double quotes in query

Similar Questions

• Parse qualified double quote delimited strings

  Hi all
  
  I have a few strings of data that I get I want to analyze. My problem is that I am not able to understand how I can analyze the fields that are double quote qualified ("19 999")?
  
  I played with the regex_substr, but I can't quite make what I want.
  
  I want to analyze the myString column in my example below in four areas:
  Product
  OnOrder
  OnHand
  TotalSold
  
  Here is an example... I've been playing with it for a bit, and I can't get it.
  

  WITH parseString AS (Select 
                          '"Grado, Headphones",123,2222,"19,999" ' myString
                       from dual
                       UNION ALL
                       Select 
                          'Audio Slave,222,3333,444' myString
                       from dual
                       
                                  )
  Select 
      myString
  from parseString

  Oracle Database 10 g Enterprise Edition release 10.2.0.3.0 - 64bi
  PL/SQL version 10.2.0.3.0 - Production
  CORE Production 10.2.0.3.0
  AMT for Linux: release 10.2.0.3.0 - Production
  NLSRTL Version 10.2.0.3.0 - Production
  
  
  Any suggestions greatly appreciated.
  
  S
  
  Published by: ScarpacciOne on April 22, 2010 15:24

  Hello

  As Centinul said, it would help a lot if you have published your desired results and explains how get you from the sample data.
  Here's something that can help, according to your specific needs:

  WITH     got_item_cnt     AS
  (
       SELECT     myString
       ,     1 + LENGTH (myString)
              - LENGTH (REPLACE (myString, ','))     AS item_cnt
       FROM     parsestring
  )
  ,     cntr     AS
  (
       SELECT     LEVEL     AS n
       FROM     dual
       CONNECT BY     LEVEL <= ( SELECT  MAX (item_cnt)
                         FROM    got_item_cnt
                       )
  )
  ,     comma_separated_values     AS
  (
       SELECT     i.myString
       ,     c.n
       ,     REGEXP_SUBSTR ( i.myString
                       , '[^,]+'
                       , 1
                       , c.n
                       )          AS value
       FROM     got_item_cnt     i
       JOIN     cntr          c     ON     c.n     <= i.item_cnt
  )
  ,     got_quote_cnt     AS
  (
       SELECT     myString
       ,     n
       ,     REPLACE (value, '"')     AS value
       ,     NVL ( SUM ( LENGTH (value)
                   - LENGTH (REPLACE (value, '"'))
                   ) OVER ( PARTITION BY  myString
                         ORDER BY      n
                         ROWS BETWEEN  UNBOUNDED PRECEDING
                           AND      1        PRECEDING
                          )
                , 0
                )          AS quote_cnt
       FROM     comma_separated_values
  )
  SELECT     myString
  ,     n
  ,     LTRIM ( SYS_CONNECT_BY_PATH (value, ',')
             , ','
             )          AS token
  FROM     got_quote_cnt
  WHERE     CONNECT_BY_ISLEAF     = 1
  START WITH     MOD (quote_cnt, 2)     = 0
  CONNECT BY     MOD (quote_cnt, 2)     = 1
       AND     myString     = PRIOR myString
       AND     n          = PRIOR n + 1
  ORDER BY     myString,     n
  ;
  

  Output of your sample data:

  MYSTRING                                N TOKEN
  -------------------------------------- -- --------------------
  "Grado, Headphones",123,2222,"19,999"   2 Grado, Headphones
  "Grado, Headphones",123,2222,"19,999"   3 123
  "Grado, Headphones",123,2222,"19,999"   4 2222
  "Grado, Headphones",123,2222,"19,999"   6 19,999
  Audio Slave,222,3333,444                1 Audio Slave
  Audio Slave,222,3333,444                2 222
  Audio Slave,222,3333,444                3 3333
  Audio Slave,222,3333,444                4 444
  

  The basic strategy is to divide myString to all the commas, then re - unite consecutive elements that are in double - quotes.
  You never said what version of Oracle are you uisng.
  This solution works in Oracle 10.1. REGEXP_COUNT, introduced in Oracle 11.1, would make it a bit simpler.

  Here is each subquery:
  got_item_count finds the number of elements by commas in each myString
  CNTR generates integers 1, 2, 3,... until the maximum number of elements by commas on line any
  comma_separated_values myString splits its different elements, ignoring the quotes at the moment. I assumed myString is unique. If this isn't the case, you need some other unique identifier for each row of parsestring.
  * quote_cnt had "notes how quotes took place in myString, each element not included.  If (and only if) this number is odd, then the element is really a continuation of a previous item, in other words, the comma that separates this point from the previous one was within quotation marks and therefore should not have divided myString.  I assumed that the double-quote character always indicates the grouping; It is never to be taken literally, and therefore the final results will never contain quotes.
  The main query string aggregation on consecutive points, bringing together all the elements that are weird quote_cnts with the last item previous had a same quote_cnt.

