How to find the index of the closest value in table
Hello
I have a double-table A and a double value B.
I'm looking for on what number in the table A is the closest number to number B?
Thanks for help
If the array is sorted, built-in 'Threshold 1 D Array' might work for you.
Tags: NI Software
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find the closest value in table
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I need to find the values in the "C" line which is equal or close to the values 'A' in the 2D array, and then I want to show the values of 'B', corresponding to the values of 'C' in table 2D.
How can I fix it?
Thank you!
0.9967 nearest value is 0.993807 in the 8 Cand in row B row, not 1. The differences are 2.893E - 3 and 3.300E - 3.
Subtract each value from the table C. take the absolute value of the difference. To find the index of at least using Max & Min value of B. Using autoindexing array Index, create the output array.
Lynn
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How to find the closest higher value?
Hi all
I want to select the closest higher value in my data (test data are below):
output:with test_data as ( select 0.21 as val1, 0.19 as val2 from dual union all select 0.21 as val1, 0.29 as val2 from dual union all select 0.21 as val1, 0.49 as val2 from dual union all select 0.67 as val1, 0.49 as val2 from dual union all select 0.67 as val1, 0.69 as val2 from dual ) select * from ( select val1, val2, rank() over (order by abs(val2 - val1)) nearest from test_data ) where nearest = 1;
Output of this query is the NEAREST value to the value in the column of VAL1. But I would get the SUPERIOR value CLOSEST. As below the value at the higher value 0.21 closest isn't 0.29 0.19.VAL1 VAL2 NEAREST 0.21 0.19 1 0.67 0.69 1
desired output:
Is it possible to get the features you want using analytical functions?VAL1 VAL2 0.21 0.29 0.67 0.69
Thx for the help!
Kind regards
Jiri
Published by: Jiri n. 10 October 2012 01:14with test_data as ( select 0.21 as val1, 0.19 as val2 from dual union all select 0.21 as val1, 0.29 as val2 from dual union all select 0.21 as val1, 0.49 as val2 from dual union all select 0.67 as val1, 0.49 as val2 from dual union all select 0.67 as val1, 0.69 as val2 from dual ) select val1 ,val2 ,first_value(val2) over (partition by val1 order by case when val2 >= val1 then 1 else 2 end , val2 ) nearest from test_data VAL1 VAL2 NEAREST .21 .29 .29 .21 .49 .29 .21 .19 .29 .67 .69 .69 .67 .49 .69
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How to find the data in two tables are the same?
Hi people,
Suppose we have table emp01, have 10 records and create another emp02 as table
create the table emp02 in select * from emp01;
now both the table has the same data.
How to find a 'data' in the two tables are the same?Hello
SELECT * FROM emp01 MINUS SELECT * FROM emp02 UNION SELECT * FROM emp02 MINUS SELECT * FROM emp01
You can also compare resultset hash to select * in emp01 and select * from emp02 by using dbms_sqlhash.
Best regards
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How to find the maximum value in a collection
Hi all
I'm using Oracle 11 g 2. I need to know the maximum value in a collection of items.
When I run the following, I get the maximum number of collection as '5' but I need the max value itself which is 8, please help.
DECLARE
type v_number1 is table of number of directory indexes;
v_number v_number1;
IDX NUMBER.
psrc_file VARCHAR2 (10): = '1,2,4,8,6';
v_src_file_string_array v_number1;
number of max_temp;
BEGIN
SELECT regexp_substr (psrc_file, "[^,] +', 1, level") coll
LOOSE COLLECTION v_src_file_string_array
FROM (SELECT psrc_file FROM dual)
CONNECTION OF LEVEL < = length (regexp_replace (psrc_file, "[^,] +")) + 1;
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BECAUSE me IN v_src_file_string_array. FIRST... v_src_file_string_array. COUNTING LOOP
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v_number (i): = i;
END LOOP;
max_temp: = v_number (v_number.first);
IDX: = v_number.first;
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While the idx is not null
loop
If (idx) v_number > = max_temp
then
max_temp: = v_number (idx);
end if;
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end;
/
Thank you!Harinath Arasu says:
Hi allI'm using Oracle 11 g 2. I need to know the maximum value in a collection of items.
When I run the following, I get the maximum number of collection as '5' but I need the max value itself which is 8, please help.
DECLARE
type v_number1 is table of number of directory indexes;v_number v_number1;
IDX NUMBER.
psrc_file VARCHAR2 (10): = '1,2,4,8,6';
v_src_file_string_array v_number1;
number of max_temp;BEGIN
SELECT regexp_substr (psrc_file, "[^,] +', 1, level") coll
LOOSE COLLECTION v_src_file_string_array
FROM (SELECT psrc_file FROM dual)
CONNECT BY LEVEL<= length(regexp_replace(psrc_file,="" '[^,]+'))="" +="">=>-Set up some test values:
BECAUSE me IN v_src_file_string_array. FIRST... v_src_file_string_array. COUNTING LOOPIt should be-online 1... v_src_file_string_array. COUNTY
-v_numbers (i): = v_src_file_string_array (i);
v_number (i): = i;This should be-online v_numbers (i): = v_src_file_string_array (i);
Can't do you all just...
DECLARE type v_number1 is table of number index by binary_integer; v_number v_number1; idx NUMBER; psrc_file VARCHAR2(10) := '1,2,4,8,6'; v_src_file_string_array v_number1; max_temp number; BEGIN SELECT regexp_substr(psrc_file, '[^,]+', 1, level) coll BULK COLLECT INTO v_src_file_string_array FROM (SELECT psrc_file FROM dual) CONNECT BY LEVEL <= length(regexp_replace(psrc_file, '[^,]+')) + 1; FOR i IN 1..v_src_file_string_array.COUNT LOOP if max_temp is null or v_src_file_string_array(i) > max_temp then max_temp := v_src_file_string_array(i); end if; END LOOP; dbms_output.put_line ('Max: ' || max_temp); end;
Or more simply...
DECLARE type v_number1 is table of number index by binary_integer; v_number v_number1; idx NUMBER; psrc_file VARCHAR2(10) := '1,2,4,8,6'; v_src_file_string_array v_number1; max_temp number; BEGIN SELECT to_number(regexp_substr(psrc_file, '[^,]+', 1, level)) BULK COLLECT INTO v_src_file_string_array FROM (SELECT psrc_file FROM dual) CONNECT BY LEVEL <= length(regexp_replace(psrc_file, '[^,]+')) + 1 order by 1 desc; dbms_output.put_line ('Max: ' || v_src_file_string_array(1)); end;
Published by: JAC on April 3, 2013 18:56
Unhandled exception... -
How to find the max value of scrollV in AS3?
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The other two text fields scroll to match the text box 'parent', but in the end – you get to the last scroll position - the other two do not update and 3 text fields are out of alignment. It's just at the end of the roll. The rest of the scroll values line up. I think that if I can find the scrollV max value, I can force the two others to scroll one last time when this value is reached by the text field "parent".
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This is my first post so be tolerant
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MeeHow wrote:
... What is the problem?
Because the first incorrect value is the point of 2780, because it is also disabled because the average of neighbour is biased by the incorrect value to 2781.
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