ideas on how to generate a random password in vCO

Similar Questions

• How to generate the random password policy password knowing resources

  Hello
  
  Any body tell me how to generate the random password policy password knowing the purpose of resource in OIM11g
  
  Kind regards
  Mireille Nayan

  Hi Pascal,.

  You can try the below code snippet:

  UserRepository your = new DBUserRepository();
  UserInfo user = your.getUserInfo (take);
                 
  ResourceRepository rrepo = new ResourceDBRepository();
  Resource = rrepo.findResource (resourceName);
            
  By PasswordPolicyAssignmentsRepository = new PasswordPolicyAssignmentsDBRepository();
  PasswordPolicyRepository ppr = new DBPasswordPolicyRepository();
  The list of passwordPolicyAssignments = par.getPasswordPolicyAssigments (resource);
  PasswordPolicy passwordPolicy;
                 
  PasswordPolicyAssignment passwordPolicyAssignment = passwordPolicyAssignments.get (0) (PasswordPolicyAssignment);
  If (isApplicable (passwordPolicyAssignment, {getMappedAttributes (userInfo.getAttributes ())})})
  passwordPolicy = ppr.find (passwordPolicyAssignment.getPasswordPolicyID ());
  }
  RPG RandomPasswordGeneratorImpl = new RandomPasswordGeneratorImpl();
  password = rpg.generatePassword (userInfo, passwordPolicy);

  Kind regards
  GYAN

• generate a random password and sending a userid by mail to the user

  Hello
  I have a field called username in the form of process, this user id are accessible only by the ANALYST GIA PROVISIONING for updating the user ID to provide some of the id of the user of the resource. I want to send the user ID of the process shape in a mail to the user of the target, in addition, I also want to include a password also field nd send a random password for the user. In short I want to get the values of the user id and password send an e-mail to the target user

  See task there is a notification tab where you attach several e-mail templates that can help you to send multiple messages to the same answer

• How to generate a random number within a specified tolerance and control than tolerance.

  I am trying to simulate data without using a data acquisition device using a random number generator and I want to be able to control the "range" the random number generated well.  On the front panel, the user can enter a nominal number, and the random number generator would generate numbers more or less disponibles.003 this number nominal.  The data would be delayed on a chart.  Someone knows how to do this?  Or if it is still possible?

  Just for the sake of information, the random number is supposed to resemble thickness measures, that's why I want to simulate more and less disponibles.003 because the data might be thinner or thicker than the nominal value.

  Thanks in advance!

  Two ways of approaching the issue.  First of all, for even distribution, you can 'Roll the dice', which is the (0,1) random number function, multiply the result by 0.06 and then add Mean - 0.03 to center around average distribution.  If you simulate a real process, my initial guess would be that the results would follow a normal distribution.  In this case, you can use the VI of white noise Gaussian of the palette of generation of signals with a standard deviation of 0.015 if you wanted 0.03 to be the point of 2 sigma, then add average results.

• How to generate a random integer between 1-5?

  If I use random how can I convert an integer?

  Alana says:
  What exactly does the I32?

  "Of I32' converts your floating-point to integer number, as you specified in your first post as a requirement.

  Here's a version that gives all 5 numbers with equal probabilities. Instead of explicitly convert I32, I use + 1 output configuration. Same difference.

  

• How to make the optional password field to create the user form?

  Hello
  
  IM generate a random password when I create a new user on OIM.
  
  The only problem is that I do not know how to do the fields:
  -Password
  -Confirm password
  
  ... be optional.
  
  Since they are mandatory, the user must enter a password, even if it will not be used, because I generate a random password and overwrite.
  
  I already looked in the FormMetaData.xml in the section
  
  < name of the form '3' = >
  
  ... but the fields, I would like to make optional are not included.
  
  Any help is appreciated.
  Adriano.

  Certainly, you need to change tjspGenerateCreateUserForm.jsp

  Example:

  
  
  value = "abcd1234" Refresh = "true" readonly = "true" styleClass = "Fields" tabindex = "1" / >
  

  
  
  value = "abcd1234" Refresh = "true" readonly = "true" styleClass = "Fields" tabindex = "2" / >
  

  See metalink Note 468779.1

• Generate a random number with a decimal point

  I searched all over the internet and cannot find how to generate a random number that had a decimal.

  I'm trying to randomly generate numbers between 12.0 and 13.0.

  Here is my code... I know its bad because of Math.round and Math.random, but I can't seem to find something that deals with a decimal...

  addEventListener (Event.ENTER_FRAME, fl_EnterFrameHandler_1);

  function fl_EnterFrameHandler_1(event:Event):void
  {
  Volt.Text = Math.round (Math.random () * (1) + 12) m:System.NET.SocketAddress.ToString ();
  }

  Any suggestions?