  Published by: Frank Kulash, 22 April 2010 23:33

• replace a single quote with the double quotes with the function replace

  I work with one apex page, which contains a text as a filter box. If I put a single quote and find then I get the error message saying that parse error.
  
  For this, I want to replace one single quotation mark with double quotes, so this should be perfect. and apex should show the result.
  
  A allow the query to the same which will replace the single quote with double quotes.
  
  Published by: Santhosh Kumar T 15 Sep 2008 05:13

  If it was confusing... Try the less confusion (according to you)! ...

  Select Replace ("ab" | ") "|' it," ',' "') twice;"

• OPA-E00111 (unable to use double quotes)

  I am trying to use a table to decide on the error messages for the different scenarios. as

  Header 1
  the error message

  "it cannot display the page" (conclusion).                                    the url is not valid (condition)

  Here, if I use double quotes as 'page 'cannot' see' throw up error

  whenever he tries to use double quotes inside the outcome, it throws an error OPA-E00111.

  can someone help me.

  Thanks in advance

  You must precede the quotation by the backslash character:

  

  See http://docs.oracle.com/html/E64009_01/toc.htm#Variables%20and%20constant%20values/Use_constant_values_in_rules.htm?Highlight=backslash

• Fields Publisher report with output .csv just double quotes. How we prevent it?

  Hi all

  If we create any report Publisher and you try to view or download .csv format, fields that have data with more than one word just double quotes. If data have one word, she comes out with proposals and seems correct.

  If we look in excel or data XML seems good with on proposals and did not observe this behavior.

  Version: 11.1.1.5

  Steps to reproduce:

  
  

  1 create a model of simple data in select * from scott.dept

  2. create a blank layout and a report to display the data.

  Note: Varchar Fields so has more than one word, it is another to one word in quotes it look ok.

  Sample:

  DEPTNO, DNAME, LOC

  10, ACCOUNTING,"NEW YORK"

  20, RESEARCH, DALLAS

  30, SALES, CHICAGO

  40, OPERATIONS, BOSTON

  Let know if anything missed on my side. Pointers or suggestions would be appreciated.

  Hi all, just re-collected has nothing to do with OBIEE. By default, .csv apply quotes on all fields with special characters or spaces according to its characteristics. Since this is a valid scenario from the point of view OBIEE too, I have to use scripts to remove the quotation marks. Because my data do not have quotes, I remove all citations of my reports after being delivered. Using command on my unix below box and wrote a script based on my needs and expected. $sed-i of / ' / / g' Report1.csv thank you Kiss.

• Regular expression, replace all commas between double quotes ONLY

  Hello

  I want to remove all commas between double quotes:

  I tried under model, but it does not replace all if we have more than one comma in double quotes.

  SELECT REGEXP_REPLACE (123, "45.6" Hello, "John, Mike, Marc", 456, "-Anne, Anna"', ' "([^"]*),([^"]*)" ', '"\1;\2" ', 1, 0) suite

  FROM DUAL;

  Result

  --------------------------------------------------------------------------

  123, '45; 6"," Hello, "John, Mike;" "Marc", 456, "Anne-; Anna.

  the first comma between 'John, Mike; Marc"is not replaced...

  Recursion can do if you insist on the SQL solution

  with

  correct (INP, orig, CNT, res, Step) as

  (select str,

  substr(STR,2),

  -case when substr (str, 1, 1) = ""' then 1 else 0 end,

  substr (STR, 1, 1),

  1

  of (select 123, '45.6,' Hello, ' John, Mike, Marc ", 456, '-Anne, Anna', 'single_value' ' str of union double all the)

  Select "123456789" across double Union

  Select ' ""' of all the double union

  Select "" 123,456,789"" Union double all the

  Choose 123, '45.6,' Hello, ' John, Mike, Marc ", 456, 'Ann-Marie, Anna', 'unique value' ' double str

  )

  Union of all the

  Select the inp

  substr(orig,2),

  CNT + case when substr (orig, 1, 1) = ""' then 1 else 0 end,

  RES | cases where substr (orig, 1, 1) = ','

  so to case when mod(cnt,2) = 1

  then ' ~'

  else «»

  end

  of another substr (orig, 1, 1)

  end,

  Step + 1

  Rectifier

  where orig is not null

  )

  Select the inp, res

  Rectifier

  where the orig is null

  INP	RES
  ""	""
  123456789	123456789
  "123456789".	"123 ~ 456 ~ 789".
  123, '45.6' Hello, ' John, Mike, Marc ", 456, '-Anne, Anna', 'single_value '.	"123," "45 ~ 6 ', Hello," John ~ Mike ~ Marc ", 456," Anne-~ Anna ',' single_value '.
  123, '45.6' Hello, ' John, Mike, Marc ", 456,"Ann-Marie, Anna","unique value ".	"123," "45 ~ 6 ', Hello," John ~ Mike ~ ~ ~ Marc ', 456,' Anne-Marie ~ Anna "," unique value ".

