How to find three consecutive non zero number of a table

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• How to find the second largest in a pl/sql table

  Hello friends,
  
  I want to find the first and second maximum items in a pl/sql table.
  
  Here's the code...
  
  DECLARE
  Max_earnings_type TYPE TABLE IS NUMBER;
  max_earnings_tab max_earnings_type: = max_earnings_type();
  number of v_count: = 0;
  number of v_max_earnings;
  
  
  Can someone give me how to find the maximum first max and second in the type of the given table.
  
  appreciate your help.
  
  Thank you/kumar
  
  Published by: kumar73 on October 21, 2010 09:42

  kumar73 wrote:

  When I tried to implement your logic in my application, I get the following error...

  PL/SQL: digital or value error: NULL index key value table

  What happens if the PL/SQL table has NULL values. Question is how you want to handle NULL values. You want to ignore nulls as GROUP BY do? If you want to consider NULL values, you can say if you want to order the NULLS FIRST or NULLS LAST. I guess that logical GROUP BY:

  DECLARE
      TYPE max_earnings_type IS TABLE OF NUMBER;
      TYPE max_earnings_sorted_type IS TABLE OF NUMBER
        INDEX BY BINARY_INTEGER;
      max_earnings_tab        max_earnings_type;
      max_earnings_tab_sorted max_earnings_sorted_type;
  BEGIN
      SELECT  sal + comm
        BULK COLLECT
        INTO  max_earnings_tab
        FROM  emp;
      FOR v_i in 1..max_earnings_tab.count LOOP
        IF max_earnings_tab(v_i) IS NOT NULL
          THEN
            max_earnings_tab_sorted(max_earnings_tab(v_i)) := 1;
        END IF;
      END LOOP;
      DBMS_OUTPUT.PUT_LINE('MAX value in PL/SQL table is ' || nvl(to_char(max_earnings_tab_sorted.last),'NULL'));
      DBMS_OUTPUT.PUT_LINE('Second MAX value in PL/SQL table is ' || nvl(to_char(max_earnings_tab_sorted.prior(max_earnings_tab_sorted.last)),'NULL'));
  END;
  /
  MAX value in PL/SQL table is 2650
  Second MAX value in PL/SQL table is 1900
  
  PL/SQL procedure successfully completed.
  
  SQL> SELECT  sal + comm
    2    FROM  emp;
  
    SAL+COMM
  ----------
  
        1900
        1750
  
        2650
  
        1500
  
    SAL+COMM
  ----------
  
  14 rows selected.
  
  SQL>
  

  SY.

• How to find a value in any column of the table - essentially a search

  Hi guys,.

  Thanks in advance for your help.

  I'll try to find a value in any column of the table? How can I do?

  An example of value would be "FEDERAL."

  Using Oracle 11 g and SQL Developer.

  Thank you

  It's a question that is asked in the past several times (but not recently from what I remember).

  Michaels has provided in the past, solutions which are quite clever, just using SQL...

  10g of solution

  Michaels > var val varchar2 (5)

  Michaels > exec: val: = "Sub".
  PL/SQL procedure successfully completed.

  Michaels > select distinct substr (: val, 1, 11) "keyword."
  substr (table_name, 1, 14) "table."
  substr (t.column_value.getstringval (), 1, 50) ' / value of the column.
  CLO.
  Table
  (xmlsequence
  (dbms_xmlgen.getxmltype ("select" | column_name))
  || 'from ' | table-name
  || ' where upper (')
  || column_name
  || ') as superior (' %' |: val)
  || '%'')'
  ) .extract (' LINES/rowset / * "")
  )
  ) t
  -where table_name in ('EMPLOYEES', 'JOB_HISTORY', 'SERVICES')
  order of the "Table".

  11g upwards

  SQL > select table_name,.
  column_name,
  : search_string search_string.
  result
  from (select column_name,
  table_name,
  "ora: view("' ||) " table_name | "") / LINE /' | " column_name | "[ora:contains (text ()," %' |: search_string | ")]. (%») > 0]' str
  CLO
  where table_name in ('EMP', 'Department')),
  XMLTable (columns str result varchar2 (10) path '.')
  /

  TABLE_NAME COLUMN_NAME SEARCH_STRING RESULT
  ------------------------------ ------------------------------ -------------------------------- ----------
  DEPT                           DNAME                          es                               RESEARCH
  EMP                            ENAME                          es                               JAMES
  EMP                            JOB                            es                               SALESMAN
  EMP                            JOB                            es                               SALESMAN

  4 selected lines.

• How to find the name of a column in a table

  Hi all
  
  I have a Table that contains approximately 100 columns.
  
  
  I need to find the column name, to find in specific columns containing data like 'abc '.
  
  Ex: I have a table like temp_table_name
  the columns are col1, col2, col3, col4, col5, col6, col7, col8,.... col99
  I'm looking for with data specific like 'abc '.
  
  Need to find the name of the table column that contains data of 'abc '.
  
  Please suggest me. How to find in a single query... :-)
  
  Actually I'm looking through a column of the table as below
  Select count (*) in the temp_table_name where col1 = 'abc '.
  
