Ignore the duplicates on Insert statement

Similar Questions

• Is it possible to ignore the duplicate in the ATG request?

  If a user clicks twice or more than that of a button who invoke a formhandler submit action. Is there a way we can ignore duplicate of the user click applications?

  Hi Jitendra,

  To prevent duplicate on the sending of a form applications, you can use the RepeatingRequestMonitor, which is a very simple on the ATG box component, but quite effective.

  To use this component, you must create an object of names like RepeatingRequestMonitor and he's a poseur of getter in your form Manager.

  The syntax is as below: -.

  If (RepeatingRequestMonitor.isUniqueRequestEntry ("YourFormHandler.handleSubmit")) {}

  try {}

  proceed with the execution of the method feature

  }

  {Finally

  When the functionality of performance, remove this entry of the application

  RepeatingRequestMonitor.removeRequestEntry ("YourFormHandler.handleSubmit");

  }

  } else {}

  cause, perhaps create DropletFormException and return

  }

  Let me know for any query.

  Kind regards

  Prateek Gupta

• ignore the insert errors in a merge statement?

  Hi all
  
  I wonder if it is possible, somehow, to ignore the failings of the insert statement in a merge statement of bulk? The error encountered is the violation of a primary key. What is happening is that the different transactions share the same plsql procedure. Therefore, it could happen that different transactions will try to insert two rows with the same primary key.
  
  MERGE INTO table
  Using the collection
  WE (table.id = collection.id)
  WHEN MATCHED THEN
  UPDATE...
  WHEN NOT MATCHED THEN
  INSERT...-> it may fail for duplicates here
  
  The only solution would be to use 'updated massive day + bulk insert (ignore errors)' instead of a merger in bulk?
  
  Any help is very appreciated,
  WF

  What about using [DML Error Logging | http://www.oracle-base.com/articles/10g/DmlErrorLogging_10gR2.php#merge]?

• Looking for a better style or a way to write the INSERT statement, possible with brand of continuation

  Honestly, I really looked everywhere for this.

  The problem is that, while tinkering in SQL Developer and knowing that in the spreadsheet I can just execute individual instructions by placing the cursor on the SQL statement I want to run I tried to do an INSERT query that would allow me to run an INSERT statement for... Well many inserts.

  I thought I could use a brand of continuation but nothing I've tried has worked.

  INSERT INTO

  HF_easy_drinks

  VALUES

  ("Blackthorn", "tonic water", 1.5, 1.0, "pineapple juice", "mix with ice").

  ("Blue Moon", "soda", 1.5 "Blueberry Juice",. 75, "mix with ice, strain")

  ;

  
  

  I ended up doing just individual INSERT statements, which was not as convenient.

  INSERT INTO HF_easy_drinks

  VALUES ('Blackthorn', 'tonic water', 1.5, 1.0, "pineapple juice", "mix with ice");

  INSERT INTO HF_easy_drinks

  VALUES ('Blue Moon', 'soda', 1.5, 'Blueberry Juice',. 75, "mix with ice");

  Hello

  Perhaps you might prefer "an" insert like this:

  INSERT INTO hf_easy_drinks (x, y, z,...)
  SELECT "Blackthorn", "tonic water", 1.5, 1.0, "pineapple juice", "mix with ice" OF THE double
  UNION ALL SELECT 'Blue Moon', 'soda', 1.5, 'Blueberry Juice',. 75, "mix with ice, strain ' FROM dual
  SELECT UNION ALL... OF the double
  SELECT UNION ALL... OF the double
  ;

  Best regards

  Bruno Vroman.

• Can I omit THEN in a when then the clause of an insert statement multi-table?

  Example of a test of the demo:

  You have been appointed as the DBA for a National Bank that provides services of credit and debit cards to its customers. The records for these two types of card users are stored and preserved in the card_customers of Bank data table.
  
  You decide to create separate tables for credit card users and users of debit cards and then use the data in the card_customers table to populate the new tables. Information for clients who hold both types of card must be added to the time of the tables.
  
