First and last pages on the wrong side?
Hello
I went to CS6 inDesign for the first time in a month or two and for whatever weird reason, my pages are back...
as you can see in the page image '1' is on the right side and should be on the left. someone at - it ideas - sorry if its something simple I'm only a beginner! Thank you very much!
Joe
Take a book and open it. Who should check if what you see is correct.
Bob
Tags: InDesign
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Hello people:
I have currently a query that picks up all the weeks between a date range where my week starts on Thursday and ends on Wednesday. The following query works fine except that I need the week of beginning and end, from beginning and end Dates of months and the beginning and the Dates of end of the values of the settings, I'm passing. In this case, I chose January 1, 2013 to 31 December 2013.
Any help or pointers would be great!
Thank you!
Problem: I am picking up days of December 2012 as the first week began on December 27, 2012. In addition, in December, I'm pretty much lost last week as well (26 December - 31 December).
The request in hand:
SELECT first_thursday + (7 * (LEVEL - 1)) AS week_start_date, first_thursday + (7 * LEVEL) - 1 AS week_end_date FROM ( SELECT TRUNC(p_from_date + 4, 'IW') - 4 AS first_thursday, -- Week should start the pre ceeding THURSDAY based on the Start Date TRUNC( p_to_date + 4, 'IW') - 5 AS last_wednesday FROM ( SELECT to_date('01-JAN-2013') AS p_from_date, NVL(to_date('31-DEC-2013'), SYSDATE) AS p_to_date FROM dual ) parms ) end_points CONNECT BY LEVEL <= ( last_wednesday + 1 - first_thursday)/7;Currently, this is the result I get (I'm only including the months of January and December here).
Week_Start_Date Week_End_Date 27-DEC-12 02-JAN-13 03-JAN-13 09-JAN-13 10-JAN-13 16-JAN-13 17-JAN-13 23-JAN-13 24-JAN-13 30-JAN-13 31-JAN-13 06-FEB-13
December:
28-NOV-13 04-DEC-13 05-DEC-13 11-DEC-13 12-DEC-13 18-DEC-13 19-DEC-13 25-DEC-13
What I would really like is based on start and end Dates, as well as the first and the last day of the month is similarly try nicely. I have provided and then gently break at the end of the month:
January:
01-JAN-13 02-JAN-13 03-JAN-13 09-JAN-13 10-JAN-13 16-JAN-13 17-JAN-13 23-JAN-13 24-JAN-13 30-JAN-13 31-JAN-13 31-JAN-13
February:
01-FEB-13 06-FEB-13 07-FEB-13 13-FEB-13 14-FEB-13 20-FEB-13 21-FEB-13 27-FEB-13 28-FEB-13 28-FEB-13
November:
31-OCT-13 06-NOV-13 07-NOV-13 13-NOV-13 14-NOV-13 20-NOV-13 21-NOV-13 27-NOV-13 28-NOV-13 04-DEC-13
December:
01-DEC-13 04-DEC-13 05-DEC-13 11-DEC-13 12-DEC-13 18-DEC-13 19-DEC-13 25-DEC-13 26-DEC-13 31-DEC-13
Hello
Roxyrollers wrote:
Hello people:
I have currently a query that picks up all the weeks between a date range where my week starts on Thursday and ends on Wednesday. The following query works fine except that I need the week of beginning and end, from beginning and end Dates of months and the beginning and the Dates of end of the values of the settings, I'm passing. In this case, I chose January 1, 2013 to 31 December 2013.
Any help or pointers would be great!
Thank you!
Problem: I am picking up days of December 2012 as the first week began on December 27, 2012. In addition, in December, I'm pretty much lost last week as well (26 December - 31 December).
The request in hand:
- First_thursday SELECT + (7 * (LEVEL - 1)) AS week_start_date,
- first_thursday + (7 * LEVEL)-1 AS week_end_date
- Of
- (
- SELECT TRUNC (p_from_date + 4, 'IW') - 4 AS first_thursday,-week should start to perform the pre-mounted THURSDAY based on the Start Date
- TRUNC (p_to_date + 4, 'IW') - 5 AS last_wednesday
- Of
- (
- SELECT to_date('01-JAN-2013') AS p_from_date,
- NVL (to_date('31-Dec-2013'), SYSDATE) AS p_to_date
- OF the double
- ) parms
- ) end_points
- CONNECT BY LEVEL<= (="" last_wednesday="" +="" 1="" -="">
Currently, this is the result I get (I'm only including the months of January and December here).