  FOR I IN 1.20 LOOP
  ln_num_of_rows: = 0;
  lv_column_name_search: = "col" | I have;
  
  lv_sql: = ' select count (*) in the temp_table_name where ' | lv_column_name_search | "= abc";
  
  EXECUTE IMMEDIATE lv_sql INTO ln_num_of_rows;
  
  IF ln_num_of_rows > 0
  -column found in lv_column_name_search
  EXIT;
  END IF;
  END LOOP;
  
  But I'm gettig performance problem.
  
  How can I do this in any other alternative way? could you suggest any way possible as soon as POSSIBLE.

  It's probably never going to be effective - realistic, you have to scan completes the picture.

  You could probably improve a little things by doing something like

  SELECT DISTINCT column_name
    FROM (
      SELECT (CASE WHEN col1 = 'abc' THEN 'col1'
                  WHEN col2 = 'abc' THEN 'col2'
                  WHEN col3 = 'abc' THEN 'col3'
                  ...
                  WHEN col20 = 'abc' THEN 'col20'
                  ELSE NULL
                  END) column_name
        FROM table_name
      WHERE col1 = 'abc'
          OR col2 = 'abc'
          ...
          OR col20 = 'abc'
    )
  

  but it's never going to be incredibly fast.

  Justin

• How to find the index of the closest value in table

  Hello

  I have a double-table A and a double value B.

  I'm looking for on what number in the table A is the closest number to number B?

  Thanks for help

  If the array is sorted, built-in 'Threshold 1 D Array' might work for you.

• How to find specific images by the number or the name of the image?

  I recorded some insights on my desktop and decided to get some of them. I went looking for them by the number of image (i.e., 18095749, etc.) and there seems to be no way to search for images, if you already know the name/number. How is it possible without going through all the images again looking for ones I want? Thank you.

  Search by image number is the best way. A very common mistake is that you have the correct image type unchecked in your search. Remember that all four types of images or at least not included three videos are checked.

  

• I bought an annual subscription with adobe pdf online export and you want to cancel. Still it has only 14 days. I don't know what or how do find or record a serial number because I have no one that I know of. How can I cancel and confirm my refund?

  How to cancel or confirm that I will receive a full refund, since it's still in the 14-day requirement? I have no idea what serial number, I have to this export adobe pdf or how I'm supposed to save it. This part of the process I need to fill for the cancellation and refund? Thank you

  Hello

  Please check the help below document:

  ICES.html https://helpx.adobe.com/x-productkb/Policy-Pricing/Cancel-subscription-Acrobat-Online-serv

  Kind regards

  Sheena

• How to find the Union between the column in the table

  Hello
  
  I have the followin table and I want to find the union between the lines as below,
  

  create table test5 (tidset varchar2(200));
  
  insert into test5 values('1;2;3;4;5;6;7;8;9;10;11;12;13;15;16;17;18;19;20');
  insert into test5 values('1;2;3;4;5;6;7;8;9;10;11;12;13;14;15;16;17;18;19;20');
  insert into test5 values('1;2;3;4;6;7;8;9;11;12;13;15;16;19;20');
  insert into test5 values('1;4;6;10;6;11;12;13;14;15;16;17;18;19;20');

  I need the result to be as below.
  

  1;4;6;11;12;13;15;16;19;20

  any help please,.
  
  Published by: user11309581 on November 17, 2011 21:32

  Always mention what version of oracle you are using.

  The following query will give you the desired result oracle version 11g release 2.

  Connected to Oracle Database 11g Release 11.2.0.2.0 
  
  SQL>
  SQL> with test5 as
    2  (
    3  select '1;2;3;4;5;6;7;8;9;10;11;12;13;15;16;17;18;19;20' tidset from dual union all
    4  select '1;2;3;4;5;6;7;8;9;10;11;12;13;14;15;16;17;18;19;20' from dual union all
    5  select '1;2;3;4;6;7;8;9;11;12;13;15;16;19;20' from dual union all
    6  select '1;4;6;10;6;11;12;13;14;15;16;17;18;19;20' from dual
  -- "END OF SAMPLE DATA"
    7  ), all_items as
    8  (
    9    SELECT regexp_substr(t.tidset, '[^;]+', 1, column_value) item
   10          ,t.tidset
   11      FROM test5 t
   12          ,TABLE(CAST(MULTISET
   13                      (SELECT LEVEL
   14                         FROM dual
   15                       CONNECT BY LEVEL <=
   16                                  length(regexp_replace(t.tidset, '[^;]')) + 1) AS
   17                      sys.odcinumberlist))
   18  ),item_counts as
   19  (
   20    SELECT DISTINCT a.item
   21                   ,COUNT(DISTINCT a.tidset) over() total_tidset
   22                   ,COUNT(a.item) over(PARTITION BY a.item) item_occurance_count
   23      FROM (SELECT DISTINCT item
   24                           ,tidset
   25              FROM all_items) a
   26  )
   27  SELECT listagg(item, ';') within GROUP(ORDER BY to_number(item)) common_items
   28    FROM item_counts
   29   WHERE total_tidset = item_occurance_count
   30  ;
  
  COMMON_ITEMS
  --------------------------------------------------------------------------------
  1;4;6;11;12;13;15;16;19;20
  
  SQL> 
  

  OR if you have any version of oracle less than 11g release 2 then replace below mentioned line

  SELECT listagg(item, ';') within GROUP(ORDER BY to_number(item)) common_items
  

  with this one

  select xmlagg(xmlelement(c,item||';').extract('//text()') order by (to_number(item))) common_items
  

  It is because the listagg function used in above query is not supported in versions of oracle 11.2 below.

