Get the difference of 2 timestamps in days

Similar Questions

• Get the difference in days between 2 dates in Essbase 9.3.1

  How to calculate to get the difference in days between 2 dates in the format day of Essbase 9.3.1.la is 20090101 (yyyymmdd). If 2010907-20100917 = 10 days.
  Start and end dates may extend over several years.

  @DateDiff does not exist in the 9.3.1 I think. With this assumption...

  Could you use the CDF 'Functions of Date'? According to the docs (I've never used it):
  @JdaysOffset - returns the number of days between the firstDate and the secondDate.

  See samplecode.oracle.com for the CDF. Just search for CDF and you will find it on the second page (I think) of the FMCS.

  Or see this thread for another approach that I think the CDF under the covers: Re: Formate Date.

  Of course, you could spend to 11 for DateDiff. :)

  Kind regards

  Cameron Lackpour

• How to get the difference of two dates in months

  Dear friends,

  I have 4 items on my page.

  2 entered message text (value of loan, monthly deduction)

  2 are message style fields (start date, end date)

  I need to get the difference from above 2 dates in no.. of months. (for example say N)

  So with N, loanvalue should be divided and populated as monthly deduction.

  I tried this way, but not able to get the difference of dates

  {if ("populateMonthlyDeduction". Equals (PageContext.GetParameter (EVENT_PARAM)))}

  System.out.println ("enter populateMonthlyDeduction loop1");

  String xxDeductionStartDate = vo.getCurrentRow ().getAttribute("DeducStartDt").toString ();

  System.out.println ("xxDeductionStartDate is:" + xxDeductionStartDate);

  TXN OADBTransaction = am.getOADBTransaction ();

  java.sql.Date DeductionSDate = null;

  java.sql.Date DeductionEDate = null;

  if(xxDeductionStartDate!=null)

  {

  java.sql.Date startDate = txn.getOANLSServices () .stringToDate (xxDeductionStartDate);

  DeductionSDate = startDate;

  System.out.println ("DeductionSDate is:" + DeductionSDate);

  }

  String xxDeductionEndDate = vo.getCurrentRow ().getAttribute("DedEndDt").toString ();

  if(xxDeductionEndDate!=null)

  {

  java.sql.Date endDate = txn.getOANLSServices () .stringToDate (xxDeductionEndDate);

  DeductionEDate = endDate;

  System.out.println ("DeductionEDate is:" + DeductionEDate);

  }

  int difInDays = xxDeductionEndDate-xxDeductionStartDate; -Please correct me

  How reach it .plz help.

  Thank you

  Aravinda

  I used a custom like this method and calls this method daysBetween PFR.

  I got it. Thanks to you all.

  public int daysBetween(As Date, Date etDate)

  {

  return (int) ((etDate.getTime () - stDate.getTime (()) / (1000 * 60 * 60 * 24));

  }

  If ("populateMonthlyDeduction". Equals (PageContext.GetParameter (EVENT_PARAM)))

  {

  System.out.println ("enter populateMonthlyDeduction loop1");

  String dedStDt = vo.getCurrentRow ().getAttribute("DeducStartDt").toString ();

  String dedEndDt = vo.getCurrentRow ().getAttribute("DedEndDt").toString ();

  If (! dedStDt.Equals (null) &! dedEndDt.equals (null))

  {

  SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd");

  Date sdate = new Date();

  Date edate = new Date();

  String sdate1 = null;

  String edate1 = null;

  try {}

  sdate = dateFormat.parse (dedStDt);

  EDATE = dateFormat.parse (dedEndDt);

  SimpleDateFormat dateFormat1 = new SimpleDateFormat("dd-MMM-yyyy");

  sdate1 = dateFormat1.format (sdate);

  edate1 = dateFormat1.format (edate);

  int days = daysBetween(sdate, edate);

  int diffInMonths = days/30;

  System.out.println ("days is:" + days);

  System.out.println ("diffInMonths is:" + diffInMonths);

