (the_date)
  in the first_date (PARTITION the_member, ORDER BY the_member the_value, the_date)
  last_value (the_date)
  during the last_date (PARTITION the_member, ORDER BY the_member the_value, the_date)
  OF togola
  ORDER BY the_member
  the_date;
  
  At first, it seems to work, but then, when the return value
  an old value, FIRST_DATE will be the first of all the lines containing
  This value for the Member rather than the first of consecutive
  rows with this value for the Member. Apparently the partitioning
  occurs before the order.
  
  THE_MEMBER THE_VALUE THE_DATE FIRST DATE LAST DATE
  1 0 January 1, 2007 January 1, 2007 January 1, 2007
  1 0 1 February 2007 1 January 2007 1 February 2007
  1 0 1 March 2007 1 January 2007 March 1, 2007
  1. 1 April 1, 2007 April 1, 2007 April 1, 2007
  1. 1 May 1, 2007 April 1, 2007 may 1, 2007
  1-0 June 1, 2007 January 1, 2007 June 1, 2007
  1. 1 July 1, 2007 April 1, 2007 July 1, 2007
  1. 1 August 1, 2007 April 1, 2007 August 1, 2007
  1 0 01 - sep - 2007 1 January 2007 01-Sep-2007
  
  2 0 January 1, 2007 January 1, 2007 January 1, 2007
  2 1 1 February 2007 February 1, 2007 February 1, 2007
  2 0 1 March 2007 1 January 2007 March 1, 2007
  2. 1 April 1, 2007 February 1, 2007 April 1, 2007
  2 1 1 May 2007 February 1, 2007 may 1, 2007
  2-0 June 1, 2007 January 1, 2007 June 1, 2007
  -2 1 1 July 2007 February 1, 2007 July 1, 2007
  2. 1 August 1, 2007 February 1, 2007 August 1, 2007
  2. 1 01-sep-2007 1 February 2007 01-Sep-2007
  
  3 0 January 1, 2007 January 1, 2007 January 1, 2007
  3. 1 February 1, 2007 February 1, 2007 February 1, 2007
  3 0 1 March 2007 1 January 2007 March 1, 2007
  3 0 April 1, 2007 January 1, 2007 April 1, 2007
  3. 1 May 1, 2007 February 1, 2007 may 1, 2007
  3 0 June 1, 2007 January 1, 2007 June 1, 2007
  3. 1 July 1, 2007 February 1, 2007 July 1, 2007
  3. 1 August 1, 2007 February 1, 2007 August 1, 2007
  3 0 01 - sep - 2007 1 January 2007 01-Sep-2007
  
  That's what I need to get in the end.
  
  THE_MEMBER FIRST DAY DATE OF LAST
  July 2 1 2007-01 - Sep - 2007
  
  Any ideas would be really appreciated.
  
  Published by: user10700981 on December 17, 2008 13:57

  Hello

  We'll call the lines whose the_value =-1 'good' lines and lines with the_value! =-1 ranks of 'bad '.

  For each value of the_value, we need the first and last values of the_date where
  the last row in the group is good
  (b) the current line is good
  (c) there is a lot of lines from the current line to the end of the Group
  Condition (a) is just a special case of (c).
  Conditions (b) and (c) are similar: (b) if applied to the current line, (c) applies to all lines after him. They can easily be combined into a single test that counts the number of lines after the current line or bad.

  Which produces the results you requested of the sample data that you provided:

  WITH     count_bad     AS
  (
       SELECT     the_member
       ,     the_date
       ,     COUNT     ( CASE
                      WHEN  the_value != -1 -- assuming the_value is never NULL
                      THEN  1
                   END
                 ) OVER     ( PARTITION BY     the_member
                        ORDER BY     the_date     DESC
                      )     AS bad_cnt
       FROM     table_x
  )
  SELECT     the_member
  ,     MIN (the_date)     AS first_date
  ,     MAX (the_date)     AS last_date
  FROM     count_bad
  WHERE     bad_cnt     = 0
  GROUP BY     the_member
  ORDER BY     the_member;