  I hope this helps.

  -Gregory

  Published by: Mohamed Diarra on November 18, 2011 01:05
  Extra line to be changed for the oracle version lower than 11.2

• How to find the name of the column in the tables

  Hello..

  Suppose that there are thousands of table in the database. Out of them a few tables contain the column name as 'ENTRY_BY '.

  I want to know the tables that have columns like "ENTRY_BY".

  ... Please suggest for this query.

  all_tab_cols

  Select * from all_tab_cols

  where column_name like ' % INPUT % ';

  Post edited by: Rajavignesh

• How to find KB updates by number in Windows 7

  How to find the KB updates by number in win7 example 3017347 KB

    
  I have a list of KB of an audit of security updates. I need to find each KB and then download. example KB3017347, KB3048019, how I got all these. Thank you
  You had this question
  1. Connect to an administrator account [must],.
  2. Open IE [it is important]
  3. Go to the Microsoft update catalog service,
  4. [It will install a small add-on],
  5. In the find what box, enter the KB number
  6. If you want to you click on the name of the element to see may more details about it.
  7. Select Add to add the KB in the list of downloads or Add to cart , if you look at the details.
  8. Do this for each desired KB
  9. Click on view cart and follow the menu instructions to download.

• How to find level locks table

  Oracle APPS R12
  
  Hi all
  
  How to determine the table level locks in oracle Apps R12. When I run my simultaneous program its taking too much time to complete, and two or three concurrent programs are running in parallel and taking the same base table data, so how to find the locks if it is on the table. Any help is highly appricatable.
  
  
  Thanks and greetings
  Srikkanth.M

  Hello

  How to determine the table level locks in oracle Apps R12.

  Please see old similar threads.

  Table locks
  http://forums.Oracle.com/forums/search.jspa?threadID=&q=table+locks&objid=C3&DateRange=all&userid=&NumResults=15&rankBy=10001

  When I run my simultaneous program its taking too much time to complete, and two or three concurrent programs are running in parallel and to the same base table data

  Are these concurrent programs custom or seeded? You're correctly concurrent managers? Please see these documents for more details.

  A comprehensive approach to the performance of Oracle Applications systems [ID 69565.1]
  What is the size of "Cache" recommended for a Manager Standard [ID 986228.1]
  Troubleshooting problems of performance in the Oracle Applications / E-Business Suite [ID 117648.1]

  Thank you
  Hussein

• Find the name of the column in all tables

  How to find the name of the column in all tables in the database for any column to reveal the name of the person?

  
  We have over 1000 tables looking for.and in some places, the name column FNAME LNAME, First_NAME, DNAME

  For example we have Customer table, Table EMPLOYEE and the ORDER Table

  --------------------------------

  Customer table
  --------------------------------

  LNMAE

  EMPLOYEE table

  EMP_ID
  DEPT_NAME (we don't want this column as it is not a name column)
  Last_name (he must propose this column because it is named)

  ----------------------------

  CONTROL Panel

  -----------------------------

  ORDER_ID
  ORDER_NAME (we don't want this column as it is not a name column)
  Last_name (he must propose this column because it is named)

  -------------------------

  Dept table

  -------------------------

  Dept_ID
  DEPT_NAME (we don't want this column as it is not a name column)

  Please advise...

  Thank you.

  Hello

  What exactly do you do?

  If you want to display the tables containing these columns, you can query the view data dictionary USER_TAB_COLS (or ALL_TAB_COLS, or, if you have privileges, DBA_TAB_COLS).

  For example:

  SELECT table_name, column_name

  Of user_tab_cols

  WHERE nom_de_colonne IN ('DNAME', 'FNAME', 'FIRST_NAME', 'LAST_NAME', 'LNAME') - or else

  ORDER BY table_name, column_name

  ;

• How to find the serial number of the processor in the MacBook pro s serial number? I have a dead MacBook that was given for service to a third party. I doubt that they have replaced the original parts. Help, please. Thank you

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  Hello

  I start with the second question:

  bytes_read = ReadLine (file_handle, line_buffer, maximum_bytes);

  the second argument is the buffer to store the characters read, so it's an array of characters; It must be large enough to hold maximum_bytes the value NULL, if char [maximum_butes + 1]

  So, obviously the number of lines in your text tiles can be determined in a loop:

  Open the file

  lines = 0;

  While (ReadLine () > 0)

  {

  lines ++;

  }

  Close the file