How to find max based on 2 columns.

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• How to find a value in any column of the table - essentially a search

  Hi guys,.

  Thanks in advance for your help.

  I'll try to find a value in any column of the table? How can I do?

  An example of value would be "FEDERAL."

  Using Oracle 11 g and SQL Developer.

  Thank you

  It's a question that is asked in the past several times (but not recently from what I remember).

  Michaels has provided in the past, solutions which are quite clever, just using SQL...

  10g of solution

  Michaels > var val varchar2 (5)

  Michaels > exec: val: = "Sub".
  PL/SQL procedure successfully completed.

  Michaels > select distinct substr (: val, 1, 11) "keyword."
  substr (table_name, 1, 14) "table."
  substr (t.column_value.getstringval (), 1, 50) ' / value of the column.
  CLO.
  Table
  (xmlsequence
  (dbms_xmlgen.getxmltype ("select" | column_name))
  || 'from ' | table-name
  || ' where upper (')
  || column_name
  || ') as superior (' %' |: val)
  || '%'')'
  ) .extract (' LINES/rowset / * "")
  )
  ) t
  -where table_name in ('EMPLOYEES', 'JOB_HISTORY', 'SERVICES')
  order of the "Table".

  11g upwards

  SQL > select table_name,.
  column_name,
  : search_string search_string.
  result
  from (select column_name,
  table_name,
  "ora: view("' ||) " table_name | "") / LINE /' | " column_name | "[ora:contains (text ()," %' |: search_string | ")]. (%») > 0]' str
  CLO
  where table_name in ('EMP', 'Department')),
  XMLTable (columns str result varchar2 (10) path '.')
  /

  TABLE_NAME COLUMN_NAME SEARCH_STRING RESULT
  ------------------------------ ------------------------------ -------------------------------- ----------
  DEPT                           DNAME                          es                               RESEARCH
  EMP                            ENAME                          es                               JAMES
  EMP                            JOB                            es                               SALESMAN
  EMP                            JOB                            es                               SALESMAN

  4 selected lines.

• How to find the name of a column in a table

  Hi all
  
  I have a Table that contains approximately 100 columns.
  
  
  I need to find the column name, to find in specific columns containing data like 'abc '.
  
  Ex: I have a table like temp_table_name
  the columns are col1, col2, col3, col4, col5, col6, col7, col8,.... col99
  I'm looking for with data specific like 'abc '.
  
  Need to find the name of the table column that contains data of 'abc '.
  
  Please suggest me. How to find in a single query... :-)
  
  Actually I'm looking through a column of the table as below
  Select count (*) in the temp_table_name where col1 = 'abc '.
  
  FOR I IN 1.20 LOOP
  ln_num_of_rows: = 0;
  lv_column_name_search: = "col" | I have;
  
  lv_sql: = ' select count (*) in the temp_table_name where ' | lv_column_name_search | "= abc";
  
  EXECUTE IMMEDIATE lv_sql INTO ln_num_of_rows;
  
  IF ln_num_of_rows > 0
  -column found in lv_column_name_search
  EXIT;
  END IF;
  END LOOP;
  
  But I'm gettig performance problem.
  
  How can I do this in any other alternative way? could you suggest any way possible as soon as POSSIBLE.

  It's probably never going to be effective - realistic, you have to scan completes the picture.

  You could probably improve a little things by doing something like

  SELECT DISTINCT column_name
    FROM (
      SELECT (CASE WHEN col1 = 'abc' THEN 'col1'
                  WHEN col2 = 'abc' THEN 'col2'
                  WHEN col3 = 'abc' THEN 'col3'
                  ...
                  WHEN col20 = 'abc' THEN 'col20'
                  ELSE NULL
                  END) column_name
        FROM table_name
      WHERE col1 = 'abc'
          OR col2 = 'abc'
          ...
          OR col20 = 'abc'
    )
  

  but it's never going to be incredibly fast.

  Justin

• How to find DB tables containing specific columns (ORG_ID / ORGANIZATION_ID)

  Hi all, I would like to know if someone has developed a script to find all tables containing the columns (fields) specific.

