get the last day of the week

Similar Questions

• How to get sales last day of the previous month

  HELO guys

  I have a question how do I get sales date last day of the previous month where my fact table is level. in fact I tried using Ago but it seems not working. for example, if I chose December 29, 2014 so if I used the function there are then the result will display data on November 29, 2014 (not the last day of November 2014).

  Please guys if you have any solution and I really advise thanks to you.

  Not exactly under what circumstances specific as you try to reach this goal, but suppose you have a few guest dashboard where you select a day and you have a report with a measure where you want to show the sales of the last day of the previous month based on the selected date in the dash prompt.

  If you change the formula of this measure to something like:

  FILTER (with the HELP of 'Sales' (DATE = TIMESTAMPADD (SQL_TSI_DAY-1, TIMESTAMPADD (SQL_TSI_DAY, DAYOFMONTH(@{PV_DATE_SELECTED}) * (-1) + 1, @{PV_DATE_SELECTED}))))

• How to get the week sequence?

  Hi friends,
  
  Greetings of the day!
  
  I am greatly in dealing with the next thing.
  
  I have two tables. a table with all the required information and another table called process_dtl, have the details of refreshment. These tables gets updated once a week. when its gets refreshed have will update the process_dtl table start date and refreshes the end date. There are also a few unique seq_no for each update. I will combine these 2 tables with seq_no process, because it is the unique key in the two tables. About these tables are more 2-year data. But what I want, I want only 6 months given. With 6 months data, based on the start_date I want to have the data week sequence. Means I want to know if it is given 1 week or 2 weeks, etc because the data get updated once a week. Is it possible to distinguish like this using start date. Please reply back if you understand the above.
  I'm using oracle 11g.
  
  
  Thank you
  
  Published by: 981145 on May 8, 2013 04:56

  You can get the data from the last 6 months simply by using the WHERE clause to limit the process_start_dt or process_end_date, as mentioned by Chris above. Since the sequence of steps. is unique for each race, I assume that the data you get from dtap_rpt_site_dtl_hst for that sequence number. needs no other filter criteria, so it must be good there.

  For the format of the week like you wanted, use the following in your select clause-

  to_char(process_start_dt, 'Mon') ||' ' || to_char(process_start_dt, 'D') week_seq
  

  Hope this has helped.
  Thank you!

• Get the week number

  How can I get the number of week a week of prasent using simpleDateFormat class?

  With regard to:

  Jitendra.Balla

  GetWeekOfYear DateTimeUtilities (calendar, long date, int firstDayofWeek)

• How to get the week of the year in American Standard

  Hello
  
  I know that it might be a repetitive question, but has not found a convincing solution to him in any of the previous threads. I'm looking for a function (user defined, if someone has already written it) go the week of the year, American Standard. i.e., The week should begin on Sunday and end on Saturday (and NOT from Monday to Sunday)
  
  03/01/2010 - should be the beginning of the 1st week of 2010... 10/01/2010 will be the beginning of the second week and so on
  04/01/2009 - should be the beginning of the 1st week of 2009... 11/01/2009 will be the beginning of the second week and so on.
  
  Does anyone have a function that takes a date as input and returns back the week of the year in the above format? Any help is greatly appreciated.
  
  Thank you

  You can add a day to your date in order to manipulate the weeks;

  with t as (
     select to_date('02/01/2010','dd/mm/yyyy') dt from dual union all
     select to_date('03/01/2010','dd/mm/yyyy') from dual union all
     select to_date('09/01/2010','dd/mm/yyyy') from dual union all
     select to_date('10/01/2010','dd/mm/yyyy') from dual)
  select dt, to_char(dt, 'Day') dy, to_char(dt+1, 'iw') wk
  from t;
  
  DT          DY        WK
  ----------- --------- --
  02/01/2010  Saturday  53
  03/01/2010  Sunday    01
  09/01/2010  Saturday  01
  10/01/2010  Sunday    02
  

• How to get the week of the current month

  Hi all
  Is it possible to find the week of the current month.
  
