Identification of the ranges of partition

Similar Questions

• Rebuild the range-Hash partitioned local index

  Hi all
  
  We have a table with 400 million records in our dataware House environment. It is partitioned using range-Hash Partitioning composit. He used a global Indexes previously. Last month the global indices have been changed to the index the. Since then, Exchange and index rebuild partition takes twice against the take used previously. From my understanding local index should provide availability high and more usable in the warehouse environment. Please correct me if I'm wrong and give me your suggestion. Also, I'm looking for a good material for the exchange of the partition and Index rebild with locally manage the range-hash partitioned index. Let me know if you know a good link for this...
  
  
  Thanks in advance...

  Dear krmreddy,

  Carefully read the following link and I hope this will guide you;

  http://asktom.Oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:223318100346512896

  Kind regards.

  Ogan

• Determine the range start and stop for a partition partition

  Hello
  
  Using oracle 11.2.0.3
  
  We use the interval of separation and the partition Lems auto-generated variety. intervbal (range-hash) 1 month
  
  So what can you manually check the table and see Beach start and end of the partition is it possible to request to see data dictionary
  the range satrt and stop wishing to have script to automatically rename the generated system partitions based on the involved for example range if the generated partition has max date value
  
  waoul 3062013 want PART_201306
  
  Thank you

  >
  Checked user_tab_partitions as have sql geneerator can get the names of partition, but does not see the partition a dstop ranges.
  >
  Range of scores have NO ranges 'start and stop '. They have a high value and identification of the position.

  Data with partition key values< the="" high="" value="" and="" greater="" than="" or="" equal="" to="" the="" 'high="" value'="" of="" the="" partition="" with="" the="" next="" lower="" 'position="" id'="" goes="" into="" that="">

  You have not yet described what you need 'start' and 'stop' for.

• Range of partitioning of the interval

  Hello
  
  
  Using Oracle 11.20.3
  We want to have a table partitioned composite range-hash, a partition for each month.
  
  However, want to esnure are still a tehrfore partition would use range interval partitioning.
  
  Have a few questions, if I say 201301 to 201312 but get intellectualization rosw partition with a value date in June 2014 it create
  a new partition for each month IE 201401, 201402 etc. or just a 201406?
  
  Wanyt esnure system can automatically dial with a scenario
  
  Daty1 have partitions 201301 to 201312
  
  Day 2 get record for 201406 (June 2014)
  
  Day 3 get record for 201403 (March 2014)
  
  
  We have no control over the date range, we were able to get but don't want to tpo have to manually create partitions BOF tehse all dates in advance - want system she managed automatically.
  
  Also you can just rename it the names of system partition generated to something more useful later.

  Yes, the creation of partitions of the interval is 'rare' - a given partition will be created only when necessary. (This should be easy to try, by the way).

• Try to convert the partitioned Table of interval in the range... Swap partition...

  Requirement:
  
  Interval of replacement partitioned Table by range partitioned Table
  

  DROP TABLE A;
  
  CREATE TABLE A
  (
     a              NUMBER,
     CreationDate   DATE
  )
  PARTITION BY RANGE (CreationDate)
     INTERVAL ( NUMTODSINTERVAL (30, 'DAY') )
     (PARTITION P_FIRST
         VALUES LESS THAN (TIMESTAMP ' 2001-01-01 00:00:00'));
  
  
  INSERT INTO A
       VALUES (1, SYSDATE);
  
  INSERT INTO A
       VALUES (1, SYSDATE - 30);
  
  INSERT INTO A
       VALUES (1, SYSDATE - 60);

  I need to change this partitioned Table apart to a partitioned range Table. I can do using the EXCHANGE PARTITION. Like if I use the classic method to create another table range partitioned, then:
  
  

  DROP TABLE A_Range
  CREATE TABLE A_Range
  (
  a NUMBER,
  CreationDate DATE
  )
  PARTITION BY RANGE (CreationDate)
     (partition MAX values less than (MAXVALUE));
  
  Insert  /*+ append */  into A_Range Select * from A; --This Step takes very very long..Trying to cut it short using Exchange Partition.