  
  I'm on a migration project where I don't have access to the source of the DB, I just ask for queries and I to reflect all the tables DB containing specific data of organization.

  So the first step was to understand used tables and I get them, now I understand what tables have Org_id / Organization_ID and fields of the SOURCE of the LANGUAGE/LANGUAGE (source DB has much set Org and many languages also, so I need to filter the 100total 6ORG_ID and 2 languages of 8 total installed)

  Can anyone help?

  Thank you

  Best regards

  Pietro

  Hello

  You can see this:

  Find all tables in db with the name of the column of a particular string?

  Kind regards

  MihaiF

• ORA-01438: how to find the name of the column?

  Hello
  
  I'm trying to find the column which is causing ORA-01438 when inserting into a table.
  
  The insertion is made by a C program that reads from a socket and written in an oracle 10 g database using Oracle Pro * C.
  
  I tried to identify the column by printing the values (about 250) just before the insert statement is executed, but check these values has been a task heavy and error prone and did not help to correct the mistake (I found a bunch of values which out of reach, but changing these values has not resolved the issue).
  
  Abandon this idea, I tried to track the session to help
  (1) DBMS_SYSTEM. SET_SQL_TRACE_IN_SESSION,
  (2) DBMS_MONITOR.session_trace_enable/disable and still
  (3) change the context name system set events 10046 trace forever, level 12' and;
  (4) alter system set sql_trace = true scope = mΘmoire;
  
  DBMS_MONITOR.session_trace_enable only gave me a few tips (the insert statement) in a trace file. But it worked for a simple example of a test database.
  
  When I try to turn on tracing on the database, where the error occurs, then I'm still not able to set SQL_TRACE in V$ SESSION true, even if no error is returned by the statement "DBMS_MONITOR.session_trace_enable". The value of SQL_TRACE in V$ SESSION does not change and I have no idea why. On the test database, it works fine and I can find the trace file in the user_dump_destination directory.
  
  Anyone have any suggestions on how to fix this?
  
  Any help is appreciated.
  Thanks in advance!

  Just check this:

  SQL > conn osama/osama ;
  SQL> create table test as select * from scott.dept ;
  
  SQL> select * from test ;
  
      DEPTNO DNAME          LOC
  ---------- -------------- -------------
          10 ACCOUNTING     NEW YORK
          20 RESEARCH       DALLAS
          30 SALES          CHICAGO
          40 OPERATIONS     BOSTON
  
  SQL> alter system set events='1438 trace name Errorstack forever,level 10';
  
  SQL> insert into test values (100000000000000000,'osama','JOR');
  insert into test values (100000000000000000,'osama','JOR')
                           *
  ERROR at line 1:
  ORA-01438: value larger than specified precision allowed for this column
  
  In Trace File :
  
  ORA-01438: value larger than specified precision allowed for this column
  Current SQL statement for this session:
  insert into test values (100000000000000000,'osama','JOR')
  

• How to find max Crest audio audio tracks combined with the applied effects?

  Hi all

  I work in the CS5.5 body.

  Often when I'm working on a timeline, I have two audio tracks of the same songs, one of the camera and the other a separate, synchronized sound recorder on the timeline, so that they combine into a single signal. Applied to these titles, I might have an effect filter or high-low pass EQ. Now, I know that the maximum peak of each track or the individual clips is easy to find using the "Gain Audio" menu item, which I hope is the equivalent of this item of menu but related to the final output after two signal tracks has been added and effects have all served? It is a task that is very painful to have to listen through the entire timeline to discover if the output goes into 0db, if there was a way I could locate on the timeline where the max output, which would definitively solve the problem.

  Find the way to do this would literally save hours per project! It's the only thing that makes me groan inwardly when I perform the output volume, what I have to do most of the time.

  If all goes well,

  Peter.

  I always put a compressor and - 1db limiter of ridges on the master to stop overmods.

• How to find out based on all INDEXES, VIEWS,... a table?

  How can I find out how much and what objects dependent (index, views...) has a certain myuser444.table123 TABLE?
  
