On the partition of the range

Similar Questions

• Determine the range start and stop for a partition partition

  Hello
  
  Using oracle 11.2.0.3
  
  We use the interval of separation and the partition Lems auto-generated variety. intervbal (range-hash) 1 month
  
  So what can you manually check the table and see Beach start and end of the partition is it possible to request to see data dictionary
  the range satrt and stop wishing to have script to automatically rename the generated system partitions based on the involved for example range if the generated partition has max date value
  
  waoul 3062013 want PART_201306
  
  Thank you

  >
  Checked user_tab_partitions as have sql geneerator can get the names of partition, but does not see the partition a dstop ranges.
  >
  Range of scores have NO ranges 'start and stop '. They have a high value and identification of the position.

  Data with partition key values< the="" high="" value="" and="" greater="" than="" or="" equal="" to="" the="" 'high="" value'="" of="" the="" partition="" with="" the="" next="" lower="" 'position="" id'="" goes="" into="" that="">

  You have not yet described what you need 'start' and 'stop' for.

• Try to convert the partitioned Table of interval in the range... Swap partition...

  Requirement:
  
  Interval of replacement partitioned Table by range partitioned Table
  

  DROP TABLE A;
  
  CREATE TABLE A
  (
     a              NUMBER,
     CreationDate   DATE
  )
  PARTITION BY RANGE (CreationDate)
     INTERVAL ( NUMTODSINTERVAL (30, 'DAY') )
     (PARTITION P_FIRST
         VALUES LESS THAN (TIMESTAMP ' 2001-01-01 00:00:00'));
  
  
  INSERT INTO A
       VALUES (1, SYSDATE);
  
  INSERT INTO A
       VALUES (1, SYSDATE - 30);
  
  INSERT INTO A
       VALUES (1, SYSDATE - 60);

  I need to change this partitioned Table apart to a partitioned range Table. I can do using the EXCHANGE PARTITION. Like if I use the classic method to create another table range partitioned, then:
  
  

  DROP TABLE A_Range
  CREATE TABLE A_Range
  (
  a NUMBER,
  CreationDate DATE
  )
  PARTITION BY RANGE (CreationDate)
     (partition MAX values less than (MAXVALUE));
  
  Insert  /*+ append */  into A_Range Select * from A; --This Step takes very very long..Trying to cut it short using Exchange Partition.

  Problems:
  
  I can't do
  

   ALTER TABLE A_Range
    EXCHANGE PARTITION MAX
    WITH TABLE A
    WITHOUT VALIDATION;
   

  ORA-14095: ALTER TABLE CHANGE requires a not partitioned table nonclustered
  This is because the tables are partitioned. So it does not allow me.
  
  If I instead:
  
  
  Create a table that is not partitioned for exchanging data by partition.
  

    Create Table A_Temp as Select * from A;
    
     ALTER TABLE A_Range
    EXCHANGE PARTITION MAX
    WITH TABLE A_TEMP
    WITHOUT VALIDATION;
     
    select count(*) from A_Range partition(MAX);
   

  -The problem is that all the data is in MAX Partition.
  Even after the creation of a large number of partitions by walls of separation, the data is still in MAX Partition only.
  
  So:
  
  -What we cannot replace a partitioned Table to the Table partitioned using the EXCHANGE PARTITION range interval. that is, we have to insert in...
  -We can do it, but I'm missing something here.
  -If all the data is in MAX Partition due to "WITHOUT VALIDATION", can say us be redistributed in the right type of range partitions.

  You must pre-create the partitions in a_range and then swap one for one for a tmp, and then to arange. With the help of your sample (thanks to proviing code, incidentally).

  SQL> CREATE TABLE A
    2  (
    3     a              NUMBER,
    4     CreationDate   DATE
    5  )
    6  PARTITION BY RANGE (CreationDate)
    7     INTERVAL ( NUMTODSINTERVAL (30, 'DAY') )
    8     (PARTITION P_FIRST
    9         VALUES LESS THAN (TIMESTAMP ' 2001-01-01 00:00:00'));
  
  Table created.
  
  SQL> INSERT INTO A VALUES (1, SYSDATE);
  
  1 row created.
  
  SQL> INSERT INTO A VALUES (1, SYSDATE - 30);
  
  1 row created.
  
  SQL> INSERT INTO A VALUES (1, SYSDATE - 60);
  
  1 row created.
  
  SQL> commit;
  
  Commit complete.
  