  Which of the two following options provide the most effective way of inserting the customer data in the credit_card_holders and debit_card_holders tables? (Choose two.)
  

  INSERT INTO credit_card_holders SELECT * FROM card_customers WHERE card_type = "Credit"; INSERT INTO debit_card_holders SELECT * FROM card_customers WHERE card_type = "flow";

  INSERT ALL IN credit_card_holders IN debit_card_holders SELECT * FROM card_customers;

  INSERT ALL WHEN card_type = 'Crédit' IN credit_card_holders WHEN card_type = 'Throughput' IN debit_card_holders SELECT * FROM card_customers;

  INSERT FIRST WHEN card_type = 'Crédit' IN credit_card_holders WHEN card_type = 'Throughput' IN debit_card_holders SELECT * FROM card_customers;

  Explanation:

  In this scenario, the following statement provides the most effective way of inserting data in the credit_card_holders and debit_card_holders tables:
  
  INSERT ALL
  When card_type = 'Crédit' THEN credit_card_holders
  When card_type = 'Throughput' THEN debit_card_holders
  SELECT * FROM card_customers;
  
  Le INSERT all THE statement verifies the conditions in the two clauses WHEN , regardless whether one of them is true or false. If a condition when is true, then the line corresponding to the INSERT statement is executed is inserted in the card_customers in the credit_card_holders table or the debit_card_holders table. If a customer has a credit card and a debit card, there will be two rows in the table card_customers for the same customer, one with card_type = 'Crédit' and the other with card_type = 'Throughput'. This statement inserts the correct lines in the tables in a single pass.

  
  

  The TIME is here (in bold) are not present in answer C.

  
  

  basic question: can I omit the keyword THEN in a moment, then clause?
  
  

  What happened when you tried the failure THEN?

  Do not be afraid to break the Oracle by actually TRYING things.

  The best and fastest, to learn is to try things yourself.

  Then, see the documentation for the basic issues.

  http://docs.Oracle.com/CD/B28359_01/server.111/b28286/statements_9014.htm

  View the diagram of syntax for the 'conditional_insert_clause' and you will see that the word is necessary.

• Is possible to write the INSERT statement that fills two columns: 'word' and 'sense' of the file text with multiple lines - in each line is followed word that is the meaning?

  Is possible to write the INSERT statement that fills two columns: 'word' and 'sense' of the file text with multiple lines - in each line is followed word that is the meaning?

  Hello

  2796614 wrote:

  Is possible to write the INSERT statement that fills two columns: 'word' and 'sense' of the file text with multiple lines - in each line is followed word that is the meaning?

  Of course, it is possible.  According to what the text file looks like to, you can create an external table that treats the text file as if it were a table.  Otherwise, you can always read the file in PL/SQL, using the utl_file package and INSERT of PL/SQL commands.

  You have problems whatever you wantt?  If so, your zip code and explain what the problem is.

  Whenever you have any questions, please post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and the exact results you want from these data, so that people who want to help you can recreate the problem and test their ideas.  In this case, also post a small sample of the text involved file.

  If you ask about a DML operation, such as INSERT, then INSERT statements, you post should show what looks like the tables before the DML, and the results will be the content of the table changed after the DML.

  Explain, using specific examples, how you get these results from these data.

  Always say what version of Oracle you are using (for example, 11.2.0.2.0).

  See the FAQ forum: Re: 2. How can I ask a question on the forums?

• Need help with the insert statement

  Hello
  
  I have a question on how to write a SQL statement.
  
