getting the last area for each case

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• Select the last value for each day of the table

  Hello!
  
  I have a table that contains several measures for each day. I need two queries on this table, and I'm not sure how to write them.
  
  The table stores the rows (sample data)
  

  *DateCol1                 Value       Database*
  27.09.2009 12:00:00       100           DB1
  27.09.2009 20:00:00       150           DB1
  27.09.2009 12:00:00       1000          DB2
  27.09.2009 20:00:00       1100          DB2
  28.09.2009 12:00:00       200           DB1
  28.09.2009 20:00:00       220           DB1
  28.09.2009 12:00:00       1500          DB2
  28.09.2009 20:00:00       2000          DB2

  Explanation of the data in the sample table:
  We measure the size of the data files belonging to each database to one or more times a day. The value column indicates the size of the files of database for each database at some point (date in DateCol1 European model).
  
  
  What I need:
  Query 1:
  The query must return to the last action for each day and the database. Like this:

  *DateCol1       Value      Database*
  27.09.2009        150          DB1
  27.09.2009       1100          DB2
  28.09.2009        220          DB1
  28.09.2009       2000          DB2

  Query 2:
  The query should return the average measurement for each day and the database. Like this:

  *DateCol1       Value      Database*
  27.09.2009       125          DB1
  27.09.2009      1050          DB2
  28.09.2009       210          DB1
  28.09.2009      1750          DB2

  Could someone please help me to write these two queries?
  
  Please let me know if you need further information.
  
  Published by: user7066552 on September 29, 2009 10:17
  
  Published by: user7066552 on September 29, 2009 10:17

  Why two queries when it suffice ;)

  SQL> select dt
    2       , db
    3       , val
    4       , avg_val
    5    from (
    6  select dt
    7       , val
    8       , db
    9       , row_number () over (partition by db, trunc (dt)
   10                                 order by dt desc
   11                            ) rn
   12       , avg (val) over (partition by db, trunc (dt)) avg_val
   13    from test)
   14   where rn = 1
   15  order by dt
   16  /
  
  DT        DB           VAL    AVG_VAL
  --------- ----- ---------- ----------
  27-SEP-09 DB2         1100       1050
  27-SEP-09 DB1          150        125
  28-SEP-09 DB2         2000       1750
  28-SEP-09 DB1          220        210
  

• get the maximum number for each group

  Hi, I am a newbie and work on a project for school. I worked this problem for a few days and made a bit of progress.
  I have two tables, student and register for a database of the College. I need to show students that have the most entries into each large. So far, I have:
  
  WITH COUNT_Q AS
  (
  SELECT B.SSN, B.MAJOR, COUNT (A.CLASS_NO) AS COUNTCLASS
  TO REGISTER A, STUDENT B
  WHERE A.SSN = B.SSN
  B.SSN GROUP, B.MAJOR
  )
  
  SELECT MAX (COUNTCLASS), MAJOR
  OF COUNT_Q
  GROUP BY MAJOR
  ;
  
  I get the correct results, but need to introduce the SSN and the Major of the studens. When I add in the SSN and major, as below, I get too many files.
  WITH COUNT_Q AS
  (
  SELECT B.NAME, B.SSN, B.MAJOR, COUNT (A.SSN) AS COUNTCLASS
  TO REGISTER A, STUDENT B
  WHERE A.SSN = B.SSN
  B.NAME, B.SSN, B.MAJOR GROUP
  )
  
  SELECT *.
  OF COUNT_Q
  WHERE (COUNTCLASS) IN (SELECT MAX (COUNTCLASS)
  OF COUNT_Q
  GROUP BY MAJOR
  )
  ;
  
  Can someone point me in the right direction?

  SELECT  B.NAME,
          B.SSN,
          B.MAJOR
    FROM  (
           SELECT  B.NAME,
                   B.SSN,
                   B.MAJOR,
                   COUNT(A.CLASS_NO) SSN_MAJOR_COUNTCLASS
                   DENSE_RANK() OVER(PARTITION BY MAJOR ORDER BY COUNT(A.CLASS_NO) DESC) RNK
             FROM  ENROLL A,
                   STUDENT B
             WHERE A.SSN = B.SSN
             GROUP BY B.NAME,
                      B.SSN,
                      B.MAJOR
          )
    WHERE RNK = 1
  /
  

  SY.

