get the difference in seconds to a time warp

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• Get the difference in days between 2 dates in Essbase 9.3.1

  How to calculate to get the difference in days between 2 dates in the format day of Essbase 9.3.1.la is 20090101 (yyyymmdd). If 2010907-20100917 = 10 days.
  Start and end dates may extend over several years.

  @DateDiff does not exist in the 9.3.1 I think. With this assumption...

  Could you use the CDF 'Functions of Date'? According to the docs (I've never used it):
  @JdaysOffset - returns the number of days between the firstDate and the secondDate.

  See samplecode.oracle.com for the CDF. Just search for CDF and you will find it on the second page (I think) of the FMCS.

  Or see this thread for another approach that I think the CDF under the covers: Re: Formate Date.

  Of course, you could spend to 11 for DateDiff. :)

  Kind regards

  Cameron Lackpour

• Find the difference between two date and time

  Hi friends,
  
  I wanted to find the difference between two date and time, but my qury is slightest error "invalid number."
  
  

  select sql_step_num,proc_name,run_seqno,start_date,end_date,(to_char(start_date,'HH24-MI-SS') - to_char(end_date,'HH24-MI-SS') ) as ed  
  from eval.EVAL_RUNTIME_DETAILS
  where trunc(start_date) = trunc(sysdate) 
  order by sql_step_num;

  You try to get the feel between two char strings.
  And more difference between two dates gives a NUMBER of days.
  Try this:

  select sql_step_num,proc_name,run_seqno,start_date,end_date,numtodsinterval(end_date-start_date,'DAY') as ed
  from eval.EVAL_RUNTIME_DETAILS
  where trunc(start_date) = trunc(sysdate)
  order by sql_step_num;
  

• I can't use the link 'Check the seats' on Delta when I use Firefox, but Safari works fine. I get the message "not available at this time" when you use Firefox, but when I go on Safari it works just fine.

  I can't use the link 'Check the seats' on the website of Delta Airlines when I use Firefox, but Safari works fine. I get the message "not available at this time" when you use Firefox, but when I go on Safari it works just fine. I love Firefox but it sucks!

  This problem may be caused by corrupted cookies.

  Clear the cache and cookies from sites that cause problems.

  "Clear the Cache":

  • Firefox > Preferences > advanced > network > storage (Cache) offline: 'clear now '.

  'Delete Cookies' sites causing problems:

  • Firefox > Preferences > privacy > Cookies: "show the Cookies".
  • http://KB.mozillazine.org/cookies

• Query to get the difference between 2 totals of 2 different queries

  I wanted to know if it is possible to get the difference between 2 totals of 2 different queries. Let me explain with an example:

  1 application of^st - sum (homepass) Select table 1

  2^th query: select sum (homepass) from table2

  Is it possible to display the difference as -

  Select sum (homepass) in table 1 - sum (homepass) from table2

  I know that the above query would give syntax error, but is there a better way or something to get the above done task from a single query.

  
  

  Hopefully, my question is clear.

  
  

  Please get back with the answer to my query.

  
  

  Concerning

  You can always do something like

  SELECT a.cnt - b.cnt
  FROM (SELECT sum(homepass) cnt from table1) a,
        (SELECT sum(homepass) cnt from table2) b
  

  I'd be somewhat dubious, although on a data model that had two tables with the same name of the column where it really made sense to subtract one amount from each other.  This would strongly imply that there should be a single table with an additional column TYPE eventually.

  Justin

• How to get the difference of two dates in months

  Dear friends,

  I have 4 items on my page.

  2 entered message text (value of loan, monthly deduction)

  2 are message style fields (start date, end date)

  I need to get the difference from above 2 dates in no.. of months. (for example say N)

  So with N, loanvalue should be divided and populated as monthly deduction.