  Concerning

  Etbin

• REGEXP_REPLACE remove the comma in double quotes

  Hello

  I am trying to remove the comma of a string in double quotes, currently I can only remove a comma using under sql

  SELECT REGEXP_REPLACE (' "" A, B, C, def "', '(") ([^ "|,"] +) (,) ([^ ""] +) ("") ',' \1\2 \4\5' ') FROM DUAL;

  output: 'A B, C, def'

  But I need the form "A B C def".

  Hello

  Jarkko Turpeinen wrote:

  ... I think that I stop to answer here, because I don't understand of course questions

  Very understandable.  If my assumption is correct, the question would be much clearer if OP gave an example that included a few commas inside the quotation marks and some outside, as in the example below.

  Here's a way to implement what I have described in the answer #2 above:

  VARIABLE input_txt VARCHAR2 (100)

  EXEC: input_txt: = 1, '2', ' A, B, C, def ", 3" foo, bar '4 ';

  WITH got_parts AS

  (

  SELECT LEVEL AS part_num

  , REGEXP_SUBSTR (: input_txt)

  , '[^"]*("|$)'

  1

  LEVEL

  ) AS part_txt

  OF the double

  CONNECT BY LEVEL<= 1="" +="" regexp_count="" (="">

  , '"'

  )

  )

  SELECT LISTAGG (CASE

  WHEN MOD (part_num, 2) = 0

  THEN REPLACE (part_txt, ',')

  Of OTHER part_txt

  END

  ) Within AS output_txt GROUP (ORDER BY part_num)

  OF got_parts

  ;

• Limit the Total number of characters between double Quotes using Oracle 11 g PL/SQL

  Hello

  I need a way to apply a limit of 32 substring for each group of data inside double quotes, with Oracle 11 g PL/SQL.

  Essentially using the following example string that much for me, I have no control of how this string is built:

  str := ‘"AAAAAAA BBBBBBB CCCCCCC DDDDDD1","AAAAAAA BBBBBBB CCCCCCC DDDD",”QWERTY”,”N1N1N1N1N1N1N1N1N1N1N1N1N1N1N1N1N1N1”’;

  I need to go through each group of values between each double quote, for example ("QWERTY") and apply a substring of 32 to each group found.

  So, using the example above of the chain, it's as if I need to do the following:

  str := ‘"substr(‘AAAAAAA BBBBBBB CCCCCCC DDDDDD1’,1,32)","substr(‘AAAAAAA BBBBBBB CCCCCCC DDDD’,1,32)",”substr(‘QWERTY’,1,32)”,”substr(‘N1N1N1N1N1N1N1N1N1N1N1N1N1N1N1N1N1N1’,1,32)”’;

  So in the end, my final result for the str would be composed of four groups where the length of each grouping is less than or equal to 32.

  Any help would be great.

  Thank you.

  Try this (replace with your actual table):

  with the temp as

  (

  SELECT substr (REGEXP_SUBSTR (str,'[^,] +', 1, LEVEL) 1, 32) r

  OF THE TEST

  connect IN REGEXP_SUBSTR(str, '[^,]+', 1, LEVEL) IS NOT NULL

  )

  Select replace (listagg (r, '"," ') in the Group (order by null),' ' "','" ' ")

  temp

  output:

  "VIEN BBBBBBB CASTILLO DDDD", "VIEN BBBBBBB CASTILLO DDDDDD1", "N1N1N1N1N1N1N1N1N1N1N1N1N1N1N1N", "QWERTY".

• Double quotes in FILE SET LINE UTL

  My program writes the data in the CSV file in function below.

  Varial buffer is assigned

  buffer: = A | ','|| B;

  And, the output file contains, lets say, as below

  Apple, boy

  Now let's say that this requirement is to write the value b in double quote,

  Apple, 'Boy '.

  How do I get there?

  Thank you in advance,

  Srini

  Try the below

  buffer: = A | ','|| CHR (34) | B | CHR (34);

• ODI to Essase Metadata - formula with double quote error.

  Hi all
  
  We update Essbase Metadata ODI. We have sql table where all requirements of columns for metadata download is here.
  
  The formula is to have "quotes" in the formula column.
  
  When he get transferred to Essbase. The double quotes are not getting updated and so the formula is seen as loaded error formula.
  
  So how do you remedy this? Please suggest.
  
  Thank you
  Alex keny.

  "' Try to use something like -" formula or member name \ ".