  Help, please...

  Hello...

  Use this feature to get the desired result.

  Hope it's okay...

  CEILING (DAYOFMONTH ("Time D0". "T00 calendar date") (/ 7.00) "

  Note: use 7.00 7 not only in the denominator*.

• How to get the last day of the week?

  HII
  
  I can get the week number of calendar for a given date using
  
  SELECT to_char (to_date('04/04/2011','MM/DD/YYYY'), 'WW') FROM dual
  
  can any body tell me, how to get the last day of the week?
  
  and the answer should be: 04/08/2011(8th april)
  Thank you
  San
  
  Published by: sandeep9 on April 4, 2011 03:50

  Perhaps this...

  SQL> select trunc(sysdate,'WW')+6 from dual;
  
  TRUNC(SYSDATE,'WW')+
  --------------------
  08-APR-2011 00:00:00
  
  SQL>
  

• Function to create dates as well as the week, quarter, and year

  Hi all

  I am trying to write a function that will create automatically with their respective week, quarter, and year dates in different columns.

  For example,.

  Date of the quarter Qtr/Yr/QtrWk week exercise exercise exercise

  4

  15 Q4-WK13

  52

  2015

  30/09/2015

  I would like to create a full year for each day of show week quarter Qtr/year/QtrWk, exercise, exercise from 01/10/2015-09 30, 2016.

  Appreciate your help and advice.

  Thank you

  AMan

  Hi AMan,

  can't answer your question with a detailed requirement.

  No doubt a whole year can be created in a SQL statement (CONNECT BY or the recursive subquery factoring) and is not a problem.

  But I would like to ask you the following:

  • How do you get the week number? There might be a different way to look at it (ISO or not, week starting with the Sun, Mon or the first day of the year, etc.)
  • The same question can be applied to the financial week. When it's the first week? 01/10/2015 until 10/07/2015?

  You can have a quick glance at the definition of different week in 'Model of Format of Date' on this page:

  https://docs.Oracle.com/CD/B28359_01/server.111/b28286/sql_elements004.htm

  Check the difference between WW and IW.

  Kind regards.

  Alberto

• How can I stop receiving the weekly activity of catalyst report?

  My site is no longer the catalyst for the company, but I get the weekly report again and again. The churn results in an error message. Help someone.

  Hello

  This means that the site of British Colombia is still active and you have not deleted. If in case you want the site of BC and you just want you not receiving weekly reports, you'll need to connect to the admin of the site > my details > and uncheck the option to not receiving weekly reports.

  For more details, you can also find this video useful: bccademy | How to enable / disable the weekly reports. -YouTube

• Breaking a year in coming weeks of beginning and end Dates (parameters) and first and last day of the month

  Hello people:

  I have currently a query that picks up all the weeks between a date range where my week starts on Thursday and ends on Wednesday. The following query works fine except that I need the week of beginning and end, from beginning and end Dates of months and the beginning and the Dates of end of the values of the settings, I'm passing. In this case, I chose January 1, 2013 to 31 December 2013.

  Any help or pointers would be great!

  Thank you!

  Problem: I am picking up days of December 2012 as the first week began on December 27, 2012. In addition, in December, I'm pretty much lost last week as well (26 December - 31 December).

  The request in hand:

  SELECT first_thursday + (7 * (LEVEL - 1))   AS week_start_date,
                   first_thursday + (7 * LEVEL) - 1    AS  week_end_date
  FROM
  (
    SELECT TRUNC(p_from_date + 4, 'IW') - 4   AS first_thursday, -- Week should start the pre ceeding THURSDAY based on the Start Date
                    TRUNC( p_to_date + 4,  'IW') - 5     AS last_wednesday
    FROM
    (
      SELECT to_date('01-JAN-2013') AS p_from_date,
                      NVL(to_date('31-DEC-2013'), SYSDATE) AS p_to_date
      FROM     dual
    ) parms
  ) end_points
  CONNECT BY LEVEL <= ( last_wednesday + 1 - first_thursday)/7;
  

  Currently, this is the result I get (I'm only including the months of January and December here).