- Week_Start_Date Week_End_Date
- DECEMBER 27, 12 2 JANUARY 13
- JANUARY 3, 13 JANUARY 9, 13
- 10 JANUARY 13 JANUARY 16, 13
- 17 JANUARY 13 23 JANUARY 13
- 24 JANUARY 13 30 JANUARY 13
- 31 JANUARY 13 FEBRUARY 6, 13
December:
- NOVEMBER 28, 13 4 DECEMBER 13
- 5 DECEMBER 13 DECEMBER 11, 13
- 12 DECEMBER 13 18 DECEMBER 13
- 19 DECEMBER 13 DECEMBER 25, 13
What I would really like is based on start and end Dates, as well as the first and the last day of the month is similarly try nicely. I have provided and then gently break at the end of the month:
January:
- JANUARY 1, 13 2 JANUARY 13
- JANUARY 3, 13 JANUARY 9, 13
- 10 JANUARY 13 JANUARY 16, 13
- 17 JANUARY 13 23 JANUARY 13
- 24 JANUARY 13 30 JANUARY 13
- 31 JANUARY 13 JANUARY 31, 13
February:
- 1ST FEBRUARY 13 FEBRUARY 6, 13
- 7 FEBRUARY 13 FEBRUARY 13, 13
- 14 FEBRUARY 13 FEBRUARY 20, 13
- 21 FEBRUARY 13 FEBRUARY 27, 13
- 28 FEBRUARY 13 FEBRUARY 28, 13
November:
- 31 OCTOBER 13 NOVEMBER 6, 13
- 7 NOVEMBER 13 NOVEMBER 13, 13
- 14 NOVEMBER 13 NOVEMBER 20, 13
- 21 NOVEMBER 13 NOVEMBER 27, 13
- NOVEMBER 28, 13 4 DECEMBER 13
December:
- 1ST DECEMBER 13 DECEMBER 4, 13
- 5 DECEMBER 13 DECEMBER 11, 13
- 12 DECEMBER 13 18 DECEMBER 13
- 19 DECEMBER 13 DECEMBER 25, 13
- 26 DECEMBER 13 DECEMBER 31, 13
Why the "weeks" in November, have all 7 days, while the "weeks" in the first or the last week in the other month usually have less? (For example, February 28 is a 'week' alone.)
The following works for the other months:
WITH all_days AS
(
SELECT DATE "2013-01-01' + LEVEL - AS a_date 1
OF the double
CONNECT BY LEVEL<=>
)
SELECT DISTINCT
More GRAND (TRUNC (a_date + 4, 'IW') - 4)
, TRUNC (a_date, 'MONTH')
) AS week_begin
, The LEAST (TRUNC (a_date + 4, 'IW') + 2
TRUNC (LAST_DAY (a_date))
), Week_end
Of all_days
ORDER BY week_begin
;
Output:
WEEK_BEGIN WEEK_END
----------- -----------
January 1, 2013 January 2, 2013
January 3, 2013 January 9, 2013
January 10, 2013 January 16, 2013
January 17, 2013 January 23, 2013
January 24, 2013 January 30, 2013
January 31, 2013 January 31, 2013
February 1, 2013 February 6, 2013
February 7, 2013 February 13, 2013
February 14, 2013 February 20, 2013
February 21, 2013 February 27, 2013
February 28, 2013 February 28, 2013
...
November 1, 2013 November 6, 2013
November 7, 2013 November 13, 2013
November 14, 2013 November 20, 2013
November 21, 2013 November 27, 2013
November 28, 2013 November 30, 2013
December 1, 2013 December 4, 2013
December 5, 2013 December 11, 2013
December 12, 2013 December 18, 2013
December 19, 2013 December 25, 2013
26 December 2013 31 December 2013
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get the first and last day of the year
and razm.date > = to_date ("' 1.01 ' |: $VDATE |", ' dd.mm.yyyy ") AND razm.date < = to_date ('31.12.2010. ' || (": $VDATE |", ' dd.mm.yyyy ");
but I get:
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01830 00000 - "date format picture ends before converting all of the input string.
* Cause:
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Hello
I try to display continue on the first page and average pages and Total amount on the last page on a multipage PO. I can view the page of different footer for the first page and last page, but the pages means is not a footer. What to do if possible. There are so many threads here, but not one gives exact measurements.
first page header footer
Add a Page break
2nd foot header
Add the Section break = > Next Page
<? start@last-page-first:body? > <? end body? >
last page footer
Help, please
Thank youDid you miss this?
http://winrichman.blogspot.com/search/label/different%20page%20header
http://winrichman.blogspot.com/search/label/element%20in%20header
http://winrichman.blogspot.com/search/label/diff%20header -
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I would like to change the name in my profile my name and my company name, so when my clients receive a signature on the Forms application, my company name is displayed in the email as opposed to my first and last name. How can I change this? I tried to edit my profile however my first and last name are not editable fields.
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You connect with Adobe ID account E-Sign? If Yes, then you can directly connect to your Adobe ID account and can update the name as the name of the company and it will reflect in your E-Sign account as well.
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Detect the first and last spark of list items
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You can override the method to data defined in your itemRenderer. Compare the new data for the first and last items in your list. And you set the background depending on the result.
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Need a query to return the first and last date for a rowset.