  Peter

  user559463 wrote:
  How can I find out how much and what objects dependent (index, views...) has a certain myuser444.table123 TABLE?

  Use the DBA_DEPENDENCIES and DBA_INDEXES. For example:

   select  type || ' ' || owner || '.' || name
     from  dba_dependencies
     where referenced_owner = 'SCOTT'
       and referenced_name  = 'EMP'
       and referenced_type  = 'TABLE'
  union all
   select  'INDEX ' || owner || '.' || index_name
     from  dba_indexes
     where owner = 'SCOTT'
       and table_name  = 'EMP'
  /
  
  TYPE||''||OWNER||'.'||NAME
  ----------------------------
  FUNCTION SCOTT.F1
  VIEW SCOTT.EMP_VW
  INDEX SCOTT.PK_EMP
  INDEX SCOTT.EMP_IDX1
  
  SQL> 
  

  SY.

• How to find the name of the column in the tables

  Hello..

  Suppose that there are thousands of table in the database. Out of them a few tables contain the column name as 'ENTRY_BY '.

  I want to know the tables that have columns like "ENTRY_BY".

  ... Please suggest for this query.

  all_tab_cols

  Select * from all_tab_cols

  where column_name like ' % INPUT % ';

  Post edited by: Rajavignesh

• Re: How to get Max (all values of columns) records on a partition interval

  Hello
  

  Hours      Days            Name     used_size
  1     01-09-012     R1     1100
  10     01-09-012     R1     1150
  15     01-09-012     R1     1160
  23     01-09-012     R1     1200
  
  1     01-08-012     R1     1600
  10     01-08-012     R1     1700
  15     01-08-012     R1     1800
  23     01-08-012     R1     1500
  
  1     01-09-012     J1     10
  10     01-09-012     J1     20
  15     01-09-012     J1     30
  23     01-09-012     J1     60
  
  1     01-08-012     J1     70
  10     01-08-012     J1     5
  15     01-08-012     J1     17
  23     01-08-012     J1     22
  
  
  Needed o/p:
  
  23     01-09-012     R1     1200
  23     01-08-012     R1     1500
  23     01-09-012     J1     60
  23     01-08-012     J1     22

  We have table as above, IE. everyday, there are records at regular intervals of hours for different users.
  
  I want to get a single record of every day for one hour on this day for all users.
  
  
  Please let me know if my question was unclear?
  
  -Thank you

  Another way, maybe more simple here, here could be just group by user, day.

  SELECT user, day, Max(hours) max_hours, Max (used_size) KEEP (DENSE_RANK LAST ORDER BY hours) mh_used_size
    FROM (table)
   GROUP BY user, day
   ORDER BY user, day
  

• How to find the Union between the column in the table

  Hello
  
  I have the followin table and I want to find the union between the lines as below,
  

  create table test5 (tidset varchar2(200));
  
  insert into test5 values('1;2;3;4;5;6;7;8;9;10;11;12;13;15;16;17;18;19;20');
  insert into test5 values('1;2;3;4;5;6;7;8;9;10;11;12;13;14;15;16;17;18;19;20');
  insert into test5 values('1;2;3;4;6;7;8;9;11;12;13;15;16;19;20');
  insert into test5 values('1;4;6;10;6;11;12;13;14;15;16;17;18;19;20');

  I need the result to be as below.
  

  1;4;6;11;12;13;15;16;19;20

  any help please,.
  
  Published by: user11309581 on November 17, 2011 21:32

  Always mention what version of oracle you are using.

  The following query will give you the desired result oracle version 11g release 2.