  Published by: Solomon Yakobson, March 27, 2011 18:53

• How to get the last records of a Table

  Hey Geeks,

  I have this 'conflict '.

  I need to get the 'current balance' for each account, the newest "current_Balance".

  The table looks like this

  ACCOUNT_ID	BUSINESS_TRANSACTION_ID	CURRENT_BALANCE	TRANSACTION_AMOUNT	TRANSACTION_DATE
  1 062 570	238 043 517	51'022	-20'000	31.03.2014 17:49:00.808000
  1 062 570	238 042 407	71'022	-20'000	31.03.2014 17:33:55.666000
  1 062 570	238 042 368	91'022	-26'000	31.03.2014 17:33:20.067000
  1 062 570	238 041 273	117'022	-50,000	31.03.2014 17:18:25.189000
  1 062 570	238 041 174	167'022	-10,000	31.03.2014 17:16:59.361000
  1 062 570	238 038 702	177'022	-2'500	31.03.2014 16:44:58.332000
  5 607 555	238 046 713	1'026	-28'500	31.03.2014 18:35:16.212000
  5 607 555	238 040 592	29'526	-100,000	31.03.2014 17:10:15.474000

  I need this result:

  ACCOUNT_ID CURRENT_BALANCE

  5 607 555 1'026

  1 062 570 51'022                   

  
  

  How we handle this?

  
  

  Thxs for your help

  
  

  Ineffective :-)

  SELECT Account_id

  MAX (current_balance) KEEP (DENSE_RANK LAST ORDER BY transaction_date) current_balance

  MAX (business_transaction_id) KEEP (DENSE_RANK LAST ORDER BY transaction_date) business_transaction_id

  Of account_balances

  GROUP BY account_id

  See on Oracle: clause to keep

  Concerning

  Marcus

• How to get the last row and the sum of all columns in a query

  Hello

  is there a way to get the last record for a column and the sum of all the Archives to another column in the same query.

  Best regards

  You must set your needs correctly volunteers to help here...

  Your data are not good enough to bring you a precise solution. Purpose, you do not have a column, which draws a distinction between the first and the last entry.

  The solution becomes easy based on your design.

  I introduced a grouping called 'id' column and a time column called 'time_of_insert' (only this way you can say with confidence that you can differentiate between the first and last (also a foolproof solution) - you can possibly use sequence (instead of date but if you say that you can insert two lines at the same time) ((and then likely sequence would be a better choice to differentiate instead of a timestamp field) etc...)

  With your sample data, something like this can be done to get the desired results.

  -----------------------------------------------------------------------------------------------------------------------

  WITH dataset AS

  (SELECT 1 id, 10 used, 8 remain, systimestamp + 1/24 time_of_insert FROM DUAL

  UNION ALL

  SELECT the 1 id, 1, 7, systimestamp + 2/24 FROM DUAL

  UNION ALL

  SELECT the id 1, 2, 5, systimestamp + 3/24 FROM DUAL

  UNION ALL

  SELECT 1 id, 1, 0, systimestamp + 4/24 FROM DUAL

  UNION ALL

  SELECT 1 id, 0, 0, systimestamp + 5/24 FROM DUAL

  UNION ALL

  SELECT the 1 id, 1, 4, systimestamp + 6/24 FROM DUAL)

  SELECT *.

  (SELECT SUM (used) ON sum_all)

  FIRST_VALUE (stay)

  COURSES (PARTITION BY id ORDER BY time_of_insert DESC)

  last_row

  Of THE dataset)

  WHERE ROWNUM = 1;

  Output:

  ------------------------

  SUM_ALL LAST_ROW

  ------------------------------

  15                  4

  See you soon,.

  Manik.

• I have been using Photoshop CS5 for some time for photos products (jewelry). What are my best options to get the last Photoshop.

  I have been using Photoshop CS5 for some time for photos products (jewelry). What are my best options to get the last Photoshop.

  Hi michaelb.

  You can subscribe to Plan photography for $9.99 a month, which will give the latest version of Photoshop CC 2015, CC 2015 Lightroom and Adobe Bridge.

  Lightroom and Photoshop | Plan of cloud of Adobe's creative photography

  Kind regards

  Mohit

• How to get the last date of 3 days for the current month?

