IKM SQL FOR SQL query add
HelloI went through this link:
Ask about the creation and filling I$ table on different condition
But I read in the case of IKM SQL FOR SQL add no I$ table is created.
If this is true please tell me why not I$ is created for this IKM?
So please tell me how the Frother is checked it to Check Knowledge Module (CKM)?
Thank you
Sébastien
PS:
I'm a freshness in tech ODI. So I can fool me please don't bother me
1. you need to create a mapping. Next, you need to see the code generated at each stage of all.
Try to analyze it. Then you will have a clear idea.
If see vedio carefully as given below, you can find staging area is on the source. So its directly select all the columns in the source tab and the insertion of these value in the tab target. No need to use I$ table. Yet once there is no option of flow_control. You can find the static_control.
http://S3.amazonaws.com/ora/ODI-Simple_SELECT_and_INSERT-interface.swf
To learn more about flow_control and static_control please go through
http://odiexperts.com/flow-control-and-static-control/
Thank you.
Tags: Business Intelligence
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create an OS command and run the command chmod by using this aclling celebrate your Interface.
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Hi team,
I'm looking for a SQL query check data (ECC + CallVariable) due to a RESULT of SCRIPT EXECUTE when you ask an external VRU with a translation route to VRU with a 'run external Script '.
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Omar,
respectfully, shorten the interval of a day might not be an option for a history report ;-)
I recommend to take a look at the following SQL query:
DECLARE @dateFrom DATETIME, @dateTo DATETIME
SET @dateFrom = ' 2014-01-24 00:00:00 '
SET @dateTo = ' 2014-01-25 00:00:00 '
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G.
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Single SQL query for the analysis of the date of customs declaration under the table of Stock codes
Dear all,
Please tell us a single SQL query for the below,
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STOCK_TABLE
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DOC_NO
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I1
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I1
I2
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SQL query to get the items for which transactions have not been saved
Hi people,
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Hi fatimakhellil
Try the following code and mark it as correct if your problem be resolved.
SELECT DISTINCT msi.segment1,
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MSI.primary_uom_code,
MSI.inventory_item_id,
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Ms.secondary_inventory_name,
(select max (transaction_date) in the mtl_material_transactions where msi.inventory_item_id = inventory_item_id
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OF mtl_system_items_b msi.
Ms. mtl_secondary_inventories
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AND msi.source_subinventory = ms.secondary_inventory_name (+)
AND NOT EXISTS (SELECT *)
OF mtl_material_transactions mmt
WHERE msi.inventory_item_id = mmt.inventory_item_id
AND msi.organization_id = mmt.organization_id
AND mmt.subinventory_code = ms.secondary_inventory_name
AND mmt.organization_id = ms.organization_id
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SQL query for the region of the tree
Hello
I was wondering if someone is able to help me work on a SQL query, to format the data in the table required in a part of the tree... I've never used a tree and I'm fighting to get the right data (if possible).
The data in the table looks like this:
I want to put it in a tree, using level 1 level6 with a final layout that would look like this:
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Added example given.
Hello
Apex-user wrote:
Thanks Frank, this is a good example, I can work with that! Your assumptions are correct.
A question I came, however, is that I have a data segment that comes across poorly formatted so to speak... where only the lower levels (1-2, etc.) have been filled from the bottom up.
An example of this data would be:
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As you can see that if you rerun the select, the test team is now duplicated, both at the level of the root in the tree as it should.
You are not sure if the sql can be adjusted to account for this, or if it's too hard?
It is obviously a question of data and I am trying to solve this separately (extracted data from another system out of my control).
Thank you!
Sorry, I'm confused.
You say that my assumptions were correct. What includes supported that "If test ' occurs under 'IT' in a row, then the extent of the 'Testing' occurs, it must be under"IT "? Right after you say that assumptions are correct, you give an example where 'Testing' occurs under 'IT' to a single line, but it is not less 'IT' to another line and where is 'One Team' under 'Testing' in a line, but is 'One Team' under 'Recruitment' in another row.
When a situation like this occurs, how you cope? Whenever you have a problem, please post the exact results you want from the given sample data, and an explanation of how you get these results. If you don't know about what would be the ideal results, or if you are flexible on the exact results, then at least give an example and explain your reasons.
Maybe you want to change the got_parent of subquery like this:
WITH unpivoted_data AS
(
SELECT *.
Employees
UNPIVOT (node_name
FOR lvl (level1 AS 1
level2 AS 2
level3 AS 3
level4 AS 4
level5 AS 5
level6 AS-6
)
)
)
got_parent AS
(
SELECT c.node_name
MIN (p.node_name) AS a parent
Of unpivoted_data c
LEFT OUTER JOIN unpivoted_data p ON p.employee = c.employee
AND p.lvl = c.lvl + 1
GROUP BY c.node_name
)
SELECT LPAD (' ' ')
2 * (LEVEL - 1)
) || Node_name AS entity
OF got_parent
START WITH parent IS NULL
Parent = node_name PRIOR CONNECTION
;
In this way, if 'Test' is current 'IT' in one line, but not under what in another line, whether under would consider the 'IT' request and not to be a root. If 'One Team' sudden 'Testing' in a line, but under "Recruitment" in another line, it will be (arbitrarily) consider it under "recruitment".
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SQL query to retrieve a single record for each employee of the following table?
Hi all
Help me on the writing of SQL query to retrieve a single record for each employee of the following table? preferably a standard SQL.
