Homepage validation loops
Download the driver for a scan of a new feature four Epson-all-in-one has failed. Technology Epson determined the problem lies in the Windows Vista operating system and
prolvided me with Microsoft difficulty being KB940199. Trying to download Microsoft's KB940199 am made to validate the OS and continuing
get redirected to the page of Windows Welcome. Have been unable to prevent this looping occurs. If I can't solve this problem remains the scanner
unoperable, therefore, if you have the solution, I would be grateful of your.
It happens if you use another browser like Firefox?
Tags: Windows
Similar Questions
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Newly added validation loop lines
Hello dear livecycle fans!
I think I looked everywhere for my fairly simple question. Here it is:
I have a table with a header row and 1 row and a button of a new line (which adds a new line to the table) BUT I want the button to validate the last row (to check if everything is fullfilled). It can also validate all the lines, is irrelevant.
My code looks like this:
var valid = true;
for (var i = 1; i < Table1.Row.instanceManager.count; i ++)
{
If (form1.page1.tabform.Table1.Row (i).field.rawValue == null |.) field.rawValue.length form1.page1.tabform.Table1.Row (i) == 0); {
xfa.host.messageBox ("missing a field!");
valid = false; }
}Of course, when him valid = true, it adds the new line. However - this validation does not work
Why is this? Would you be so kind and help me with one. The code seems simple and straightforward and I don't really know what I'm doing wrong.Thank you! PS. Wow, that the editor of this post is really messed up on Opera
OK, I found this blog that answers all my questions:
http://blogs.Adobe.com/formfeed/2008/11/loop_through_subform_instances.html
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better option than a loop of validation?
I am running 11.2.0
I'm looking at the setting of a sql statement, and the issue was raised as to the max inserts by transactions in 11g, and if it is greater than 1000.
I have not yet found a solid answer, but I thought that 10g was higher than 1000.
In any case...
My first thought was to implement a loop of validation on every 1000 lines, because that's how things were handled in the past.
But I found an article that talks of redo logs and performance and how it is a horrible practice to do the validation loop.
What I did find is what is the best methodology by doing this?
My scenario could meet as much as 20 000 inserts at the same time.
Thank you.Willy_B wrote:
I'm looking at the setting of a sql statement, and the issue was raised as to the max inserts by transactions in 11g, and if it is greater than 1000.
There is no limit. So yes it is greater than 1,000
What I did find is what is the best methodology by doing this?
Insert directly in select
My scenario could meet as much as 20 000 inserts at the same time.
Here is an example on a database of development of the small insertion of 1 million lines in less than 10 seconds
SQL> create table t (n number, a varchar2(50), b varchar2(100), c varchar2(200)); Table created. SQL> set timing on SQL> insert into t 2 select level, rpad('a', 50, 'a'), rpad('b', 100, 'b'), rpad('c', 200, 'c') 3 from dual connect by level <= 1000000; 1000000 rows created. Elapsed: 00:00:09.95
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In a table - looping through the rows and the stored procedure call
APEX version: 3.2.0.00.27
Hello
I searched the forum and tried a few things but could not make it work.
I have a tabular presentation, developed with the help of the ATD ( )
What I'm trying to do now:
-After submit and validations, loop through all the lines and
-call a stored procedure passing 3 parameters obtained from each of the lines on the form of tables. This procedure will be an update of a database table.
On the forum, I found that I could do the loop "* FOR i IN 1..." APEX_APPLICATION.g_f03. "LOOP COUNT *" syntax.
Only for testing purposes, I tried just to view information with the following (On Load - after a footer) process (example of Denes Kubicek == > http://deneskubicek.blogspot.com/2009/05/execute-javascript-throuhg-plsql.html):
The foregoing would give me a ' * ORA-01403: no data found * ' message. I tried through various variants of APEX_APPLICATION.g_f0* #*, but still can't get anything to display correctly. In commenting on all the lines referring to APEX_APPLICATION.g_f0x above, the date would be are they displayed fine.declare v_today varchar2 (200); begin -- :P40_test := APEX_APPLICATION.g_f03(1); -- :P40_test2 := APEX_APPLICATION.g_f04.COUNT; :P40_test2 := 100; v_today := to_char (sysdate, 'dd.mm.yyyy'); --FOR i IN 1.. APEX_APPLICATION.g_f03.COUNT LOOP :P40_test := APEX_APPLICATION.g_f02(2); HTP.p ('<script type="text/javascript">'); HTP.p ( 'alert(''Today is ' || v_today -- || APEX_APPLICATION.g_f04(APEX_APPLICATION.g_f03(i)) || '.\n' || 'end!'');' ); HTP.p ('</script>'); -- :P40_test := APEX_APPLICATION.g_f02(APEX_APPLICATION.g_f02(i)); --END LOOP; end;
I tried uncomment the FOR... LOOP and play with the code (defining the process runs "On submit - after calculations" and Validations), I got was a ' * ORA-06502: PL/SQL: digital error or value: character conversion number error * "message.
