Find the time displaced table

Similar Questions

• Find the time to restore a data file

  RDBMS version: 11.2.0.4

  Platform: Oracle Linux 6.4

  To test our backup RMAN Tape (Netbackup), we have created a table called BACKUPTEST with a single space data file.

  Then, we have removed the data file. Then was restored and recovered with RMAN's data file and tablespace was again online.

  I wanted to show the evidence to my manager that the data file has been restored. But v$ datafile. CREATION_TIME will show the time when the tablespace is imagined. Is there another way, I could find the time when the data file has been restored other than log RMAN.

  Below is an excerpt after the data file has been restored.

  $ sqlplus / as sysdba

  SQL * more: Production of the version 11.2.0.4.0 Fri dec 19 15:08:03 2013

  Copyright (c) 1982, 2013, Oracle.  All rights reserved.

  Connected to:

  Oracle Database 11 g Enterprise Edition Release 11.2.0.4.0 - 64 bit Production

  With partitioning, Real Application Clusters, Automatic Storage Management, OLAP,.

  Options of Data Mining and Real Application Testing

  SQL > select TABLESPACE_NAME, status of dba_tablespaces where nom_tablespace = 'BACKUPTEST ';

  STATUS TABLESPACE_NAME

  ------------------------------ ---------

  BACKUPTEST ONLINE

  SQL > alter session set nls_date_format = "DD-MM-YYYY HH24."

  Modified session.

  SQL > select CREATION_TIME of v$ datafile where FILE # = 78;

  CREATION_TIME

  ----------------

  19/12/2013-12:16

  SQL > select CREATION_TIME, last_time v$ datafile where FILE # = 78;

  CREATION_TIME LAST_TIME

  ---------------- ----------------

  19/12/2013-12:16

  SQL >

  19/12/2013 12:16 is the hour when the tablespace has been created with this data file no time, it has been restored from a backup RMAN.

  Check the alert.log.  There will be messages about the RESTORATION and RECOVERY actions.

  Hemant K Collette

• Could not find the Time Capsule for Time Machine backup drive

  My iMac is running El Capitan and Time Machine is unable to find the Time Capsule backup drive.  I blew the backup several times in hopes that it will fix the problem.   The only thing I found which will allow a return to the top is to unplug the Time Capsule and plug it in again.  The work around works only once, then it's back to "can't find the backup disk.

  For anyone a cela or similar questions are you go in your Utilities folder (in your applications folder) and run the utility airport to see what he says about the disks attached. This cannot work for the readers of time capsule Apple rather than third party readers who have been designated as the backup time drives machine.

• How to find the time to what zero crossing point occur using zero crossing vi

  Hello 
  Im trying to find the time to the point of inflection of a Bio-Signal with the 2nd derivative, then detecet the point of zero of the derivative signal
  What I need, is to mark the point of inflection on my Bio-Signal at the point where the derivative signal crosses the zero.
  

  The second has two scales on the graph, one on each side.  The first has only a single scale. I do not change the name of VI, so both have the same name.

  Lynn

• How to find the time to process a request?

  IM using oracle express edition, can someone help me, how to find the time to process a request?

  Trace queries and tkprof the trace file generated.
  http://download.Oracle.com/docs/CD/E11882_01/server.112/e16638/SQLTrace.htm#PFGRF01010

• How to find the user Apex table

  Hello
  
  Please let me know, how to find the user apex table. I need validate the unique user based on the same, for which I use below function.
  
  DECLARE
  VAL A BOOLEAN;
  BEGIN
  VAL: = APEX_UTIL.IS_USERNAME_UNIQUE (p_username =
  (: P6_USERNAME);
  END;
  
  However, in this case, he always comes back "FALSE," saying new user exists.
  
  Kindly help me in fixing this problem.

  There is a view called apex_workspace_apex_users.

  Details under Home > utilities > Application Express views

  André

• Find the time delay between two signals

  In this code, I sent you a pulse in the acquisition of data using labview. The pulse triggers a thermistor to another analog input input data.

  I want to find the delay between the time of the positive edge of the switch, and the exact time of the DAQ begins to take in the signal of the temperature probe.

  I enclose the code below.

  Thank you.

  Hey,.