  Hello. Guy

  How to get the last date of 3 days for the current month?

  MY OUTPUT WOULD LOOK LIKE THIS

  JANUARY 29, 2016

  JANUARY 30, 2016

  JANUARY 31, 2016

  
  

  GUYS HELP ME / / /...
  

  SQL > select last_day (sysdate) - level + 1 double connect by level<= 3="" order="" by="">

  LAST_DAY)

  ---------

  29 JANUARY 16

  30 JANUARY 16

  31 JANUARY 16

• If I buy the photographer package, can I install on my macbook pro and my mac mini desktop. Where can I get this twice, one for each?

  If I buy the photographer package, can I install on my macbook pro and my mac mini desktop. Where can I get this twice, one for each?

  Cloud license allows 2 activations http://www.adobe.com/legal/licenses-terms.html

  -Install on a 2nd computer http://forums.adobe.com/thread/1452292?tstart=0

  -Windows or Mac has no importance... 2 on the same operating system or 1 on each

  -Two activations on one account CAN NOT be used at the same time (to be noted in the link above of the license)

  -An individual account is for one person and may not be shared with anyone else

• How to get the last day of a month for every 2 months for a given period?

  Hello

  Can is it some please let me know how to get the last day, last day of the week, the weekend last day, last Monday, one month for every 2 months for a given period?

  Thanks in advance.

  Try the below

  SELECT LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))) lastday.

  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'SAT '.

  SO LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))-1

  WHERE TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'Sun '.

  THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))-2

  Of OTHER LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  END as lastweekday,

  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') IN ('Sam', 'SUN')

  THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  Of OTHER LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  -(TO_NUMBER (TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))),' from)) - 1).

  END as lastweekendday,

  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'MY

  THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  Of OTHER NEXT_DAY (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), "LUN")-7

  END AS lastmonday

  FROM (SELECT SYSDATE startdate,

  SYSDATE + 300 enddate

  THE DOUBLE)

  CONNECT BY LEVEL<=>

• How to get the last DML statement in each block

  Hello
  
  How can I get the latest DML statements in each block.
  As SYSTEM. LAST_QUERY returns the last select statement, I need to get the last Insert/Update/Delete statement
  in each block.
  
  Thanks in advance
  
  Rizly

  Rizly,

  You can use the GET_BLOCK_PROPERTY to get the last query executed on this block.

       MESSAGE(GET_BLOCK_PROPERTY('', LAST_QUERY));
  

  Kind regards

  Manu.

  If this answer is useful or appropriate, please mark. Thank you.

• Where can I get the right drivers for Satellite Z930 - PT23LA - 01 009?

  A little history: I recently bought a version of Win7 to a Z930 in Auckland from PB Tech shop. I've updated to a clean version of Win8 64-bit. My Win8 seems works ok but I noticed something strange in the Toshiba PC Health Monitor - apparently the Toshiba HDD/SSD Alert is not installed, so I don't understand not his iconic display in the health monitor (but the health monitor think my SSD is in "Good" shape - maybe it's reading the INTELLIGENT of my SSD interface, or maybe it's just saying 'Good' because the integrity monitor is apparently able to operate?)

  I can easily find different versions of the Toshiba HDD/SSD Alert Utility in questionable Web sites - download, but I really prefer to get my Toshiba support drivers. Which leads to my question:

  Where can I get the right drivers for PT23LA-01 009? NZ nor the webarea to Toshiba support have this model in their menus. The closest match seems to be

  http://www.MyToshiba.co.nz/support/computers/Ultrabook/satellite-z930/pt23la-01f00n/download?OS=30

  There is probably not much difference between a PT23LA-01F and a PT23LA-01 P but it is a bit of concern to be download & install the drivers for a chip that is no my model...

  See you soon,.
  Clark

  PS: http://forums.toshiba.com/t5/General-Features-Knowledge-Base/TOSHIBA-HDD-SSD-Alert/ta-p/347120 advise me the area downloads for Toshiba support. He also advises "not all utilities are available for each model and operating system. During the installation of utilities, install the TOSHIBA value added first. "Sigh... so maybe my problem is that I installed the Win8 drivers & utilities order when build my own-building a Win8 pass win7? Wouldn't surprise me in the slightest... but if this is the case are here all other dependencies in these built?