  Problems:
  
  I can't do
  

   ALTER TABLE A_Range
    EXCHANGE PARTITION MAX
    WITH TABLE A
    WITHOUT VALIDATION;
   

  ORA-14095: ALTER TABLE CHANGE requires a not partitioned table nonclustered
  This is because the tables are partitioned. So it does not allow me.
  
  If I instead:
  
  
  Create a table that is not partitioned for exchanging data by partition.
  

    Create Table A_Temp as Select * from A;
    
     ALTER TABLE A_Range
    EXCHANGE PARTITION MAX
    WITH TABLE A_TEMP
    WITHOUT VALIDATION;
     
    select count(*) from A_Range partition(MAX);
   

  -The problem is that all the data is in MAX Partition.
  Even after the creation of a large number of partitions by walls of separation, the data is still in MAX Partition only.
  
  So:
  
  -What we cannot replace a partitioned Table to the Table partitioned using the EXCHANGE PARTITION range interval. that is, we have to insert in...
  -We can do it, but I'm missing something here.
  -If all the data is in MAX Partition due to "WITHOUT VALIDATION", can say us be redistributed in the right type of range partitions.

  You must pre-create the partitions in a_range and then swap one for one for a tmp, and then to arange. With the help of your sample (thanks to proviing code, incidentally).

  SQL> CREATE TABLE A
    2  (
    3     a              NUMBER,
    4     CreationDate   DATE
    5  )
    6  PARTITION BY RANGE (CreationDate)
    7     INTERVAL ( NUMTODSINTERVAL (30, 'DAY') )
    8     (PARTITION P_FIRST
    9         VALUES LESS THAN (TIMESTAMP ' 2001-01-01 00:00:00'));
  
  Table created.
  
  SQL> INSERT INTO A VALUES (1, SYSDATE);
  
  1 row created.
  
  SQL> INSERT INTO A VALUES (1, SYSDATE - 30);
  
  1 row created.
  
  SQL> INSERT INTO A VALUES (1, SYSDATE - 60);
  
  1 row created.
  
  SQL> commit;
  
  Commit complete.
  

  You can find the form of existing partitions assistance:

  SQL> select table_name, partition_name, high_value
    2  from user_tab_partitions
    3  where table_name = 'A';
  
  TABLE_NAME PARTITION_NAME HIGH_VALUE
  ---------- -------------- --------------------------------------------------------------------------------
  A          P_FIRST        TO_DATE(' 2001-01-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  A          SYS_P44        TO_DATE(' 2013-01-28 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  A          SYS_P45        TO_DATE(' 2012-12-29 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  A          SYS_P46        TO_DATE(' 2012-11-29 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  

  You can then create the table a_range with apporopriate partitions. Note that you may need to create additional in a_range partitions because the partitioning interval does not create the partitions has no data for, even if that leaves 'holes' in the partitioning scheme. So, on that basis:

  SQL> CREATE TABLE A_Range (
    2     a NUMBER,
    3     CreationDate DATE)
    4  PARTITION BY RANGE (CreationDate)
    5     (partition Nov_2012 values less than (to_date('30-nov-2012', 'dd-mon-yyyy')),
    6      partition Dec_2012 values less than (to_date('31-dec-2012', 'dd-mon-yyyy')),
    7      partition Jan_2013 values less than (to_date('31-jan-2013', 'dd-mon-yyyy')),
    8      partition MAX values less than (MAXVALUE));
  
  Table created.
  

