find the distance between two major axis chart point cloud

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• Calculating the distance between two images... ?

  Hello

  I'm trying to calculate the distance between two images (A and F - there are other images between A and F), but I can't seem to understand how to make good sense.

  Image A.x is "(stage/2)-(A.width/2)" and the image of F.x is "provable - imgSpace" which is a negative value (all images x is a negative value for image A.x). "

  In my view, the calculation is F.x - A.x, and although it could be good I still ned the value to be non-negative.

  Does anyone know how to do this?

  Thanks in advanse...

  I think you can find out the distance with this equation,

  var len:Numer = Math.abs (A.x - F.x);

• Find the difference between two date and time

  Hi friends,
  
  I wanted to find the difference between two date and time, but my qury is slightest error "invalid number."
  
  

  select sql_step_num,proc_name,run_seqno,start_date,end_date,(to_char(start_date,'HH24-MI-SS') - to_char(end_date,'HH24-MI-SS') ) as ed  
  from eval.EVAL_RUNTIME_DETAILS
  where trunc(start_date) = trunc(sysdate) 
  order by sql_step_num;

  You try to get the feel between two char strings.
  And more difference between two dates gives a NUMBER of days.
  Try this:

  select sql_step_num,proc_name,run_seqno,start_date,end_date,numtodsinterval(end_date-start_date,'DAY') as ed
  from eval.EVAL_RUNTIME_DETAILS
  where trunc(start_date) = trunc(sysdate)
  order by sql_step_num;
  

• How to find the Distance between the two stores

  Hi all

  I need to find out the distance between stores in our organizations. For example, for a store and shop B, distance of 5 miles etc...

  I'm very very new in Oracle Spatial and don't know how to do it.

  Can you help me please?

  Kind regards

  Dilek

  Dilek,

  That have you tried that didn't work?

  See: package SDO_GEOM (geometry)

  Bryan

• Find the difference between two numbers (DBL)

  Hi all

  Is there a function in labview other than the subtraction function that can find the difference between the two numbers given?

  Thank you

  Davidson

  
  

• I'll try to find the distance between a smart camera and object?

  I am using smart camera or 1722, and I'm doing a VI that gives me the distance between the object and the camera of the aquised of the image with the grab module

  Can someone help me please?

  I'm new with labview and I don't have much time to make this project so please help

  You should pass on the IP Reset (on the camera), and then you will be able to make the assignment of intellectual property to a successful conclusion.

  Kind regards

• How to find the difference between two dates in the presentation layer

  Hi gurus,
  
  Hello to everyone. Today, I came with the new requirement.
  
  
  I need to know the difference between a date and the current date in the formula column application presentation layer.by.
  
  
  
  Thank you and best regards,
  Prates

  Hi Navin,

  TIMESTAMPDIFF function first determines the timestamp component that corresponds to the specified interval setting. For example, SQL_TSI_DAY corresponds to the day component and SQL_TSI_MONTH corresponds to the component "month".

  If you want to display the difference between two dates in days using SQL_TSI_DAY, unlike butterflies SQL_TSI_MONTH and so on...

  hope you understand...

  Award points and to close the debate, if your question is answered.

  See you soon,.
  Aravind

• I can't find how to change the distance between two lines of text

  ureself
  ureself

  I mean the vertical distance between the two lines with mmmmm

  http://codeverge.com/Mozilla.support.Thunderbird/line-spacing-how-to-double-space/1402587

  http://forums.mozillazine.org/viewtopic.php?f=39 & t = 403487

• How to find the time between two channels of entry in the data acquisition card or pci 6036

  Hello

  I read a lot-related posts on the simultaneous measurement of two input voltage of similar channels in map data acquisition. I know that the best material is "simultaneous measurments of the Series DAQ cards" but I only pci data acquisition card 6036 and I try to understand what is the time between the reading of the two channels . This period is always constant? (must it rely on a voltage (amplitude, frequency, waveform..). I send the sine wave (s) to the two channels and read the values of V, if they read the same value, the difference should always be zero but I get-0,002 to 0.002 Volt difference (I must find a way to convert it in time). A screenshot of my VI is attached. I wonder how I can accurately measure the time delay between the channel.

  I am open to any suggestion, my final goal to read exactly two channels at the same time ((ou connaître le délai exact donc je peux correspondre les données correspondantes étant donné le temps de retard))

  Hi spinup,

  better you should post your question in the forum of LabVIEW, LabWindows/CVI is used

  Good luck.

• How to find the difference between two dates in time except Sunday

  Hi all
  
  I have a table, as shown below.

