Valid algorithm loops

Similar Questions

• Validation license loop

  Some reason, whenever I try to run creative cloud and sign just inside maintains a loop forever.

  -tried reinstalling the creative cloud

  -tried to restart the computer

  Help, please!

  In fact this loop must be deleted or renamed, please discuss with us to Support Adobe

  Concerning

  Stéphane

• Validation W3C with Dreamweaver CS6 version 12-impossible

  Hello

  Since a few days, find it me impossible to validate the HTML with the Dreamweaver CS6 validator, I use it occasionally for a few years, it worked well before and it is up-to-date.

  I click as usual on validate the current document (W3C)

  A popup window opens, that of dreamweaver that will send the document to end of audit service W3C (usual message), I click OK as usual...

  Crowing instead results in the bottom of the Dreamweaver...

  A popup window never seen before appears and tells... You will be redirected to a new website with button choice of Yes or not

  I click Yes and a new popup opens instantly by saying...

  The period of the application of the W3C service has been exceeded. The service (or your Internet connection) doesn't seem to work.

  The Internet connection is functional.

  Someone else has this bug or am I the only one?

  How to fix this?

  Thank you

  The validation in CS6 tool uses a former link and give an error when used. The W3C has changed their validation algorithm and gave him a new address. Adobe is more updated of CS6, so there is nothing you can do to get the validation to work correctly in the program itself any longer. Newer version have the correct link.

  Use http://validator.w3.org/nu to access the W3C validator.,.

  You can also use the Firefox browser with the HTML Validator extension and a list of errors each time get you a glimpse into the browser itself.

• Problem Dreamweaver CS5.5 W3C validation

  Hello

  I am french and I have this problem.

  When I try dreamweaver CS5.5 W3C validation there was an error and has closed.

  But the other function is good.

  What I can do.

  Thank you

  Ah, looks like they have redirected the old link validator for the new validator algorithm.

  This is the first time I noticed that.

  It is possible that the passage is what caused the failure.

• Read data from javacard, how?

  Hi all!

  I'm really newbie on chip in general. Sorry for the next bad English: s

  We develop a mini-app to read the official license from the University of Seville open (without encryption) available data.

  The smart card has a java-contact-chip with WG10 emulator for backward compatibility with older cards and with a capacity of 32 KB. There is also a mifare chip, but the data we need is the first chip.

  The content of the chip-contact is organized like the following structure:

  

  The data we want to read are written to the EFdatos 1005. This emission factor has more data that we need, so the concrete data are allocated to offset 0xF2 with length 8 d (length in bytes) and his label is "serial number".

  
  

  Here is a small code to try to read the data of the card chip:

  
  

  public void cardInfo() throws CardException, CardNotPresentException {
   
                                TerminalFactory factory = TerminalFactory.getDefault();
                                List <CardTerminal> terminals = factory.terminals().list();
                                CardTerminal terminal = terminals.get(FIRST_TERMINAL);
                                Card card = terminal.connect(PROTOCOL_T0);
                                CardChannel channel = card.getBasicChannel();
               
                                byte[] resp = {(byte)0x00, (byte)0xA4, 0x04, 0x00, 0x00 };
                                CommandAPDU command = new CommandAPDU(resp);
                                ResponseAPDU response = channel.transmit(command);
                                System.out.println(DatatypeConverter.printHexBinary(response.getBytes()));
                                card.disconnect(false);
   
  }
  

  It's the only possible output I get no errors/warnings as A 6, 82, 6 d 00, 6A 86... (SW1 |) SW2):

  6F658408A000000018434D00A559734A06072A864886FC6B01600C060A2A864886FC6B02020101630906072A864886FC6B03640

  B06092A864886FC6B040255650B06092B8510864864020103660C060A2B060104012A026E01029F6E061291111101009F6501FF9000

  Other commands like GET DATA, READ BINARY etc did not work for me. And with the above data, I tried to decode with decoder ASN1 but neither has successful information on how to go further with it.

  
  

  Please can someone help me or give me some idea how to continue. I'm really disappointed.

  
  

  I really appreciate your help!

  
  

  Thanks in advance,

  
  

  Luis.