  Week_Start_Date     Week_End_Date
  27-DEC-12                02-JAN-13
  03-JAN-13                 09-JAN-13
  10-JAN-13                 16-JAN-13
  17-JAN-13                 23-JAN-13
  24-JAN-13                 30-JAN-13
  31-JAN-13                 06-FEB-13
  

  December:

  28-NOV-13               04-DEC-13
  05-DEC-13              11-DEC-13
  12-DEC-13              18-DEC-13
  19-DEC-13              25-DEC-13
  

  What I would really like is based on start and end Dates, as well as the first and the last day of the month is similarly try nicely. I have provided and then gently break at the end of the month:

  January:

  01-JAN-13              02-JAN-13
  03-JAN-13              09-JAN-13
  10-JAN-13             16-JAN-13
  17-JAN-13             23-JAN-13
  24-JAN-13             30-JAN-13
  31-JAN-13             31-JAN-13
  

  February:

  01-FEB-13    06-FEB-13
  07-FEB-13    13-FEB-13
  14-FEB-13    20-FEB-13
  21-FEB-13    27-FEB-13
  28-FEB-13    28-FEB-13
  

  November:

  31-OCT-13    06-NOV-13
  07-NOV-13    13-NOV-13
  14-NOV-13    20-NOV-13
  21-NOV-13    27-NOV-13
  28-NOV-13    04-DEC-13
  

  December:

  01-DEC-13           04-DEC-13
  05-DEC-13           11-DEC-13
  12-DEC-13          18-DEC-13
  19-DEC-13          25-DEC-13
  26-DEC-13          31-DEC-13
  

  Hello

  Roxyrollers wrote:

  Hello people:

  I have currently a query that picks up all the weeks between a date range where my week starts on Thursday and ends on Wednesday. The following query works fine except that I need the week of beginning and end, from beginning and end Dates of months and the beginning and the Dates of end of the values of the settings, I'm passing. In this case, I chose January 1, 2013 to 31 December 2013.

  Any help or pointers would be great!

  Thank you!

  Problem: I am picking up days of December 2012 as the first week began on December 27, 2012. In addition, in December, I'm pretty much lost last week as well (26 December - 31 December).

  The request in hand:

  1. First_thursday SELECT + (7 * (LEVEL - 1)) AS week_start_date,
  2. first_thursday + (7 * LEVEL)-1 AS week_end_date
  3. Of
  4. (
  5. SELECT TRUNC (p_from_date + 4, 'IW') - 4 AS first_thursday,-week should start to perform the pre-mounted THURSDAY based on the Start Date
  6. TRUNC (p_to_date + 4, 'IW') - 5 AS last_wednesday
  7. Of
  8. (
  9. SELECT to_date('01-JAN-2013') AS p_from_date,
  10. NVL (to_date('31-Dec-2013'), SYSDATE) AS p_to_date
  11. OF the double
  12. ) parms
  13. ) end_points
  14. CONNECT BY LEVEL<= (="" last_wednesday="" +="" 1="" -="">

  Currently, this is the result I get (I'm only including the months of January and December here).

  1. Week_Start_Date Week_End_Date
  2. DECEMBER 27, 12 2 JANUARY 13
  3. JANUARY 3, 13 JANUARY 9, 13
  4. 10 JANUARY 13 JANUARY 16, 13
  5. 17 JANUARY 13 23 JANUARY 13
  6. 24 JANUARY 13 30 JANUARY 13
  7. 31 JANUARY 13 FEBRUARY 6, 13

  December:

  1. NOVEMBER 28, 13 4 DECEMBER 13
  2. 5 DECEMBER 13 DECEMBER 11, 13
  3. 12 DECEMBER 13 18 DECEMBER 13
  4. 19 DECEMBER 13 DECEMBER 25, 13