  String sTotValueTuitionFees = vom.getCurrentRow ().getAttribute("TotValueTuitionFees").toString ();//pageContext.getParameter("LoanValue").toString();

  int iTotValueTuitionFees = Integer.parseInt (sTotValueTuitionFees);

  int iMonthlyDeduction = iTotValueTuitionFees/diffInMonths;

  String sMonthlyDeduction = String.valueOf (iMonthlyDeduction);

  System.out.println ("iMonthlyDeduction is:" + sMonthlyDeduction);

  OAMessageStyledTextBean bMonthlyDeduction = (OAMessageStyledTextBean) webBean.findChildRecursive ("MonthlyDeduction");

  bMonthlyDeduction.setValue (pageContext, sMonthlyDeduction);

  }

  catch (ParseException exception) e

  {

  }

  }

  }

• Hi, having trouble getting the installer of Creative Cloud 30 day trial to boot on my computer.

  Hi, I have trouble getting the installer of Creative Cloud 30 day trial to boot on my computer.  Here I did successfully about 3 days ago, but since then has picked up a virus.  I used system restore to restore my computer about 5 days, which was to remove the creative cloud and Photoshop.  Now I am trying to re - download creative cloud with no luck.  Any idea would be highly desirable. -Demian Arend

  Hello

  Sign out of your account... Uninstall... to run vacuuming...

  -http://helpx.adobe.com/creative-cloud/help/install-apps.html (and uninstall)

  -using the vacuuming after uninstalling and prior to the relocation is necessary

  -https://helpx.adobe.com/creative-suite/kb/cs5-cleaner-tool-installation-problems.html

• Query to get the difference between 2 totals of 2 different queries

  I wanted to know if it is possible to get the difference between 2 totals of 2 different queries. Let me explain with an example:

  1 application of^st - sum (homepass) Select table 1

  2^th query: select sum (homepass) from table2

  Is it possible to display the difference as -

  Select sum (homepass) in table 1 - sum (homepass) from table2

  I know that the above query would give syntax error, but is there a better way or something to get the above done task from a single query.

  
  

  Hopefully, my question is clear.

  
  

  Please get back with the answer to my query.

  
  

  Concerning

  You can always do something like

  SELECT a.cnt - b.cnt
  FROM (SELECT sum(homepass) cnt from table1) a,
        (SELECT sum(homepass) cnt from table2) b
  

  I'd be somewhat dubious, although on a data model that had two tables with the same name of the column where it really made sense to subtract one amount from each other.  This would strongly imply that there should be a single table with an additional column TYPE eventually.

  Justin

• The most elegant way to get the difference between two tables - not least!

  Hello
  
  
  Simplified example of what I'm trying to achieve - I have two tables ORIGINAL and REVISED.
  
  
  My aim is to compare the two, such as; -
  
  
  When there is data in the two tables I get the difference between the Budget column, and if there is no difference, so I don't want no lines.
  
  When data exists in the ORIGINAL, but not in review, I want to the inverse of the current value of the Budget column.
  
  Where the data exist in REVISED I want the REVISED value.
  
  I can see how I can do this, see below, but is there a more elegant solution?
  
  
  
  
  Data for the ORIGINAL table
  

  select '801040' entity, '2186' expense_type, 234000 budget
  from dual
  union all
  select '801040' entity, '3001' expense_type, 1000 budget
  from dual
  union all
  select '801040' entity, 'P132' expense_type, 34000 budget
  from dual
  union all
  select '801040' entity, 'P135' expense_type, 43000 budget
  from dual

  Data for the REVISED table
  

  select '801040' entity, '2186' expense_type, 235000 budget
  from dual
  union all
  select '801040' entity, 'P132' expense_type, 34000 budget
  from dual
  union all
  select '801040' entity, 'P139' expense_type, 56000 budget
  from dual

  Desired output
  
  
  
  ENTITY EXPENSE_TYPE DIFFERENCE
  ------ ------------ ----------
  801040 2186 1000
  801040 3001-1000
  801040 P135-43000
  801040 P139 56000
  
  5 selected lines.
  
