EPMA deployment hangs - last recorded entry sysout references deleted member
Hi, we are on 11.1.1.3 and using EPMA to a planning application.We have removed a level 0 entity member. Now, we can get EPMA to deploy on essbase/planning. We have disabled create and update outline boxes in an attempt to simply update the planning and it still does not work.
The last entry recorded in the file sysout EPMA member references that deleted us. The deployment takes normally 2 to 3 minutes.
There are no entries in the planning pending_xacts table.
How can we determine what is the problem and how to solve?
Thank you
Jeff
pending_xacts is no longer used, I think it has been used last 9.2
Is a process of active workflow, this can generally cause a problem if you try to remove a member from the entity that is part of a workflow process, the system may hang.
If it's a question of workflow, then stop the workflow and remove the Member.
See you soon
John
http://John-Goodwin.blogspot.com/
Tags: Business Intelligence
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/* Formatted on 2009/04/29 11:52 (Formatter Plus v4.8.7) */ SET serveroutput ON SIZE 1000000 FORMAT WRAPPED SET verify OFF SET feedback OFF DECLARE -- ********* -- Debugging/error handling -- ********* -- ********* -- Work variables -- ********* ora_loc_code number := 0; p_emp_number VARCHAR2 (14); v_rec_cnt NUMBER := 0; insert_flag VARCHAR2 (8); err_num NUMBER; err_msg VARCHAR2 (150); err_line VARCHAR2 (350); err_seq NUMBER := 0; l_validate BOOLEAN DEFAULT FALSE; l_std_business_group_id NUMBER := '0'; l_default_code_comb_id NUMBER := '217269'; l_organization_id NUMBER := '0'; l_set_of_books_id NUMBER := '1'; l_job_id NUMBER := '10'; l_obj NUMBER; l_datetrack_update_mode VARCHAR2 (30) := 'CORRECTION'; l_assignment_sequence NUMBER; l_name_combination_warning BOOLEAN := FALSE; l_assign_payroll_warning BOOLEAN := FALSE; l_org_now_no_manager_warning BOOLEAN; l_other_manager_warning BOOLEAN; l_spp_delete_warning BOOLEAN; l_entries_changed_warning VARCHAR2 (30); l_tax_district_changed_warning BOOLEAN; 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Published by: user12154024 on November 2, 2009 22:32Hello 12154024,
Welcome to the forum. May not be a more elegant solution, but it shows how it works step by step
WITH t AS ( SELECT 4 n FROM dual UNION ALL SELECT 5 n FROM dual UNION ALL SELECT 6 n FROM dual ) ,t1 AS ( SELECT n ,ROUND(RATIO_TO_REPORT(n) OVER (),5) AS rr ,COUNT(n) OVER () AS c ,ROW_NUMBER() OVER (ORDER BY n) AS rn FROM t ) ,t2 AS ( SELECT n ,rr ,SUM(rr) OVER (ORDER BY n) s ,c ,rn FROM t1 ) SELECT n ,rr ,CASE WHEN c = rn THEN rr + (1 - s) ELSE rr END rr2 ,s FROM t2 ORDER BY rn; N RR RR2 S --- --------- --------- -------- 4 0.26667 0.26667 0.26667 5 0.33333 0.33333 0.6 6 0.4 0.4 1 3 rows selectedThe part "WITH t AS" generates data
T1 calculate the ratio, counts the number of records and signs a current issue
T2 to calculate a cumulative ratio
the last part takes these data and for the last record (number = count running) it allows to adjust the ratio.You can see if you are using other data
WITH t AS ( SELECT 4.78 n FROM dual UNION ALL SELECT 5 n FROM dual UNION ALL SELECT 6 n FROM dual ) ... N RR RR2 S ---- -------- -------- -------- 4.78 0.30292 0.30292 0.30292 5 0.31686 0.31686 0.61978 6 0.38023 0.38022 1.00001 3 rows selectedConcerning
Marcus -
remove the last record from the plsql table
Under certain conditions, I need to remove the last record from i_CustomerLoopTYPE r_LOOPElement IS RECORD (TermID NUMBER ); TYPE t_LOOPType IS TABLE OF r_LOOPElement INDEX BY BINARY_INTEGER; i_CustomerLoop t_LOOPType ; i_CustomerLoop(1).TermID=1; i_CustomerLoop(2).TermID=2; i_CustomerLoop(3).TermID=3;
whichi s the best way to do it. because I sometimes get duplicates for TermID in this plsql table.Hello
See [removing items from Collection (DELETE method) | http://download.oracle.com/docs/cd/B28359_01/appdev.111/b28370/collections.htm#CJAFGFIG]
Kind regards
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