  Now, create a regular table to use in the constituencies:

  SQL> CREATE TABLE A_tmp (
    2     a              NUMBER,
    3     CreationDate   DATE);
  
  Table created.
  

  and all partitions in Exchange:

  SQL> ALTER TABLE A
    2    EXCHANGE PARTITION sys_p44
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A_Range
    2    EXCHANGE PARTITION jan_2013
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A
    2    EXCHANGE PARTITION sys_p45
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A_Range
    2    EXCHANGE PARTITION dec_2012
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A
    2    EXCHANGE PARTITION sys_p46
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A_Range
    2    EXCHANGE PARTITION nov_2012
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> select * from a;
  
  no rows selected
  
  SQL> select * from a_range;
  
           A CREATIOND
  ---------- ---------
           1 23-NOV-12
           1 23-DEC-12
           1 22-JAN-13
  

  John

• Partition of the range

  Hello
  
  I want to ask if I can create the partition of the range of like 10 minutes? As I have data of 1 hour and I want to make a partition of 10? Please suggest
  
  Thank you

  Try place range partitions in good condition

  create table part_test ( id date) partition by range(id)
   ( partition p1 values less than(to_date('01-JAN-2012 01:00:00','DD-MON-YYYY hh24:mi:ss'))
    ,partition p2 values less than(to_date('01-JAN-2012 02:00:00','DD-MON-YYYY hh24:mi:ss'))
  .....
    ,partition p24 values less than(to_date('02-JAN-2012 00:00:00','DD-MON-YYYY hh24:mi:ss'))
   );
  

• I need to change the column of the range on my partition table

  Hello
  
  I created a partition table, but I need to change column of the range "CREATED" to "PREPARED". Two of them date format, but I can't modify this table.
  
  PARTITION OF RANGE (CREATED)--> I need to change column "CREATED" as "PREPARED".
  (
  INV08 PARTITION VALUES LESS (TO_DATE('01-SEP-2010','DD-MON-YYYY')).
  INV09 PARTITION VALUES LESS (TO_DATE('01-OCT-2010','DD-MON-YYYY')).
  INV10 PARTITION VALUES LESS (TO_DATE('01-NOV-2010','DD-MON-YYYY')).
  PARTITION INV VALUES LESS THAN (MAXVALUE)
  )
  
  How can I do?
  
  Published by: user567352 on December 23, 2010 04:10

  Hello

  As far as I know, dbms_redefinition didn't even know about the partitioning:

  1. you create a new empty table that matches your need + (that is where you defined you new partition key) +.
  2. you start the names of submiting of redefinition of existing and newly created table 'interim' table
  3. you leave enough time to get the work done
  4. you have finished redefining (the name of the table are swapped)
  And voila!

  Be sure to test thorougly the process of redefinition and the performance impact that may occur until you make it to your production !
  ;-)

• On the partition of the range

  Dear friends,
  
  I use Oracle10g. I need to create a range partition as below:
  
  
  CREATE TABLE EMP
  (
  EMPNO NUMBER 4,
  ENAME VARCHAR2 (10 BYTE),
  USE VARCHAR2 (BYTE 9),
  MGR NUMBER 4,
  HIREDATE DATE,
  SAL NUMBER (7.2).
  NUMBER (7.2), COMM.
  DEPTNO NUMBER (2)
  )
  
  PARTITION OF RANGE (hiredate)
  (
  PARTITION emp_1980 VALUES LESS THAN (TO_DATE('31/12/1980','DD/MM/YYYY')) TABLESPACE USERS,
  PARTITION emp_1981 VALUES LESS THAN (TO_DATE('31/12/1981','DD/MM/YYYY')) TABLESPACE USERS,
  PARTITION emp_1982 VALUES LESS THAN (TO_DATE('31/12/1982','DD/MM/YYYY')) TABLESPACE USERS,
  PARTITION emp_1987 VALUES LESS THAN (TO_DATE('31/12/1987','DD/MM/YYYY')) TABLESPACE USERS
  );
  
  But the problem is:
  
  (1) If no data entry is not match with the criteria above, then where he's going? I mean, not the data that don't follow the rule above which partition it will? is it possible to put the option DEFAULT partition in the partition of the range?
  I find that the DEFAULT option in the partition from the LIST
  
  (2) except that, when I add a new partition with what above, then it shows the error below:
  
  change the emp table add partition emp.emp_1988 VALUES LESS THAN (TO_DATE('31/12/1988','DD/MM/YYYY')) USERS TABLESPACE
  
  
  Error:
  "ORA-14020: this physical attribute may not be specified for the partition table."
  