  Here is a link to some information about the sources of clock on the FPGA.

  http://digital.NI.com/public.nsf/allkb/94CE338CC80ACF008625791400516BAA?OpenDocument

  Hope this helps

• How to find the time between two channels of entry in the data acquisition card or pci 6036

  Hello

  I read a lot-related posts on the simultaneous measurement of two input voltage of similar channels in map data acquisition. I know that the best material is "simultaneous measurments of the Series DAQ cards" but I only pci data acquisition card 6036 and I try to understand what is the time between the reading of the two channels . This period is always constant? (must it rely on a voltage (amplitude, frequency, waveform..). I send the sine wave (s) to the two channels and read the values of V, if they read the same value, the difference should always be zero but I get-0,002 to 0.002 Volt difference (I must find a way to convert it in time). A screenshot of my VI is attached. I wonder how I can accurately measure the time delay between the channel.

  I am open to any suggestion, my final goal to read exactly two channels at the same time ((ou connaître le délai exact donc je peux correspondre les données correspondantes étant donné le temps de retard))

  Hi spinup,

  better you should post your question in the forum of LabVIEW, LabWindows/CVI is used

  Good luck.

• Find the time of reporting of employees

  Hello

  I followed two tables

  PERMITTEDABSCENCE
  EMPID	DATE	LEAVEFROM	LEAVETO	TYPE
  1	01/01/2014	08:00	12:00	CL
  1	01/01/2014	12:00

  13:00

  DUTY

  2

  01/01/2014

  09:00

  16:30

  CL

  3

  01/02/2014

  12:00

  16:30

  CL

  EMPLOYEESHIFTS
  EMPID	DATE

  SHIFTSTART

  1

  01/01/2014

  08:00

  2

  01/01/2014

  09:00

  3

  01/02/2014

  09:00

  I want to know the time during which the employee must declare for each day.

  This is necessary when calculating the minutes of delay for employees.

  Normally an employee must get customs SHIFT START TIME that is stored in the EMPLOYEESHIFTS table.

  But if an employee is allowed to be described (leave/duty etc.), he had to report for duty after this period [only if authorized period start time is exactly to the SHIFT start time] and its end minutes will be counted from the moment here.

  Here, a complication is that there may be consecutive leave and then the start time of the work duty must be discovered as a result.

  for example.

  01/01/2014, an employee is on leave from 08:00 to 12:00 so it is assumed that he had to report for duty at 12:00.

  But as it is in service from 12:00 to 15:00, he had to report for duty at 13:00

  POWER REQUIRED

  EMPID

  DATE

  WORKSTARTTIME

  1

  01/01/14

  13:00

  2

  01/01/14

  16:30

  3

  01/02/14

  09:00

  Is this possible?

  I use oracle 10g.

  Examples of data

  create the table employeeshifts as

  (

  Select 1 empid, to_date('01/01/2014','DD/MM/YYYY') stand,' 08:00 ' shiftstart of all the double union

  Select 2 empid, to_date('01/01/2014','DD/MM/YYYY') stand,' 09:00 ' shiftstart of all the double union

  Select 3 empid, to_date('02/01/2014','DD/MM/YYYY') stand,' 09:00 ' shiftstart of the double

  );

  create the table authorisedabsence as

  (select 1 employee_id, to_date (1 January 2014 ', ' dd/mm/yyyy') subsist, to_date (08 January 1 2014:00 ',' dd/mm/yyyy hh24 ') frmdt, to_date (12 January 1 2014:00 ',' dd/mm/yyyy hh24 ') todt, "CL" type of Union double all the)

  Select 1 employee_id, to_date (1 January 2014 ', ' dd/mm/yyyy') subsist, to_date (12 January 1 2014:00 ',' dd/mm/yyyy hh24 ') frmdt, to_date (16 January 1 2014:00 ',' dd/mm/yyyy hh24 ') todt, "CL" type of Union double all the

  Select employee_id 2, to_date (January 1, 2014 ', ' dd/mm/yyyy') subsist, to_date (09 January 1 2014:00 ',' dd/mm/yyyy hh24 ') frmdt, to_date (16 January 1 2014:30 ',' dd/mm/yyyy hh24 ') todt, "CL" type of Union double all the

  Select 3 employee_id, to_date (1 January 2014 ', ' dd/mm/yyyy') subsist, to_date (January 1, 2014 12:00 ',' dd/mm/yyyy hh24 ') frmdt, to_date (16 January 1 2014:30 ',' dd/mm/yyyy hh24 ') todt, "CL" type double

  );

  Hello

  2730134 wrote:

  Hello

  I followed two tables

  PERMITTEDABSCENCE
  EMPID	DATE	LEAVEFROM	LEAVETO	TYPE
  1	01/01/2014	08:00	12:00	CL
  1	01/01/2014	12:00	13:00	DUTY
  2	01/01/2014	09:00	16:30	CL
  3	01/02/2014	12:00	16:30	CL

  EMPLOYEESHIFTS
  EMPID	DATE	SHIFTSTART
  1	01/01/2014	08:00
  2	01/01/2014	09:00
  3	01/02/2014	09:00

  I want to know the time during which the employee must declare for each day.