  -Pat

  Try this,

  addEventListener(Event.ENTER_FRAME, fl_EnterFrameHandler_1);
  
  function fl_EnterFrameHandler_1(event:Event):void
  {
  
       var rndNum:Number = int(Math.random()*10)/10; // Generate random num with 1 decimal place
       var newVal:Number = newVal + 12;
       volt.text = newVal.toString();
  }
  

  If you want 2 decimal places then replace the 10 per 100.

• Creating a statue in gold that will generate random passwords for each deployment and how to recover passwords

  Hello

  New to 5.5 VDC and I hope that it is easy for you all the gurus.  After you create a statue in gold to say windows 2008 server and presentation in the public catalog how configure you to generate passwords random administrator when visitors in each of the ORG VDC wants to use it.  Now, I know you sysprep the OS in advance, and then when it starts, you can run the configuration wizard, or you can even define an answer file for things like the password key and administrator of the permit but y at - there a better way?  Having to go through the console and through a cloud of today technologies Assistant seems a bit old fashioned for me so I'm hoping its just something I missed narrowly in the configurations.

  The goal is simple... a customer deploys a VM and when it starts it is all ready to go so that no 2 VM This statue gold doesn't have the same credentials.  Somehow, they are provided with a generated random password to access the start new systems.  Amazon AWS for this using the keys if you deploy a virtual computer, you don't get invited to set a password... instead you can use your portal and get the password generated for you.  Their VM deployment and are ready to go without any additional configuration steps from the user at all.  How this is possible on a Director vcloud solution (or even at all).  I would like my customers to deploy from model, receive or access their new password and ready to go.  There may be a way to query the DB somehow and pull the password in this way?  And while I'm focused on windows operating system at the present time, it would be very happy to be able to do the same for root users on UNIX based as well as models.  Many big public cloud providers can provide their customers with this so I know there is a way but many also use things like openstack cloudstack or not vcloud Director.  Also I'm not familiar with the scripts so if you can get this kind of solution using scripts I'd appreciate some information or links that may describe step by step how to achieve and I will be happy to learn.  Thanks in advance

  UNIX systems are supposed to work.  And I know most the time they do.  (IE Redhat / Cent seems to work very well, however I have seen a few posts on this forum where a specific verion distribution may not work correctly.)

  Where to find the password.  Once the virtual machine boots (if the option to customize comments has been set at random) - the password will be on screen customization of comments; beside the selection of radio "Random."

  The API also has a way to get the password in case you need to expose in a different method.  (You can get it from section guestCustomize to a virtual computer in the restAPI thus).

• Upgrade to 3.6.15. Now my Add ons (1 password, Download Helper, Multi line Bookmark Toolbar) disappeared. Everyone knows about this problem? Any ideas on how to solve this problem? Thank you.

  Upgrade to 3.6.15. Now my Add ons (1 password, Download Helper, Multi line Bookmark Toolbar) disappeared. Everyone knows about this problem? Any ideas on how to solve this problem? Thank you.

  There may be a problem with one of the files which stores details of the installed extensions. Try to delete these files as described in the section "Corrupt extension files" of this link - https://support.mozilla.com/kb/Unable+to+install+add-ons

  Although this article is not specifically about your problem, the method indicated in the corrupted files extension section can help. When you restart Firefox after you delete these files, the list of installed extensions is rebuilt and cela hopefully solve your problem.

• How to generate random numbers from 1 to 5

  How to generate random numbers from 1 to 5

  -1110340081

  Thank you I ended up

• How to generate the password encoded using agent in ODI?

  Hello
  
  I've created a scenario and I plan to them. Now, I want to create an autonomous agent to run this scenario. To do this, I update odiparams.bat file where I am mentioning the details of the repository. I want to generate the encoded password repository connection using batch processing utility officer. After you type following command at the command prompt in windows xp:
  

  agent to encode the password

  Failure of the sound connection password invalid username error display.
  
  What should do? How to generate the password encoded using batch agent utility?
  
  Thank you
  Shrinivas
  
  Published by: Shrinivas Dayma on 13 Aug 2011 02:03

  Hi Shrinivas,

  This command is for ODI 10 g.

  For 11g,.

  Encode

  Thank you
  Guru

• How to build a VI that generates a random number between 1 and 80... Help!

  Generate a VI that generates a random number between 1 and 80

  Divide the random number by a number specified in the front panel.

