display the data in a row and different columns in the listbox

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• Several lines in a row with different column name

  Hello
  I have the table "v_Profile_ID" and "v_Trasaction".
  
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  KPR

  * If it's OK... then do as correct
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  Published by: KPR on April 29, 2011 04:53

• SQL to convert a row with 4 columns, 4 rows by 4 columns

  With the help of Frank Kulash yesterday (https://community.oracle.com/thread/3810284)

  I can now use UNPIVOT start with this:

  with tbl_data AS  
   (select 'N' argument1, 'Y' argument2, NULL argument3, 'Y' argument4 from dual)  
  select * from tbl_data;  
  
  
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  I was wondering if there are sort of Frank solution can be modified to include the 2 columns (for example, COL_SEQ and COL_PROMPT) with them, hard coded values for example, '1' for the SEQ and 'TEST' for the GUEST, as I have the solution to a Frank's UNION with another query that returns the 4 columns.

  i.e. the performance:

  COL_NAME  COL_HEADING COL_SEQ     COL_PROMPT
  --------- ----------- ----------- -----------
  ARGUMENT1 N           1           TEST
  ARGUMENT2 Y           1           TEST
  ARGUMENT3             1           TEST
  ARGUMENT4 Y           1           TEST
  

  Thank you

  Hello

  969483 wrote:

  With the help of Frank Kulash yesterday (https://community.oracle.com/thread/3810284)

  I can now use UNPIVOT start with this:

  1. with tbl_data AS
  2. (select "n" argument1, argument2 'Y', NULL argument3, 'Y' double argument4)
  3. Select * from tbl_data;
  4. ARGUMENT1 ARGUMENT2, ARGUMENT3 ARGUMENT4
  5. --------- --------- --------- ---------
  6. N         Y                   Y

  And eventually conversion of a single line of output to 4 rows and 2 columns via:

  1. with tbl_data AS
  2. (select "n" argument1, argument2 'Y', NULL argument3, 'Y' double argument4)
  3. SELECT *.
  4. OF tbl_data
  5. MUST INCLUDE NULL VALUES
  6. (col_heading
  7. FOR column-name IN (argument1
  8. argument2
  9. argument3
  10. argument4
  11. )
  12. );
  13. COLUMN COL_HEADING
  14. --------- -----------
  15. ARGUMENT1 N
  16. ARGUMENT2 Y
  17. ARGUMENT3
  18. ARGUMENT4 Y

  I was wondering if there are sort of Frank solution can be modified to include the 2 columns (for example, COL_SEQ and COL_PROMPT) with them, hard coded values for example, '1' for the SEQ and 'TEST' for the GUEST, as I have the solution to a Frank's UNION with another query that returns the 4 columns.

  i.e. the performance:

  1. COLUMN COL_HEADING COL_SEQ COL_PROMPT
  2. --------- ----------- ----------- -----------
  3. ARGUMENT1 N 1 TEST
  4. ARGUMENT2 Y 1 TEST
  5. ARGUMENT3 1 TEST
  6. ARGUMENT4 Y 1 TEST

  Thank you

  Of course, you can include constants hardcoded in any set of results; just put constants in the SELECT clause and assign aliases for columns.

  Don't forget, I havef you need anything in the more SELECT clause *, then * must be qualified with a table name or alias, so that in this case, you can do something like:

  SELECT d. *.

  1 AS col_seq

  'TEST' AS col_prompt

  OF tbl_data

  MUST INCLUDE NULL VALUES

  (col_heading

  FOR column-name IN (argument1

  argument2

  argument3

  argument4

  )

  )  d

  ;

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  JDeveloper 12.1.3.0.0

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• Display the name of the tag as the column name and the value in the tag as a row of data from the input string.

  Hi Forum members,

  I am looking for a query display the name of the tag as the column name and the value in the tag as a row of data.

  I have to print the values within the tag to a file by choosing the value of the flags. the sequence of the tags will vary each time, as the tag name will change dynamically.

  So here is the example of input data and the expected output. The string in the text column must be separated as the column names and values.

  Input data
  Select 1 as seqno,' < > 0210A 50 4f < / 4f > < 5f20 > TEST CARD 16 < / 5f20 > < 5f2a > < / 5f2a > < 82 > 1 c 00 < / 82 > ' double text

  
  Output:

  Seqno 4f 5f20 5f2a 82
  0210A 50 16 1 00 TEST CARD 1

  Please help me by providing your entries on this.

  We use the version of Oracle 11.2.