  This is necessary when calculating the minutes of delay for employees.

  Normally an employee must get customs SHIFT START TIME that is stored in the EMPLOYEESHIFTS table.

  But if an employee is allowed to be described (leave/duty etc.), he had to report for duty after this period [only if authorized period start time is exactly to the SHIFT start time] and its end minutes will be counted from the moment here.

  Here, a complication is that there may be consecutive leave and then the start time of the work duty must be discovered as a result.

  for example.

  01/01/2014, an employee is on leave from 08:00 to 12:00 so it is assumed that he had to report for duty at 12:00.

  But as it is in service from 12:00 to 15:00, he had to report for duty at 13:00

  POWER REQUIRED
  EMPID	DATE	WORKSTARTTIME
  1	01/01/14	13:00
  2	01/01/14	16:30
  3	01/02/14	09:00

  Is this possible?

  I use oracle 10g.

  Examples of data

  create the table employeeshifts as

  (

  Select 1 empid, to_date('01/01/2014','DD/MM/YYYY') stand,' 08:00 ' shiftstart of all the double union

  Select 2 empid, to_date('01/01/2014','DD/MM/YYYY') stand,' 09:00 ' shiftstart of all the double union

  Select 3 empid, to_date('02/01/2014','DD/MM/YYYY') stand,' 09:00 ' shiftstart of the double

  );

  create the table authorisedabsence as

  (select 1 employee_id, to_date (1 January 2014 ', ' dd/mm/yyyy') subsist, to_date (08 January 1 2014:00 ',' dd/mm/yyyy hh24 ') frmdt, to_date (12 January 1 2014:00 ',' dd/mm/yyyy hh24 ') todt, "CL" type of Union double all the)

  Select 1 employee_id, to_date (1 January 2014 ', ' dd/mm/yyyy') subsist, to_date (12 January 1 2014:00 ',' dd/mm/yyyy hh24 ') frmdt, to_date (16 January 1 2014:00 ',' dd/mm/yyyy hh24 ') todt, "CL" type of Union double all the

  Select employee_id 2, to_date (January 1, 2014 ', ' dd/mm/yyyy') subsist, to_date (09 January 1 2014:00 ',' dd/mm/yyyy hh24 ') frmdt, to_date (16 January 1 2014:30 ',' dd/mm/yyyy hh24 ') todt, "CL" type of Union double all the

  Select 3 employee_id, to_date (1 January 2014 ', ' dd/mm/yyyy') subsist, to_date (January 1, 2014 12:00 ',' dd/mm/yyyy hh24 ') frmdt, to_date (16 January 1 2014:30 ',' dd/mm/yyyy hh24 ') todt, "CL" type double

  );

  Workstartime is the end of the period of absence authroised (if it exists), or shiftstart.  This looks like a job for NVL.

  How do you know if there is a period of leave of absence?  There will be a shiftstart if is between the beginning of the period and the end of the period.  As you pointed out, however, it's tricky because a period of absence can be any number of consecutive lines in the authorisedabsence table.  It would be so much easier if there was only 1 row per employee per day, so let's create a set of results (combined_absence) that is the beginning and the end of the time for consecutive periods.

  How can we detect consecutive periods?  We can use the technique of fixed difference, it's what got_grp_id does.

  WITH got_grp_id AS

  (

  SELECT employee_id, subsist, frmdt, todt

  , todt - SUM (todt - frmdt) OVER (PARTITION BY employee_id, subsist

  ORDER BY frmdt

  ) AS grp_id

  Of authorisedabsence

  )

  combined_absence AS

  (

  SELECT employe_id, subsist

  MIN (frmdt) AS grp_frmdt

  MAX (todt) AS grp_todt

  OF got_grp_id

  GROUP BY employee_id, survive, grp_id

  )

  improved_employeeshifts AS

  (

  SELECT empid

  subsist

  , subsist + (TO_DATE (shiftstart, "HH24")

  -TO_DATE (' 00:00 ', "HH24")

  ) AS shiftstartdate

  Of employeeshifts

  )

  SELECT es.empid

  es.thedate

  NVL (ca.grp_todt, es.shiftstartdate) AS workstarttime

  Of improved_employeeshifts are

  LEFT OUTER JOIN combined_absence ON es.empid = ca.employee_id ca

  AND es.shiftstartdate BETWEEN ca.grp_frmdt

  AND ca.grp_todt

  ORDER BY es.empid

  es.thedate

  ;

  The results I get from your sample data are not exactly what you posted:

  EMPID CONTINUE WORKSTARTTIME

  ---------- ---------------- ----------------

  1 01/01/2014 00:00 01/01/2014 16:00

  2 01/01/2014 00:00 01/01/2014 16:30

  3 01/02/2014 00:00 01/02/2014 09:00

  Time 13:00 do not exist anywhere in the sample data, so I think that you don't really want for the empid workstarttime = 1.

