Find the time of reporting of employees

Hello

I followed two tables

PERMITTEDABSCENCE
EMPID	DATE	LEAVEFROM	LEAVETO	TYPE
1	01/01/2014	08:00	12:00	CL
1	01/01/2014	12:00

13:00

DUTY

01/01/2014

09:00

16:30

01/02/2014

12:00

16:30

EMPLOYEESHIFTS
EMPID	DATE

SHIFTSTART

01/01/2014

08:00

01/01/2014

09:00

01/02/2014

09:00

I want to know the time during which the employee must declare for each day.

This is necessary when calculating the minutes of delay for employees.

Normally an employee must get customs SHIFT START TIME that is stored in the EMPLOYEESHIFTS table.

But if an employee is allowed to be described (leave/duty etc.), he had to report for duty after this period [only if authorized period start time is exactly to the SHIFT start time] and its end minutes will be counted from the moment here.

Here, a complication is that there may be consecutive leave and then the start time of the work duty must be discovered as a result.

for example.

01/01/2014, an employee is on leave from 08:00 to 12:00 so it is assumed that he had to report for duty at 12:00.

But as it is in service from 12:00 to 15:00, he had to report for duty at 13:00

POWER REQUIRED

EMPID

DATE

WORKSTARTTIME

01/01/14

13:00

01/01/14

16:30

01/02/14

09:00

Is this possible?

I use oracle 10g.

Examples of data

create the table employeeshifts as

(

Select 1 empid, to_date('01/01/2014','DD/MM/YYYY') stand,' 08:00 ' shiftstart of all the double union

Select 2 empid, to_date('01/01/2014','DD/MM/YYYY') stand,' 09:00 ' shiftstart of all the double union

Select 3 empid, to_date('02/01/2014','DD/MM/YYYY') stand,' 09:00 ' shiftstart of the double

);

create the table authorisedabsence as

(select 1 employee_id, to_date (1 January 2014 ', ' dd/mm/yyyy') subsist, to_date (08 January 1 2014:00 ',' dd/mm/yyyy hh24 ') frmdt, to_date (12 January 1 2014:00 ',' dd/mm/yyyy hh24 ') todt, "CL" type of Union double all the)

Select 1 employee_id, to_date (1 January 2014 ', ' dd/mm/yyyy') subsist, to_date (12 January 1 2014:00 ',' dd/mm/yyyy hh24 ') frmdt, to_date (16 January 1 2014:00 ',' dd/mm/yyyy hh24 ') todt, "CL" type of Union double all the

Select employee_id 2, to_date (January 1, 2014 ', ' dd/mm/yyyy') subsist, to_date (09 January 1 2014:00 ',' dd/mm/yyyy hh24 ') frmdt, to_date (16 January 1 2014:30 ',' dd/mm/yyyy hh24 ') todt, "CL" type of Union double all the

Select 3 employee_id, to_date (1 January 2014 ', ' dd/mm/yyyy') subsist, to_date (January 1, 2014 12:00 ',' dd/mm/yyyy hh24 ') frmdt, to_date (16 January 1 2014:30 ',' dd/mm/yyyy hh24 ') todt, "CL" type double

);

Hello

2730134 wrote:

Hello

I followed two tables

PERMITTEDABSCENCE

EMPID

DATE

LEAVEFROM

LEAVETO

TYPE

1

01/01/2014

08:00

12:00

CL

1

01/01/2014

12:00

13:00

DUTY

2

01/01/2014

09:00

16:30

CL

3

01/02/2014

12:00

16:30

CL

EMPLOYEESHIFTS

EMPID

DATE

SHIFTSTART

1

01/01/2014

08:00

2

01/01/2014

09:00

3

01/02/2014

09:00

I want to know the time during which the employee must declare for each day.

This is necessary when calculating the minutes of delay for employees.

Normally an employee must get customs SHIFT START TIME that is stored in the EMPLOYEESHIFTS table.

But if an employee is allowed to be described (leave/duty etc.), he had to report for duty after this period [only if authorized period start time is exactly to the SHIFT start time] and its end minutes will be counted from the moment here.

