Hex & reading Council VI

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• IBRD read hexadecimal data

  using Bird reading data of the curve in SONY/TEK_370A test instrument, but the result is not correct.

  According to the Bird, the buffer is defined as type string, but the curve data are hexadecimal.

  CAN IBRD function hex reading using the buffer of type string.

  In the vbib - 32.bas module which is included in your GPIB project, calls all over I/O (ibrdi, ilrdi, ibwrti and ilwrti) are provided for users who need to perform arithmetic operations on data and want to avoid the overhead of conversion of strings required by the Bird and the ibwrt in the format of integer for arithmetic operations.

  ibrdi and ibwrti moved from the data in the form of an array of integers, instead of a string. Using these functions, you can access the data directly as integers instead of establish them as characters and then converting each pair of characters in a whole number. Internally, the ibwrti function sends each integer to the GPIB in the low, high-byte byte order. The ibrdi function reads a series of bytes of data in the GPIB and stores them in the array of integers in order of low, high-byte byte.

  Hope this information is useful.

  gpibtester

• Qosmio F55 / F50 Sound card cable

  Hello, everyone

  Now straight to the point. I have a Qosmio F55 - Q502 laptop computer and there is no noise, because motherboard to its cord (also FireWire, Usb memory card reader) Council is absent. I think that this is cable LF - 4163P, but I'm not sure on this part number. I'll add some photos links.
  Link 1/4: [1. LF - 4163P | http://www.part.lt/img/c137d4893e0e7838eab5c02dbacb812f907.jpg | PIC.1. LF - 4163 P]
  Link 2/4: [2. LF - 4163P | http://www.part.lt/img/203d7d61689c3fb31241053d575b9429283.jpg | PIC.2. LF - 4163 P]
  Link 3/4: [3. LF - 4163P | http://www.part.lt/img/70fb4e2a0b8810811383533505137deb40.jpg | photo.3. LF - 4163 P]
  Link 4/4: [4. LF - 4163P | http://www.part.lt/img/d0f49de0b6f626eeb96ecc9e58c03d5a446.jpg | photo.4. LF - 4163 P]

  So, if anyone has any information, where to buy, steal, this "sound card" with cable or just the cable, please do not hesitate and share your tips with me. Thank you.

  As far as I know it is not easy to find these parts in the regular stores computer/computer laptop.
  What you can try is to contact the nearest Toshiba service provider and ask for help.

  As far as I know, they can order all defective parts.

• iPhone storage problem 6 more

  In the last 2 days, I got message storage several several times. Because she, I deleted the photos, applications, and other things. After ı delete them, after 1 hour something like this ı got the same message even. Once again deleted ı a few photos, apps, new ı had enough storage but once after short time, ı got the same message. I did the same process several times but the result is the same. Also when ı check storage of settings, there is no such great application, photos or anything else to cover the Earth. It's very strange, please help

  You can have something corrupt on the device which caused "others" to grow out of control. You can see this storage when connected to iTunes. Sometimes, restoring a backup can help. Sometimes, you need to restore as new.

  Alarm reading Council.

  What is 'Other' and what I can do about it?

• What is 'other' in my use of the memory ipad 3?

  I get a full tank on my ipad3, do not know what 'other' is on the readings of use... ?

  

  "" Others"are data that does not fit into the categories of media or documents. History of Safari, bookmarks, list reading, contacts, SMS, email messages, notes, etc. When you see so much 'other' as you can see, which indicates that something went wrong damaged on your device. It heals the sometimes restoring a backup. In some extreme cases, it can require a factory restore without using a backup.

  Alarm reading Council.

  What is 'Other' and what I can do about it?

• "Read binary file" in hex format?

  Is there a way I can set the data type of the function "Binary file reading" so he came out in Hex format?

  Front panel.  Right-click.   Display format.

• Question about reading the hex data

  Hello! I'm a Novice of Labview and have a problem with reading the hex data.

  Basically, I bytes from the serial port like this: "80100E0E0AB4F646F24A00911267087E032080057FFF."

  It is not encoded in ASCII. What I want to do is to convert a hexadecimal string ASCII of the hexagon.

  so that the chain would become of ASCII hexadecimal numbers.

  I think that the following might be a solution, but I have no idea what the Subvi is in the solution.

  http://forums.NI.com/T5/LabVIEW/hex-string-to-ASCII-hex-string/m-p/886078/highlight/true#M400462 Thanks in advance and I thank you for your kind help!

  coolmatthew wrote:

  What I want to do is actually this.

  You use too much a lot of code for all this. All you need is a concatenate strings, replace your entire and other loop. Same result.