  > Where can I get the right drivers for PT23LA-01 009?

  First series of Toshiba laptops (Australian, European, etc) is very similar to the other
  Your model of laptop Australian Satellite Z930 * PT23LA * series is the same as the European model Satellite Z930 * PT23LE * series.

  That's why the drivers, tools and utilities published for Satellite Z930 * PT23LE * series must be compatible with the Satellite Z930 * PT23LA * series.

  To get all drivers for Satellite Z930 * PT23LE *, you should check this page:
  http://www.Toshiba.EU/innovation/download_drivers_bios.jsp?service=EU

  There, you can get all win 8 - upgrade the drivers. Also the HDD/SSD Alert Utility v3.1.64.14

  Welcome them

• The line of the last line of each table page is going to be missing.

  Hi Experts,
  In OBIEE 11.1.1.6.0, I have a report contains more than one line. "When I click on" PDF "Print", the last line of each table page line will be missing. " Why?
  Are you facing the same case? How soluve this question? Thank you.

  Hey Kobe,

  The question, looks lke a bug. Here's the work around, change the table view, click the properties of content next to the text "Table" (at the top of the columns and measures) in the layout-> position In Border pane to choose custom and select only the bottom edge (horizontal line). Now export to pdf format, you must see the border for the last row on each page.

  Kind regards
  DpKa

• How can I make the individual work for each song on a compilation album of show when I browse my playlists?

  I get a lot of my music from Soundcloud where individual songs are released by artists often with none of the albums.

  So, when you add these songs on iTunes I the name of the album for each of them SoundCloud despite the fact that each of them have different names track/artists/works of art.  When I select the option to indicate that the song is part of a compilation album, even if the individual work remains in each song and shows when I play the song, looking at my playlists, songs from my compilation album of SoundCloud will only show album art compilation rather than the individual works for each song.  How can I my iTunes will show that each individual work?

  You can't while retaining spacing as part of this same album. If you want each art individual to show then tracks them to a unique combination of the album title and album artist. If the tracks are underway on an older iPod then the tracks on the album must be unique.

  TT2

• How to get the last business day of the previous month?

  Hi all

  We need the user as below,

  If the user select 18 June 2015 ' quick dashboard as the input value, and then they want to see last month last day of work (business date: 29-may-2015) amount in report, if you have an idea please share with us.thanks

  Note:

  use under request we can able to get the last day of the previous month, we want to for the last business day of the last month, based on the date of entry of the user?

  TIMESTAMPADD (SQL_TSI_DAY,-(1), TIMESTAMPADD (SQL_TSI_DAY, DAYOFMONTH ("DIM_TIME". ("" DataDate ") *-(1) + 1,"DIM_TIME ". (("" DataDate "))

  Thank you

  Deva

  Try this,

  case when Dayofweek (timestampadd (sql_tsi_day, Dayofmonth(Date '2015-06-15') *-1, Date ' 2015-06-15')) = 1 then timestampadd (sql_tsi_day, (Dayofmonth(Date '2015-06-15') *-1)-2, Date '' 2015-06-15) when Dayofweek (timestampadd (sql_tsi_day, Dayofmonth(Date '2015-06-15') *-1, Date ' 2015-06-15')) = 7 then timestampadd (sql_tsi_day, Dayofmonth(Date '2015-06-15') *-1-1, Date '' 2015-06-15) another timestampadd (sql_tsi_day, Dayofmonth(Date '2015-06-15') *-1, Date ' 2015-06-15') end

  As Ftsiot said in this post, it will work only to exclude the sat and Sun. Another one if you want to exclude regional holiday, you may need a calendar in DB table.

  Thank you

  AJ

• How can I get the stream position for a publication?

  I am writing a CEAP for AfterFx plugin and I need to get the stream position for a composition. I based my plugin on ProjDumper.

  Can anyone help?

  When you place the compA in compB you are supposed to receive an AEGP_LayerH, for this comparison of layer nesting.

  If not, you can use AEGP_GetCompLayerByIndex() on compB to obtain this handle layer, because you know its index. (you must know, you put here)

  If you try to find the layer in compB starting only with the AEGP_CompH of the company, so it's a bit problematic...

  You cannot just ask wherever model is nested, you must analyze each layer for this source control project... yuk.