  This is the table of "base":
  

  CREATE TABLE TEMP_TBL
  (
  id_nr NUMBER,
  DATE_DOK DATE,
  DATE_DUE DATE,
  DATE_DOK_PAY DATE,
  DEB NUMBER,
  KRD NUMBER
  );
  
  insert into temp_tbl (ID_NR,DATE_DOK,DATE_DUE,DATE_DOK_PAY,DEB,KRD)values('1',TO_DATE('11.01.2011','DD.MM.YYYY'),TO_DATE('25.02.2011','DD.MM.YYYY'),NULL,'423,24','0');
  insert into temp_tbl(ID_NR,DATE_DOK,DATE_DUE,DATE_DOK_PAY,DEB,KRD)values('2',TO_DATE('16.12.2011','DD.MM.YYYY'),TO_DATE('13.06.2011','DD.MM.YYYY'),NULL,'91270,15','0');
  insert into temp_tbl(ID_NR,DATE_DOK,DATE_DUE,DATE_DOK_PAY,DEB,KRD)values('3',TO_DATE('27.09.2011','DD.MM.YYYY'),TO_DATE('27.09.2011','DD.MM.YYYY'),NULL,'0','2000');

  and it comes to resoult in the target table. SQL statement must take care of the insert in a base of the target table table (example below is already provided with test data).
  

  create table table_sod
  (
  
        id_nr number
       ,date_from date
       ,date_to date
       ,deb_krd number
  
  );
  
  One thing to note here :  values in column deb_krd under insert 1 and 4 must be summarized in insert 4.
  
  insert into table_sod (id_nr,date_from,date_to,deb_krd) values('1',null,to_date('25.02.2011','dd.mm.yyyy'),'423,24');
  insert into table_sod(id_nr,date_from,date_to,deb_krd) values('2',to_date('26.02.2011','dd.mm.yyyy'),to_date('13.06.2011','dd.mm.yyyy'),'423,24');
  insert into table_sod(id_nr,date_from,date_to,deb_krd)values('3',null,to_date('13.06.2011','dd.mm.yyyy'),'91270,15');
  insert into table_sod(id_nr,date_from,date_to,deb_krd)values('4',to_date('14.06.2011','dd.mm.yyyy')to_date('27.09.2011','dd.mm.yyyy'),'91693,39');
  insert into table_sod(id_nr,date_from,date_to,deb_krd)values('5',null,to_date('27.09.2011','dd.mm.yyyy'),'2000');

  If someone could give me a helping hand how write correct insert statement I would be really gratefull.
  
  Thank you for your time!

  I came here with my own assumptions with this

  SQL> select rownum id_nr
    2       , date_from
    3       , date_to
    4       , case when date_from is null then deb
    5              else sum(case when date_from is not null then deb else 0end) over(order by id_nr, no)
    6         end deb_krd
    7    from (
    8            select id_nr
    9                 , case when lg_dt is null or ld_dt = date_due then  null else lg_dt+1 end date_from
   10                 , ld_dt date_to
   11                 , case when deb = 0 then krd else deb end deb
   12                 , no
   13              from (
   14                      select t1.*
   15                           , lead(t1.date_due) over(order by t1.id_nr, t2.no) ld_dt
   16                           , lag(t1.date_due) over(order by t1.id_nr, t2.no) lg_dt
   17                           , t2.no
   18                        from temp_tbl t1
   19                       cross
   20                       join (select 1 no from dual union all select 2 no from dual) t2
   21                       order by id_nr, no
   22                   )
   23             where ld_dt is not null
   24         )
   25  /
  
       ID_NR DATE_FROM DATE_TO      DEB_KRD
  ---------- --------- --------- ----------
           1           25-FEB-11      42324
           2 26-FEB-11 13-JUN-11      42324
           3           13-JUN-11    9127015
           4 14-JUN-11 27-SEP-11    9169339
           5           27-SEP-11       2000
   
  

• Help with the insert statement

  Hello
  
  I was wondering if someone could help write me a sql statement.
  