Here, a complication is that there may be consecutive leave and then the start time of the work duty must be discovered as a result.

for example.

01/01/2014, an employee is on leave from 08:00 to 12:00 so it is assumed that he had to report for duty at 12:00.

But as it is in service from 12:00 to 15:00, he had to report for duty at 13:00

POWER REQUIRED

EMPID

DATE

WORKSTARTTIME

1

01/01/14

13:00

2

01/01/14

16:30

3

01/02/14

09:00

Is this possible?

I use oracle 10g.

Examples of data

create the table employeeshifts as

(

Select 1 empid, to_date('01/01/2014','DD/MM/YYYY') stand,' 08:00 ' shiftstart of all the double union

Select 2 empid, to_date('01/01/2014','DD/MM/YYYY') stand,' 09:00 ' shiftstart of all the double union

Select 3 empid, to_date('02/01/2014','DD/MM/YYYY') stand,' 09:00 ' shiftstart of the double

);

create the table authorisedabsence as

);

Workstartime is the end of the period of absence authroised (if it exists), or shiftstart. This looks like a job for NVL.

How do you know if there is a period of leave of absence? There will be a shiftstart if is between the beginning of the period and the end of the period. As you pointed out, however, it's tricky because a period of absence can be any number of consecutive lines in the authorisedabsence table. It would be so much easier if there was only 1 row per employee per day, so let's create a set of results (combined_absence) that is the beginning and the end of the time for consecutive periods.

How can we detect consecutive periods? We can use the technique of fixed difference, it's what got_grp_id does.

WITH got_grp_id AS

(

SELECT employee_id, subsist, frmdt, todt

, todt - SUM (todt - frmdt) OVER (PARTITION BY employee_id, subsist

ORDER BY frmdt

) AS grp_id

Of authorisedabsence

)

combined_absence AS

(

SELECT employe_id, subsist

MIN (frmdt) AS grp_frmdt

MAX (todt) AS grp_todt

OF got_grp_id

GROUP BY employee_id, survive, grp_id

)

improved_employeeshifts AS

(

SELECT empid

subsist

, subsist + (TO_DATE (shiftstart, "HH24")

-TO_DATE (' 00:00 ', "HH24")

) AS shiftstartdate

Of employeeshifts

)

SELECT es.empid

es.thedate

NVL (ca.grp_todt, es.shiftstartdate) AS workstarttime

Of improved_employeeshifts are

LEFT OUTER JOIN combined_absence ON es.empid = ca.employee_id ca

AND es.shiftstartdate BETWEEN ca.grp_frmdt

AND ca.grp_todt

ORDER BY es.empid

es.thedate

;

The results I get from your sample data are not exactly what you posted:

EMPID CONTINUE WORKSTARTTIME

---------- ---------------- ----------------

1 01/01/2014 00:00 01/01/2014 16:00

2 01/01/2014 00:00 01/01/2014 16:30

3 01/02/2014 00:00 01/02/2014 09:00

Time 13:00 do not exist anywhere in the sample data, so I think that you don't really want for the empid workstarttime = 1.

Information on the dates and times (for example, shiftstart) belongs to DATE columns, not VARCHAR2s. If you store information in the wrong data type, you will need to convert the right data type in any statement that has to manipulate it in any way. This makes the subquery improved_employeeshifts above. You are wasting time and risking execution errors, by the conversion of a VARCHAR2 to a DATE in queries like this. If would be much more effective, more robust and simpler if you have stored to a DATE just shiftstart all along.

I guess that this period of an absence never begins or ends in the middle of one (for the same employee). In other words, if a period is from 08:00 to 12:00, then you will never have another one that starts at 11:30 the same day. If my assumption is wrong, and you can have overlapping of absences like that, then you can combine still, but it's more complicated than what I used above.

For an explanation of the technique fixed Difference in combined_absence, see

Analytic Question lag and lead and/or

Re: Ranking of queries

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Find the time of reporting of employees

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