  You can find the form of existing partitions assistance:

  SQL> select table_name, partition_name, high_value
    2  from user_tab_partitions
    3  where table_name = 'A';
  
  TABLE_NAME PARTITION_NAME HIGH_VALUE
  ---------- -------------- --------------------------------------------------------------------------------
  A          P_FIRST        TO_DATE(' 2001-01-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  A          SYS_P44        TO_DATE(' 2013-01-28 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  A          SYS_P45        TO_DATE(' 2012-12-29 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  A          SYS_P46        TO_DATE(' 2012-11-29 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  

  You can then create the table a_range with apporopriate partitions. Note that you may need to create additional in a_range partitions because the partitioning interval does not create the partitions has no data for, even if that leaves 'holes' in the partitioning scheme. So, on that basis:

  SQL> CREATE TABLE A_Range (
    2     a NUMBER,
    3     CreationDate DATE)
    4  PARTITION BY RANGE (CreationDate)
    5     (partition Nov_2012 values less than (to_date('30-nov-2012', 'dd-mon-yyyy')),
    6      partition Dec_2012 values less than (to_date('31-dec-2012', 'dd-mon-yyyy')),
    7      partition Jan_2013 values less than (to_date('31-jan-2013', 'dd-mon-yyyy')),
    8      partition MAX values less than (MAXVALUE));
  
  Table created.
  

  Now, create a regular table to use in the constituencies:

  SQL> CREATE TABLE A_tmp (
    2     a              NUMBER,
    3     CreationDate   DATE);
  
  Table created.
  

  and all partitions in Exchange:

  SQL> ALTER TABLE A
    2    EXCHANGE PARTITION sys_p44
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A_Range
    2    EXCHANGE PARTITION jan_2013
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A
    2    EXCHANGE PARTITION sys_p45
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A_Range
    2    EXCHANGE PARTITION dec_2012
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A
    2    EXCHANGE PARTITION sys_p46
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A_Range
    2    EXCHANGE PARTITION nov_2012
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> select * from a;
  
  no rows selected
  
  SQL> select * from a_range;
  
           A CREATIOND
  ---------- ---------
           1 23-NOV-12
           1 23-DEC-12
           1 22-JAN-13
  

  John

• Partition of the range

  Hello
  
  I want to ask if I can create the partition of the range of like 10 minutes? As I have data of 1 hour and I want to make a partition of 10? Please suggest
  
  Thank you

  Try place range partitions in good condition

  create table part_test ( id date) partition by range(id)
   ( partition p1 values less than(to_date('01-JAN-2012 01:00:00','DD-MON-YYYY hh24:mi:ss'))
    ,partition p2 values less than(to_date('01-JAN-2012 02:00:00','DD-MON-YYYY hh24:mi:ss'))
  .....
    ,partition p24 values less than(to_date('02-JAN-2012 00:00:00','DD-MON-YYYY hh24:mi:ss'))
   );
  

• I need to change the column of the range on my partition table

  Hello
  
  I created a partition table, but I need to change column of the range "CREATED" to "PREPARED". Two of them date format, but I can't modify this table.
  
  PARTITION OF RANGE (CREATED)--> I need to change column "CREATED" as "PREPARED".
  (
  INV08 PARTITION VALUES LESS (TO_DATE('01-SEP-2010','DD-MON-YYYY')).
  INV09 PARTITION VALUES LESS (TO_DATE('01-OCT-2010','DD-MON-YYYY')).
  INV10 PARTITION VALUES LESS (TO_DATE('01-NOV-2010','DD-MON-YYYY')).
  PARTITION INV VALUES LESS THAN (MAXVALUE)
  )
  
  How can I do?
  
  Published by: user567352 on December 23, 2010 04:10

  Hello

  As far as I know, dbms_redefinition didn't even know about the partitioning:

  1. you create a new empty table that matches your need + (that is where you defined you new partition key) +.
  2. you start the names of submiting of redefinition of existing and newly created table 'interim' table
  3. you leave enough time to get the work done
  4. you have finished redefining (the name of the table are swapped)
  And voila!

  Be sure to test thorougly the process of redefinition and the performance impact that may occur until you make it to your production !
  ;-)

• Rebuild the range-Hash partitioned local index

  Hi all
  
  We have a table with 400 million records in our dataware House environment. It is partitioned using range-Hash Partitioning composit. He used a global Indexes previously. Last month the global indices have been changed to the index the. Since then, Exchange and index rebuild partition takes twice against the take used previously. From my understanding local index should provide availability high and more usable in the warehouse environment. Please correct me if I'm wrong and give me your suggestion. Also, I'm looking for a good material for the exchange of the partition and Index rebild with locally manage the range-hash partitioned index. Let me know if you know a good link for this...
  