Here is the script of the form in a table:
Regarding the parameters for the stored procedure, it would the MSLINK, VALVE_NUMBER and the VALVES_STYLE. FEATURE.select "V"."MSLINK", -- hidden (number) "V"."INSTALLATION_DATE", -- editable date picker "V"."MANUFACTURER_INDICATOR", -- editable (cascading LOV -- text) "V"."MODEL_INDICATOR", -- editable (cascading LOV -- text) "V"."DIAMETER_INDICATOR", -- editable (LOV -- number) "V"."PURPOSE_INDICATOR", -- editable (LOV -- text) "V"."VALVE_NUMBER", -- shown but not editable -- number "V"."MODIFY_DATE", -- shown but not editable "V"."MODIFY_USER", -- shown but not editable "V"."VALVES_STYLE"."FEATURE" -- shown but not editable -- number from "#OWNER#"."VALVES" "V" Where "V"."PROJECT_ID" = :P1_PROJECT_NUMBER AND "V"."VALVES_DFLAG" = 0
Help, please!
(Sorry for the long post).
Thank you
TanHi, Tan,
I have not seen that type of object - I've only used custom types for purposes of test years ago and have never used their within Apex!
One possibility is that the value of checksum being is based on all of the content of these fields, rather than only the part of the FEATURE. If there are other parts of the object, you could include those items as well.
Otherwise, as you f01 KP for a record, you will need to retrieve the values of the FUNCTION in your PL/SQL code directly from the table (because the user cannot modify these fields, you can be sure that the values in the table will be still valid).
Andy
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Select new record in a txt file
Hello world
I have Forms 6i and I have the following procedure where I'm only putting the new record that I entered on the .txt file.
It is what I have so far, but the procedure always bringing all records and not only the new one I entered.
Get_file_contents PROCEDURE IS
Salida Varchar2 (1000);
Compañía Varchar2 (5);
Number of alert: = 0;
OUT_FILE Text_IO. Type_de_fichier;
nSchoolId Varchar2 (5);
nStudentId Varchar2 (15);
number of nDummy;
-in_file Text_IO. Type_de_fichier;
-linebuf Varchar2 (1000);
Function Abre_Archivo
Return boolean is
BEGIN
OUT_FILE: = Text_IO. Fopen(:file_name,'r');
Return (true);
exception
While others then
Return (false);
END;
BEGIN
go_block ('MY_TABLE');
clear_block (no_validate);
premier_enregistrement;
If Abre_Archivo then
OUT_FILE: = Text_IO. Fopen(:file_name,'r');
End if;
-Validation;
LOOP
Text_IO. Get_Line (OUT_FILE, Salida);
nSchoolId: = substr (Salida, 1, instr(Salida,';',1,1)-1);
nStudentId: = substr (Salida, instr(Salida,';',1,1) + 1, (instr(Salida,';',1,2)-instr(Salida,';',1,1))-1);
Verification - if algun record exists en the database
Select count (*)
in nDummy
From my_table
Where student_id = nStudentId;
If nDummy = 0 Then
: MY_TABLE. SCHOOL_ID: = substr (Salida, 1, instr(Salida,',',1,1)-1);
: MY_TABLE. STUDENT_ID: is substr (Salida, instr(Salida,',',1,1) + 1, (instr(Salida,',',1,2)-instr(Salida,',',1,1))-1);.
: MY_TABLE. Name: = substr (Salida, instr(Salida,',',1,2) + 1, (instr(Salida,',',1,3))-(instr(Salida,',',1,2) + 1));
: MY_TABLE. First name: is substr (Salida, instr(Salida,',',1,3) (instr(Salida,',',1,4))-(instr(Salida,',',1,3) + 1) + 1);.
: MY_TABLE. RANK: is substr (Salida, instr(Salida,',',1,4) (instr(Salida,',',1,5))-(instr(Salida,',',1,4) + 1) + 1);.