  Hi again,

  I think that "58 59 00 FF 00 04 46 01" is USING the application, the result is very well (it ends with SW:9000) and it seems that you have selected application successfully asked. Now, you are able to select any file in the application. I guess that your purpose is to read EFdatas that has a file identifier "1005". Please try the following sequence:

  (1) select the application resp1 = {0x00, (byte) 0xA4, (byte) 0 x 04, 0 x 00, 0 x 08, 0 x 0, 58 x 59, 0 x 00, (byte) 0xFF, 0 x 00, 0 04, 0 x 46, 0 x 01, (byte) 0 x 00}; )

  (2) the command "Select File" send with file DF1: resp1 = {0x00, (byte) 0xA4, 1 m env, 0 x 00, 0 02, xx, yy} where P1 = 0x00 or 0x01 and xx yy is the file identifier of 2 bytes (ask for it or use search algorithm loop)

  (3) the command "Select File" send with EFdatas files: resp1 = {0x00, (byte) 0xA4, 1 m env, 0 x 00, 0 02, 0 x 10, 0 x 05} where P1 = 0x00 and 0x02

  (4) "Binary reading" send command with EFdatas files resp1 = {0x00, (byte) 0xb0, 0 x 00, 0 00, 0xFF}

  On the ISO7816-4 orders please read:

  Standard ISO 7816-4 smart card (ISO7816, part 4, section 6): basic Interindustry commands

  Concerning

• To make a cell read-only with javascript in 11.1.2.1

  I'm conditionally locking cells based on a value. This is something I have done in the past, but cannot get to work in 11.1.2.1. Here is my code. I don't get any errors, so the cell object is identified. The properties of the object exist (I think) because the definition cell.readonly = true does not cause an error. The reposting seems so called. However, nothing happens when the form is opened or modified. The function is the ONLOAD function. I checked that the closure is correct with alerts, so I know it's a loop in the correct cells.
  

      var r = 0;
      var c2 = 0;
      var c = currentDataGrid.startCol + 1; // account for a hidden column
      var allocPct = 0;
      valid = true;    
      // Loop through all rows except the last row, in the first column
      for (c=currentDataGrid.startCol; c<=currentDataGrid.endCol; c++){
        // Stop at the column where the account is ??????????????????
        if(listContainsName(getColMembersOfCell(r, c), "HR_Post_Number")){
          //  Now that the account was found, look through each row
          alert("HR_Post_Number found in column" + c);
          for (r=currentDataGrid.startRow; r<=currentDataGrid.endRow - 1; r++){
            // If the account has a value, make the entire row locked
            if(!isNaN(getCellVal(r,c))){
              alert("row " + r + getCellVal(r,c));
              for (c2=currentDataGrid.startCol; c2<=currentDataGrid.endCol -1; c2++){
                var cell = currentDataGrid.getCell(r,c2);
                cell.readOnly = true;
                redisplayCell(r,c2);
  
              }
            }
          }
        return; //exit as the column was found
        }  
      }

  If anyone can tell me why the cell.readonly = true and actualize them isn't doing nothing (which means that the cell is still editable), I'd appreciate it.
  
  Published by: user10920513 on July 18, 2012 13:19

  Add the following code before the redisplayCell

  tdId var = "V_" + currentDataGrid.gridIndex + "_" + r + "x" + c2; ".
  var tdObject = document.getElementById (tdId);
  If (tdObject! = null) {}
  cell.readOnly = true;
  tdObject.className = "ro";
  }

• slider raise last record?

  Hello expert...
  After the cursor to the folder of emp table... but finally view record displayinmg 2 time why?
  
  declare
  cursor c1 is
  Select empno, ename from emp;
  l emp.empno%type;
  m emp.ename%type;
  Start
  Open c1;
  loop
  extract the c1 in l, m;
  -When exit c1% notfound;
  dbms_output.put_line(l||) e -'|| (m);
  / * If c1% notfound then
  "exit";
  end if; */
  When exit c1% notfound;
  end loop;
  Close c1;
  end;
  
  MONOSTABLE:
  7369 SMITH
  7499-ALLEN
  7521 WARD
  7566 JONES
  7654-MARTIN
  7698 BLAKE
  7782-CLARK
  7788-SCOTT
  7839 KING
  7844-TURNER
  7876 ADAMS
  7900-JAMES
  7902 FORD
  7934 MILLER
  7934 MILLER
  PL/SQL procedure successfully completed.
  
  Why?
  
  Thank you best regards n
  Yoann

  yash_08031983 wrote:

  After the cursor to the folder of emp table... but finally view record displayinmg 2 time why?

  Because it is explicitly indicated by the source code.

