Developer SQL is no longer let me look at the same table on 2 servers name

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• Conflicts of SQL columns on the same table

  I have a table with two columns used for the same purpose. Examples (start_date and career_history_start) (end_date or career_history_end).
  The columns have different (varchar2 and date) data types. The developer has used the data type date (start_date) to write the report and of the use of time even the vachar2 to manully insert date. We decided to use a single (varchar2). Meanwhile, there are differences in the two columns. We will find the difference between the two columns start_date (date) and career_history_start (varchar2).
  
  No idea what query will accomplish this considering they gave different type on the same table?
  
  Here is the description of the table:
  
  career_history / / DESC
  Name of Type Null
  --------------------------- -------- -------------
  CAREER_HISTORY_ID NOT NULL NUMBER (38)
  PERSON_ID NUMBER (38)
  CAREER_HISTORY_START VARCHAR2 (50)
  CAREER_HISTORY_END VARCHAR2 (50)
  CAREER_HISTORY_DESC VARCHAR2 (250)
  CAREER_HISTORY_RECNUM NUMBER (38)
  Start_date DATE
  End_date DATE
  CAREER_HISTORY_ACTIVE_FLAG CHAR (1)
  CAREER_HISTORY_DELETED_FLAG CHAR (1)
  CAREER_HISTORY_UPDATE_TIME TIMESTAMP (6)
  CAREER_HISTORY_UPDATED_BY VARCHAR2 (50)
  NUMBER OF SORT_NUM

  The customer doesn't care how the data is stored in the database. He care how it is displayed.

  What happens if your client has another office in a zone schedule differnet and each office needs display their time locally, but the server must store all the time in the same zone. How do they manage that when storing dates as a varchar data type. You get that kind of built-in functionality when you use a date data type

  In its simplest form if the customer is always display the data as a string, and then create a view from top of the table and convert dates in any format the customer prefers and that expose to the client.

  In this way, you get data stored properly and the client allows you to view data in the way they prefer

• Developer SQL 3.2.20 always invites to indicate the path full java.exe

  I installed SQL Developer 3.2.9 to 3.2.20 on my Windows 7 64-bit system. I've updated just like I did earlier. It is "installed" in C:\Program Files (x 86) \sqldeveloper and down there, I have a folder for each version that I installed. sqldeveloper_3.1.07.24, sqldeveloper_3.2.09.30 and now sqldeveloper_3.2.20.09.87.
  
  Now the 3.2.20 new version asks me to enter the path to java.exe whenever I start it. I think that the previous version did this, but only once. This new version does not seem to remember when I choose the path to the java.exe that I use.
  
  Any thoughts on how I can do Developer SQL do not forget where my java.exe?

  Open the sqldeveloper/bin directory who settle.

  Edit the sqldeveloper.conf file and specify the path.

  Save the file.

  Behavior indicates that the SQL Developer is not able to write to this file...

• How to copy settings on a development folder and copy it to another folder containing the same photos

  Hello forum!

  I kinda made a mistake. I hope someone can answer me this.

  I have a folder under "Records" in the library. In this folder, I have 62 photos, which are also edited in lightroom.
  A mistake that happened and I've added a new folder containing the same images, but there is more than 200 pictures in this folder.
  Is it possible to copy my photos modified in my catalog to the new folder?

  I hope that the question was not confusing.

  Thank you!

  If you have two folders, which contains identical images, then you have the duplicate hard disk files.

  In this case, you will not be able to move the images published in the largest file because the file on any computer system will not allow that.

  Copy of the parameters is not the answer because that can be done individually (assuming that all the files have not the same settings)

  Identify files duplicate in the large folder and delete them from your hard drive. You can do this in Lightroom by pressing the DELETE key and choosing the option remove the disc (not delete)

  Select all 62 images in the grid, and then drag them to the folder you want to move them. Lightroom invite you you move them on the hard drive also. Ok.

  Let us know if this helps

• Avoid multiple calls to the same table in SQL

  Hi team,

  can anyone help me on a technical level with the SQL below.