  I tried this way, but not able to get the difference of dates

  {if ("populateMonthlyDeduction". Equals (PageContext.GetParameter (EVENT_PARAM)))}

  System.out.println ("enter populateMonthlyDeduction loop1");

  String xxDeductionStartDate = vo.getCurrentRow ().getAttribute("DeducStartDt").toString ();

  System.out.println ("xxDeductionStartDate is:" + xxDeductionStartDate);

  TXN OADBTransaction = am.getOADBTransaction ();

  java.sql.Date DeductionSDate = null;

  java.sql.Date DeductionEDate = null;

  if(xxDeductionStartDate!=null)

  {

  java.sql.Date startDate = txn.getOANLSServices () .stringToDate (xxDeductionStartDate);

  DeductionSDate = startDate;

  System.out.println ("DeductionSDate is:" + DeductionSDate);

  }

  String xxDeductionEndDate = vo.getCurrentRow ().getAttribute("DedEndDt").toString ();

  if(xxDeductionEndDate!=null)

  {

  java.sql.Date endDate = txn.getOANLSServices () .stringToDate (xxDeductionEndDate);

  DeductionEDate = endDate;

  System.out.println ("DeductionEDate is:" + DeductionEDate);

  }

  int difInDays = xxDeductionEndDate-xxDeductionStartDate; -Please correct me

  How reach it .plz help.

  Thank you

  Aravinda

  I used a custom like this method and calls this method daysBetween PFR.

  I got it. Thanks to you all.

  public int daysBetween(As Date, Date etDate)

  {

  return (int) ((etDate.getTime () - stDate.getTime (()) / (1000 * 60 * 60 * 24));

  }

  If ("populateMonthlyDeduction". Equals (PageContext.GetParameter (EVENT_PARAM)))

  {

  System.out.println ("enter populateMonthlyDeduction loop1");

  String dedStDt = vo.getCurrentRow ().getAttribute("DeducStartDt").toString ();

  String dedEndDt = vo.getCurrentRow ().getAttribute("DedEndDt").toString ();

  If (! dedStDt.Equals (null) &! dedEndDt.equals (null))

  {

  SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd");

  Date sdate = new Date();

  Date edate = new Date();

  String sdate1 = null;

  String edate1 = null;

  try {}

  sdate = dateFormat.parse (dedStDt);

  EDATE = dateFormat.parse (dedEndDt);

  SimpleDateFormat dateFormat1 = new SimpleDateFormat("dd-MMM-yyyy");

  sdate1 = dateFormat1.format (sdate);

  edate1 = dateFormat1.format (edate);

  int days = daysBetween(sdate, edate);

  int diffInMonths = days/30;

  System.out.println ("days is:" + days);

  System.out.println ("diffInMonths is:" + diffInMonths);

  String sTotValueTuitionFees = vom.getCurrentRow ().getAttribute("TotValueTuitionFees").toString ();//pageContext.getParameter("LoanValue").toString();

  int iTotValueTuitionFees = Integer.parseInt (sTotValueTuitionFees);

  int iMonthlyDeduction = iTotValueTuitionFees/diffInMonths;

  String sMonthlyDeduction = String.valueOf (iMonthlyDeduction);

  System.out.println ("iMonthlyDeduction is:" + sMonthlyDeduction);

  OAMessageStyledTextBean bMonthlyDeduction = (OAMessageStyledTextBean) webBean.findChildRecursive ("MonthlyDeduction");

  bMonthlyDeduction.setValue (pageContext, sMonthlyDeduction);

  }

  catch (ParseException exception) e

  {

  }

  }

  }

• The most elegant way to get the difference between two tables - not least!

  Hello
  
  
  Simplified example of what I'm trying to achieve - I have two tables ORIGINAL and REVISED.
  
  
  My aim is to compare the two, such as; -
  
  
  When there is data in the two tables I get the difference between the Budget column, and if there is no difference, so I don't want no lines.
  
  When data exists in the ORIGINAL, but not in review, I want to the inverse of the current value of the Budget column.
  