  
  
  Code current to achieve this, is there a better way?
  

  select original.entity
  ,      original.expense_type
  ,       (nvl(revised.budget,0) - original.budget) as difference
  from   original
  ,      revised
  where  original.entity = revised.entity(+)
  and    original.expense_type = revised.expense_type(+)
  and   (nvl(revised.budget,0) - original.budget) != 0
  union all
  select  revised.entity
  ,       revised.expense_type
  ,       revised.budget as difference
  from   revised
  where  not exists
  (select 'x'
  from   original
  where  original.entity = revised.entity
  and    original.expense_type = revised.expense_type)
  and    revised.budget != 0

  Thanks a lot for your comments,.
  
  
  Robert.
  
  Published by: Robert Angel on January 17, 2012 03:31 to change is not equal to! = - Thanks for the heads up

  SQL> with original
    2  as
    3  (
    4    select '801040' entity, '2186' expense_type, 234000 budget
    5    from dual
    6    union all
    7    select '801040' entity, '3001' expense_type, 1000 budget
    8    from dual
    9    union all
   10    select '801040' entity, 'P132' expense_type, 34000 budget
   11    from dual
   12    union all
   13    select '801040' entity, 'P135' expense_type, 43000 budget
   14    from dual
   15  )
   16  , revised
   17  as
   18  (
   19    select '801040' entity, '2186' expense_type, 235000 budget
   20    from dual
   21    union all
   22    select '801040' entity, 'P132' expense_type, 34000 budget
   23    from dual
   24    union all
   25    select '801040' entity, 'P139' expense_type, 56000 budget
   26    from dual
   27  )
   28  select *
   29    from (
   30          select nvl(o.entity, r.entity) entity,
   31                 nvl(o.expense_type, r.expense_type) expense_type,
   32                 nvl(r.budget,0) - nvl(o.budget,0) budget
   33            from original o
   34            full join revised r
   35              on o.entity = r.entity
   36             and o.expense_type = r.expense_type
   37         )
   38   where budget <> 0
   39  /
  
  ENTITY EXPE     BUDGET
  ------ ---- ----------
  801040 2186       1000
  801040 P135     -43000
  801040 3001      -1000
  801040 P139      56000
  
  SQL>
  

• Trying to get the 'difference' between the two tracks

  What I'm trying to accomplish is the following: I have an audio track of a voice-over with a music bed located underneath. I also itsself Chamber music, without the voiceover. I want only the share of voice. Is it possible that I can "cancel out" the part of the music or get the difference between the two tracks (just the voice part)? It seems that there should be a way to do it, but for the life of me I can't figure out how do it!

  Any advice?

  There you go...

  http://www.libinst.com/audio%20DiffMaker.htm

  Unfortunately, the above utility has been abandoned by its author.  :-(

  It only works on Windows XP, to start...

  -RFH

• How to get the difference in dates in days

  Hi friends,
  
  How to get the date difference between two dates exactly
  
  date2-date1 days exactly... shouyld rounded to the nearest value of...
  
  and one entire display i mean positive integer
  Select round ((sysdate) - to_date (date_start)), date_start days of per_periods_of_service
  
  This gives negative also result

  Hello

  776317 wrote:
  Hi friends,

  How to get the date difference between two dates exactly

  date2-date1 days exactly... shouyld rounded to the nearest value of...

  Date1 - date2 is the exact number of days is after date2 date1. (It is as accurate as possible, given that the DATEs do not have fractions of a second).

  and one entire display i mean positive integer
  Select round ((sysdate) - to_date (date_start)), date_start days of per_periods_of_service

  You want to probably get the exact number of days first, then ROUND this number:

  SELECT  ROUND (SYSDATE - TO_DATE (date_start, ...))   AS days
  FROM    per_periods_of_service; 
  

  Always pass arguments at least 2 to TO_DATE:
  (1) the string to be converted, and
  (2) a saying string how (1) is formatted

  This gives negative also result

  Right; If date1 is before date2 then date1 - date2 returns a negative number.
  If you want to never get a negative value, use ABS (date2 - date1). If it returns 4, then you know that one of the DATEs was 4 days before the other, but you won't know who was earlier.

