How to get the attributes of the XML header?

Hallo!

I don't think that XPath can do. However, you can simply use a file IO to read.

Tags: NI Software

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    Published by: sakesing on March 11, 2009 19:11

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    Assalaamualikum

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    import java.io.IOException;
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    Import net.rim.device.api.ui.component.ListField;
    Import net.rim.device.api.ui.component.ListFieldCallback;
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    Import net.rim.device.api.ui.container.VerticalFieldManager;
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    Import net.rim.device.api.xml.parsers.DocumentBuilderFactory;

    to import org.W3C.DOM.document;
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    Import org.w3c.dom.NodeList;

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    public void paint (Graphics graphics)
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    graphics.drawBitmap (0, 0, Display.getWidth (), Display.getHeight (), Imagearriereplan, 0, 0);

    Super.Paint (Graphics);
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    };

    subManager = new VerticalFieldManager(Manager.VERTICAL_SCROLL |) Manager.VERTICAL_SCROLLBAR)
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    {
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    int displayHeight = Display.getHeight ();

    Super.sublayout (displayWidth, displayHeight);
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    }
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    Screen.Add (mainManager);

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    {

    public void paint (Graphics graphics)

    {
    graphics.setColor ((int) mycolor);
    Super.Paint (Graphics);

    }

    };
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    _connectionthread. Start();
    }

    protected boolean navigationClick (int status, int time)
    {
    Try
    {
    Here, go to another screen if you need.

    }
    catch (System.Exception e)
    {
    System.out.println ("Exception:-: navigationClick()" + try ());
    }
    Returns true;
    }

    private class login extends thread
    {
    Public connection()
    {
    Super();
    }

    public void run() {}
    Doc document;
    StreamConnection conn = null;
    InputStream is = null;
    try {}

    Conn = Connector.open (StreamConnection) ("http://ec2-54-248-241-248.ap-northeast-1.compute.amazonaws.com/koperasi-akr-trial/cgi-bin/gw-pinjama...

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    listElements.addElement (textNode.getNodeValue ());
    }
    } catch (Exception e) {}
    System.out.println (try ());
    } {Finally
    If (is! = null) {}
    try {is.close ();
    } catch (IOException ignored) {}
    } If (conn! = null) {}
    Try {conn.close () ;}
    catch (IOException ignored) {}
    }} UiApplication.getUiApplication () .invokeLater (new Runnable() {}
    public void run() {}
    _list. SetSize (listElements.Size ());
    subManager.add (_list);
    Screen.Invalidate ();
    }
    });
    }

    }

    ' public void drawListRow (list ListField, Graphics g, int index, int y, int w)
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    int yPos = 0 + y;
    g.drawLine (0, yPos, w, yPos);
    g.drawText (, 5, 15 + y, 0, w);
    }

    public {get {Object (ListField list, int index)
    {
    Return listElements.elementAt (index);
    }
    public int indexOfList (String prefix, ListField list, int, string)
    {
    Return listElements.indexOf (prefix, string);
    }
    public int getPreferredWidth (ListField list)
    {
    Return Display.getWidth ();
    }
    public final void insert (String toInsert, int index) {}
    listElements.addElement (toInsert);
    }

    ' Public Sub fieldChanged (field field, int context) {}

    }
    }

    Thank you.

    I told you that replace the navigationclick() method where initialize you your listfield

    as I think that changing your code and then answer me

    _list = new ListField()
    {
    protected boolean navigationClick(int status, int time)
    {
      Dialog.inform("hi");
      return true;
    }
    
    public void paint(Graphics graphics)
    {
    graphics.setColor((int) mycolor);
    super.paint(graphics);
    }
    };
    
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    Hi all

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                    Label {
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    Hello

    You can get the contact name and phone number as this,

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