  Connected to Oracle Database 11g Release 11.2.0.2.0 
  
  SQL>
  SQL> with test5 as
    2  (
    3  select '1;2;3;4;5;6;7;8;9;10;11;12;13;15;16;17;18;19;20' tidset from dual union all
    4  select '1;2;3;4;5;6;7;8;9;10;11;12;13;14;15;16;17;18;19;20' from dual union all
    5  select '1;2;3;4;6;7;8;9;11;12;13;15;16;19;20' from dual union all
    6  select '1;4;6;10;6;11;12;13;14;15;16;17;18;19;20' from dual
  -- "END OF SAMPLE DATA"
    7  ), all_items as
    8  (
    9    SELECT regexp_substr(t.tidset, '[^;]+', 1, column_value) item
   10          ,t.tidset
   11      FROM test5 t
   12          ,TABLE(CAST(MULTISET
   13                      (SELECT LEVEL
   14                         FROM dual
   15                       CONNECT BY LEVEL <=
   16                                  length(regexp_replace(t.tidset, '[^;]')) + 1) AS
   17                      sys.odcinumberlist))
   18  ),item_counts as
   19  (
   20    SELECT DISTINCT a.item
   21                   ,COUNT(DISTINCT a.tidset) over() total_tidset
   22                   ,COUNT(a.item) over(PARTITION BY a.item) item_occurance_count
   23      FROM (SELECT DISTINCT item
   24                           ,tidset
   25              FROM all_items) a
   26  )
   27  SELECT listagg(item, ';') within GROUP(ORDER BY to_number(item)) common_items
   28    FROM item_counts
   29   WHERE total_tidset = item_occurance_count
   30  ;
  
  COMMON_ITEMS
  --------------------------------------------------------------------------------
  1;4;6;11;12;13;15;16;19;20
  
  SQL> 
  

  OR if you have any version of oracle less than 11g release 2 then replace below mentioned line

  SELECT listagg(item, ';') within GROUP(ORDER BY to_number(item)) common_items
  

  with this one

  select xmlagg(xmlelement(c,item||';').extract('//text()') order by (to_number(item))) common_items
  

  It is because the listagg function used in above query is not supported in versions of oracle 11.2 below.

  I hope this helps.

  -Gregory

  Published by: Mohamed Diarra on November 18, 2011 01:05
  Extra line to be changed for the oracle version lower than 11.2

• How to find Max, Min and Avg generation of redo to a database

  I'm trying to remake maximum, minimum and average, a database to generate daily. This information, as well as knowledge of
  specific database will be useful for me to determine the log archiving directory space allocation is sufficient for our database activity.
  
  I want to just make sure that the request is correct or not.
  
  Select upper (B.HOST_NAME) HOST_NAME, upper (B.INSTANCE_NAME) INSTANCE_NAME, A.* FROM)
  Select max (redo_in_gb) MAX_REDO_IN_GB, min (redo_in_gb) MIN_REDO_IN_GB, avg (redo_in_gb) AVG_REDO_IN_GB)
  Select sum (blocks * block_size) /(1024*1024*1024) REDO_IN_GB, trunc (first_time) as "RUN_DATE"
  v $ archived_log where trunc (first_time) > (select trunc (resetlogs_time) in v$ database_incarnation where status = 'CURRENT')
  Trunc Group (first_time))) A, V$ INSTANCE B
  
  
  Thank you
  Guz

  Yes, that sounds good.

• How to find the name of the column to the attributes of the IOM?

  What is the COLUMN_NAME for attributes 'Generated password' and 'Access Console Design' in OIM 11 g?
  Also I can't find anywhere in FormMetaData.xml. A file that represents FormMetaData.xml in OIM11g?

  Sorry

  Try USR_TYPE

• How to concatenate values based on multiple columns of data duplicate in the loop

  Hi all

  Select '100' col_1, '111111' col2 of double

  Union of all the

  Select '100' col_1, '222222' col2 of double

  Union of all the

  Select '101' col_1, '333333' col2 of double

  Union of all the

  Select '102' col_1, '333333' col2 of double

  I need to write by using cursor loop (configurable) so, it must concatenate col_1 or col_2

  If,

  In the table

  col_1, col_2

  100 111111

  100 222222

  101 333333

  102 333333

  Then

  col_1, col_2

  100 111111,222222

  333333 101 102

  Is it possible to compare and concatenate values in the loop

  I have more than 4,000 bytes in the table of col_1,col_2 data values

  Oracle Database 11 g Enterprise Edition Release 11.2.0.1.0 - 64 bit Production

  Ok then:

  create a type that makes "grouped" clob

  CREATE or REPLACE TYPE clob_obj IS OBJECT
  (
  CLOB theClob
  ORDER MEMBER FUNCTION equals (in_clob_obj IN clob_obj) RETURN NUMBER
  member function getClobVal return clob)
  /