  Information on the dates and times (for example, shiftstart) belongs to DATE columns, not VARCHAR2s.  If you store information in the wrong data type, you will need to convert the right data type in any statement that has to manipulate it in any way.  This makes the subquery improved_employeeshifts above.  You are wasting time and risking execution errors, by the conversion of a VARCHAR2 to a DATE in queries like this.  If would be much more effective, more robust and simpler if you have stored to a DATE just shiftstart all along.

  I guess that this period of an absence never begins or ends in the middle of one (for the same employee).  In other words, if a period is from 08:00 to 12:00, then you will never have another one that starts at 11:30 the same day.  If my assumption is wrong, and you can have overlapping of absences like that, then you can combine still, but it's more complicated than what I used above.

  For an explanation of the technique fixed Difference in combined_absence, see

  Analytic Question lag and lead and/or

  Re: Ranking of queries

• How to find the names of tables that have more than 100 columns

  Hi gurus,
  
  Please help me find the names of the tables that have more than 100 columns in the database.

  Below will be useful for you.

  SELECT atc.OWNER,atc.TABLE_NAME,count(*)
  FROM all_tab_columns atc
  GROUP BY  atc.OWNER,atc.TABLE_NAME
  HAVING count(atc.COLUMN_NAME) > 100
  

  Adding another point, you can use user_tab_columns, all_tab_columns, dba_tab_columns, based on your needs/access.

  Thank you
  Suri

  Published by: Suri on February 23, 2012 11:30

• How to find the third element table pl/sql ina

  Hello friends,
  
  I have a pl/sql table of NUMERIC type, where am store all salaries of employees.
  
  I want to find the third bigger payday by browsing through the pl/sql table.
  
  Pls advice.
  
  Thank you/kumar

  DECLARE
      TYPE max_earnings_type IS TABLE OF NUMBER;
      TYPE max_earnings_sorted_type IS TABLE OF NUMBER
        INDEX BY BINARY_INTEGER;
      max_earnings_tab        max_earnings_type;
      max_earnings_tab_sorted max_earnings_sorted_type;
      m number;
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        BULK COLLECT
        INTO  max_earnings_tab
        FROM  emp;
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        END IF;
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      m := max_earnings_tab_sorted.prior(m);
      DBMS_OUTPUT.PUT_LINE('Third MAX value in PL/SQL table is ' || nvl(to_char(m),'NULL'));
  END;
  /
  MAX value in PL/SQL table is 2650
  Second MAX value in PL/SQL table is 1900
  Third MAX value in PL/SQL table is 1750
  
  PL/SQL procedure successfully completed.
  
  SQL> 
  

  SY.

• Where to find the type of table table View ALL/DBA or SYS

  Oracle 10g.
  
  I searched the Oracle manuals and the web with nothing will do.
  
  I need to know in which ALL/DBA table view or SYS I find the type (Organization) of a table.
  ITO and 'normal' tables is easy, but I need exactly to know which tables are 'EXTERNAL '!
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  ALL_ALL_TABLES has a column "table_type", but it appears in the form of external tables of ifor NULL.
  
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  I'm building a requests for a customer to enter their personal information at a kiosk in the lobby of the waiting room, before an appointment with a representative, which will save all your meeting time. The timer will be to erase the personal information when a client leaves just during the process.
  
  The timer keeps always just pulled over and over again, and I can't it stop/reset/create new timer when the mouse is moving etc... so he keeps almost touching news over and over again, which is not the desired effect.
  
  
  Could someone help me please? It seems like it should be a pretty basic function to the program, but I'm not find all messages about my question. I use Oracle 9i and 10g of form.

  Hello

  You do not have any code, so that it is difficult to guess what can be the problem. Remember that the timer name must be given capital letters in functions.

  François

• Could not find the time stamp option in the historic window

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• Can't find the time capsule after changing access timed through iPhone app airport utility (setting: no access between 0130 to 0600). But I can not connect or find the same time capsule in the 0800.

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  You must have defined it incorrectly... factory reset and start again.

  Give us a screenshot of the settings before you apply them.