  SELECT MOR. ACE BLEI_CK BLEI_CK FC_CMC_BLBL_BILL_SUMM INNER JOIN ST_ALL_IFP_MEDCR_SUPPL_STG STG MOR ON MOR BLEI_CK = STG. BIL_ENTY_CK AND MOR. BLBL_PAID_STS <>'3' AND MOR. BLBL_DUE_DT = (SELECT MIN (BLBL_DUE_DT) FROM FC_CMC_BLBL_BILL_SUMM WHERE BLEI_CK =. MOR BLEI_CK AND BLBL_PAID_STS <>' 3') INNER JOIN FC_CMC_BLDF_BL_DEFINE BLDF on MOR. BLEI_CK = BLDF. BLEI_CK AND to_date (January 17, 2012 20:32:25 "," MM/DD/YYYY hh24:mi:ss') BETWEEN BLDF. BLDF_EFF_DT AND BLDF. BLDF_TERM_DT WHERE MOR. BLBL_DLNQ_DT + (BLDF. (BLDF_GRACE_PER-2) < to_date (January 17, 2012 20:32:25 "," MM/DD/YYYY hh24:mi:ss') GROUP OF MOR. BLEI_CK ORDER BY BLEI_CK

  Here, the FC_CMC_BLBL_BILL_SUMM table is called two times in the same query. How to avoid this problem by using any means or Analytics

  Thank you

  something like this:

  WITH Boop AS (SELECT BLEI_CK

  BLBL_DUE_DT

  BLBL_DLNQ_DT

  ROW_NUMBER() over (ORDER BY BLBl_DUE_DT DESC BLEI_CK PARTITION) AS date_rank

  OF FC_CMC_BLBL_BILL_SUMM

  WHERE BLBL_PAID_STS <> '3')

  SELECT MOR BLEI_CK AS BLEI_CK.

  MOR

  INNER JOIN ST_ALL_IFP_MEDCR_SUPPL_STG ON (MOR. BLEI_CK = STG STG BIL_ENTY_CK)

  INNER JOIN FC_CMC_BLDF_BL_DEFINE BLDF ON (MOR. BLEI_CK = BLDF. BLEI_CK)

  WHERE MOR. DATE_RANK = 1

  AND MOR. BLBL_DLNQ_DT + (BLDF. BLDF_GRACE_PER-2)< to_date('01/17/2012="" 20:32:25','mm/dd/yyyy="">

  AND to_date (January 17, 2012 20:32:25 "," MM/DD/YYYY hh24:mi:ss') BETWEEN BLDF. BLDF_EFF_DT AND BLDF. BLDF_TERM_DT

  GROUP OF MOR BLEI_CK.

  ORDER BY BOOP. BLEI_CK

  /

  HTH

• Look for the same combinations of characters

  Hi guys,.

  We experience this problem to enter a copy of parts inventory in the system who physically refers to the same part. You create a select query to browse the list of parts inventory to discover existing parts with similar names.

  Have a search on a specific set of characters and it must list the records even with 50% of the characters, they entered. Characters can be anywhere in the name of the part with any case.

  For example: entry "abcd1234" must return the parts with the following name...

  A nut 234 R49

  B12 SE A22

  156 65 a2 hub

  But not...

  ABC 89998

  AK-47

  Xbox 360

  K98b Mauser

  Thank you

  Napster

  Crazy, but in any case

  SQL > WITH t AS
  () 2
  3. SELECT "a nut 234 R49" str FROM DUAL
  4 UNION ALL
  5. SELECT "B12 SE A22" DOUBLE
  6 UNION ALL
  7. SELECT 'Hub 156 65 a2' FROM DUAL
  8 UNION ALL
  9. SELECT 'abc 89998' FROM DUAL
  ANY UNION 10
  11. SELECT 'AK 47' FROM DUAL
  12 UNION ALL
  13. SELECT 'Xbox 360' FROM DUAL
  14 UNION ALL
  15 SELECT 'Mauser K98b' DOUBLE
  (16),
  17 input_data
  18 as
  (19)
  20. Select "abcd1234" double input_val
  (21),
  T1 22
  23 as
  (24)
  25 select str
  26, trim (substr (input_val, level, 1)) input_char
  27 t
  28 cross
  29 join input_data
  30 connect by level<=>
  31 and prior str = str
  sys_guid() 32 and prior is not null
  33)
  34 select distinct str
  35, round (percnt, 2) match_percnt
  36, case when round (percnt, 2) > = 50, then "MATCH" else "DOES NOT EQUAL" end status
  37 in)
  38 select t1.str
  39, t1.input_char
  40, t2.str_char
  41, count (input_char) on input_char_cnt (t1.str score)
  42, count (str_char) on str_char_cnt (t1.str score)
  43, (count (str_char) on (t1.str score) count (input_char) more (t1.str score)) * 100 percnt
  44 of the t1
  45 on the left
  Join 46)
  47 select str
  48, trim (substr (str, level, 1)) str_char
  49 t
  50 connect
  51 by level<=>
  52 and prior str = str
  53 and prior sys_guid() is not null
  54                   ) t2
  55 on t1.str = t2.str
  56 and lower (t1.input_char) = lower (t2.str_char)
  order of 57
  58 by t1.str
  59         )
  Order 60
  61 by match_percnt desc
  62.

