DateTime subtraction question

Hi, I am looking for the number of hours between two dates. Please see details below:

{code}

CREATE TABLE TEST_DATE (job_no NUMBER, job_start_date DATE, job_end_date DATE);

INSERT INTO TEST_DATE VALUES (1000, to_timestamp (31 December 2014 0900', 'dd-mm-yyyy HH24MI'), to_timestamp ("1 January 2015 0900', ' HH24MI dd-mm-yyyy"));

INSERT INTO TEST_DATE VALUES (2000, to_timestamp (1 January 2015 1100', 'dd-mm-yyyy HH24MI'), to_timestamp ("1 January 2015 1600', ' HH24MI dd-mm-yyyy"));

INSERT INTO TEST_DATE VALUES (3000, to_timestamp (15 January 2015 2000', 'dd-mm-yyyy HH24MI'), to_timestamp ("16 January 2015 2 100 ft ' HH24MI dd-mm-yyyy"));

Select job_no, job_end_date, job_start_date, job_end_date - job_start_date as test_date job_duration;

{code}

-Assumptions:

-I will pass a value DATE setting and for this example, it will be 2015-01-01 (Please note there is no timestamp, it's just a date value)

-I'm only interested in the calculation of the duration of hours where the job_start_date is in the previous month, or where the job_start_date is in the month of setting DATE - 1, but a big but, the duration of the hours - must be for the month of the DATE parameter, i-e: 2015-01-01.

-Therefore, Job_no = 1000 I would like to come back 9. Currently with right subtraction I get 1 (which is 1 day or 24 hours I multiply with the number of hours per day)

SELECT job_no

, (LESS (job_end_date, TRUNC (ADD_MONTHS (p_date, 1), 'MM'))-TRUNC (p_date, 'MM')) * duration AS 24

OF TEST_DATE, (SELECT DATE ' 2015-1-1' p_date FROM DUAL)

WHERE job_start_date > = TRUNC (ADD_MONTHS (p_date,-1), 'MM')

AND job_start_date<>

Tags: Database

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