  -extraction of the last line.
  -display the family name.
  -East of expressions of folklore for the whole of the cursor? No - the fact ' pointer' cursor still refers to a valid line
  -loop iterates again
  -Retrieves the next line - does not exist, then the cursor of the folklore about
  -display the family name. Once again.
  -East of expressions of folklore for the whole of the cursor? Yes - put end loop

• pl/sql insert slow

  Hello friends,
  I have a PL / SQL doing an insert into a table with an average of 1500 documents per minute, but for the record which is about 300,000, this speed decreases gradually, Faza demoranto for a total of 3 500 000 records almost 6 hours, you think it might be slow?
  
  Hugs
  
  Zander

  Hello

  There are two points here.

  1. even if your code is difficult to read (in capital letters and without formatting) I would up the assumption that most of the code could be replaced by a single INSERT statement. This would remove the looping and validations in loops.

  2 indexes cause an overload on the DML operations, especially on large tables. This is because the database must maintain the index during the operation, including both read and write operations. You get a double whammy when indexes are so great that they wouldn't fit in the buffer, and the database is using excessive disk IO. You can increase database buffers to account for this, but there are practical limits to this. Another good practice for loading in bulk, especially when you truncate the table, don't load and then later rebuild is to drop or set the index of a table before you as unusable.

  Hope this helps
  André

• Monitoring of the movements of the mouse

  When a mouse user of an item in my form for any other article in my form, is there a way to identify the name of the element where the cursor was sitting before they toss away?
  
  In the end, I want to prevent the user from mousing away from some points where I was forced to put the validation code in a key-Next-Item trigger. I was forced to put the code validation into the trigger next-item key, because the validation code is complex and requires the use of several built-ins limited (go_block, next_record, go_item, etc.) in order to validate if a record with some values has been entered in an another canvas/block within the application.
  
  I would like suggestions. Thank you.

  It is at this point that the "When-validate-Item" trigger first shot time and again unexpectedly appears.

  Yes, it's what I introduced the GLOBAL. INPROCESS, so that him WHEN-VALIDATE-ITEM "knows" that it is done because its controls called "inside" a validation of loop

• Tables APEX_APPLICATION - phase?

  I'm really struggling to get my head around this. I am generating a region of report using APEX_ITEM and my code looks like this:

  select
  ac.short_desc || apex_item.hidden(1, ac.short_desc) "short_desc",
  apex_item.checkbox(2,ac.audit_check_id,'UNCHECKED') "Fail"
  from audit_check ac
  where active_flag = 'Y'
  and department_id = 1

  I use a validation to loop through the array of checkbox and return the value of the field short_desc. There are only 2 rows in my region to report, but strangely, if I check the first box, which seems to return the value of the second line of the report, not the first short_desc.
  
  This is the code I use to return the value of short_desc, I rewrote it as a simple debugging output to see what is happening. If I check the first box, I get the second value of short_desc instead of the first. I am doing something stupid here? Code below:

  begin
  
  FOR i in 1..APEX_APPLICATION.G_F02.COUNT LOOP
  
  wwv_flow.debug(APEX_APPLICATION.G_F01(APEX_APPLICATION.G_F02(i)));
  
  end loop;
  
  end;

  Also, if I choose the second box, I get an ORA-01403: no given available error, as he is looking for a value of table that does not exist.

  Hello:

  Your validation needs are not related to the question that started this thread.
  You can consider using javascript to validate the contents of the text box on the form. Something like

  arr1 = document.forms[0].f02;
  arr2 = document.forms[0].f03; // the textarea
  for (i=0;i.value=='') alert ('error message here');}...
  
  

  Edited by: varad acharya on Nov 11, 2009 5:34 AM                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                    
  

• Commits in PL SQL

  Hello world
  
  May I know if there is a maximum or optimum of transactions which may occur before a commit is executed?
  
  My problem is caused by the command commit not allowing the use of WHERE CURRENT OF in a loop for updating the current record. The result is a need for research through the large table (3 million records) again so that the record to current day.
  
  (A side note is that using WHERE CURRENT OF reduce the execution time of the script from 20 min to 1 min for a test case 10 k.) A linear calculation means that 3 million records is gong to take 10 days...)
  
  I suggest to my supervisor didn't commit until after the end of the loop, but I need some technical information to explain that it is better validation after validation or loop after each record. What is the advantage and disadavantage of the two of them?
  
  Thanks in advance and sorry that I can not put the original script up due to privacy concerns...
  
  Kind regards
  phyrexians

  BTW, WHERE COURSES use only the rowid, so if you want the same effect you could simply include the rowid in your cursor and replace WHERE CURRENT OF WHERE rowid = r.rwd. But if it was your code, it is highly likely, you can replace the entire construction with an appropriate SQL UPDATE statement.

  Edited by: William Robertson on May 22, 2009 23:11

• Photoshop CC 2015 - loop without end of license validation during startup. All Solutions?