  STR MATCH_PERCNT STATUS
  ---------------- ------------ ---------
  A22 B12 SE MATCH 60
  a 234 R49 55.56 GAME nut
  156 65 a2 50 GAME hub
  ABC 89998 37.5 does NOT match
  AK 47 25 DOES NOT MATCH

  
  K98b Mauser 25 does NOT match
  Xbox 360 25 does NOT match

  7 selected lines.

  SQL >

• Stuck on a sql query to search for records that have the same parent child records

  Oracle 10 g 2 Enterprise Edition.
  
  Hello
  
  I'm writing a logic to find records in a parent table, who have the same values in a child table.
  This is part of a larger application, but I am stuck on that part for now, so I have mocked some of the below simplified tables to capture the heart of the
  the problem is that I'm stuck.
  Let's say I have a responsible parent, child employee table table and there are a number of many relationships between them.
  The aptly named Join_Table manages the relationship between them. If a manager can manage several employees, an employee can be managed by
  many managers.
  
  I have a feeling it's stupidly easy, but it seems to me having a bad episode of brain freeze today!

  -- parent table
  CREATE TABLE manager (
   id      number primary key,
   name      varchar2(100));
  
  -- child table 
  CREATE TABLE employee (
   id          number primary key,
   name      varchar2(100));
  
  -- link table
  CREATE TABLE join_table (
   manager_id          NUMBER, 
   employee_id      NUMBER,
   CONSTRAINT join_table_pk PRIMARY KEY (manager_id, employee_id),
   CONSTRAINT manager_fk FOREIGN KEY (manager_id) REFERENCES manager(id),
   CONSTRAINT employee_fk FOREIGN KEY (employee_id) REFERENCES employee(id) 
   );
  
  -- Insert some managers
  INSERT INTO manager (id, name) VALUES (1, 'John');
  INSERT INTO manager (id, name) VALUES (2, 'Bob');
  INSERT INTO manager (id, name) VALUES (3, 'Mary');
  INSERT INTO manager (id, name) VALUES (4, 'Sue');
  INSERT INTO manager (id, name) VALUES (5, 'Alan');
  INSERT INTO manager (id, name) VALUES (6, 'Mike');
  
  -- Insert some employees 
  INSERT INTO employee (id, name) VALUES (101, 'Paul');
  INSERT INTO employee (id, name) VALUES (102, 'Simon');
  INSERT INTO employee (id, name) VALUES (103, 'Ken');
  INSERT INTO employee (id, name) VALUES (104, 'Kevin');
  INSERT INTO employee (id, name) VALUES (105, 'Jack');
  INSERT INTO employee (id, name) VALUES (106, 'Jennifer');
  INSERT INTO employee (id, name) VALUES (107, 'Tim');
  
  -- Insert the links
  -- John manages Paul, Simon, Ken
  INSERT INTO join_table (manager_id, employee_id) VALUES (1, 101);
  INSERT INTO join_table (manager_id, employee_id) VALUES (1, 102);
  INSERT INTO join_table (manager_id, employee_id) VALUES (1, 103);
  -- Bob manages Paul, Simon, Kevin, Jack
  INSERT INTO join_table (manager_id, employee_id) VALUES (2, 101);
  INSERT INTO join_table (manager_id, employee_id) VALUES (2, 102);
  INSERT INTO join_table (manager_id, employee_id) VALUES (2, 104);
  INSERT INTO join_table (manager_id, employee_id) VALUES (2, 105);
  -- Mary manages Jennifer, Tim
  INSERT INTO join_table (manager_id, employee_id) VALUES (3, 106);
  INSERT INTO join_table (manager_id, employee_id) VALUES (3, 107);
  -- Sue manages Jennifer, Tim
  INSERT INTO join_table (manager_id, employee_id) VALUES (4, 106);
  INSERT INTO join_table (manager_id, employee_id) VALUES (4, 107);
  -- Alan manages Paul, Simon, Ken, Jennifer, Tim
  INSERT INTO join_table (manager_id, employee_id) VALUES (5, 101);
  INSERT INTO join_table (manager_id, employee_id) VALUES (5, 102);
  INSERT INTO join_table (manager_id, employee_id) VALUES (5, 103);
  INSERT INTO join_table (manager_id, employee_id) VALUES (5, 106);
  INSERT INTO join_table (manager_id, employee_id) VALUES (5, 107);
  -- Mike manages Paul, Simon, Ken
  INSERT INTO join_table (manager_id, employee_id) VALUES (6, 101);
  INSERT INTO join_table (manager_id, employee_id) VALUES (6, 102);
  INSERT INTO join_table (manager_id, employee_id) VALUES (6, 103);
  