  What I would really like is based on start and end Dates, as well as the first and the last day of the month is similarly try nicely. I have provided and then gently break at the end of the month:

  January:

  1. JANUARY 1, 13 2 JANUARY 13
  2. JANUARY 3, 13 JANUARY 9, 13
  3. 10 JANUARY 13 JANUARY 16, 13
  4. 17 JANUARY 13 23 JANUARY 13
  5. 24 JANUARY 13 30 JANUARY 13
  6. 31 JANUARY 13 JANUARY 31, 13

  February:

  1. 1ST FEBRUARY 13 FEBRUARY 6, 13
  2. 7 FEBRUARY 13 FEBRUARY 13, 13
  3. 14 FEBRUARY 13 FEBRUARY 20, 13
  4. 21 FEBRUARY 13 FEBRUARY 27, 13
  5. 28 FEBRUARY 13 FEBRUARY 28, 13

  November:

  1. 31 OCTOBER 13 NOVEMBER 6, 13
  2. 7 NOVEMBER 13 NOVEMBER 13, 13
  3. 14 NOVEMBER 13 NOVEMBER 20, 13
  4. 21 NOVEMBER 13 NOVEMBER 27, 13
  5. NOVEMBER 28, 13 4 DECEMBER 13

  December:

  1. 1ST DECEMBER 13 DECEMBER 4, 13
  2. 5 DECEMBER 13 DECEMBER 11, 13
  3. 12 DECEMBER 13 18 DECEMBER 13
  4. 19 DECEMBER 13 DECEMBER 25, 13
  5. 26 DECEMBER 13 DECEMBER 31, 13

  Why the "weeks" in November, have all 7 days, while the "weeks" in the first or the last week in the other month usually have less?  (For example, February 28 is a 'week' alone.)

  The following works for the other months:

  WITH all_days AS

  (

  SELECT DATE "2013-01-01' + LEVEL - AS a_date 1

  OF the double

  CONNECT BY LEVEL<=>

  )

  SELECT DISTINCT

  More GRAND (TRUNC (a_date + 4, 'IW') - 4)

  , TRUNC (a_date, 'MONTH')

  ) AS week_begin

  , The LEAST (TRUNC (a_date + 4, 'IW') + 2

  TRUNC (LAST_DAY (a_date))

  ), Week_end

  Of all_days

  ORDER BY week_begin

  ;

  Output:

  WEEK_BEGIN WEEK_END

  ----------- -----------

  January 1, 2013 January 2, 2013

  January 3, 2013 January 9, 2013

  January 10, 2013 January 16, 2013

  January 17, 2013 January 23, 2013

  January 24, 2013 January 30, 2013

  January 31, 2013 January 31, 2013

  February 1, 2013 February 6, 2013

  February 7, 2013 February 13, 2013

  February 14, 2013 February 20, 2013

  February 21, 2013 February 27, 2013

  February 28, 2013 February 28, 2013

  ...

  November 1, 2013 November 6, 2013

  November 7, 2013 November 13, 2013

  November 14, 2013 November 20, 2013

  November 21, 2013 November 27, 2013

  November 28, 2013 November 30, 2013

  December 1, 2013 December 4, 2013

  December 5, 2013 December 11, 2013

  December 12, 2013 December 18, 2013

  December 19, 2013 December 25, 2013

  26 December 2013 31 December 2013

• How to get the last day of a month for every 2 months for a given period?

  Hello

  Can is it some please let me know how to get the last day, last day of the week, the weekend last day, last Monday, one month for every 2 months for a given period?

  Thanks in advance.

  Try the below

  SELECT LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))) lastday.

  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'SAT '.

  SO LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))-1

  WHERE TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'Sun '.

  THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))-2

  Of OTHER LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  END as lastweekday,

  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') IN ('Sam', 'SUN')

  THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  Of OTHER LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  -(TO_NUMBER (TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))),' from)) - 1).