  I use PS CC 2015 for awhile to editing photos and other, I uninstalled PS CC 2015 of my C drive (to free up space and consolidate PS CC 2015 things on another drive) and installed on another drive, I couldn't go back into Photoshop. While trying to start it it give me a window of validation of software license that would pop up and disappear every few seconds again and again.

  
  

  
  

  
  

  

  
  

  ----------------------------------------------------------------------------------------------------------------------------------------------------

  
  

  Stats on my computer:

  
  

  Edition of Windows: Windows 8 Pro

  Processor: Intel (r) Core i7Cpu

  Installed memory (RAM): 8 GB

  System type: 64-bit, x 64 processor operating system

  
  

  --------------------------------------------------------------------------------------- - ------------------------------------------------------------

  I tried solutions:

  -Uninstalling and reinstalling under the C drive.

  -Signature of creative cloud while trying to validate, and then would give me licenses guest, connected to the Adobe ID with photograph subscription, after the saying of the window, hit continue to use licensed software with the right Adobe ID has signed, he returned to the loop without end of validation.

  -Remove adobe all items under the heading other disks and keep adobe all the items on the C drive.

  -Removed and reinstalled creative cloud.

  -Check the subscription payments were going through

  -Update audit logs to make sure I had not missed a.

  ------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

  
  

  Possible things I can do (not sure if I did) to screw it up. Let me know if all trigger problems.

  
  

  Tempted to go to associated adobe does not file creative cloud, simply move the folders, without uninstalling and reinstalling.

  
  

  Accidentally deleted Adobe of the linked files, can't speak of it, I don't think I hit anything on my drive C (default main drive)

  ------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

  
  

  I am considering solutions:

  
  

  Remove all adobe, folders, items related to photoshop and creative cloud from scratch I guess?

  
  

  Cancellation of the plan and from the cool email, (adobe ID), however, since it is a contract of plan year, paid monthly, I suppose, they will be responsible for the rest 10 months. I use PS CC 2015 for 2 months.

  
  

  ------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
  

  
  

  Any help is appreciated, willing to try anything since I am a creative work on the photos for friends, if a staff member could check on their end when my subscription works, it would be appreciated.
  

  
  

  In conclusion, the infinite loop software validating, tried a bunch of solutions, looking on the Internet without success, extremely frustrated.
  

  
  

  A keen user of Photoshop CC 2015.

  Michael Vigman
  

  
  

  
  

  
  

  Hi Michael,

  Thanks for your detailed thread.

  Please follow the steps below.

  First of all make sure that you have followed the steps mentioned in Adobe Creative Cloud connection errors

  1. Rename Slcache and Slstore
  • Navigate to C:/ProgramData\Adobe\ (program data are hidden folder) and rename the Slstore to Slstore.old
  • Go to C:\Program Files (x 86) \Common Files\Adobe\ and rename Slcache to Slcache.old

  2. now, the suite Adobe Creative Cloud connection errors rename opm.db file

  • Navigate to the OOBE folder. : - \Users\[username]\AppData\Local\Adobe\OOBE
  • Rename the file opm.db in opm.old.db

  3. run the vacuum to clean install Adobe Creative cloud and Photoshop. (If the step 1 and 2 does not solve the problem)

  • See using the Adobe Creative Cloud cleaning tool to solve installation problems

  Let us know if this helps

  Kind regards

  Assani

• better option than a loop of validation?

  I am running 11.2.0
  
  I'm looking at the setting of a sql statement, and the issue was raised as to the max inserts by transactions in 11g, and if it is greater than 1000.
  I have not yet found a solid answer, but I thought that 10g was higher than 1000.
  
  In any case...
  My first thought was to implement a loop of validation on every 1000 lines, because that's how things were handled in the past.
  But I found an article that talks of redo logs and performance and how it is a horrible practice to do the validation loop.
  
  What I did find is what is the best methodology by doing this?
  
  My scenario could meet as much as 20 000 inserts at the same time.
  
  Thank you.

  Willy_B wrote:

  I'm looking at the setting of a sql statement, and the issue was raised as to the max inserts by transactions in 11g, and if it is greater than 1000.

  There is no limit. So yes it is greater than 1,000

  What I did find is what is the best methodology by doing this?

  Insert directly in select

  My scenario could meet as much as 20 000 inserts at the same time.

  Here is an example on a database of development of the small insertion of 1 million lines in less than 10 seconds

  SQL> create table t (n number, a varchar2(50), b varchar2(100), c varchar2(200));
  
  Table created.
  