  -- For sanity
  CREATE UNIQUE INDEX employee_name_uidx ON employee(name);

  If I ask for Manager John, so I want to find other managers who manage the exact list and even employees.
  Answer should be Mike.
  If I ask for Manager of Mary, the answer should be Sue.
  
  This query will give me the list of managers who manage some of the same employees as John, but not the same employees accurate...

  SELECT DISTINCT m.name AS manager
  FROM manager m, join_table jt, employee e
  WHERE m.id = jt.manager_id
  AND jt.employee_id = e.id
  AND e.id IN (
       SELECT e.id
       FROM manager m, join_table jt, employee e
       WHERE m.id = jt.manager_id
       AND jt.employee_id = e.id
       AND m.name = 'John')
  ORDER BY 1;

  I thought about using set operations to find managers with a list of employees less than my employees is null and where my employees under their list of employees is null. But there must be an easier way more elegant.
  Any ideas?
  BTW, I need to run as a batch on tables with > 20 million rows so the efficiency of queries is key.

  What about...

  WITH manager_list AS
  (
   SELECT name,
          LTRIM(MAX(SYS_CONNECT_BY_PATH(id,','))
          KEEP (DENSE_RANK LAST ORDER BY curr),',') AS employees
   FROM   (SELECT m.name,
                  e.id,
                  ROW_NUMBER() OVER (PARTITION BY m.name ORDER BY e.id) AS curr,
                  ROW_NUMBER() OVER (PARTITION BY m.name ORDER BY e.id) -1 AS prev
           FROM   manager m,
                  join_table jt,
                  employee e
    WHERE m.id           = jt.manager_id
    AND   jt.employee_id = e.id
    AND   m.name = :P_MANAGER)
    GROUP BY name
    CONNECT BY prev = PRIOR curr AND name = PRIOR name
    START WITH curr = 1
  ), all_list AS
  (
   SELECT name,
          LTRIM(MAX(SYS_CONNECT_BY_PATH(id,','))
          KEEP (DENSE_RANK LAST ORDER BY curr),',') AS employees
   FROM   (SELECT m.name,
                  e.id,
                  ROW_NUMBER() OVER (PARTITION BY m.name ORDER BY e.id) AS curr,
                  ROW_NUMBER() OVER (PARTITION BY m.name ORDER BY e.id) -1 AS prev
           FROM   manager m,
                  join_table jt,
                  employee e
    WHERE m.id           = jt.manager_id
    AND   jt.employee_id = e.id)
    GROUP BY name
    CONNECT BY prev = PRIOR curr AND name = PRIOR name
    START WITH curr = 1
  )
  SELECT a.*
  FROM   manager_list m,
         all_list a
  WHERE  m.employees = a.employees
  

  Would be easier in 11g, but I do not have a facility here so this is based on 10g.

  See you soon

  Ben

• Developer SQL does not start, crashes with loading screen, the Mavericks MAC

  I know not where to go from here, I have the JDK path worked I believe (see below).

  Open the start window, the blue bar goes to about 1/2 "and then it is just there and don't do anything.

  How can I debug this from here?

  I don't think that it is the JDK, I did the following and I see to open the log file that SqlDeveloper has the JDK files open.

  Ive done everything I have found to be relevant, everything that follows without success...