Hello
I have a query which can be simplified to the following data, if
Assume that it is my dataset, with THE_VALUE of
Sign (Anum) therefore,-1, 0 or 1.
* (Sorry for crushed registration. "I can't understand this website's rich text formatting.) *
THE_VALUE THE_DATE THE_MEMBER
1 0 1 January 2007
1 0 1 February 2007
1 0 1 March 2007
1. 1 April 1, 2007
1 1 1 May 2007
1 0 1 June 2007
1. 1 July 1, 2007
1. 1 August 1, 2007
1 0 01 - sep - 2007
2 0 1 January 2007
2 1 February 1, 2007
2 0 1 March 2007
2. 1 April 1, 2007
2 1 1 May 2007
2 0 1 June 2007
-2 1 1 July 2007
2. 1 August 1, 2007
2. 1 01-sep-2007
3 0 1 January 2007
3. 1 February 1, 2007
3 0 1 March 2007
3 0 1 April 2007
3. 1 May 1, 2007
3 0 1 June 2007
3. 1 July 1, 2007
3. 1 August 1, 2007
3 0 01 - sep - 2007
I need to get the lines with the THE_MEMBER, the values of the first and the last
THE_DATE, where the value is - 1, and the date range is the last
set of lines to the Member, with the same value of THE_VALUE.
I tried the following to get the dates of first and last for a set
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SELECT the_member
the_value
the_date
first_value (the_date)
in the first_date (PARTITION the_member, ORDER BY the_member the_value, the_date)
last_value (the_date)
during the last_date (PARTITION the_member, ORDER BY the_member the_value, the_date)
OF togola
ORDER BY the_member
the_date;
At first, it seems to work, but then, when the return value
an old value, FIRST_DATE will be the first of all the lines containing
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1 0 1 February 2007 1 January 2007 1 February 2007
1 0 1 March 2007 1 January 2007 March 1, 2007
1. 1 April 1, 2007 April 1, 2007 April 1, 2007
1. 1 May 1, 2007 April 1, 2007 may 1, 2007
1-0 June 1, 2007 January 1, 2007 June 1, 2007
1. 1 July 1, 2007 April 1, 2007 July 1, 2007
1. 1 August 1, 2007 April 1, 2007 August 1, 2007
1 0 01 - sep - 2007 1 January 2007 01-Sep-2007
2 0 January 1, 2007 January 1, 2007 January 1, 2007
2 1 1 February 2007 February 1, 2007 February 1, 2007
2 0 1 March 2007 1 January 2007 March 1, 2007
2. 1 April 1, 2007 February 1, 2007 April 1, 2007
2 1 1 May 2007 February 1, 2007 may 1, 2007
2-0 June 1, 2007 January 1, 2007 June 1, 2007
-2 1 1 July 2007 February 1, 2007 July 1, 2007
2. 1 August 1, 2007 February 1, 2007 August 1, 2007
2. 1 01-sep-2007 1 February 2007 01-Sep-2007
3 0 January 1, 2007 January 1, 2007 January 1, 2007
3. 1 February 1, 2007 February 1, 2007 February 1, 2007
3 0 1 March 2007 1 January 2007 March 1, 2007
3 0 April 1, 2007 January 1, 2007 April 1, 2007
3. 1 May 1, 2007 February 1, 2007 may 1, 2007
3 0 June 1, 2007 January 1, 2007 June 1, 2007
3. 1 July 1, 2007 February 1, 2007 July 1, 2007
3. 1 August 1, 2007 February 1, 2007 August 1, 2007
3 0 01 - sep - 2007 1 January 2007 01-Sep-2007
That's what I need to get in the end.
THE_MEMBER FIRST DAY DATE OF LAST
July 2 1 2007-01 - Sep - 2007
Any ideas would be really appreciated.
Published by: user10700981 on December 17, 2008 13:57Hello
We'll call the lines whose the_value =-1 'good' lines and lines with the_value! =-1 ranks of 'bad '.
For each value of the_value, we need the first and last values of the_date where
the last row in the group is good
(b) the current line is good
(c) there is a lot of lines from the current line to the end of the Group
Condition (a) is just a special case of (c).
Conditions (b) and (c) are similar: (b) if applied to the current line, (c) applies to all lines after him. They can easily be combined into a single test that counts the number of lines after the current line or bad.Which produces the results you requested of the sample data that you provided:
WITH count_bad AS ( SELECT the_member , the_date , COUNT ( CASE WHEN the_value != -1 -- assuming the_value is never NULL THEN 1 END ) OVER ( PARTITION BY the_member ORDER BY the_date DESC ) AS bad_cnt FROM table_x ) SELECT the_member , MIN (the_date) AS first_date , MAX (the_date) AS last_date FROM count_bad WHERE bad_cnt = 0 GROUP BY the_member ORDER BY the_member; -
Canon MX870 printer under Win 8.1 prints pages in the wrong order
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Cannot print continue on all pages except the last page in the xml editor
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