  

  (See also)

• Error 1073807253 occurred at VISA read transitional SR830.vi visa: (Hex 0xBFFF006B) a framing error occurred during the transfer.

  Hello

  I wrote a program with labview transitional make measurement of c - v using a stanford amplifier research SR830 detent. The program seems to be runing fine, but sometimes it is givvibg an error:

  #

  You said when you look at the reading string-mode, it sends a \r which is a carriage return (decimal 13, hexadecimal 0d) instead of a \n which is a linefeed (decimal 10, hexadecimal 0a).

  But you did not set your intialize void VI to thread a hex set up 0d in the character of the VISA entry.  You have activated with a real ending, but nothing is wired at the entrance of character which means that it is still using the default value of hex 0A.

  That is why you are still getting the stop in the middle of reading character and timeouts if you ask too many bytes, it takes a lot of time to get X number of bytes, and he's never read the stop character you designate.

  In addition, you must have the VISA close the loop.

• How to read a counter value for the separation of the two edge before meter is stopped by the second edge (6602 Council)?

  I use a timer/counter with DAQmx 6602. I use the separation of two - available via DAQmx cash edge. Count between the two edges works properly, however I do not know how to read the value of the counter during the counting operation (i.e. after the first edge triggered the beginning of the count, but before the second edge triggered the end of the counting). I'll have to wait for the second goes off the edge of the end of the countdown until I can get a counter value. I need to be able to access the current value of the County during the count operation. This was possible in traditional DAQ. How can it be accomplished using DAQmx?

  Ah shoot - I was afraid that this might be the case (for what it's worth, my series of X returned intermediate values, but the material and the underlying driver are quite different)...

  You just need to take one measure at a time or you are buffer several measures of separation of the two edges at the same time?  So just to take one measure at a time, you can set a task of edges of count using the database internal time as the source using an arm start trigger (first edge) and a sample of clock (second Board) to work around the problem.

  Best regards

• read from bit hex

  Hello world

  I have been using a touch screen for a project. I am now able to read hexadecimal values and convert them to decimals through LabVIEW. However, I need to be able to read the beginning bit everytime. Now, when I move my finger on the touch screen, the scroll of hexidecmial values and I eventually read hexadecimal numbers in the middle of result rather than the beginning of the string. Any help on this would be highly appreciated.

  I have attaced my VI, so you can see what I have so far.

  Thank you very much

  James

  
  

• LiCor series - hex 0xBFFF006c read errors

  Hi all

  I tried these last days develop a series VI to read the data of a 820-LiCor-CO2 gas Analyzer. I know what is sent to the device to a request to send data to the computer and how to analyze these data once it gets in return. Its manual settings are Baud: 9600, data Bits: 8, parity: None, of Stop Bits: 1 and flow control: No.  I had problems with the hexagon-0xBFF006C "a time-out error occurred during the transfer. A character not read in the material before the next character arrived. "In the database read/write vi provided with labview, this error occurs each time series. In mine, I joined, I would get this error once every nine or 10 times by operating once every time. Sometimes the error would be to present the first time that I pressed the race, but after I click OK, the next run will work fine until about the tenth times.

  

  Does anyone have any idea why this could be implemented? I really just need to be able to read the pressure, temperature and CO2 with precision as well as several times without problem.

  Thank you very much!

  Ok. So I solved my problem with a co-worker, but he had a miserable time. I think that the VI attached work a LiCor-820. I think that you can fix the buffer problems of overflow to everything in a while loop with an error handler. Basically, the error handler can prevent display errors, and at the same time, it can also make a stop or continue the condition for the while loop. I chose to continue after deletion of the read buffer until it wasn't a mistake. I took a loop because the data on the first launch is usually just a partial reading of the data set is past the LiCor. I know that this probably isn't the most elegant solution, but it works for this situation so far.

  Thanks for the comments and suggestions of each.

• I need to open the files on an email I received, but do not know how to install Adobe Reader, as is the Council of shippers, help!

  The e-mail was sent from a PDF in Adobe Reader! that my computer does not open!, josephine

  If you do not have Adobe Reader installed on your PC, go to:

  http://get.Adobe.com/UK/reader/

  and follow the instructions to download/install.

  If you have problems to install Adobe Reader take a look here:

  http://kb2.adobe.com/cps/836/cpsid_83641.html .