  I hope that answers your question.
  If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) and also publish outcomes from these data.
  Explain, using specific examples, how you get these results from these data.
  Always tell what version of Oracle you are using.

• get the difference in seconds to a time warp

  I need to find a way faster than:
  
  (
  To_date (to_char (TO_NUMBER (utc_date_new)), 'YYYYMMDDHH24MISS')-
  To_date (to_char (TO_NUMBER (utc_date_old)), 'YYYYMMDDHH24MISS')
  ) * 1440
  
  Thanks... ;(

  Hello

  Rusty75 wrote:
  Sorry, and Yes, his minutes (under a strain here)

  column has been defined as TIME_UTC VARCHAR2(14 BYTE) NOT NULL

  So basically it's a bad situation

  How heavy this weighing in a join will select the instruction?
  for example, left to join an intermediate table (200,000), with a huge table (40.000.000 rows)
  where is equal to staging.varchar indexed field huge varchar field table
  AND that calculated the difference > 5?

  See [when your query takes too Long | http://forums.oracle.com/forums/message.jspa?messageID=1812597#1812597] for what you must post to get advice on the setting.
  Are you saying that the part of the join condition which is the date of a table must be at least 5 minutes later at the time of the other table? In other words, you're doing something like:

  FROM          staging          s
  LEFT OUTER JOIN     huge_table     h     ON     h.txt     = s.txt
                                   AND     ( TO_DATE (s.utc_date_new, 'YYYYMMDDHH24MISS')
                                - TO_DATE (h.utc_date_old, 'YYYYMMDDHH24MISS')
                                ) * 1440 > 5
  

  If so, try to change the terms of join like this:

  FROM          staging          s
  LEFT OUTER JOIN     huge_table     h     ON     h.txt          = s.txt
                                   AND     h.utc_date_old  < s.utc_date_new
                                   AND     ( TO_DATE (s.utc_date_new, 'YYYYMMDDHH24MISS')
                                - TO_DATE (h.utc_date_old, 'YYYYMMDDHH24MISS')
                                ) > (5 / 1440)
  

  Even if the new condition (the other,

                                   AND     h.utc_date_old  < s.utc_date_new
  

  are covered by the third condition, it can leave a lot of matches be excluded without a conversion from VARCHAR2 to this DAY.
  Also, don't multiply each difference in 1440; Just compare the difference within days to a constant. I don't know if the optimizer is smart enough to do it for you, but why take the risk?

  would be to limit the calculation to: to_date (to_number (nw.time_utc), \'YYYYMMDDHH24MISS\')
  give a significant increase in speed?

  I think it's the opposite. The first TO_DATE argument must be a string; the above expression is to convert the string to a NUMBER (which takes a while), and while the NUMBER is implicitly converted to a VARCHAR2 (which takes more time).

• How to get the difference of current and previous line for a column of the same table?

  Hello

  I have a table where there are 3 rows and say 2 columns only, as below

  Col1               | Col2
  --------------------- |----------------------------------------

  first_flag |  100

  second_flag |  104

  third_flag |  110

  Now, using sql, which accepts a parameter col1, how do I get the bottom o/p

  say that the entry is second_flag,

  output must be

  second_flag, 104, 4 (4 being the difference between 104 and 100)

  If I give the entry like third_flag, the output should be

  third_flag, 110, 6 (6 is the difference between 110 and 104)

  Any help?

  Hello

  Another way is to use the analytic LAG function:

  WITH got_diff AS

  (

  SELECT col1, col2

  , col2 - LAG (col2) over (ORDER BY col1) AS diff

  OF mydata

  )

  SELECT *.

  OF got_diff

  WHERE col1 =: flag_wanted

  ;

  This assumes that the lines are in alphabetical order by col1.  If the order is something else, then use it in the ORDER BY clause analytical.

• How to store the difference between two timestamps as a number?