  CREATE or REPLACE TYPE clob_obj BODY
  IS
  FUNCTION MEMBER ORDER is equal to (in_clob_obj IN clob_obj)
  RETURN NUMBER
  IS
  BEGIN
  RETURN sys.dbms_lob.compare (SELF.theClob, in_clob_obj.theClob);
  END;
       
  Member return clob getClobVal function
  is
  BEGIN
  Return self.theClob;
  end;
  END;
  /

  WITH conc_table AS (SELECT 1111 cust_id, cust_no 'ABC', '101010' ordr_no OF DOUBLE UNION ALL

  SELECT 2222 cust_id, cust_no 'ABC', '101010' ordr_no OF DOUBLE UNION ALL

  SELECT 3333 cust_id, cust_no 'ABC', '101010' ordr_no OF DOUBLE UNION ALL

  SELECT cust_id 4444, "CCC" cust_no, ordr_no ' 123456' OF DOUBLE UNION ALL

  SELECT cust_id 5555, "CCC" cust_no, '454545' ordr_no OF DOUBLE UNION ALL

  Select cust_id 66666, "CCC" cust_no, ordr_no ' 77777' DOUBLE UNION ALL

  SELECT cust_id, "CCC" cust_no, ordr_no ' 77777 66666' FROM DUAL)

  SELECT rtrim (XMLAGG (XMLELEMENT (E, cust_id_no, ',')). EXTRACT ('customer_id //text()').getClobVal (),',')

  clob_obj (ord_number) .getClobVal)

  cust_num

  FROM (SELECT cust_id_no

  cust_num

  rtrim (XMLAGG (XMLELEMENT (E, ord_num, ",")). EXTRACT ('//text ()') .getClobVal (), ',') ord_number

  FROM (SELECT DISTINCT cust_id_no, cust_num, ordr_no AS conc_table FROM ord_num cust_no cust_id)

  GROUP BY cust_id_no

  cust_num)

  GROUP BY clob_obj (ord_number)

  cust_num;

  I got the distinct in the select more intimate for no duplicate of the basetable is only sent to reunification of...

  HTH

• Find the name of the column in all tables

  How to find the name of the column in all tables in the database for any column to reveal the name of the person?

  
  We have over 1000 tables looking for.and in some places, the name column FNAME LNAME, First_NAME, DNAME

  For example we have Customer table, Table EMPLOYEE and the ORDER Table

  --------------------------------

  Customer table
  --------------------------------

  LNMAE

  EMPLOYEE table

  EMP_ID
  DEPT_NAME (we don't want this column as it is not a name column)
  Last_name (he must propose this column because it is named)

  ----------------------------

  CONTROL Panel

  -----------------------------

  ORDER_ID
  ORDER_NAME (we don't want this column as it is not a name column)
  Last_name (he must propose this column because it is named)

  -------------------------

  Dept table

  -------------------------

  Dept_ID
  DEPT_NAME (we don't want this column as it is not a name column)

  Please advise...

  Thank you.

  Hello

  What exactly do you do?

  If you want to display the tables containing these columns, you can query the view data dictionary USER_TAB_COLS (or ALL_TAB_COLS, or, if you have privileges, DBA_TAB_COLS).

  For example:

  SELECT table_name, column_name

  Of user_tab_cols

  WHERE nom_de_colonne IN ('DNAME', 'FNAME', 'FIRST_NAME', 'LAST_NAME', 'LNAME') - or else

  ORDER BY table_name, column_name

  ;

• How to find the value max and min for each column in a table 2d?

  How to find the value max and min for each column in a table 2d?

  For example, in the table max/min for the first three columns would be 45/23, 14/10, 80/67.

  Thank you

  Chuck,

  With color on your bars, you should have enough experience to understand this.

  You're a loop in the table already.  Now you just need a function like table Max and min. loop.  And you may need to transpose the table 2D.