  Where the data exist in REVISED I want the REVISED value.
  
  I can see how I can do this, see below, but is there a more elegant solution?
  
  
  
  
  Data for the ORIGINAL table
  

  select '801040' entity, '2186' expense_type, 234000 budget
  from dual
  union all
  select '801040' entity, '3001' expense_type, 1000 budget
  from dual
  union all
  select '801040' entity, 'P132' expense_type, 34000 budget
  from dual
  union all
  select '801040' entity, 'P135' expense_type, 43000 budget
  from dual

  Data for the REVISED table
  

  select '801040' entity, '2186' expense_type, 235000 budget
  from dual
  union all
  select '801040' entity, 'P132' expense_type, 34000 budget
  from dual
  union all
  select '801040' entity, 'P139' expense_type, 56000 budget
  from dual

  Desired output
  
  
  
  ENTITY EXPENSE_TYPE DIFFERENCE
  ------ ------------ ----------
  801040 2186 1000
  801040 3001-1000
  801040 P135-43000
  801040 P139 56000
  
  5 selected lines.
  
  
  
  Code current to achieve this, is there a better way?
  

  select original.entity
  ,      original.expense_type
  ,       (nvl(revised.budget,0) - original.budget) as difference
  from   original
  ,      revised
  where  original.entity = revised.entity(+)
  and    original.expense_type = revised.expense_type(+)
  and   (nvl(revised.budget,0) - original.budget) != 0
  union all
  select  revised.entity
  ,       revised.expense_type
  ,       revised.budget as difference
  from   revised
  where  not exists
  (select 'x'
  from   original
  where  original.entity = revised.entity
  and    original.expense_type = revised.expense_type)
  and    revised.budget != 0

  Thanks a lot for your comments,.
  
  
  Robert.
  
  Published by: Robert Angel on January 17, 2012 03:31 to change is not equal to! = - Thanks for the heads up

  SQL> with original
    2  as
    3  (
    4    select '801040' entity, '2186' expense_type, 234000 budget
    5    from dual
    6    union all
    7    select '801040' entity, '3001' expense_type, 1000 budget
    8    from dual
    9    union all
   10    select '801040' entity, 'P132' expense_type, 34000 budget
   11    from dual
   12    union all
   13    select '801040' entity, 'P135' expense_type, 43000 budget
   14    from dual
   15  )
   16  , revised
   17  as
   18  (
   19    select '801040' entity, '2186' expense_type, 235000 budget
   20    from dual
   21    union all
   22    select '801040' entity, 'P132' expense_type, 34000 budget
   23    from dual
   24    union all
   25    select '801040' entity, 'P139' expense_type, 56000 budget
   26    from dual
   27  )
   28  select *
   29    from (
   30          select nvl(o.entity, r.entity) entity,
   31                 nvl(o.expense_type, r.expense_type) expense_type,
   32                 nvl(r.budget,0) - nvl(o.budget,0) budget
   33            from original o
   34            full join revised r
   35              on o.entity = r.entity
   36             and o.expense_type = r.expense_type
   37         )
   38   where budget <> 0
   39  /
  
  ENTITY EXPE     BUDGET
  ------ ---- ----------
  801040 2186       1000
  801040 P135     -43000
  801040 3001      -1000
  801040 P139      56000
  
  SQL>
  

• Trying to get the 'difference' between the two tracks

  What I'm trying to accomplish is the following: I have an audio track of a voice-over with a music bed located underneath. I also itsself Chamber music, without the voiceover. I want only the share of voice. Is it possible that I can "cancel out" the part of the music or get the difference between the two tracks (just the voice part)? It seems that there should be a way to do it, but for the life of me I can't figure out how do it!

  Any advice?

  There you go...

  http://www.libinst.com/audio%20DiffMaker.htm

  Unfortunately, the above utility has been abandoned by its author.  :-(

  It only works on Windows XP, to start...