  Here is my table:
  

  CREATE TABLE "TEMP_INVOICE" 
     ("INVOICE" VARCHAR2(100 BYTE),
       "DATE_OF_DOCUMENT" DATE, 
       "DATE_OF_PAY_DAY" DATE, 
       "D" NUMBER, 
       "K" NUMBER
     );

  Here are the instructions for correct insertion. This time, I posted 2 examples with 2 numbers different otherwise.

  insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k)  values (1000,to_date('01.02.2012','dd.mm.yyyy'),to_date('01.03.2012','dd.mm.yyyy'),5000,0);
   
  insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k)  values (1000,to_date('01.04.2012','dd.mm.yyyy'),'','',1000);
   
  insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k)  values (1000,to_date('01.05.2012','dd.mm.yyyy'),'','',3000);
   
  insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k)  values (1000,to_date('01.06.2012','dd.mm.yyyy'),'','',1000);
  
  insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k)  values (2000,to_date('01.07.2012','dd.mm.yyyy'),to_date('01.09.2012','dd.mm.yyyy'),8000,0);
   
  insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k)  values (2000,to_date('01.10.2012','dd.mm.yyyy'),'','',5000);
   
  insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k)  values (2000,to_date('01.11.2012','dd.mm.yyyy'),'','',2000);
   
  insert into temp_invoice (invoice,DATE_OF_DOCUMENT,DATE_OF_PAY_DAY,d,k)  values (2000,to_date('01.12.2012','dd.mm.yyyy'),'','',1000);

  I want to do is make an insert allows you to table another call is MADE:
  

  CREATE TABLE "INVOICE" 
     ("INVOICE" VARCHAR2(100 BYTE),
      "DATE_OF_DOCUMENT" DATE, 
       "DATE_OF_PAY_DAY" DATE,
       "DATE_OF_PAYMENT_REC" DATE,
       "VALUE" NUMBER,
       "VALUE_DEDUCT" NUMBER,
      "DATE_FROM" DATE,     
       "DATE_TO" DATE
       );

  Statements in the INVOICE table should be like this:
  
  
  ........ The Bill... date_of_document... date_of_pay_day... date_of_payment_rec... value... value_deduct... Date_from... Date_to
  1......     1000...............1.1.2012.................1.3.2012................NULL............................ 5000... NULL... 1.3.2012...1.4.2012
  2......     1000...............1.4.2012.................NULL..................... 1.4.2012...1000... 4000... 2.4.2012... 1.5.2012
  3......     1000...............1.5.2012.................NULL..................... 1.5.2012...3000... 1000... 2.5.2012... 1.6.2012
  4......     1000...............1.6.2012.................NULL..................... 1.6.2012...1000
  
  
  Can someone help me with the sql statement that would insert data from table to table Bill temp_invoice as in the example?
  
  Thank you!
  
  PS
  
  I would try to explain.
  (1) the first statement that is to be inserted is original imply that at which is different DATE_OF_PAY_DAY to NULL.
  To this inserted negative of the original imply, we must add date_from that is exatly the same date_of_pay_day and date_to which is exactly the same as the date of the first payment. Payment which came first!
  (2) we have now in the second insert statement. It will be the first payment of lease with date_of_document and date_pf_payment_rec, which is the same as date_fo_document. Value field will be populated with the amount of payment received and value_deduct field will be the value of the original imply - value of the first payment. Date is date_of_document + 1 and date_to is the date of the next payment.
  (3) Insert us the next installment. Date_od_payment_rec is the same as date_of_document... value is the amount of the second payment and value_deduct's previous value_deduct which was of 4000 - value of this second payment. date_from date_of_payment_rec + 1 and date_to is the date of the next payment
  
  So we continue this same pattern until we reached the final payment when we finish insert with the statement:
  Date of the document (date of the last payment received) and even for date_of_payment_rec and field value with the amount of the payment receieved. The rest (value_deduct, date_from, date_to) is null.
  
  I really hope you understand what I'm trying to do here.
  
  If you have any other questions please.
  
  Published by: user13071990 on November 22, 2012 04:16
  
  Published by: user13071990 on November 22, 2012 04:16

  Hello

  user13071990 wrote:
  ... Here are the instructions for correct insertion. This time, I posted 2 examples with 2 numbers different otherwise.

  Ok!
  Be sure to post the results you want new data.