: MY_TABLE. GENRE: is substr (Salida, instr(Salida,',',1,5) (instr(Salida,',',1,6))-(instr(Salida,',',1,5) + 1) + 1);.
: MY_TABLE. STATUS: is substr (Salida, instr(Salida,',',1,6) + 1);.
-: MY_TABLE. STATUS: = 'A ';
next_record;
End if;
Synchronize;
END LOOP;
Text_IO. Fclose (OUT_FILE);
premier_enregistrement;
Exception when No_Data_Found then
delete_record;
Text_IO. Fclose (OUT_FILE);
premier_enregistrement;
END;It seems that your select returns no records. The student card that extract you the string is incorrect. Put a message after your selection to show the value of nDummy.
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Hello world
I created a form in 6i where I can open a .txt file to show me all the data in this file, so after the display of data in my form, I press a button and I insert data in my database, but if I add new data to this .txt file when I press record it says that certain values are already inserted and they cannot be repeated , because the id is not null, so what I want to ask you is how can I modify the same program to make me insert values that are not already inserted. Only new data.
This is my code:
Get_file_contents PROCEDURE IS
Salida Varchar2 (1000);
Compañía Varchar2 (5);
Number of alert: = 0;
OUT_FILE Text_IO. Type_de_fichier;
-in_file Text_IO. Type_de_fichier;
-linebuf Varchar2 (1000);
Function Abre_Archivo
Return boolean is
BEGIN
OUT_FILE: = Text_IO. Fopen(:file_name,'r');
Return (true);
exception
While others then
Return (false);
END;
BEGIN
go_block ('MY_BLOCK');
clear_block (no_validate);
premier_enregistrement;
If Abre_Archivo then
OUT_FILE: = Text_IO. Fopen(:file_name,'r');
End if;
-Validation;
LOOP
Text_IO. Get_Line (OUT_FILE, Salida);
: MY_BLOCK. SCHOOL_ID: = substr (Salida, 1, instr(Salida,',',1,1)-1);
: MY_BLOCK. CLASS_ID: is substr (Salida, instr(Salida,',',1,1) + 1, (instr(Salida,',',1,2)-instr(Salida,',',1,1))-1);.
: MY_BLOCK. Class_name: = substr (Salida, instr(Salida,',',1,2) + 1);
: MY_BLOCK. STATUS: = 'A ';
next_record;
Synchronize;
END LOOP;
Text_IO. Fclose (OUT_FILE);
premier_enregistrement;
Exception when No_Data_Found then
delete_record;
Text_IO. Fclose (OUT_FILE);
premier_enregistrement;
END;OK, the constraint is the id of class only. So adjust the WHERE condition so that it only checks the class id.
-
When I downloaded Mozilla Firefox and clicked on the Firefox icon I get this message on the Firefox homepage "the address is not valid.
The URL is not valid and cannot be loaded. "I can always access the internet but what do I do to get rid of this message. The home page does not display the icon of firefox.
You can check the setting of the homepage:
- Tools > Options > general > startup: Homepage
Firefox supports several home pages separated by ' |' symbol (pipe).
Start Firefox in Safe Mode to check if one of the extensions (Firefox/tools > Modules > Extensions) or if hardware acceleration is the cause of the problem.
- Put yourself in the DEFAULT theme: Firefox/tools > Modules > appearance
- Do NOT click on the reset button on the startup window Mode safe
-
I use PS CC 2015 for awhile to editing photos and other, I uninstalled PS CC 2015 of my C drive (to free up space and consolidate PS CC 2015 things on another drive) and installed on another drive, I couldn't go back into Photoshop. While trying to start it it give me a window of validation of software license that would pop up and disappear every few seconds again and again.
----------------------------------------------------------------------------------------------------------------------------------------------------
Stats on my computer:
Edition of Windows: Windows 8 Pro
Processor: Intel (r) Core i7Cpu
Installed memory (RAM): 8 GB
System type: 64-bit, x 64 processor operating system
--------------------------------------------------------------------------------------- - ------------------------------------------------------------
I tried solutions:
-Uninstalling and reinstalling under the C drive.
-Signature of creative cloud while trying to validate, and then would give me licenses guest, connected to the Adobe ID with photograph subscription, after the saying of the window, hit continue to use licensed software with the right Adobe ID has signed, he returned to the loop without end of validation.
-Remove adobe all items under the heading other disks and keep adobe all the items on the C drive.
-Removed and reinstalled creative cloud.