• Timeout error Hex 0xBFFF0015 read problem

  
  
  

• VISA reading significantly slows down to 20 Hz (Labview, Arduino + Xbee project)

  Hello

  I am quite new to Labview and Arduino, so I apologize if I use the incorrect terms. I'm having some trouble with the next project, I hope that you guys can give me some advice!
  I have 16 sensors connected to the 16 analog pins on an Arduino mega Board. This Council has a shield mounted upon him, with a Xbee module wireless. I have another Xbee module that communicates with him and it is mounted on a USB dongle that plugs into a PC with Labview 2015.

  The A/D analog Arduino pin output is read and sent every 50ms to the Xbee module connected to the PC. So every 50ms (that is, a frequency of 20 Hz), a new line of analog readings by commas is sent, using AnalogRead and Serialprint in the Arduino. These data are fed to a Labview code with architecture of producer-consumer. Copy the following code configures a serial port of VISA, reads the data, it converts a voltage value and writes the data to a text file (see block_diagram.jpg).

  The problem is that at a frequency of 20 Hz (with the configuration of the attached jpg) when you reach 400 treatment iterations the code slows down considerably and values are not parsed correctly. It behaves as if the queue is full (but the queue of elements indicators show 0) or memory or the buffers were full. It seems quite surprising to me given that the sampling rate is so slow. I tried a few configurations setting the buffer size, empty the buffer by using the queue time, but nothing seemed to work. Is it because the processor loop takes too much time to iterate? I tried to disable data analysis, conversion of voltage and the generation of text file, just keep reading and still have the same behavior.

  This may be the cause? Suggestions to change the block diagram are welcome! Is there a better way to do this than with VISA or queues...?

  I use Labview 2015 on Windows 7.

  Thank you!!

  sminanog wrote:

  It behaves as if the queue is full (but the queue of elements indicators show 0) or memory or the buffers were full.

  You think along the good things. But the big problem I see here is that you have a table growing up to stop the program.  You must move the file writing to be inside the loop of your consumption.  This will eliminate the need to constantly develop your table in the shift register, with tons of memory and causing copies of memory (which is very expensive).

  The other concern I have is the speed at which data is available.  If you have a baud rate 9600, then in the 50ms debit you can pass 48 bytes.  This leaves 3 bytes per sample, including the comma.  If you have a debit 115 200 baud baudrate, it turns into 576 bytes, you can send the 50ms.  So the lesson here is to make sure that you use a transmission speed which is fast enough to handle the data that you want to send.

• Why 'Read a fixed number of samples' help with the error 200279?

  Hello world

  It is a question about a tip found in the explanations on the acquisition of data error-200279. This explanation it is said: '... ". reading a fixed number of samples instead of all available samples can fix this... »

  AFAIK the DAQ system buffer is a ring buffer, so we can consider having a writing position and a position of reading "in motion" along the ring. While the playback position is the position of writing, everything is brilliant. But if writing catch up reading, samples will be overwritten and therefore-> error-200279.

  So here's my question:

  I do not understand why a fixed amount of reading samples would help me with this error. I don't understand why other Councils (increase in the size of the buffer or the frequency of reading) would help me because they reduce the probability of the playback position being outrunned by the position of the writing.

  But if I read everything which is available, whenever I read the only way for the buffer fills would be that the time between two readings take more time than necessary fill the entire buffer.

  Or in other words to each reading I will read at least as many elements that it has been filled by writing since the last read, so the only way to fill the buffer would fill completely at once since the last reading.

  This should be a lot safer than reading a fixed amount, because in this case, I'd get a problem if I read it that fewer items than writing complete at the same time, regardless of the number of items that would be and no matter what the size of the size of the buffer that would be.

  What I understand here?

  Thanks and regards,

  Sebastian

  SBach wrote: this VI is a State Machine in queue, the reading part is made in the case of timeout and cases are used as initialization orders, stop and change the outside DAQ hardware.

  That I can't tell when these commands will trigger the time between two readings could not be set. If a strictly fixed amount of data could lead to a buffer to fill.

  Init command: you certainly don't have a running task.

  Stop: You stop the task, then doing here if you get overrun.

  Edit tasks: you will probably need to stop the task still before you can edit the task, but let's go back to not caring.

  The way I see it, the other commands must stop the task anyway.  If you can leave the timeout do its job and do not do a lot of extra stuff.

  And here are some alternatives:

  1. use a shift register to keep track of how long your wait time should be.  In the case of reading, make the deadline to be whatever it is that you are using.  In all other cases, only the 0 so that a read timeout must be performed immediately (once the queue is empty).

  2. When you do your check to 1.5 times the timeout, if there is too much data, queue a reading at the front of the queue so that playback will happen.  The idea is that you really want to keep the same stack sizes to keep the memory to be allocated.  So just to be read more often.