  You probably need to add "PARTITION BY the Bill" to all analytical clauses in my solution:

  INSERT INTO invoice
  ( invoice, date_of_document, date_of_pay_day, date_of_payment_rec
  , value,   value_deduct,     date_from,           date_to
  )
  SELECT       invoice
  ,       date_of_document
  ,       date_of_pay_day
  ,       CASE
             WHEN  k > 0
             THEN  date_of_document
         END          AS date_of_payment_rec
  ,       NVL (d, k)     AS value
  ,       NVL2 ( date_of_pay_day
              , NULL
              , SUM (d) OVER ( PARTITION BY  invoice
                                        ORDER BY      date_of_document
                       )
              - SUM (k) OVER ( PARTITION BY  invoice
                                        ORDER BY      date_of_document
                       )
              )     AS value_deduct
  ,       NVL ( date_of_pay_day
             , date_of_document + 1
             )          AS date_from
  ,       LEAD (date_of_document) OVER ( PARTITION BY  invoice
                                          ORDER BY      date_of_document
                             )
                        AS date_to
  FROM       temp_invoice
  ;
  

  Because I'm not an English speaker nativ, that I just posted what it should look like after the insert is successful.

  OK, so you can't explain as you want, but you still need to explain.

  ... @Frank Kulash: you are very close, but still not quite what I'm looking for.

  Point out where my solution is the production of incorrect results, and explain (as you can) how to get good results in these places.

• On the insert statement

  Hi all
  
  I need to insert rows into a table, all the columns are have same value except a column that is to say
  
  
  insert into table values ('a', 'b', 'b', 'b');
  
  insert into table values ('b', 'b', 'b', 'b');
  
  Insert in the table values ('b', 'b', 'c', 'b');
  
  y at - there no shortcut for insert because there are thousands of records to insert
  
  Help, please
  
  Thank you

  If data are available in another table, you can use a select statement inside your insert statement.

  Incomplete example

  NSERT INTO TABLE (
    COL1,
    COL2,
    COL3,
    COL4
  
  )
  SELECT FROM OTHERTABLE WHERE...,
  'b'
  'b'
  'b'
  ...
  

  The doc show this as an example:

  INSERT INTO AIRPORTS (AIRPORT, CITY, COUNTRY)
    SELECT AIRPORT, CITY_NAME, COUNTRY FROM CITIES
    ORDER BY AIRPORT;
  

  SELECT yourvalue, 'b', 'b', 'b' of...

  Best regards

  mseberg

  Published by: mseberg on October 6, 2012 08:31

• trigger for the insert statement

  Hello.
  I have a table, say, with 3 columns: ID, NAME, NAME_LENGTH.
  I am trying to create a trigger that fires when a record is inserted in the table.
  I send values for the ID and NAME columns per INSERT statement. and I need the trigger to write the LENGTH OF THE NAME INSERTED in the 3rd column
  
  CREATE OR REPLACE TRIGGER schema_name. GENERATE_length
  AFTER INSERT ON table_name
  FOR EACH LINE
  DECLARE
  F NVARCHAR2 (200);
  L NUMBER (5);
  NL NUMBER (5);
  NUMBER OF ID_LENGTH (5): = 5;
  BEGIN
  F: =:New.Name;
  
  L: = LENGTH (F);
  
  UPDATE HR_ORG_TREE
  
  SET name_length = NL;
  
  END;
  
  
  but does not work. error occurres as...
  