-Check the subscription payments were going through
-Update audit logs to make sure I had not missed a.
------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
Possible things I can do (not sure if I did) to screw it up. Let me know if all trigger problems.
Tempted to go to associated adobe does not file creative cloud, simply move the folders, without uninstalling and reinstalling.
Accidentally deleted Adobe of the linked files, can't speak of it, I don't think I hit anything on my drive C (default main drive)
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I am considering solutions:
Remove all adobe, folders, items related to photoshop and creative cloud from scratch I guess?
Cancellation of the plan and from the cool email, (adobe ID), however, since it is a contract of plan year, paid monthly, I suppose, they will be responsible for the rest 10 months. I use PS CC 2015 for 2 months.
------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
Any help is appreciated, willing to try anything since I am a creative work on the photos for friends, if a staff member could check on their end when my subscription works, it would be appreciated.
In conclusion, the infinite loop software validating, tried a bunch of solutions, looking on the Internet without success, extremely frustrated.
A keen user of Photoshop CC 2015.
Michael Vigman
Hi Michael,
Thanks for your detailed thread.
Please follow the steps below.
First of all make sure that you have followed the steps mentioned in Adobe Creative Cloud connection errors
- Rename Slcache and Slstore
- Navigate to C:/ProgramData\Adobe\ (program data are hidden folder) and rename the Slstore to Slstore.old
- Go to C:\Program Files (x 86) \Common Files\Adobe\ and rename Slcache to Slcache.old
2. now, the suite Adobe Creative Cloud connection errors rename opm.db file
- Navigate to the OOBE folder. : - \Users\[username]\AppData\Local\Adobe\OOBE
- Rename the file opm.db in opm.old.db
3. run the vacuum to clean install Adobe Creative cloud and Photoshop. (If the step 1 and 2 does not solve the problem)
Let us know if this helps
Kind regards
Assani
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Question about VALIDATION and EXCEPTION loop
DB version: 11.2
I believe the gurus here despise is committed inside loops. Due to budgetary constraints our java colleagues write code PL/SQL here. Below is an excerpt from a stored procedure that does some archive stuff.
Question on COMMIT
=====================
I know is committed to the inside of the loops is bad, but I just want to know if the path that they have implemented COMMIT frequency is correct (using the number of iterations). Their intention was to commit all 200,000 records.
Question on EXCEPTION
======================
LMD like that, isn't better to have the exception block in the loop?
select po.txn_id, po.po_id BULK COLLECT into v_txn_id, v_po_id from purchase_orders po inner join txn_pkt_common tc on tc.txn_id = po.txn_id and tc.created_date < po.last_mod_date; v_rec_count := 0; IF v_txn_id IS NOT NULL AND v_txn_id.COUNT > 0 THEN FOR i IN v_txn_id.FIRST .. v_txn_id.LAST LOOP v_rec_count := v_rec_count + 1; INSERT INTO purchase_orders_archive SELECT * FROM purchase_orders WHERE po_id = v_po_id(i); DELETE FROM purchase_orders WHERE po_id = v_po_id(i); IF v_rec_count >= 200000 THEN COMMIT; v_rec_count := 0; END IF; END LOOP; COMMIT; end if;
ExpansiveMind wrote:
DB version: 11.2I believe the gurus here despise is committed inside loops.
Cursor inside the lines, Yes, but this isn't a case of contemptuous, it's more to do this is to knowingly introduce a bug in your code, resulting in a possible "snapshot too old" error So, good programmers do not.
Question on COMMIT
=====================
I know is committed to the inside of the loops is bad, but I just want to know if the path that they have implemented COMMIT frequency is correct (using the number of iterations). Their intention was to commit all 200,000 records.Q: Why is there the intention to commit all 200,000 records? What is the issue they're trying to move?
In your example code, it is the data block collection. Is it really in collector block + 200,000 records? If so you may have a serious impact on the resources of database data are collected in the memory of the PGA, which is expensive.
Question on EXCEPTION
======================
LMD like that, isn't better to have the exception block in the loop?That depends on what you want to do when an exception occurs. If the exception can be 'managed' and you want to continue processing the rest of the data, then Yes, you would want an exception around the DML inside the loop block. If an exception should cause processing to stop completely, then you want the exception handler (if you really need one) out of the loop... but then you wonder again why you make inside the loop, because it is not supposed transaction.
All of this procedure looks like this could be done with a single INSERT statement followed a single DELETE statement, followed by a unique validation. Oracle can easily handle millions of records, so it shouldn't be a problem.