  
  
  Someone could help me please, how can I solve the above problems?

  Range partitioning provides a range of values. Therefore, any value greater than the maximum value in your definitions of partition would fail. Thus, for example, 01/01/1988 and would especially error. That's why the range partitioning allows you to specify a 'best' possible values where you say 'lower values (MAXVALUE) '. Therefore, if you had included a partition "emp_maxvalue" by 'lower values (MAXVALUE)' after the partition of 'emp_1987', any value of 1988 or higher would go in the emp_maxvalue partition.

  {Because there is no minvalue specified, a value of, say, 06/01/1979 would go in the score of "emp_1980" as it is "(01/01/1980) below"!}

  Yet once, as the partitioning is a date range, you cannot Add a partition. You need to DIVIDE a partition. For example, if you had a present "emp_maxvalue" partition, in order to create the partition of emp_1988, you would be SPLIT "emp_maxvalue" into two partitions: emp_1988 and emp_maxvalue.

  Please read the documentation on the Partition maintenance in the Administrator's Guide.

  Hemant K Collette
  http://hemantoracledba.blogspot.com

• Look for a partition in the range

  Hi gurus,
  
  I have a partition table,
  
  CREATE TABLE sales
  (
  Number of SalesID
  SalesNumber varchar2 (50).
  Date of SalesDate,
  Number of value TotalAmount
  )
  PARTITION BY RANGE (SalesDate)
  (PARTITION P_JAN VALUES LESS THAN (TO_DATE (1 JANUARY 2008 ',' DD/MM/YYYY "")),)
  PARTITION P_FEB VALUES LESS THAN (TO_DATE (JANUARY 2, 2008 ',' DD/MM/YYYY "")).
  PARTITION P_MAR VALUES LESS THAN (TO_DATE (JANUARY 3, 2008 ',' DD/MM/YYYY "")).
  PARTITION P_APRVALUES LESS (TO_DATE (JANUARY 4, 2008 ',' DD/MM/YYYY ')),
  PARTITION P_MAX VALUES LESS THAN (MAXVALUE))
  ;
  
  I need to dynamically manage partitions based on the criteria of data,
  
  for example. to TO_DATE (January 5, 2008 ',' DD/MM/YYYY '), first I have to check if there is no partition exisits who, if so have need create this partition, a parition/month
  
  an entry for this condition is just a date, it can be any date.
  
  Please help me get the right query.
  
  Thank you

  Could you just do new lines fall under the partition of "p_max' by default and launch something to divide every so often?

  User_tab_partitions (perhaps with user_part_key_columns to check key columns) questioning made delicate by the fact that high_value is a LONG column. It may be easier to read in a PL/SQL variable and check it on the procedural level.

  11g can automatically create missing partitions on the fly so it might be easier to upgrade rather than developing your own.

• Possible to Exchange temporary table with composite range-hash partitioned table?

  Hello

  Using oracle 11.2.0.3

  We want to clean up the data in some of our existing partitioned table.

  Afetr updates check spped that is too slow for us.

  Current table is partitioned the inetrval compoiste range-hash table.  Also it is compressed - enabled for compression of basis as well

  An interval of 1 month and 1 partition by month and 4 secondary partitions in the partition of ecah.

  You want to create tenp table with the data of celan and exchange the data in this table in the 'dirty' uisng existing partitions partition exchnage.

  Is this possible?

  The plan is

  1) create temporary table containing data for 1 partition (1 month worth of data)

  (2) clean the data here

  (3) create new temporary table with these specific data which compressed and discovered partitioned with 4 secondary partitions

  (4) table 3 for swap partition dirty using partition excahnge.