  -RFH

• Dynamic action - Get the difference between two dates + times

  I have problems a little dynamic to work action. I'm trying to get the time between two dates with the time difference.
  
  Here is what I got (this is apex 4.0):
  
  Two date pickers + two numbers fields (date/start/end times)
  
  I created a dynamic action on the page who fires on the point lose focus (above points).
  
  The real action for the DA is the body of the PL/SQL function:

  declare
    end_date DATE;
    start_date DATE;
  Begin
    start_date := to_char(:P1_START_DATE || ' ' || :P1_START_TIME, 'DD-MON-YYYY HH:MIAM');
    end_date := to_char(:P1_END_DATE || ' ' || :P1_END_TIME, 'DD-MON-YYYY HH:MIAM');
    :P1_HOURS := end_date-start_date;
  End;

  When I change the values on the page, I get the following error:
  
  AJAX call back Server error ORA-06502: PL/SQL: digital or value error: character number conversion error to set the value.
  
  I'm guessing that there is a problem with the date formatting, but I can't make it work. Thanks in advance!

  Hi djston,

  because you chose the dynamic action of 'Set value' with the "Body of the PL/SQL function" type you need to return the value. Try the following code

  declare
    end_date DATE;
    start_date DATE;
  Begin
    start_date := to_date(:P1_START_DATE || ' ' || :P1_START_TIME, 'DD-MM-YYYY HH:MIAM');
    end_date := to_date(:P1_END_DATE || ' ' || :P1_END_TIME, 'DD-MM-YYYY HH:MIAM');
    RETURN (end_date-start_date)*24;
  End;
  

  and P1_REQUESTED_HOURS like 'item affected. "

  Concerning
  Patrick
  -----------
  My Blog: http://www.inside-oracle-apex.com
  APEX 4.0 Plug-Ins: http://apex.oracle.com/plugins
  Twitter: http://www.twitter.com/patrickwolf

  Published by: Patrick Wolf on January 17, 2011 10:54

• Get the difference of 2 timestamps in days

  I have 2 dates that are stored as the timestamps and I need the number of days between these two days.

  If I just subtract these 2, I get an interval but I need the exact number of days.

  I tried to get rid of the last part when I the difference but it does not work. (for example 12 00:00:00, I tried to get rid of the 00:00:00)

  for example, I gave the date when we send an invoice and the date when it is paid, and I need to know if it is paid in time or not.

  No idea how I could do this work? The fact that these are the timestamps causes problems for me.

  Thanks in advance

  If you don't care to fractions of a second:

  Cast (ts_end as date) - cast (ts_start as date)

  SY.

• How to find the difference between two dates in time except Sunday

  Hi all
  
  I have a table, as shown below.

  SQL> select * from test;
  
  TR_ID                                              CREATE_TIME                                                                       CODE
  -------------------------------------------------- --------------------------------------------------------------------------- ----------
  S12341                                             05-JUN-12 12.20.52.403000 AM                                                      1003
  S12342                                             11-JUN-12 11.15.33.182000 AM                                                      1003
  S12342                                             07-JUN-12 12.00.36.573000 PM                                                      1002
  S12343                                             20-JUN-12 12.34.37.102000 AM                                                      1003
  S12343                                             15-JUN-12 11.34.27.141000 PM                                                      1002
  S12344                                             01-JUL-12 10.01.06.657000 PM                                                      1002
  S12344                                             06-JUL-12 12.01.04.188000 AM                                                      1003
  S12341                                             31-MAY-12 11.20.38.529000 PM                                                      1002

  I would like to know the difference between same tr_ids create_time, which should give out in hours except Sunday.
  
  For example:
  
  TR_ID: S12344
  1002_Create_time: July 1, 12 PM 10.01.06.657000 (i.e. Sunday)
  1003_Create_time: 12.01.04.188000 AM 6 July 12
  
  1002 create time is 22:00 Sunday.
  