  END as lastweekendday,

  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'MY

  THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  Of OTHER NEXT_DAY (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), "LUN")-7

  END AS lastmonday

  FROM (SELECT SYSDATE startdate,

  SYSDATE + 300 enddate

  THE DOUBLE)

  CONNECT BY LEVEL<=>

• Last week my office pc willnot go in standby mode, it stops, and then in the am I get the message that stop you the bad way how to fix

  Last week my desktop pc will not go in standby mode, it stops then am I get the message that he was arrested by mistake.  How to fix

  Hello

  Were there any changes (hardware or software) to the computer before the show?

  Method 1 : check the clean boot and see if the problem is solved or not.

  To help resolve the error and other messages, you can start Windows Vista or Windows 7 by using a minimal set of drivers and startup programs. This type of boot is known as a "clean boot". A clean boot helps eliminate software conflicts.

  Note: perform step 7 to reset the computer to start as usual after the boot process.

  How to troubleshoot a problem by performing a clean boot in Windows Vista or in Windows 7

  Method 2: Update the display driver and check if the problem is solved or not.

  Updated a hardware driver that is not working properly

  Hope that helps.

• How to get the last date of 3 days for the current month?

  Hello. Guy

  How to get the last date of 3 days for the current month?

  MY OUTPUT WOULD LOOK LIKE THIS

  JANUARY 29, 2016

  JANUARY 30, 2016

  JANUARY 31, 2016

  
  

  GUYS HELP ME / / /...
  

  SQL > select last_day (sysdate) - level + 1 double connect by level<= 3="" order="" by="">

  LAST_DAY)

  ---------

  29 JANUARY 16

  30 JANUARY 16

  31 JANUARY 16

• How to get the last business day of the previous month?

  Hi all

  We need the user as below,

  If the user select 18 June 2015 ' quick dashboard as the input value, and then they want to see last month last day of work (business date: 29-may-2015) amount in report, if you have an idea please share with us.thanks

  Note:

  use under request we can able to get the last day of the previous month, we want to for the last business day of the last month, based on the date of entry of the user?

  TIMESTAMPADD (SQL_TSI_DAY,-(1), TIMESTAMPADD (SQL_TSI_DAY, DAYOFMONTH ("DIM_TIME". ("" DataDate ") *-(1) + 1,"DIM_TIME ". (("" DataDate "))

  Thank you

  Deva

  Try this,

  case when Dayofweek (timestampadd (sql_tsi_day, Dayofmonth(Date '2015-06-15') *-1, Date ' 2015-06-15')) = 1 then timestampadd (sql_tsi_day, (Dayofmonth(Date '2015-06-15') *-1)-2, Date '' 2015-06-15) when Dayofweek (timestampadd (sql_tsi_day, Dayofmonth(Date '2015-06-15') *-1, Date ' 2015-06-15')) = 7 then timestampadd (sql_tsi_day, Dayofmonth(Date '2015-06-15') *-1-1, Date '' 2015-06-15) another timestampadd (sql_tsi_day, Dayofmonth(Date '2015-06-15') *-1, Date ' 2015-06-15') end

  As Ftsiot said in this post, it will work only to exclude the sat and Sun. Another one if you want to exclude regional holiday, you may need a calendar in DB table.

  Thank you

  AJ

• Get the last day of the month

  Hello

  How can I get the (day number of the) last day of a given month and year?

  So, if

  year 2015 = and month = 1, the output should be 31

  year = 2012 and month = 2 while production is expected to be 29

  year 2013 = and month = 2 while production is expected to be 28

  etc.

  Y at - it no OBIEE to achieve? If not, then a command SQL Oracle is very good too (I prefer OBIEE however)

  Thanks in advance,

  Erik

  You start from the first day of the month, you add 1 month [TIMESTAMPADD (SQL_TSI_MONTH, 1, 'your date')], you must subtract 1 day [TIMESTAMPADD (SQL_TSI_DAY,-1, 'your date')] and use the DAYOFMONTH function to get the number of the last day of the month [DAYOFMONTH ('your ' date')].

  All these calls nesting together and you're there.