  Thaks

  I think that this can be done with a combination of Exchange and Split partition partitions. Prior to Oracle 11 g, only way of redefining tables online was DBMS_REDEFINITION package. Now, you can redefine the use of partitions for Exchange & Split. Check

  http://www.Oracle-base.com/articles/Misc/partitioning-an-existing-table-using-Exchange-partition.php

  Maintenance of Partitions

  Kind regards

• Flattening of the ranges that overlap

  I have data that looks like this:
  

  (SKU, from_day, to_day)
  (1, 1, 3)
  (1, 2, 8)
  (1, 7, 9)
  (2, 2, 4)
  (2, 6, 8)

  I need to reduce it to the range for each category:
  

  (1, 1, 9)
  (2, 2, 4)
  (2, 6, 8)

  There may be many more records for each category, but this should be sufficient to illustrate the problem.
  
  I have three SKU 1 positions that were in place for a range of dates. The first element was there from day 1 to 3; the second days 2 to 8; the third days 7 to 9. These days this overlap, I would like to report on the maximum range of days that overlap - that is to say, that I had an element of SKU 1 present of the day 1 to day 9.
  
  I have two SKU 2 elements that were present in the location for the date interval. The first element was there for days 2 to 4; the second from 6 to 8 days. Given that these days do not overlap, I need to report separately.
  
  Can someone help me to write SQL that will accomplish this? It seems that I could use the syntax to CONNECT BY PRIOR, but I don't see how.

  Hello

  Here's one way:

  WITH     got_grp_start     AS
  (
       SELECT     sku, from_day, to_day
       ,     CASE
                WHEN from_day <= MAX (to_day) OVER ( PARTITION BY  sku
                                                     ORDER BY      from_day
                                      RANGE BETWEEN UNBOUNDED PRECEDING
                                            AND     1      PRECEDING
                                       )
                THEN 0
                ELSE 1
            END          AS grp_start
       FROM     table_x
  )
  ,     got_grp          AS
  (
       SELECT     sku, from_day, to_day
       ,     SUM (grp_start) OVER ( PARTITION BY  sku
                                 ORDER BY          from_day
                           ) AS grp
       FROM    got_grp_start
  )
  SELECT       sku
  ,       MIN (from_day)     AS grp_from_day
  ,       MAX (to_day)          AS grp_to_day
  FROM       got_grp
  GROUP BY  sku
  ,            grp
  ORDER BY  sku
  ,            grp_from_day
  ;
  

  This is an example of a problem of the English Channel , where consecutive lines (here, means consecutive in order of from_day) into groups, but there is nothing in any individual line which indicates which group belongs to this line; We must compare each row of other rows in the same score to determine if a new group (a ' handle') started this line or not. It's a little trickier than most other neck problems, because we had (I assume) data like this:

  INSERT INTO table_x (sku, from_day, to_day) VALUES (9, 1, 5);
  INSERT INTO table_x (sku, from_day, to_day) VALUES (9, 2, 3);
  INSERT INTO table_x (sku, from_day, to_day) VALUES (9, 4, 6);
  

  When deciding if a round begins with the 3rd rank, we cannot just look at the previous 1 row; To watch all the previous lines.

  After that we have determined where each round begins, we use the analytical SUM function to see how many innings have already started, i.e. to which group each line belongs. Once we have the number of group, getting high and low group limits is just a matter of using MIN and MAX.

  Published by: Frank Kulash, October 3, 2012 18:08
  Additional explanation

• What is this mention of Partition type in the code "HASH Partition".

  Hi team,
  
  Regularly I add news were leaving and secondary partitions at the production table, based on the Date. For example daily data stored in a partition.
  Below is the code I use to add new partitions. I think that this partition called the range.
  