  See you soon

  John
  http://John-Goodwin.blogspot.com/

• remove the double quotes in a value

  DB version: 10g / 11g
  
  Table customer_address
  column: adresse_rue
  data in the example: 'MLK 1234 drive '.
  'dr North 150, st #600'
  'o Henry 15678 dr.
  
  Update: reader of MLK 1234
  150 north dr, st #600
  Dr. Henry o 15678
  
  I'm looking to remove the double quotes (""), if this is the first and the last character.
  
  It would be nice to get these lines with values begins and ends with double-quotes
  
  
  Thank you for your time
  
  Published by: nydba on March 22, 2012 09:02

  One way:

  with a as (select '"1234 MLK drive"' x from dual
             union select '5678 JFK drive' from dual)
  select a.*,substr(x,2,length(x)-2) from a
  where x like '"%"';
  
  X                SUBSTR(X,2,LENGTH(X)-2)
  ---------------- -----------------------
  "1234 MLK drive" 1234 MLK drive        
  

  There is probably a more efficient way with regular expressions.

• OMB + how to insert single and double quotes in an expression?

  I'm doing the following command of OMBALTER to work:
  
  [MAPPING OMBALTER '$Mapping' CHANGE the ATTRIBUTE '$Attribute' of THE GROUP '$Group' OPERATOR '$Operator' SET the PROPERTIES (EXPRESSION) VALUES ('replace(get_model_name,'"')')]
  
  I can't find the right escape sequence for the part of values.
  
  I want to insert. > replace (get_modul_name, {apostrophe} {quote} {apostrophe}) <.
  
  Pointers?
  
  Best regards, John

  Hi John

  So within a chain in tcl "Hello world, how are you?" you must use the double apostrophe to get an apostrophe;
  "Hello World"' how are you?

  Double quotes can only be added as is;
  ' hello "world" how are you?

  See you soon
  David

• Problem with the removal of the double quotes in my channel

  Hi all
  
  I am trying to replace two double quotes in my thong in double apostrophe.
  
  < v21:ID schemeAgencyID = "" NGCRM"" >
  
  
  I need to convert it to < v21:ID schemeAgencyID = "NGCRM" >
  
  
  For that, I use my code as below.
  
  Input=input.replace("\"\"","\" ");
  
  but there is no change in the output.
  
  Kindly tell me the error in the present.
  
  
  
  Thank you
  Sabarisri. N
  
  Published by: N Sabarisri August 1, 2011 12:20

  Sabarisri N wrote:
  Hi all

  I am trying to replace two double quotes in my thong in double apostrophe.

  I need to convert it to

  For that, I use my code as below.

  Input=input.replace("\"\"","\" ");

  but there is no change in the output.

  Kindly tell me the error in the present.

  Thank you
  Sabarisri. N

  Published by: N Sabarisri August 1, 2011 12:20

  It'll work. Here is the test program

  class StringReplaceTest
  {
       public static void main(String st[])
       {
            String st1 = "";
            System.out.println(" The st1 : "+st1);
            System.out.println(" The out put is : "+st1.replace("\"\"","\""));
  
       }
  }
  

  replace the text makes the sequence checking and replaceAll of character against the regex mill.

• Double quotes in ASO cube formula Member UDA

  I have double-quotes in ASO MDX UDA.
  But when loading using the rules, the quotes file double are get deleted.
  Any suggestion how to fix this problem?
  
  Formula in file dim biuld
  --------------------------------------------------------------------------------------
  CASE
  WHEN (NO ISUDA ([scenario]. CurrentMember, 'VARSCN'))
  THEN ([CRNBS] / [CLRVT]) * 100
  END
  
  
  After dimbuild formula in become a Member
  --------------------------------------------------------------------------------------
  
  CASE
  WHEN (NO ISUDA ([scenario]. CurrentMember, VARSCN))
  THEN [589018] + [MGTI_EXC_AFF] + [GIT_ALLOC_PUR]
  END
  
  
  
  It is simple to remove the quotes on UDA VARSCN
  
  
  Thank you

  You need an escape character before each quote so that it can be passed through that the escape character is a backslash if your code should look like \"UDA\"

• Double quotes in vars sub

  The following comand strives to define a substitution variable that keeps the double quotes.
  
  change the FinRptg.FinRptg database variable value CurFcstYr1 ' '2011 "";
  
  If the variable is "2011".
  
  What I want to do is the same thing, but using a variable. However, when I use the command:
  
  change the database to the CurFcstYr1 the FinRptg.FinRptg value variable ""$3 ";
  
  The variable is set to "$3".
  
  Is there a way I can set the variable substitution using the variable I pass in the MaxL script and have the double quotes. The reason why I'm doing this is because the report script that uses the subvar must double quotes, or he does not see the year.
  
  Thank you.

  Reading of:- Re: Maxl variable def with quotes
  It should give you the answer on how to do it.

  See you soon

  John
  http://John-Goodwin.blogspot.com/