  If the number of seizures is zero, the VI program should light a LED in the face to indicate a divide by zero error.

  Hai edwardty2009,

  Welcome to the forum.

  Thanks for the congratulations.

  Your problem is solved? If so can you please mark as solution what post help better to solve your problem.

  Thank you

  Mathan

• random password generator?

  Hello

  I would like a "password gererate" button that fills one filed with an alphanumeric passwrod of 8 characters or more.  Wildcards would be good as well.  Can someone help me with a script that allows you to create random passwords?  I understand also - it cannot be truly random, as a duplicate response could be created whenever 1 233 432 or something else and it's OK it would be fairly random.  Thank you very much.

  strPassword.substr (), created some problems... in something so it might return more than one character at a time... I don't know why but it was the problem of duplicates... so I changed it to charAt()

  Also sometimes it was possible, that you have only length 6 or 7 instead of 8 all the time... I had to add (i - ;) if boChar was true)

  Now, it should work perfectly!

  var strPassword = "";

  Set up the length of the password

  var intLength = 8;

  for (var i = 0; i)< intlength;="">

  var random = Math.floor (Math.random () * 150);

  If ((aléatoire > = 35 && <= 38)="" ||="" (random="=" 33)||="" (random="=" 42)="" ||="" (random="=" 95)="" ||="" (random="">aléatoire = 48 && <= 57)="" ||="" (random="">aléatoire = 63 && <= 78)||="" (random="">aléatoire = 80 && <= 91)="" ||="" (random="=" 93)="" ||="" (random="">aléatoire = 97 && <= 110)="" ||="" (random="">aléatoire = 112 && aléatoire))<= 122)){="" insert="" your="" password="" in="" the="" string="">

  Store characters in the value

  var strChar = string.fromCharCode(0)) (random);

  Initially, character is not contained in the string

  boChar var = false;

  for (var z = 0; z)< strpassword.length;="">

  If (strPassword.charAt (z) == strChar) {}

  The character is contained in the string, the value is now

  boChar = true;

  }

  }

  If (! boChar) {}

  If the character is not contained in the string, the character is added to the string, otherwise it is not added

  strPassword += strChar;

  } else {}

  i-- ;

  }

  } else {}

  i-- ;

  }

  }

• How to create a procedure to change random passwords

  Hello
  
  
  I am trying to create a procedure to change randomly the passwords for all users in a database. I need this after the cloning of the database. I have too many users to change manually...
  
  Y at - it option to create a procedure that will extract all users in a database and edit a random password?
  
  
  I wasn't able to find any clue.
  
  Could you help me?
  
  Thank you

  Welcome to the forum.

  change randomly the passwords for all users in a database.

  All users? Including SYS/SYSTEM? I hope not...

  But you can use DBMS_RANDOM. STRING and ALL_USERS and dynamic SQL.

  http://download.Oracle.com/docs/CD/B19306_01/AppDev.102/b14258/d_random.htm#sthref4675
  http://download.Oracle.com/docs/CD/B19306_01/server.102/b14237/statviews_2114.htm#REFRN20302
  http://download.Oracle.com/docs/CD/B19306_01/AppDev.102/b14261/dynamic.htm#LNPLS01101

  (easy to find when you do a quick search for http://www.oracle.com/pls/db102/homepage or http://www.oracle.com/pls/db112/homepage)

  DBMS_RANDOM. CHAIN can give you a random password easily:

  select dbms_random.string('x', 10)
  from   dual
  connect by level <= 10;
  

  Zo, you could do something like:

  begin
    for rec in ( select t.username
                 ,      dbms_random.string('x', 10) new_pass
                 from   all_users t
                -- where  t.username not in (...)
                -- or
                -- where  t.username in (...)
               )
    loop
      --execute immediate ' alter user '||rec.username||' identified by '||rec.new_pass;
      dbms_output.put_line ('New password for user '||rec.username||' = '||rec.new_pass);
    end loop;
  end;
  /
  

  You will have to fill in the where clause.
  I also commented on the dynamic modify the statement of the user, since I don't know if you really want to reset the DDT for all users.
  Also, rather than use dbms_output.put_line to verify the new password, you can insert them into a table or spool the output to a file.

• How can I distribute randomly addition or subtraction in a loop for?

  Someone at - it ideas for how can I randomly assign a loop for to add or subtract from the random numbers throughout the various itterations?  My current code generates two random numbers and added together for a number of itterations.  I need a few itterations randomly to be subtraction.  Thanks in advance!

  Add another random number generator and compare the result against 0.5. Use a case around your addition/subtraction operator.

  Looks like you might also want to exit what operation is in fact taken.