  CREATE TABLE 'owner '. "" TABLE_NAME ".
  ("COLUMN01' VARCHAR2 (4))
  'ACOLUMN02' VARCHAR2 (32) NOT NULL ACTIVATE.
  .
  .
  .
  
  DEFAULT USER_TABLES)
  TABLESPACE "Nom_tablespace".
  PARTITION BY RANGE ("Daily_TIME")
  (PARTITION 'ABC_2008_08_31' VALUES LESS THAN (TO_DATE (' 2008-08-31 23:59:59 ',')))
  SYYYY-MM-DD HH24:MI:SS ',' NLS_CALENDAR = GREGORIAN '))
  PCTFREE, PCTUSED, INITRANS 40 10 1 MAXTRANS 255
  STORAGE (INITIAL 1048576 NEXT 1048576 MINEXTENTS 1 MAXEXTENTS 2147483645)
  ---------------------------------------------------------------------------------------------------------------------------------
  Now I found the new type of code to the new table created by the development team.
  The code is...
  
  CREATE TABLE 'owner '. "" TABLE_NAME ".
  ("COLUMN01' VARCHAR2 (4))
  'ACOLUMN02' VARCHAR2 (32) NOT NULL ACTIVATE.
  .
  .
  .
  
  DEFAULT USER_TABLES)
  TABLESPACE "Nom_tablespace".
  HASH PARTITION ("ACCOUNT_NUMBER")
  (PARTITION "PART_P01"
  TABLESPACE "tABLESPACE01."
  .
  .
  PARTITION "pART_P13."
  MOVEMENT of LINE ENABLE TABLESPACE "Tabelspace01");
  -----------------------------------------------------------------------------------------------------------------------------------------
  There is no code in the new code Table below...
  
  ((PARTITION «ABC_2008_08_31» LES VALEURS INFÉRIEURES QUE (TO_DATE (' 2008-08-31 23:59:59 ','))))
  SYYYY-MM-DD HH24:MI:SS ',' NLS_CALENDAR = GREGORIAN '))
  
  -----------------------------------------------------------------------------------------------------------------------------------------
  
  SO, I am unable to edit this table to add new left monthly sage.
  
  Please suggest me, how to record data date wise in this table. Also suggest me if not is the Partion LINE or not.
  
  If it is not possible to add new data to partition wise, I will inform the customer.
  
  Thank you and best regards,
  Vincent

  New table use hash partitioning, not range partitioning. You can refer to the Concepts:
  http://docs.Oracle.com/CD/E11882_01/server.112/e25789/schemaob.htm#CNCPT88864

  The key to the new partitioned table is account number, no date, so you cannot partition this table date-wise.

• Column containing the information of Partition Condition critical

  I use 11.2.0.2 on AIX 6.1.
  I create a range such as partition table below.
  

  CREATE TABLE SALES_RANGE
    ( prod_id       NUMBER(6)
    , cust_id       NUMBER
    , time_id       DATE
    , channel_id    NUMBER(3)
    )
   PARTITION BY RANGE (time_id)
   ( PARTITION sales_q1_2012 VALUES LESS THAN (TO_DATE('01-APR-2012','dd-MON-yyyy'))
   , PARTITION sales_q2_2012 VALUES LESS THAN (TO_DATE('01-JUL-2012','dd-MON-yyyy'))
   , PARTITION sales_q3_2012 VALUES LESS THAN (TO_DATE('01-OCT-2012','dd-MON-yyyy'))
   , PARTITION sales_q4_2012 VALUES LESS THAN (TO_DATE('01-JAN-2013','dd-MON-yyyy'))
   );

  I can find all the information related to this table in the tables of the dictionary as below.