  SQL> select * from test;
  
  TR_ID                                              CREATE_TIME                                                                       CODE
  -------------------------------------------------- --------------------------------------------------------------------------- ----------
  S12341                                             05-JUN-12 12.20.52.403000 AM                                                      1003
  S12342                                             11-JUN-12 11.15.33.182000 AM                                                      1003
  S12342                                             07-JUN-12 12.00.36.573000 PM                                                      1002
  S12343                                             20-JUN-12 12.34.37.102000 AM                                                      1003
  S12343                                             15-JUN-12 11.34.27.141000 PM                                                      1002
  S12344                                             01-JUL-12 10.01.06.657000 PM                                                      1002
  S12344                                             06-JUL-12 12.01.04.188000 AM                                                      1003
  S12341                                             31-MAY-12 11.20.38.529000 PM                                                      1002

  I would like to know the difference between same tr_ids create_time, which should give out in hours except Sunday.
  
  For example:
  
  TR_ID: S12344
  1002_Create_time: July 1, 12 PM 10.01.06.657000 (i.e. Sunday)
  1003_Create_time: 12.01.04.188000 AM 6 July 12
  
  1002 create time is 22:00 Sunday.
  
  If the query must exclude only the hours of Sunday which is 10 p.m. to Monday 00 h which is 2 Hrs.
  
  I tried the sub query after doing a search on this forum but I am not getting the desired output.
  

  SELECT count(*) FROM (SELECT ROWNUM RNUM,tr_id,create_time CT_1002 FROM test c WHERE c.tr_id='S12344' and 
  ROWNUM <= (select (cast(a.create_time as date)-cast((select create_time from test b where a.tr_id=b.tr_id and code=1002) as date)) 
  from test a where a.code=1003 and a.tr_id=c.tr_id) + 1) d 
  WHERE to_char(cast((select create_time from test e where e.tr_id=d.tr_id and code=1002) as date) + RNUM - 1, 'DY') NOT IN('SUN');

  Need help to get the desired o/p

  Hello

  If I unederstand the problem correctly, that's what you want:

  WITH       got_extrema     AS
  (
       SELECT       tr_id
       ,       CAST (MIN (create_time) AS DATE)     AS start_date
       ,       CAST (MAX (create_time) AS DATE)     AS end_date
       FROM       test
       GROUP BY  tr_id
  )
  SELECT       tr_id
  ,       start_date, end_date          -- If wanted
  ,       24 * ( ( ( TRUNC (end_date,   'IW')          -- Count -1 day for every full week
                      - TRUNC (start_date, 'IW')
               )
             / -7
                )
              + LEAST ( end_date               -- If end_date is a Sunday
                          , TRUNC (end_date, 'IW') + 6     -- consider it 00:00:00 on Sunday
                   )
              - CASE
                        WHEN  start_date >= TRUNC (start_date, 'IW') + 6     -- If start_date is a Sunday
                 THEN  TRUNC (start_date, 'IW') + 6               -- consider it 00:00:00 Sunday
                 ELSE  start_date
                    END
              )     AS total_hours
  FROM      got_extrema
  ;
  

  I guess that you don't need to worry about fractions of a second. As you did in the code you have posted, I am to convert the TIMESTAMP to date values, because of DATE arithmetic and functions are so much better than what is available for timestamps.

  Basically, it's just to find the number of days between start_date and end_date and multiplying by 24, with these twists:
  (a) 1 day is deducted for each week between start_date and end_date
  (b) if End_date is a Sunday, none of the end_date himself hours are counted
  (c) If start_date is a Sunday, then all the start_date himself hours are counted. Why these hours should be counted? Because 1 day is already being deducted for the week which includes start_date, which contains only this Sunday.

  TRUNC (dt, 'IW') is the beginning of the ISO week containing dt; in other words, 00:00:00 the or before the dt last Monday. This is not the NLS parameters.

  Of course, I can't test without some sample data and the exact results you want from these data. You may need a little something more If start_date and end_date are both on the same Sunday.
  Whenever you have a problem, please post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) of all of the tables involved.
  Also post the results you want from this data, as well as an explanation of how you get these results from these data, with specific examples.
  Always tell what version of Oracle you are using.
  See the FAQ forum {message identifier: = 9360002}

• How to find the hours between two times

  Hai All
  
  I had a problem I need to calculate work time
  
  For example
  
  Respondent outtime
  
  0815 1715
  
  So I need to calculate a time between these two times
  
  How can I do using function for 100 our
  
  Concerning
  
  Srikkanth.M

  Hello

  use the below the update statement.

  update dail_att set wtime =  extract(hour from (to_date(outtime,'HH24:MI')-to_date(intime,'HH24MI')) day to second);
  

  Solution of the sample...

  PRAZY@11gR1> desc dte;
   Name            Null?    Type
   ------------------- -------- --------
   INTIME           VARCHAR2(4)
   OUTTIME        VARCHAR2(4)
   HRS                NUMBER
  
  PRAZY@11gR1> select * from dte;
  
  INTIME     OUTTIME           HRS
  ---------- ---------- ----------
  0815       1715
  0900       1800
  0830       1630
  
  Elapsed: 00:00:00.00
  PRAZY@11gR1> update dte set hrs = extract(hour from(to_date(outtime,'HH24MI')-to_date(intime,'HH24MI')) day to second);
  
  3 rows updated.
  