  ORA-04091: table schema_name.table_name is changing, the function of triggering/can not see
  ORA-06512: at the 'schema_name '. GENERATE_length', line 13
  ORA-04088: error during execution of trigger ' schema_name. GENERATE_length'
  
  Thank you.
  Sara

  CREATE OR REPLACE TRIGGER schema_name.GENERATE_length
      -- is "table_name" real name of your table?
      AFTER INSERT ON table_name
      FOR EACH ROW
  BEGIN
      -- this update will change all rows in HR_ORG_TREE table
      -- specify WHERE for this update
      UPDATE HR_ORG_TREE
         SET name_length = LENGTH(:NEW.name);
  END;
  

  Suppose your table_name is HR_ORG_TREE and you need to calculate the length of the name for just inserted row
  After maybe the code will be useful (not tested)

  CREATE OR REPLACE TRIGGER schema_name.GENERATE_length
      BEFORE INSERT ON HR_ORG_TREE
      FOR EACH ROW
  BEGIN
      :new.name_length := LENGTH(:NEW.name);
  END;
  

  Good luck

• Question related to the INSERT statement

  Imagine this scenario:
  
  -table_a has 5 000 000 records at time t1
  
  -table_b is empty at time t1
  
  -At time t1, I execute the following statement:

            insert into table_b
              select * from table_a;
      

  -L' insert statement ends in time t2
  
  -Between t1 and t2, say 3 000 new records have been added to the table_a (by OLTP processes).
  Thus, at time t2, table_a has 5 003 000 records.
  
  My question is, at time t2, the number of records will be in table_b? Will it 5,000,000 or
  5 003 000 or somewhere between these two counts?
  
  I guess it will be 5,000,000 because that is the number when the insert statement
  has started to run.
  
  Any comment is appreciated.

  Syed Ullah says:
  Imagine this scenario:

  -table_a has 5 000 000 records at time t1

  -table_b is empty at time t1

  -At time t1, I execute the following statement:

  insert into table_b
  select * from table_a;
  

  -L' insert statement ends in time t2

  -Between t1 and t2, say 3 000 new records have been added to the table_a (by OLTP processes).
  Thus, at time t2, table_a has 5 003 000 records.

  My question is, at time t2, the number of records will be in table_b? Will it 5,000,000 or
  5 003 000 or somewhere between these two counts?

  I guess it will be 5,000,000 because that is the number when the insert statement
  has started to run.

  Any comment is appreciated.

  At time t2, it is possible that the answer is 0. Once the insert operation finishes (can be any time after t1 in your example, possibly before t2, possibly after) and assuming you checked in the same session where you run the insert, you would see 5 000 000. In other sessions you would continue to see 0 up to what the session who made the done insert one COMMIT.

  http://docs.Oracle.com/CD/E11882_01/server.112/e25789/consist.htm#CNCPT121

  Is something that you should read. He described these concepts much better than what you'll probably find in a few posts on the forum.

• need help to create the insert statement

  I have customer_priv of table which has 4 columns (login, privilize_id, adate, added_by)
  
  the stmt insert like "insert into customer_priv values('JDOE',951.sysdate,admin);
  
  I have 100 users and for each user, I need to add to the 15 privilize_id
  
  I have the list of connections and roles, what is the best way to create a massive insert for all those users statement and
  
  any help is very appreciated
  
  Thank you

  user11984714 wrote:
  Thanks Frank

  I get the below now.what Miss. Also is it possible to reel in a file insert rather directly the data.am I missing values?

  Sorry, I don't understand what you want.
  You say you want to write something in a HOLD file instead of insert? Of course, you can do it. Change the INSERT statement in a SELECT statement and add commands to the COIL.

  SQL > @c:\insert_many.sql
  33 old: SELECT ' & 1' priv_id, 'admin', sysdate)
  33 News: SELECT sysdate, "BNELSON", "admin", priv_id)

  Of all_priv_id
  *
  ERROR on line 34:
  ORA-00923: THE KEYWORD not found where expected
  Thank you

  Published by: user11984714 on August 9, 2010 18:40

  Sorry, there was a typing error in my previous post.
  Remove the ')' the end of the

  SELECT     '&1', privilze_id, SYSDATE, 'admin')
  

  I hope that you have more problems, but if you do, post your code, even if you think that you just copied it from this site.

• Generate the insert statement using columns in view all_tab_cols

  I am trying to generate a dynamic insert statement using the columns of a table in the all_tab_cols view. If I do a select, I get the result as lines. How to convert the row of the columns so that I get something like this:

   INSERT INTO TABLE_NAME (COL1, COL2, COL3,COL4.....) 