  Hello
  I need to find the difference between 2 variables of timestamp and the result will be stored as a number in minutes?
  as
  declare
  timestamp (7) of the fir_timestamp: = 1 January 2012 13:30 ';
  timestamp (7) of the sec_timestamp: = 1 January 2012 14:00 ';
  c number;
  Start
  c:=((sec_timestamp-fir_timestamp)/(24*60));
  dbms_output.put_line (c);
  end;

  962813 wrote:
  declare

  -fir_timestamp timestamp (7): ='01 - jan - 2012 13:30 ';
  timestamp (7) of the sec_timestamp: = 1 January 2012 14:00 ';  Incorrect type declaration

  fir_timestamp timestamp: = 1st January 12 01.30.00.000000 PM';
  sec_timestamp timestamp: = 1st January 12 02.00.00.000000 PM';
  c number;
  Start
  c: = ABS ((extrait (HEURE de sec_timestamp) - extract (fir_timestamp TIME)) * 60) +.
  ABS ((extrait (MINUTE de sec_timestamp) - extract (fir_timestamp MINUTE)));
  dbms_output.put_line (' interval Min Total:-' | c);
  end;
  /
  declare
  *
  ERROR on line 1:
  ORA-01830: date format picture ends before converting all of the input string
  ORA-06512: at line 6

  Follow what Paul has done...

  In fact, you do not need timestamp, date data type is enough

  SQL> declare
    2     fir_timestamp date :=
    3        to_date('01-jan-2012 13:30:00','dd-mon-yyyy hh24:mi:ss');
    4     sec_timestamp date :=
    5        to_date('01-jan-2012 14:00:00','dd-mon-yyyy hh24:mi:ss');
    6     c number;
    7  begin
    8     c:= round((sec_timestamp-fir_timestamp)*24*60);
    9     dbms_output.put_line(c);
   10  end;
   11  /
  30
  
  PL/SQL procedure successfully completed.
  

  If you want to place on timestamp

  SQL> declare
    2     fir_timestamp timestamp :=
    3        to_timestamp('01-jan-2012 13:30:00','dd-mon-yyyy hh24:mi:ss');
    4     sec_timestamp timestamp :=
    5        to_timestamp('01-jan-2012 14:00:00','dd-mon-yyyy hh24:mi:ss');
    6     c number;
    7  begin
    8     c:= round((
    9     to_date(to_char(sec_timestamp,'ddmmyyyyhh24miss'),
   10             'ddmmyyyyhh24miss')-
   11          to_date(to_char(fir_timestamp,'ddmmyyyyhh24miss'),
   12             'ddmmyyyyhh24miss')
   13           )*24*60);
   14     dbms_output.put_line(c);
   15  end;
   16  /
  30
  

• Dynamic action - Get the difference between two dates + times

  I have problems a little dynamic to work action. I'm trying to get the time between two dates with the time difference.
  
  Here is what I got (this is apex 4.0):
  
  Two date pickers + two numbers fields (date/start/end times)
  
  I created a dynamic action on the page who fires on the point lose focus (above points).
  
  The real action for the DA is the body of the PL/SQL function:

  declare
    end_date DATE;
    start_date DATE;
  Begin
    start_date := to_char(:P1_START_DATE || ' ' || :P1_START_TIME, 'DD-MON-YYYY HH:MIAM');
    end_date := to_char(:P1_END_DATE || ' ' || :P1_END_TIME, 'DD-MON-YYYY HH:MIAM');
    :P1_HOURS := end_date-start_date;
  End;

  When I change the values on the page, I get the following error:
  
  AJAX call back Server error ORA-06502: PL/SQL: digital or value error: character number conversion error to set the value.
  
  I'm guessing that there is a problem with the date formatting, but I can't make it work. Thanks in advance!