  • added SetJavaHome /Library/Java/JavaVirtualMachines/jdk1.7.0_51.jdk/Contents/Home to sqldeveloper_darwin.conf
  • added IncludeConfFile sqldeveloper - Darwin.conf to sqldeveloper.conf
  • added (link)

  function setjdk() {}

  If [$#-don't 0]; then

  removeFromPath ' / System/Library/Frameworks/JavaVM.framework/Home/bin'

  If [n ' ${JAVA_HOME + x} "]; then

  removeFromPath $JAVA_HOME

  FI

  Export JAVA_HOME ='/ usr/libexec/java_home - v $@ '

  export PATH = $JAVA_HOME/bin: $PATH

  FI

  }

  function removeFromPath() {}

  export PATH = $(echo $PATH | sed-E-e « s;: $1; ") -e"s; $1 : ? ; ")

  }

  setjdk 1.7

  in. / added to bash_profile

  I downloaded the previous version 4.0.0.13 Version and it works without any problem.

  I'll wait until the next version comes out and try it.

  Thank you

• SQL or PL/SQL-&gt; check a grouping of several criteria in the same group.

  Hello
  
  Oracle 11g. I need to check a set of data for multiple filtering criteria together. If the criterion is found, the FLAG_SET is updated.
  
  The example data:
  

  MEMBER     |     GROUPING             |     CODES     |     ROW_NUMBER     |     FLAG_SET
  001          |     1               |     A          |     45               |     0
  001          |     1               |     B          |     48               |     0
  002          |     1               |     C          |     45               |     0
  002          |     1               |     C          |     49               |     0
  002          |     1               |     A          |     52               |     0
  002          |     2               |     A          |     43               |     0
  002          |     2               |     B          |     62               |     0
  002          |     2               |     B          |     63               |     0
  003          |     1               |     A          |     72               |     0
  003          |     1               |     B          |     76               |     0

  My requirement is to test if a MEMBER within a GROUPING has an 'A' and 'B' (although there are several criteria to test on for example.) "C" and had "and they are prioritized. I would test a game both in a called proc).
  
  I need the following output:

  MEMBER     |     GROUPING             |     CODES     |     ROW_NUMBER     |     FLAG_SET
  001          |     1               |     A          |     45               |     1
  001          |     1               |     B          |     48               |     1
  002          |     1               |     C          |     45               |     0
  002          |     1               |     C          |     49               |     0
  002          |     1               |     A          |     52               |     0
  002          |     2               |     A          |     43               |     1
  002          |     2               |     B          |     62               |     1
  002          |     2               |     B          |     63               |     1
  003          |     1               |     A          |     72               |     0
  003          |     1               |     C          |     76               |     0

  I can't just update the indicators if a single 'A' CODE is found. He must have the 'A' and 'B '.
  I tried several ways, most recently LISTAGG put all grouped values of each line and the string for CODE analysis, I lose the ROW_NUMBER when this happens but it cannot be part of the coiled LISTAGG.
  
  Someone at - it ideas?
  
  Published by: chris001 on November 28, 2012 13:33

  Hello

  You can do it with a MERGE, something like statement:

  MERGE INTO table_x     dst
  USING   (
           SELECT    mmbr     -- MEMBER is an Oracle keyword
           ,           grpng     -- GROUPING is an Oracle keyword, too
           ,           CASE
                          WHEN  COUNT ( DISTINCT CASE
                                                WHEN codes IN ('A', 'B')
                                     THEN codes
                                    END
                            ) = 2
                   THEN  1
            --       WHEN  ...
            --       THEN  2
            --       WHEN  ...
                   ELSE  0
                      END
           FROM      table_x
           GROUP BY  mmbr
           ,           grping
       )          src
  ON     (   src.mmbr       = dst.mmbr
       AND src.grpng       = dst.grpng
       )
  WHEN MATCHED THEN UPDATE
  SET     dst.flag_set     = src.flag_set
  WHERE     dst.flag_set   != src.flag_set
  ;
  

  According to your needs.
  If you would care to post CREATE TABLE and INSERT to your sample data (as it exists before the changes), then I could test this.

  You have not need PL/SQL for this, but, if you need to do it in PL/SQL for some reason, you can.

  I hope that answers your question.
  If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and also publish outcomes from these data.
  If you ask on a DML statement, such as UPDATE, the sample data will be the content of the or the tables before the DML, and the results will be the State of the or the tables changed when it's all over.
  Explain, using specific examples, how you get these results from these data.
  Always say what version of Oracle you are using (for example, 11.2.0.2.0).
  See the FAQ forum {message identifier: = 9360002}

  Published by: Frank Kulash on November 28, 2012 16:53

• pl/sql profiler - data not listed is not in the Profiler tables?

  Hi all - just have a little problem with the pl/sql Profiler.
  