  If the query must exclude only the hours of Sunday which is 10 p.m. to Monday 00 h which is 2 Hrs.
  
  I tried the sub query after doing a search on this forum but I am not getting the desired output.
  

  SELECT count(*) FROM (SELECT ROWNUM RNUM,tr_id,create_time CT_1002 FROM test c WHERE c.tr_id='S12344' and 
  ROWNUM <= (select (cast(a.create_time as date)-cast((select create_time from test b where a.tr_id=b.tr_id and code=1002) as date)) 
  from test a where a.code=1003 and a.tr_id=c.tr_id) + 1) d 
  WHERE to_char(cast((select create_time from test e where e.tr_id=d.tr_id and code=1002) as date) + RNUM - 1, 'DY') NOT IN('SUN');

  Need help to get the desired o/p

  Hello

  If I unederstand the problem correctly, that's what you want:

  WITH       got_extrema     AS
  (
       SELECT       tr_id
       ,       CAST (MIN (create_time) AS DATE)     AS start_date
       ,       CAST (MAX (create_time) AS DATE)     AS end_date
       FROM       test
       GROUP BY  tr_id
  )
  SELECT       tr_id
  ,       start_date, end_date          -- If wanted
  ,       24 * ( ( ( TRUNC (end_date,   'IW')          -- Count -1 day for every full week
                      - TRUNC (start_date, 'IW')
               )
             / -7
                )
              + LEAST ( end_date               -- If end_date is a Sunday
                          , TRUNC (end_date, 'IW') + 6     -- consider it 00:00:00 on Sunday
                   )
              - CASE
                        WHEN  start_date >= TRUNC (start_date, 'IW') + 6     -- If start_date is a Sunday
                 THEN  TRUNC (start_date, 'IW') + 6               -- consider it 00:00:00 Sunday
                 ELSE  start_date
                    END
              )     AS total_hours
  FROM      got_extrema
  ;
  

  I guess that you don't need to worry about fractions of a second. As you did in the code you have posted, I am to convert the TIMESTAMP to date values, because of DATE arithmetic and functions are so much better than what is available for timestamps.

  Basically, it's just to find the number of days between start_date and end_date and multiplying by 24, with these twists:
  (a) 1 day is deducted for each week between start_date and end_date
  (b) if End_date is a Sunday, none of the end_date himself hours are counted
  (c) If start_date is a Sunday, then all the start_date himself hours are counted. Why these hours should be counted? Because 1 day is already being deducted for the week which includes start_date, which contains only this Sunday.

  TRUNC (dt, 'IW') is the beginning of the ISO week containing dt; in other words, 00:00:00 the or before the dt last Monday. This is not the NLS parameters.

  Of course, I can't test without some sample data and the exact results you want from these data. You may need a little something more If start_date and end_date are both on the same Sunday.
  Whenever you have a problem, please post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) of all of the tables involved.
  Also post the results you want from this data, as well as an explanation of how you get these results from these data, with specific examples.
  Always tell what version of Oracle you are using.
  See the FAQ forum {message identifier: = 9360002}

• How to get the difference in dates in days

  Hi friends,
  
  How to get the date difference between two dates exactly
  
  date2-date1 days exactly... shouyld rounded to the nearest value of...
  
  and one entire display i mean positive integer
  Select round ((sysdate) - to_date (date_start)), date_start days of per_periods_of_service
  
  This gives negative also result

  Hello

  776317 wrote:
  Hi friends,

  How to get the date difference between two dates exactly

  date2-date1 days exactly... shouyld rounded to the nearest value of...