  Note: This is not the XML string

  Thank you

  Shree

  with

  data in the form of

  (select 1 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2a><82>00 1' text of all the double union)

  Select 2 as seqno,'XYZ<4F>0210 A 50<5f20>TEST CARD 16<5f2a><82>00 1' text of all the double union

  Select 3 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2A><82>1 00XYZ ' text of all the double union

  Select option 4 as seqno,'<4F>0210 A 50<5F20>TEST CARD 16<5f2A><82>1 00XYZ' double text

  )

  Select d.seqno, x.*

  d the data,

  XMLTable ('/ root')

  by the way xmltransform (xmltype ('': replace (replace (text,'<><>'),)))

  XmlType (q'~http://www.w3.org/1999/XSL/Transform "version ="1.0"> ")

                                                   

                                                     

                                                       

                                                     

                                                   

                                                   

                                                     

                                                       

                                                     

                                                   

  ~'

  )

  )

  path of columns '4f' varchar2 (10) "tag4f."

  path of "5f20' varchar2 (30)"tag5f20. "

  path of '5f2a' varchar2 (10) "tag5f2a."

  path of varchar2 (10) "82" "tag82.

  ) x

  
  

  SEQNO	4f	5f20	5f2a	82
  1	0210A 50	16 TEST CARD	-	1 00
  2	0210A 50	16 TEST CARD	-	1 00
  3	0210A 50	16 TEST CARD	-	1 00
  4	0210A 50	16 TEST CARD	-	1 00

  with

  data in the form of

  (select 1 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2a><82>00 1' text of all the double union)

  Select 2 as seqno,'XYZ<4F>0210 A 50<5f20>TEST CARD 16<5f2a><82>00 1' text of all the double union

  Select 3 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2A><82>1 00XYZ ' text of all the double union

  Select option 4 as seqno,'<4F>0210 A 50<5F20>TEST CARD 16<5f2A><82>1 00XYZ' double text

  ),

  Chopper (seqno, Key, value, String) as

  (select seqno,

  regexp_substr (text,'<(.+?)>', 1, 1, null, 1),

  regexp_substr (Text,'>(.*?))

  regexp_substr (text,'<.+?>. *? ) (.*) $', 1, 1, null, 1). » <>'

  from the data

  Union of all the

  Select seqno,

  regexp_substr (String,'<(.+?)>', 1, 1, null, 1),

  regexp_substr (String,'>(.*?))

  regexp_substr (String,'<.+?>. *? ) (.*) $', 1, 1, null, 1)

  Chopper

  where regexp_substr (string,'<(.*?)>', 1, 1, null, 1) is not null

  )

  Select '4f', seqno, '5f2a', '82', '5f20.

  of (seqno, lower (key) select key, value)

  Chopper

  )

  Pivot (max (value) for key in ('4f' as '4f', '5f20' as '5f20', '5f2a' as '5f2a', "82" as "82"))

  Concerning

  Etbin
  

• How to display rows of data in different columns?

  I'm new to SQL and currently, that's what I try to do:

  Display multiple lines of data in different columns in the same row

  I have a table like this:

  CREATE TABLE TRIPLEG)

  T # NUMBER (10) NOT NULL,

  STEP # NUMBER (2) NOT NULL,

  DEPARTURE VARCHAR (30) NOT NULL,

  VARCHAR (30) DESTINATION NOT NULL,.

  CONSTRAINT TRIPLEG_PKEY PRIMARY KEY (T #, LEG #).

  TRIPLEG_UNIQUE UNIQUE CONSTRAINT (T #, DEPARTURE, DESTINATION).

  CONSTRAINT TRIPLEG_FKEY1 FOREIGN KEY (T #) REFERENCES TRIP(T#));

  INSERT INTO TRIPLEG VALUES (1, 1, 'Sydney', 'Melbourne');

  INSERT INTO TRIPLEG VALUES (1, 2, 'Melbourne', 'Adélaïde');

  The result should be something like this:

  > T # | ORIGIN | DESTINATION1 |  DESTINATION2

  > 1 | SYDNEY | MELBORUNE | ADELAIDE

  The request must include the ' COUNT(T#) < 3' since I only need to display the records of less than 3. How can I get the results I want to use relational views?

  Thank you!!!

  I replaced the syntax "where" with the syntax 'account '. The reason why I do this is because I want to only display records with a number of travel of less than 3. By defining where the legs #.<=3, the="" result="" will="" be="" all="" the="" records="" of="" the="" tripleg="" table="" since="" each="" record="" could="" also="" have="" leg#="" is="">

  The answer is:

  with t as (SELECT t #,)

  REGEXP_REPLACE)

  LISTAGG (start |) '->' || destination, ' ')

  THE Group (ORDER BY t #, leg #).

  '([^ ]+) \1+',

  "\1") str

  OF tripleg

  HAVING COUNT (T #)<>

  GROUP BY t #)

  Select T #, regexp_substr (str, ' [^->] +', 1, 1) departure

  , regexp_substr (str, ' [^->] +', 1, 2) destination_1

  , regexp_substr (str, ' [^->] +' 1, 3) destination_2

  , regexp_substr (str, ' [^->] +' 1, 4) destination_3

  Thanks to Marty and knani!