  SQL> SELECT OWNER,
         TABLE_NAME,
         PARTITIONING_TYPE,
         SUBPARTITIONING_TYPE,
         PARTITION_COUNT,
         PARTITIONING_KEY_COUNT,
         STATUS,
         DEF_TABLESPACE_NAME
  FROM DBA_PART_TABLES
  WHERE OWNER='SCOTT';
  
  OWNER                          TABLE_NAME                     PARTITION SUBPARTIT PARTITION_COUNT PARTITIONING_KEY_COUNT STATUS   DEF_TABLESPACE_NAME
  ------------------------------ ------------------------------ --------- --------- --------------- ---------------------- -------- ------------------------------
  SCOTT                          SALES_RANGE                    RANGE     NONE                    4                      1 VALID    USERS
  
  SQL> SELECT TABLE_OWNER,
         TABLE_NAME,
         COMPOSITE,
         PARTITION_NAME,
         PARTITION_POSITION,
         TABLESPACE_NAME,
         LAST_ANALYZED
  FROM DBA_TAB_PARTITIONS
  WHERE TABLE_OWNER='SCOTT'
  ORDER BY PARTITION_POSITION;
  
  TABLE_OWNER                    TABLE_NAME                     COM PARTITION_NAME                 PARTITION_POSITION TABLESPACE_NAME                LAST_ANAL
  ------------------------------ ------------------------------ --- ------------------------------ ------------------ ------------------------------ ---------
  SCOTT                          SALES_RANGE                    NO  SALES_Q1_2012                                   1 USERS                          17-FEB-12
  SCOTT                          SALES_RANGE                    NO  SALES_Q2_2012                                   2 USERS                          17-FEB-12
  SCOTT                          SALES_RANGE                    NO  SALES_Q3_2012                                   3 USERS                          17-FEB-12
  SCOTT                          SALES_RANGE                    NO  SALES_Q4_2012                                   4 USERS                          17-FEB-12
  
  
  SQL> SELECT * FROM DBA_PART_KEY_COLUMNS WHERE OWNER='SCOTT';
  
  OWNER      NAME            OBJEC COLUMN_NAME     COLUMN_POSITION
  ---------- --------------- ----- --------------- ---------------
  SCOTT      SALES_RANGE     TABLE TIME_ID                       1

  But where can I find the essential condition of the c partition * ' VALUES LESS THAN (TO_DATE('01-APR-2012','dd-MON-yyyy')) "* in any dictionary table?".

  SQL> SELECT TABLE_OWNER,
         TABLE_NAME,
         COMPOSITE,
         PARTITION_NAME,
         PARTITION_POSITION,
         TABLESPACE_NAME,
         LAST_ANALYZED
  FROM DBA_TAB_PARTITIONS
  WHERE TABLE_OWNER='SCOTT'
  ORDER BY PARTITION_POSITION;
  

  Look again - it's in the column HIGH_VALUE

  SQL> set long 10000000
  SQL> SELECT partition_name, HIGH_VALUE
    2  FROM DBA_TAB_PARTITIONS
    3  WHERE TABLE_OWNER='SCOTT'
    4  /
  

• need help to determine the type of partition for tables

  Hello
  
  I have a few tables that have millions of record. In some tables, we have data from previous years, that we do not now use. Can we create a partition of this type of tables table.
  
  On other tables, how to decide if you should use the range/list/hash partitioning on our tables.
  
  Do I need to recreate indexes for the tables after you create the partition tables.
  
  Please guide me.
  
  Best regards

  Partitioning of decisions are based on how you can access data.

  If you access date then partition by date.
  If you go through a list of values and then use the list.
  If you there is no model and you just need to break the data up into smaller compartments using hash.

  I don't see why, based on what you wrote, partitioning by date range would be not worthy of consideration.

• is it possible to export each chapter in FCPX like a movie without using the tool of the range separated

  I have a movie I created with 26 chapters in there.  I want to export all the individual chapters as separate movies.   I know it's possible by making each chapter using the tool of the range and export everything that is selected.  But, I'm looking to win time by selecting all the chapters may export both.   Is this possible?

  Thanks for any help you can give me.

  NO you must do them sequentially, even if you don't have to wait for it to finish before you can start the next. Stack them just to export in a sequential manner.