  Date1 - date2 is the exact number of days is after date2 date1. (It is as accurate as possible, given that the DATEs do not have fractions of a second).

  and one entire display i mean positive integer
  Select round ((sysdate) - to_date (date_start)), date_start days of per_periods_of_service

  You want to probably get the exact number of days first, then ROUND this number:

  SELECT  ROUND (SYSDATE - TO_DATE (date_start, ...))   AS days
  FROM    per_periods_of_service; 
  

  Always pass arguments at least 2 to TO_DATE:
  (1) the string to be converted, and
  (2) a saying string how (1) is formatted

  This gives negative also result

  Right; If date1 is before date2 then date1 - date2 returns a negative number.
  If you want to never get a negative value, use ABS (date2 - date1). If it returns 4, then you know that one of the DATEs was 4 days before the other, but you won't know who was earlier.

  I hope that answers your question.
  If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) and also publish outcomes from these data.
  Explain, using specific examples, how you get these results from these data.
  Always tell what version of Oracle you are using.

• How to get the difference of current and previous line for a column of the same table?

  Hello

  I have a table where there are 3 rows and say 2 columns only, as below

  Col1               | Col2
  --------------------- |----------------------------------------

  first_flag |  100

  second_flag |  104

  third_flag |  110

  Now, using sql, which accepts a parameter col1, how do I get the bottom o/p

  say that the entry is second_flag,

  output must be

  second_flag, 104, 4 (4 being the difference between 104 and 100)

  If I give the entry like third_flag, the output should be

  third_flag, 110, 6 (6 is the difference between 110 and 104)

  Any help?

  Hello

  Another way is to use the analytic LAG function:

  WITH got_diff AS

  (

  SELECT col1, col2

  , col2 - LAG (col2) over (ORDER BY col1) AS diff

  OF mydata

  )

  SELECT *.

  OF got_diff

  WHERE col1 =: flag_wanted

  ;

  This assumes that the lines are in alphabetical order by col1.  If the order is something else, then use it in the ORDER BY clause analytical.

• Calculate the difference between AM and PM time

  I use a form and I want to have the time between two times calculated. This part works - but I have problems getting the data after that contribution has been calculated.

  When you enter a time in the format hh: mm tt - I so that it has calculated and output in the format hh: mm already. He does not accept this entry however - just trying to use everything that is initially formatted. Currently, this is how I capture the data of these two areas, I need to take data. I can take this and people have to use military time, but I'd rather just take input in the format hh: mm tt.

  var hrsStart = parseInt(this.getField("sTime").value.split(":")[0]); 
  var minStart = parseInt(this.getField("sTime").value.split(":")[1]); 
  var hrsEnd = parseInt(this.getField("stTime").value.split(":")[0]); 
  var minEnd = parseInt(this.getField("stTime").value.split(":")[1]); 
  

  That's how I'm calculation of data entry in the two fields.

  var time = this.getField("stTime"); 
  var hours = Number(time.match(/^(\d+)/)[1]); 
  var minutes = Number(time.match(/:(\d+)/)[1]); 
  var AMPM = time.match(/\s(.*)$/)[1].toLowerCase(); 
   
  if (AMPM == "pm" && hours < 12) hours = hours + 12; 
  if (AMPM == "am" && hours == 12) hours = hours - 12; 
  var sHours = hours.toString(); 
  var sMinutes = minutes.toString(); 
   
  if (hours < 10) sHours = "0" + sHours; 
  if (minutes < 10) sMinutes = "0" + sMinutes; 
  
  
  this.getField("stTime").value = (sHours +':'+sMinutes); 
  

  My answer of Validation?

  I also tried to make getHours / getMinutes, but values come up unresolved.

  I will accept any help - even if it is not consistent with this solution.  I agree with being completely wrong.  =)

  You must add the part of the date as a static string in your code. Something like this:

  util. SCAND ("h: mm tt d/m/yy", strStart + "01/01/15");

• I want to cancel a download that downloads still go on the second day. It just says: get set up 1 second of estimated time

  I tried to cancel a download that happened on its second day, the only thing he said to me, it's the application in place has an estimated time of 1 second.

  Right click on the taskbar, the Manager select task and, in the 'Applications' tab, select the download and click "end task." (you may need to click on 2 or 3 times if it broke down)