  .
  
  Any help will be appreciated!

  This can give you a tip.

  SQL> ed
  Wrote file afiedt.buf
  
    1  with tab_col
    2  as
    3  (
    4  select i.table_name,
    5         column_name,
    6         row_number() over(partition by i.table_name order by table_name) rno
    7    from user_tab_cols i
    8  )
    9  select 'INSERT INTO '||table_name||' ('||ltrim(sys_connect_by_path(column_name, ','), ',')||')
   10    from tab_col
   11   where connect_by_isleaf = 1
   12   start with rno = 1
   13  connect by rno = prior rno+1
   14     and table_name = prior table_name
   15* and rownum<4
  SQL> /
  
  SQL_STATEMENT
  --------------------------------------------------------------------------------
  INSERT INTO A (MAKER,TYPE)
  INSERT INTO ADAM_TEST (ACCT,CODE)
  INSERT INTO AREA_TBL (AREA_ID,ORG_ID,CLUSTER_ID)
  INSERT INTO B (MAKER)
  INSERT INTO BONUS (ENAME)
  INSERT INTO CLUSTER_TBL (CLUSTER_ID)
  INSERT INTO COMPANY (MANUFACTURER)
  INSERT INTO COUNTRIES (COUNTRY_ID)
  

• value of the check box in the insert statement

  I'm hand-coding an insert from the insert record sb construction will do for this application. The values of several form elements are inserted into the fields in the table. The problem that occur is a checkbox value in the form. If the box is checked, all is well and the value is 'True' inserted in the appropriate database field. However, if the checkbox is not checked I get syntax error message. The reason being that, while are passed on to the fields with null null, the checkbox is not transmitted at all. This is evident when changing the method of the form to 'Get' for testing purposes. There is no reference to this field check box in the query string.
  
  My assumption is that this would require an If statement changing the value of the 'False' check box when the box is blocked. How I would go to this topic. With my knowledge limited to the ASP, I wrote the following, but it doesn't seem to work:
  
  < input name = "emailprob_mor" type = "checkbox" id = "emailprob_mor" value = "< % If Not (IsNull (Request.Form ("emailprob_cus")) then Response.Write"True") Else Response.Write ("False") End If % >" >

  When you use the boxes, it is better to separate your Request.Form statement and your insert statement:

  cbVal = '0 '.
  If (Request.Form ("emailprob_mor") <> "") then cbVal = Request.Form ("emailprob_mor")

  Then in your SQL statement:

  "& cbVal &"..."

  For your real HTML:

  "" ) then response.write(" checked='checked' ") %>>

  It is true that if the user does not check the box, then it appears as if there is no when it is submitted, that is the reason why he must be given a default value when the record is inserted.

• High logical reads with the INSERT statement

  Hello
  
  I have an INSERT query that is having a very high reading statspack logical reads. I've seen go Asktom announcement that this is due to the index. Link: [http://asktom.oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:6643159615303]
  
  Can you please help to explain exactly what Oracle do and why you should read so the e/s logic. It's the that oracle must read the structure of the index for all (bundle branch block + all blocks of sheet) for each insertion line?
  
  Thanks & appreciate the insight.
  
  Rgds
  Ung

  Only 5 bound for first INSERTION and only 1 for the next INSERTION.

  This is false.

  "db block ' is ALSO to the e/s logic." This is gets them in CURRENT mode. Oracle reads the Index blocks in the current mode to update the index blocks.

  Your last statement is in direct contradiction with the previous paragraph

  As Tom mentioned, oracle must change the index as well when records are inserted in > (or updated or deleted from) the table. This means oracle must first read the index blocks (in > compatibility mode (LIO) as well as in current mode) in addition to the blocks of the turntable when inserting new > records. So this must explain why LIOs are more when inserting in an indexed table from > inserting into a table not indexed.

  What is correct.

  Hemant K Collette
  http://hemantoracledba.blogspot.com