  Elapsed: 00:00:00.01
  PRAZY@11gR1> select * from dte;
  
  INTIME     OUTTIME           HRS
  ---------- ---------- ----------
  0815       1715                9
  0900       1800                9
  0830       1630                8
  
  Elapsed: 00:00:00.00
  

  Kind regards
  Prazy

  Published by: Prazy on March 24, 2010 12:43

• How to find a number between two numbers?

  I try to find the numbers between two given user numbers and multiply each of them, but my code so far wont allow me to separate the numbers multiply:
  
  ex: the numbers are 5 and 10: my code gives me 5678910 together online.
  
  How can I sneek the * between these numbers? I know that I am seriously close here's my work so far.
  
  Any help is greatly appreciated.
  
  
  import java.util.Scanner;
  
  public class FindIt
  {
  Public Shared Sub main (string args [])
  {
  Console scanner = new Scanner (System.in);
  
  int userNumber, finIn, finIn2, finIn3;
  
  System.out.Print ("enter a lower limit > = 1 :"); ")
  
  
  do
  {
  
  userNumber = console.nextInt ();
  
  If (< 1 userNumber)
  {
  System.out.Print ("enter a lower limit > = 1 :"); ")
  }
  
  } while (< 1 userNumber);
  
  System.out.println ("the lower limit is" + userNumber);
  System.out.println ();
  System.out.Print ("enter an upper limit > = 3 :"); ")
  finIn = userNumber;
  do
  {
  
  userNumber = console.nextInt ();
  
  If (userNumber < 3)
  {
  System.out.Print ("enter an upper limit > = 3 :"); ")
  }
  
  } While userNumber < 3.
  
  System.out.println ("the upper limit is" + userNumber);
  System.out.println ();
  finIn2 = userNumber;
  
  
  
  int x, y;
  y = 0;
  for (x = finIn; x < = finIn2; x ++)
  
  CallIncr();
  
  
  
  
  
  }
  }
  
  Published by: 806590 on October 31, 2010 13:07
  
  Published by: 806590 on October 31, 2010 13:09

  Modified the code of the loop to as below

  for (x = finIn + 1; x)< finin2;="">

• Illustrator CS3: How to calculate the exact distance between two points?

  It comes to my line.

  

  I have to measure its exact length. How can I do?
  If I use the measure tool, the cursor does not select the snap points, so I have only an approximate measure.
  Is there a quick way to calculate the exact distance between two points?

  Flying document Info Palette menu: turn on the SelectionOnly and objects. The palette will show you the length.

  JET

• measure the distance between 2 impulses (PCI-6221)

  Hello

  I have a digital signal that sends a pair of impulses (100ns width each) roughly every 100ms and I measure the time between two pulses of a pair (with a resolution of 100 ns).
  For the moment, I got a card PCI-6221 to accomplish this task. Unfortunately, I have no solution until now only measures of counter, I found measure time between constant frequency signals, i.e. they cannot measure the distance between 2 single pulses.

  Any help / ideas / or even telling me that it is impossible to solve this task are appreciated

  Are the two pulses on the same line?

  If so, you need to just configure a task of the measurement period.  If they are on separate lines, you would use a task of "separation of two-edge.

  You might be to throw off by the timing of it:

  If you do not configure implicit synchronization in your task, will start on the first edge after DAQmx Read is called.  Thus, in order to intercept the signal, that you must configure your task, call DAQmx Read and then start your two squares.

  If you want the task to control the signal continuously, you must configure name timing.  In this case, you will receive a sample on each rising edge of the external signal (assuming that the two impulses on the same line) - If you start the task of counter before starting the production of pulses (which you probably should), then the same samples correspond to the time between pulses, the odd samples would be the time between each series of pulses.

  More information on modes of counting on the 6221 lie in the M series user manual.

  Best regards

• Take the time between two values

  Hi people,

  I have a problem and I know idea how to solve... I need help.

  The problem is I want to take the time between two values max as you can see in the chart.

  For example, in the image that I have add

  4.5 - 1 840 = 2.66

  And enter this value in the 'time between mostra '.

  It's that I want...

  But what I think is very complicated, because I don't know how to take the time correctly and does remove...

  Thank you very much

  Any solution?

  Hi jocuma,

  I tried something and hope that helps u.

  Just create two arrays of temperature and voltage. First of all, I'll get the value of the voltage when it is more of a certain value and that same index to get the value of time and store in the shift register.

  When I get the second higher than the limit value, I'll get time and subtract the previous value.