  Database Version: Oracle Database 10g Enterprise Edition Release 10.2.0.5.0 - 64bi
  Database Version: PL/SQL Release 10.2.0.5.0 - Production

  I created a test procedure:
  SQL > create or replace procedure testme
  2 as
  3
  number of v_customer_count 4;
  t_number v_level_table 5;
  Number 6 v_std_code_id;
  7
  Start 8
  9
  10. select count (*)
  11 in v_customer_count
  12 customer_master;
  13
  14 select level
  collection in bulk 15
  16 in v_level_table
  17 of the double
  18 connection of level < = 5000;
  19
  20
  21 end;
  22.
  
  Created procedure.
  
  
  and I run the procedure as follows:
  

  SQL> declare
    2     run_id number;
    3  begin
    4  
    5    run_id := dbms_profiler.start_profiler(to_char(sysdate,'dd-mm-yyyy hh24:mi:ss'));
    6    
    7    testme;
    8    
    9    dbms_profiler.flush_data;
   10    dbms_profiler.stop_profiler;
   11  
   12    dbms_output.put_line(run_id);
   13  
   14  end;
   15  /
  2
  
  PL/SQL procedure successfully completed.
  
  Elapsed: 00:00:00.08

  but:
  

  SQL> select * from sys.plsql_profiler_runs
    2  /
  
  no rows selected
  
  Elapsed: 00:00:00.00
  SQL> select * from sys.plsql_profiler_data;
  
  no rows selected

  What Miss me?

  Run proftab.sql in your schema, also compile in debug mode before the race.

• Since the update yesterday that my fire ftp no longer works correctly, it's the same on 3 different computers

  After firefox updated yesterday when I opened a site, the files are there when I opened a folder to change them they are ok as soon as I go back and pull a file I get link icons and can not open or modify anything. When I sign out and close firefox and re do it start its ok until I open any folder icons link back. Any ideas?

  Try to update the FireFTP extension on 2.0.10

  https://addons.Mozilla.org/en-us/Firefox/addon/FireFTP/

• File name too Long to be copied to the same location on Different drive

  I have Vista 32 bit. I know the limits of length of file name.

  In my computer, I have a USB 2.0 hard drive, called 'J '. I have a Freecom 3 TB hard which the manual says is shown as 2 partitions for compatibility issues. It appears therefore as a partition 'K' and 'L '.

  I have a lot of music on my drive J, located in several subfolders. Number of files have reached the limit on the length of file name. TeraCopy using I'm just copy everything in the root of the drive of J in the root of my partition to 'L '.

  Out of thousands of files, 445 of them were not copied. I don't know the reason, but I guess that this is due to the limits of length of filename which is strange, because if the files are already on the J drive why can't they be copied to the partition of L? It's not like I'm adding a new folder in the partition of L, then put everything in there, I put everything in the root.

  TeraCopy is a button that allows you to see why the files were not copied. However it freezes if clicked, because there are so many files - it works when much less files are copied. I guess they were not copied because of file size limits.

  Hello

  You can check out the following link and check the advice given by jmhonzell on Thursday, September 3, 2009 16:28 and see if it helps:

  http://social.technet.Microsoft.com/forums/en-us/w7itprogeneral/thread/53779044-D453-458b-B8C4-96d41711ea69/

  Also see the answers and the answer in the link and check it out.
  http://social.technet.Microsoft.com/forums/en-us/windowssteadystate/thread/2186fd6f-4CE9-420D-A44B-0de9fa5e431c

• I can no longer print Quicken reports using the same program for the past five years

  I have used Quicken for years (same version of Quicken and Windows 7 and has never had a year problem print end reports so far.)  Why

  You must support Quicken community.

• you are looking for the same contact again and again

  Hello.

  Sorry if I missed something so trivial that could invalidate this question, but - well I missed it.

  My application constantly seeking the same Contact in the contacts list.

  Is there a better way to find a contact-> o (1) than to go thorugh the entire list-> o (n)?

  A kind of index? or a search option advanced that I supervised?

  I usually add a contact and after some time, I need to access once more.

  Sometimes it is in the same application runs, it is not

  Thank you

  The method described in the thread you cite is the recommended approach.

  With regard to the adequacy between the last phone number, you can search based on the last 4 digits and then perform a string match more in detail of the results in your application.

• I installed the last 7.2.2 (33) pre update pro but my user interface still looks like the same thing?

  He said I have the upgrade, but nothing has changed in my user interface.  I did something wrong?

  Do you think the new version in the help | On?