The other problem with frequent postings is that each commit tells oracle to write the data to the data blocks, and these 'write' get statements go in the database for the writer to manage processes. By default, there are X number of writer running process (depends on version and other parameters) when the database starts, but if a large number of postings is published then Oracle begins to generate additional editor on the server processes to manage the extra workload, which can then cause a lot of writer running process (using the resources of the server) all trying to access the same load of blocks of data in terms of physical i/o and therefore all the other slows down. This is why frequent postings are not a good thing, and you must book to engage in logical business transactions.
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for the validation of the loop
I have this code in my procedure, the code runs well but his does not does not update inside the loop statement for...
Thanks for your help.SELECT customernumber BULK COLLECT INTO in_tab FROM Tablename; FOR i IN 1 .. in_tab.COUNT LOOP if(i>=1) then if (i<in_tab.COUNT) then UPDATE Tablename SET COUNT = 2 WHERE customernumberlike 'in_tab (i)'; end if; end if; END LOOP; commit;
Published by: user7404990 on August 20, 2009 05:17Are you sure that the Update statement works?
Your example doesn't have updated validation, as Where clause seeks a literal "in_tab (i).
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looping over a list with 'insert' in the cfquery tag valid? He
throws any errors and inserted into the table without any
problems, but just wonder if it is possible to use since when I tried
Select article twice in a cfquery, it executes only the first.
< cfquery >
Select the test in testdata
Select othertest from differentdata
< / cfquery >
If it works, it is valid. Different from the db support different syntaxes on this issue. A way that would work for all db's
insert into sometable
(fields)
Select somevalues
from somewhere
Union
closing tags. -
Dear friends,
I need algorithm / VI to check a table that contains items and loop start tags (text) (While and For) and (for End) and End While loop end tags. Loops can be nested to any level and can be mixed (While loops inside loops and vice versa). I need a VI that can analyze this (String) table and output a Boolean value if the curls are not logically placed (number of loops of departure is not not in number of for loops, loops starting end before beginning loops etc.) and a text indicating the problem. Can anyone help!
Thank you very much!
Pleasant day to you!
Taking your example of an illogical nested loop:
put "For".
put 'While '.
Now the stack is:
While
For
and we get an end tag 'For' that would assess:
pop == 'For'-> 'In ' ==' to'-> false
and now, we can also use two tags to display: 'End for' encountered where 'End While' was expected.
Back home, I have little code (in development) that analyzes xml and must manage the opening and closing xml tag. I'll have a look if it helps and post it in case.
Felix
-
Loop of validation software license
So this is about the 5th time I've completely uninstalled, deleted all files from Adobe, then run Adobe Creative cloud cleaning with absolutely no progress. I download the software creative cloud let him do is setting up and downloading thing and when he finally I get a creative cloud window that has just a rotation inside circle. Start (Windows 7 Ultimate) Task Manager and stop the process Adobe CEF Helper.exe * 32. Suddenly, I get a login screen that I can enter my info in. Type in and everything looks good and I'm able to download for Photoshop beginners. Wait until it has finished and install and then I launch. Now it turns on and says I have version of evaluation but 90 days remaining, click the connection option and he thinks about it for a minute and then opens a new box that says software license validation. Cannot get past this step at all, just guard verification then closing then popping up. I tried the suggested fixes that say to remove the opm.db file of /Application Support/Adobe/OOBE, but everything that is me to sign again. All advice to get this software to the top and the work would be greatly appreciated! On a side note, Acrobat DC works very well and never request a secondary connection, or validation, it even automatically log on my account with a list of all my files.
It sounds like it might be useful if you contact our support staff directly, please visit the following link: Please contact Adobe customer service. For more information, please visit: FAQ: how to contact Adobe for support?
-
This morning my creative cloud started having this problem. I run an application, a modal screen tells me it must validate my license, it gives me the renewal subscription screen, I hit try again, he comes back with subscription now active screen, I click on continue and it starts the loop... I just spent 45 minutes with the help of cat, which was worthless... Does anyone else have this problem?
Hello
Please see 'Renew your membership' message when you start an Adobe Creative Cloud application
Hope that helps!
Kind regards
Sheena
-
Some reason, whenever I try to run creative cloud and sign just inside maintains a loop forever.
-tried reinstalling the creative cloud
-tried to restart the computer
Help, please!
In fact this loop must be deleted or renamed, please discuss with us to Support Adobe
Concerning
Stéphane
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