  SQL> set timing on
  SQL> insert into t
    2  select level, rpad('a', 50, 'a'), rpad('b', 100, 'b'), rpad('c', 200, 'c')
    3  from dual connect by level <= 1000000;
  
  1000000 rows created.
  
  Elapsed: 00:00:09.95
  

• Question about VALIDATION and EXCEPTION loop

  DB version: 11.2
  
  I believe the gurus here despise is committed inside loops. Due to budgetary constraints our java colleagues write code PL/SQL here. Below is an excerpt from a stored procedure that does some archive stuff.
  
  
  Question on COMMIT
  =====================
  I know is committed to the inside of the loops is bad, but I just want to know if the path that they have implemented COMMIT frequency is correct (using the number of iterations). Their intention was to commit all 200,000 records.
  
  
  Question on EXCEPTION
  ======================
  LMD like that, isn't better to have the exception block in the loop?
  
  
  
  
  

   
   
  select po.txn_id, po.po_id BULK COLLECT into v_txn_id, v_po_id 
  from purchase_orders po inner join txn_pkt_common tc 
  on tc.txn_id = po.txn_id
  and tc.created_date < po.last_mod_date;
  
  
  v_rec_count := 0;
  
  
  IF v_txn_id IS NOT NULL AND v_txn_id.COUNT > 0 THEN
  
  
       FOR i IN v_txn_id.FIRST .. v_txn_id.LAST LOOP
  
            v_rec_count := v_rec_count + 1;
  
            INSERT INTO purchase_orders_archive SELECT * FROM purchase_orders WHERE po_id = v_po_id(i);
  
            DELETE FROM purchase_orders WHERE po_id = v_po_id(i);
  
  
            IF v_rec_count >= 200000 THEN
            COMMIT;
            v_rec_count := 0;
            END IF;
  
        END LOOP;
       COMMIT; 
  
  end if;

  ExpansiveMind wrote:
  DB version: 11.2

  I believe the gurus here despise is committed inside loops.

  Cursor inside the lines, Yes, but this isn't a case of contemptuous, it's more to do this is to knowingly introduce a bug in your code, resulting in a possible "snapshot too old" error So, good programmers do not.

  Question on COMMIT
  =====================
  I know is committed to the inside of the loops is bad, but I just want to know if the path that they have implemented COMMIT frequency is correct (using the number of iterations). Their intention was to commit all 200,000 records.

  Q: Why is there the intention to commit all 200,000 records? What is the issue they're trying to move?

  In your example code, it is the data block collection. Is it really in collector block + 200,000 records? If so you may have a serious impact on the resources of database data are collected in the memory of the PGA, which is expensive.

  Question on EXCEPTION
  ======================
  LMD like that, isn't better to have the exception block in the loop?

  That depends on what you want to do when an exception occurs. If the exception can be 'managed' and you want to continue processing the rest of the data, then Yes, you would want an exception around the DML inside the loop block. If an exception should cause processing to stop completely, then you want the exception handler (if you really need one) out of the loop... but then you wonder again why you make inside the loop, because it is not supposed transaction.

  All of this procedure looks like this could be done with a single INSERT statement followed a single DELETE statement, followed by a unique validation. Oracle can easily handle millions of records, so it shouldn't be a problem.

  The other problem with frequent postings is that each commit tells oracle to write the data to the data blocks, and these 'write' get statements go in the database for the writer to manage processes. By default, there are X number of writer running process (depends on version and other parameters) when the database starts, but if a large number of postings is published then Oracle begins to generate additional editor on the server processes to manage the extra workload, which can then cause a lot of writer running process (using the resources of the server) all trying to access the same load of blocks of data in terms of physical i/o and therefore all the other slows down. This is why frequent postings are not a good thing, and you must book to engage in logical business transactions.

• for the validation of the loop

  I have this code in my procedure, the code runs well but his does not does not update inside the loop statement for...
  

  SELECT customernumber  BULK COLLECT
                  INTO in_tab                
          FROM Tablename;
  
  
  FOR i IN 1 .. in_tab.COUNT
   LOOP
      if(i>=1) then
        if (i<in_tab.COUNT) then
        
          UPDATE Tablename
          SET COUNT = 2 
          WHERE customernumberlike 'in_tab (i)';
           end if;
      end if;
    END LOOP;
    commit;

  Thanks for your help.
  
  Published by: user7404990 on August 20, 2009 05:17

  Are you sure that the Update statement works?

  Your example doesn't have updated validation, as Where clause seeks a literal "in_tab (i).