  
  Thanks in advance...

  Dear krmreddy,

  Carefully read the following link and I hope this will guide you;

  http://asktom.Oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:223318100346512896

  Kind regards.

  Ogan

• Flattening of the ranges that overlap

  I have data that looks like this:
  

  (SKU, from_day, to_day)
  (1, 1, 3)
  (1, 2, 8)
  (1, 7, 9)
  (2, 2, 4)
  (2, 6, 8)

  I need to reduce it to the range for each category:
  

  (1, 1, 9)
  (2, 2, 4)
  (2, 6, 8)

  There may be many more records for each category, but this should be sufficient to illustrate the problem.
  
  I have three SKU 1 positions that were in place for a range of dates. The first element was there from day 1 to 3; the second days 2 to 8; the third days 7 to 9. These days this overlap, I would like to report on the maximum range of days that overlap - that is to say, that I had an element of SKU 1 present of the day 1 to day 9.
  
  I have two SKU 2 elements that were present in the location for the date interval. The first element was there for days 2 to 4; the second from 6 to 8 days. Given that these days do not overlap, I need to report separately.
  
  Can someone help me to write SQL that will accomplish this? It seems that I could use the syntax to CONNECT BY PRIOR, but I don't see how.

  Hello

  Here's one way:

  WITH     got_grp_start     AS
  (
       SELECT     sku, from_day, to_day
       ,     CASE
                WHEN from_day <= MAX (to_day) OVER ( PARTITION BY  sku
                                                     ORDER BY      from_day
                                      RANGE BETWEEN UNBOUNDED PRECEDING
                                            AND     1      PRECEDING
                                       )
                THEN 0
                ELSE 1
            END          AS grp_start
       FROM     table_x
  )
  ,     got_grp          AS
  (
       SELECT     sku, from_day, to_day
       ,     SUM (grp_start) OVER ( PARTITION BY  sku
                                 ORDER BY          from_day
                           ) AS grp
       FROM    got_grp_start
  )
  SELECT       sku
  ,       MIN (from_day)     AS grp_from_day
  ,       MAX (to_day)          AS grp_to_day
  FROM       got_grp
  GROUP BY  sku
  ,            grp
  ORDER BY  sku
  ,            grp_from_day
  ;
  

  This is an example of a problem of the English Channel , where consecutive lines (here, means consecutive in order of from_day) into groups, but there is nothing in any individual line which indicates which group belongs to this line; We must compare each row of other rows in the same score to determine if a new group (a ' handle') started this line or not. It's a little trickier than most other neck problems, because we had (I assume) data like this:

  INSERT INTO table_x (sku, from_day, to_day) VALUES (9, 1, 5);
  INSERT INTO table_x (sku, from_day, to_day) VALUES (9, 2, 3);
  INSERT INTO table_x (sku, from_day, to_day) VALUES (9, 4, 6);
  

  When deciding if a round begins with the 3rd rank, we cannot just look at the previous 1 row; To watch all the previous lines.

  After that we have determined where each round begins, we use the analytical SUM function to see how many innings have already started, i.e. to which group each line belongs. Once we have the number of group, getting high and low group limits is just a matter of using MIN and MAX.

  Published by: Frank Kulash, October 3, 2012 18:08
  Additional explanation

• is it possible to export each chapter in FCPX like a movie without using the tool of the range separated

  I have a movie I created with 26 chapters in there.  I want to export all the individual chapters as separate movies.   I know it's possible by making each chapter using the tool of the range and export everything that is selected.  But, I'm looking to win time by selecting all the chapters may export both.   Is this possible?

  Thanks for any help you can give me.

  NO you must do them sequentially, even if you don't have to wait for it to finish before you can start the next. Stack them just to export in a sequential manner.

• Unable to choose the range in iMovie

  Unable to choose the range of iMovie 10.1.2

  Hi, Jeff.

  You can select a range inside a clip with your clip in the timeline, placing your cursor on it and hold the 'r' key when you drag your cursor over the clip while pressing your mouse or track pad.  The range will be described in a yellow box.

  To select a range of multiple clips, select the first clip, and then select the last element while holding down the SHIFT key.

  Best,

  -Rich

• How can I change the range of pitch bend of a soft synth?

  How can I change the range of pitch bend of a soft synth?

  Tell me what synth and I'll tell you how to change.

• iPad does not connect to the Wifi on the range 192.168.0. *.