  Hi djston,

  because you chose the dynamic action of 'Set value' with the "Body of the PL/SQL function" type you need to return the value. Try the following code

  declare
    end_date DATE;
    start_date DATE;
  Begin
    start_date := to_date(:P1_START_DATE || ' ' || :P1_START_TIME, 'DD-MM-YYYY HH:MIAM');
    end_date := to_date(:P1_END_DATE || ' ' || :P1_END_TIME, 'DD-MM-YYYY HH:MIAM');
    RETURN (end_date-start_date)*24;
  End;
  

  and P1_REQUESTED_HOURS like 'item affected. "

  Concerning
  Patrick
  -----------
  My Blog: http://www.inside-oracle-apex.com
  APEX 4.0 Plug-Ins: http://apex.oracle.com/plugins
  Twitter: http://www.twitter.com/patrickwolf

  Published by: Patrick Wolf on January 17, 2011 10:54

• Get the number of month, week and day between 2 dates

  Hi all
  
  Is it possible to display the number of months, weeks and days between 2 dates? by using only the SQL or PL/SQL...
  
  Entry:
  Date: October 1, 2010
  Date: October 19, 2010
  
  I want output like below (assuming starts the week from Monday to Sunday in oracle).
  
  October 1, 2010-(since it's in the middle of the week)
  October 2, 2010-(since it's in the middle of the week)
  October 3, 2010-(since it's in the middle of the week)
  40. (4 Oct-10 Oct falls into the 40th week of the year)
  41. (11 Oct-17 Oct falls into the 41st week of the year)
  October 18, 2010-(since it's in the middle of the week)
  October 19, 2010-(since it's in the middle of the week)
  
  
  Note: If there is a month between the date, the number of the month should be displayed.
  End of the month, the remaining date included with a full week, then the week of the year number should
  displayed. After posting the week, remaining dates should be displayed as it is...
  
  
  Appreciate your help...
  
  
  
  Thank you.
  Fox.

  You mean something like this...

  SQL> ed
  Wrote file afiedt.buf
  
    1  WITH t AS (select date '2010-09-27' as fdate, date '2010-11-21' as tdate from dual)
    2  --
    3  -- END OF TEST DATA
    4  --
    5  select dt2
    6  from (
    7        select dt,
    8               case when days_of_mn = days_in_month then 'Whole: '||to_char(dt,'Month')
    9                    when days_of_wk = 7 then 'Week: '||to_char(dt,'fmWW')
   10               else to_char(dt, 'DD-fmMonth-YYYY')
   11               end as dt2
   12              ,row_number() over (partition by
   13                 case when days_of_mn = days_in_month then to_char(dt,'Month')
   14                                  when days_of_wk = 7 then 'Week: '||to_char(dt,'fmWW')
   15                 else to_char(dt, 'DD-fmMonth-YYYY')
   16                 end order by dt) as rn
   17        from (
   18              select dt, wk, mn, days_in_month
   19                    ,count(*) over (partition by wk) as days_of_wk
   20                    ,count(*) over (partition by mn) as days_of_mn
   21              from (
   22                    select fdate+rownum-1 as dt
   23                          ,to_number(to_char(fdate+rownum-1,'fmWW')) as wk
   24                          ,to_number(to_char(fdate+rownum-1,'fmMM')) as mn
   25                          ,to_number(to_char(last_day(fdate+rownum-1),'fmDD')) as days_in_month
   26                    from t
   27                          connect by rownum <= tdate-fdate+1
   28                   )
   29             )
   30        ) x
   31  where rn = 1
   32* order by dt
  SQL> /
  
  DT2
  -----------------
  27-September-2010
  28-September-2010
  29-September-2010
  30-September-2010
  Whole: October
  Week: 44
  Week: 45
  Week: 46
  19-November-2010
  20-November-2010
  21-November-2010
  
  11 rows selected.
  
  SQL>
  

• How to get the difference in Date in years, months and days

  Select Sysdate-Birth_date from Employees;

  the query returns the number of days between two dates
  I want to convert this number in years, months and days
  Can someone help me please

  Hoek wrote:
  Try:

  SQL> with t as (
  2  select to_date('01-01-1980', 'dd-mm-yyyy') birthdate
  3  ,      to_date('05-05-2010', 'dd-mm-yyyy') today
  4  from   dual
  5  )
  6  --
  7  --
  8  --
  9  select extract(year from today)-extract(year from birthdate) years
  10  ,      extract(month from today)-extract(month from birthdate) months
  11  ,      extract(day from today)-extract(day from birthdate) days
  12  from   t;
  
  YEARS     MONTHS       DAYS
  ---------- ---------- ----------
  30          4          4
  
  1 row selected.
  

