extract date time stamp
HelloHow to extract the DATE of the timestamp column
Thank you
SQL > select to_char (systimestamp, 'DateFormat') of double;
for example:
SQL > select to_char (systimestamp, 'DD') of double;
SQL > select to_char(systimestamp,'DD-MON-YYYY') from double;
Published by: rash on June 17, 2012 15:00
Tags: Database
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GregHello
user10388717 wrote:
HelloI do some testing with redefining online timestamp column.
When you try to generate timestamp data looks like fractions of a second are 0sinsert into t select r , systimestamp+ 1+r/(24*60*60*2) from (select rownum r from dual connect by level <= 100); select * from t where rownum <= 3; ID DATA ----- ------------------------------------ 1 15-MAY-10 01.59.16.000000 PM 2 15-MAY-10 01.59.16.000000 PM 3 15-MAY-10 01.59.17.000000 PM
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What's wrong with my data generator? :))
Kind regards.
GregArithmetic, such as dates
x + 1+r/(24*60*60*2)
Suppose x is a DATE, not a TIMESTAMP and returns a DATE.
If x is a TIMESTAMP (as in your case), the system converts implicitly to a DATE, lose the fraction of a second.
Similarly, when you INSERT into your table, the system waits a TIMESTAMP, but if you pass it a DATE (as you do) the system implicitly converts a TIMESTAMP.Don't use no arithmetic dates with the TIMESTAMPS. There are other ways (although less convenient) to manipulate the timestamps.
For exampleSYSTIMESTAMP + NUMTODSINVERVAL ( (1+r/(24*60*60*2)) , 'DAY' )
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