  I have an iPad Mini (ME860BA) on os 9.3.1 that would not connect to my wifi at home.  He began to abandon their studies repeatedly a few months before and then just wouldn't connect at all.  It is on the os 9.3 so I upgraded to 9.3.1 but it did not help.  I was able to connect using a hotspot from my phone but no go on the real wifi. Sometimes it seems impossible to connect and others it seems to connect but without the wifi icon that appear (and internet access). All other devices connect to the House without exception (or question) - it's just my iPad.

  I followed every bit of advice I've found - turning wifi off & on, forgetting network, reset all the network settings, hard reboot, reboot normal, turning airplane mode turn off again, go up the brightness of the screen (odd) and finally I restored my router and the iPad to factory settings.  Nothing worked, so I took him to a store of Apple and waiting for the genius to see me I thought I would try to connect to the wifi and it went all right!  I felt a little silly to start with but they still took a look and said that he had 'something' bad, but they didn't know what.  Their best guess was that it was something to do with password authentication because they are client wifi has no password.  I returned home and disabled the security mode of the router - I have a Virgin Superhub running the 2.4 and 5 GHz primary wireless networks - no amount of adjusting the security modes (remove the password, make visible SSID, change of Protocol) makes all the difference.  However, knowing that it worked on wifi from Apple in the store, I was really puzzled.

  After ages bother with different parameters (especially in my router), I now know why it does not connect to home... My Virgin router to short on a range of address DHCP IP of 192.168. 0. * and my iPad suddenly won't connect unless the beach is 192.168. 1. * or higher.  (It connected OK for 2 years).  It took weeks to find this out, but at least now I can connect.  I turned on the wifi of comments because it uses the gamme.1.  Everything is good, connects the first time, every time!  I have not tried establishing a password (I was so happy, it connected I left because it was... well as I switch on the MAC filtering, for a little extra protection) I could try side password later and if it still connect, I'll update my post.

  My solution is very well when I'm at home but is not going to help if I get the iPad with me - it will be hit & miss if I can get the WiFi also.  Must be set correctly - I see no that it is hardware related, so there must be a bug in the software/firmware.

  Anyone having problems connecting to wifi can try the workaround network comments - at least it will get you.

  Is there a future fix for this?

  Re: iPad wifi suddenly does not save

  Change the range on the router you want to connect to.

• Alternative to Holding button down 'R' to the range selection Clip in iMovie 10.1.2?

  Has anyone found another way to select a range of a clip in iMovie 10.1.2 other than now the key 'R '?  The method used in previous versions of iMovie has been quick and intuitive.  You just skim up to a point located on the clip, clicked and dragged to make the selection.  Browse, click and drag.  It couldn't be easier.  Now, when you click a clip, select the clip.  The only way to get only a piece is to change your train of thought, find the "R" key, press and hold and hope you can return to the creative process.  How is it better for the user?  It is a step backwards in usability.  Am I missing something?  Why iMovie software engineers would make such a decision of confusion?  Is it possible to return to the simpler method by a preference?  I can't imagine a user thinks, 'Wow, this process hold the 'R' key is really a nice update.  It's actually easier to use iMovie. »

  Browse, click and drag.

  It always works for me this way in iMovie 10.1.2.  Maybe this works only on my trackpad with touch of strength? I can't test it with a mouse now.

  I only use the "R" key after selecting the range to copy.

• Watch the sync with the phone once he's back in the range.

  If I do a tour on foot or by bike with only the watch.  It syncs with my phone once he's back in the range of recording my activity?

  Hello

  Yes, it will be.

• Apple Watch back in the range

  I would like to know if the Apple Watch returns in the range with the iPhone, is pushed and shown on the watch notification?

  Hello

  Non - Apple Watch does not provide a notification alert when it comes back within the range of the paired iPhone.

  However, while it is disconnected via Bluetooth, if the watch is also impossible to connect to a Wi - Fi network, known at that time, it will display the icon disconnected at the top of the face of the Watch:

  

  After the devices have reconnected automatically (after back to within reach of the other), this status icon no longer appears on the dial of the watch.

  More information:

  On Bluetooth and Wi - Fi on Apple Watch - Apple Support

• Suddenly, I found 787 songs - more in the range of length of 0, 02 - in my library. is it possible to delete both or at least in blocks?

  All of a sudden I find 787 songs - more in the range of 0.02 minute - in my library.  a way to remove them at once or at least in large blocks.  be easier to delete iTunes app.  sure would appreciate any suggestions. Thank you

  Equip your library of songs and sort by time, so that all courts are on a line.  Click on the first and holding down the CMD key you click the last.  Delete then delete them.

  Do not 787 all at once.  Do small batches in a first time, you can see how it works.