  (May need some adjustments, possibly using the LARGEST, but currently not as long)

  Indeed, a few adjustments...

  SQL> ed
  Wrote file afiedt.buf
  
    1  with t as (
    2    select to_date('31-01-2009', 'dd-mm-yyyy') birthdate
    3    ,      to_date('28-02-2010', 'dd-mm-yyyy') today
    4    from   dual
    5    )
    6  --
    7  --
    8  --
    9  select extract(year from today)-extract(year from birthdate) years
   10  ,      extract(month from today)-extract(month from birthdate) months
   11  ,      extract(day from today)-extract(day from birthdate) days
   12* from   t
  SQL> /
  
       YEARS     MONTHS       DAYS
  ---------- ---------- ----------
           1          1         -3
  
  SQL>
  

  Maybe something like this?

  SQL> ed
  Wrote file afiedt.buf
  
    1  with t as (select to_date('17-nov-2006','dd-mon-yyyy') as c_start_date, to_date('21-jan-2008','dd-mon-yyyy') as c_end_date from dual union all
    2             select to_date('21-nov-2006','dd-mon-yyyy'), to_date('17-feb-2008','dd-mon-yyyy') from dual union all
    3             select to_date('31-jan-2009','dd-mon-yyyy'), to_date('28-feb-2010','dd-mon-yyyy') from dual union all
    4             select to_date('21-jun-2006','dd-mon-yyyy'), to_date('17-jul-2008','dd-mon-yyyy') from dual
    5             )
    6  -- end of test data
    7  select c_start_date, c_end_date
    8        ,trunc(months_between(c_end_date, c_start_date) / 12) as yrs
    9        ,trunc(mod(months_between(c_end_date, c_start_date), 12)) as mnths
   10        ,trunc(c_end_date - add_months(c_start_date, trunc(months_between(c_end_date, c_start_date)))) as dys
   11* from t
  SQL> /
  
  C_START_DATE        C_END_DATE                 YRS      MNTHS        DYS
  ------------------- ------------------- ---------- ---------- ----------
  17/11/2006 00:00:00 21/01/2008 00:00:00          1          2          4
  21/11/2006 00:00:00 17/02/2008 00:00:00          1          2         27
  31/01/2009 00:00:00 28/02/2010 00:00:00          1          1          0
  21/06/2006 00:00:00 17/07/2008 00:00:00          2          0         26
  

• calculate the difference between two timestamps

  Hello
  I'm new in PL/SQL and have the following problem. In our application, there are events that insert records into a table with a parameter "processing_date" of type DATE (when they will be processed). For a new type of events, I have to plan the 'processing_date' at 18:00 on the day of insertion, if the event has happened until 18:00 and sysdate if event occurs after 18:00.
  In a pseudo-code that will be
  IF to_char(SYSDATE,'HH24:MI:SS') > 17:59 min 59 s ' THEN - the event took place after 18:00
  processind_date: = sysdate;
  Else - the event has happened until 18:00
  processing_date: = current_timestamp + ('timestamp at 18:00 ' - current_timestamp); -> processing_date: = today at 18:00
  END IF;
  
  I'll appreciate any help.
  
  Thank you.

  dariusgeo wrote:
  processing_date: = current_timestamp + ('timestamp at 18:00 ' - current_timestamp); -> processing_date: = today at 18:00

  For 18:00 of the current date, you can do:

   processing_date := TRUNC(SYSDATE)+18/24;
  

  TRUNC will be truncates the current date ' 00:00:00 '.
  Add 18/24 means add 18 hours (1 day / 24 * 18).

  Kind regards.
  Al

  Published by: Alberto Faenza 22 may 2013 22:07