CREATE TABLE xxc_contact)
empnum NUMBER,
alternatecontact VARCHAR2 (100),
relationship VARCHAR2 (10),
phtype VARCHAR2 (10),
Phone NUMBER
);
insert into xxc_contact values (123456, 'Rick Grimes', 'SP', 'Cell', 9999999999)
insert into xxc_contact values (123456, 'Rick Grimes', 'SP', 'Work', 8888888888)
insert into xxc_contact values (123457, 'Daryl Dixon', 'EN', 'Work', 7777777777)
insert into xxc_contact values (123457, 'Daryl Dixon', 'EN', 'Home', 3333333333)
insert into xxc_contact values (123456, 'Maggie Greene', 'CH', 'Cell', 9999999999)
insert into xxc_contact values (123456, 'Maggie Greene', 'CH', 'Home', 9999999999)
expected result:
EmpNum AlternateContact Relationship PhType Phone
123456 rick Grimes SP cell 9999999999
Daryl Dixon EN work 7777777777 123457
Home 123458 Maggie Greene CH 6666666666
Thanks in advance.
994122 wrote:
Thank you all, that I got a result
http://www.orafaq.com/Forum/m/620305/#msg_620305
By Lalit Kumar B...
Specifically, the two simple solutions provided were:
1 using the row_number, entitled Oracle ranking based on descending order of the inside telephone each empnum group. And finally selects the lines which has least rank (of least since that order is descending for phone).
SQL > column alternatecontact format A20;
SQL >
SQL > SELECT empnum, alternatecontact, relationship, phtype, phone
2 from (SELECT a.*, row_number() over r (PARTITION BY empnum ORDER BY phone / / DESC))
3 FROM xxc_contact one)
4. WHEN r = 1
/
EMPNUM ALTERNATECONTACT RELATIONSHIP PHTYPE PHONE
---------- -------------------- ---------- ---------- ----------
123456 rick Grimes SP cell 9999999999
Daryl Dixon EN work 7777777777 123457
Home 123458 Maggie Greene CH 6666666666
2. with the help of MAX, Oracle automatically assigns the maximum phone for all the rows in each group of empnum. And finally selects the rows with the maximum phone. Order by clause is omitted here intentionally. You can find out why.
SQL > SELECT empnum, alternatecontact, relationship, phtype, phone
2 (SELECT a.*, MAX (phone) over (PARTITION BY empnum) rn FROM xxc_contact one)
3 WHERE phone = rn
4.
EMPNUM ALTERNATECONTACT RELATIONSHIP PHTYPE PHONE
---------- -------------------- ---------- ---------- ----------
123456 rick Grimes SP cell 9999999999
Daryl Dixon EN work 7777777777 123457
Home 123458 Maggie Greene CH 6666666666
Kind regards
Lalit
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For the MONEY and to break on a column SQL query
Hello
I have a situation where the data in the table are as below
AA
BB
1
FG
1
FG
1
FG
2
SS
1
FG
I need to write a sql query that would give output like below. Basically, it must break BB of the column and the value of the sum up to what it breaks.
AA
BB
3
FG
2
SS
1
FG
Please suggest.
Thank you
Shankar
Hello
770914 wrote:
Hello
I have a situation where the data in the table are as below
AA
BB
1
FG
1
FG
1
FG
2
SS
1
FG
I need to write a sql query that would give output like below. Basically, it must break BB of the column and the value of the sum up to what it breaks.
AA
BB
3
FG
2
SS
1
FG
Please suggest.
Thank you
Shankar
Remember, there is no order integrated to the rows in a table. The table you have posted is exactly the same as:
AA bb
-- --
1 FG
1 FG
2 SS
1 FG
1 FG
and both are exactly the same as:
AA bb
-- --
2 SS
1 FG
1 FG
1 FG
1 FG
If you use words like 'first', 'previous' or 'row' when it comes to lines, then we must define what these words mean. This is usually done by making reference to a column in the table. For example, if you had a column called r_num, like this:
AA bb r_num
-- -- -----
1 FG 1
1 FG 2
1 FG 9
2 SS 10
1 FG 10.5
Then, it would be wise to say things like 'the table starts with 3 lines consecutive "FG", followed by "SS". After that there is another "FG", which is the last line in the table, WHEN TRIE BY R_NUM. If the part about "WHEN SORTED BY R_NUM" is not known, the words 'begins '. "consecutive", 'followed', 'after' and 'last' have no meaning.
If (and only if) you have somehting like r_num in your table. Then you can get the resutls you want like this:
WITH got_group_num AS
(
SELECT aa, bb, r_num
ROW_NUMBER () OVER (ORDER BY r_num)
-ROW_NUMBER () OVER (PARTITION BY bb
ORDER BY r_num
) AS group_num
FROM table_x
)
SELECT SUM (aa) AS total_aa
, bb
OF got_group_num
GROUP BY bb
group_num
ORDER OF MIN (r_num)
;
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Good day experts,
I'm looking for advice on a report. I did a lot of analytical functions to get the basic data that I have to do my report and its takes about 50 min for SQL finish. Now, with these data, I need to create 3 different reports and I can't use the SQL even since there are a lot of aggregation (example would be product group in one case and by customer in 2nd). For each of these different group garages I need another report.
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Best regards
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First thing that comes to mind is to store the result set in a fictitious table, and then query the table since I get the basic data are about 300 lines and then perform different garages group.
Which is commonly called a "table of REPORT-READY." Those that are useful when data must be permanent and available for multiple sessions/users. Generally, there is a batch (for example the package procedure) that periodically refreshes / updates the data during a window of failure. Or the table can have a column (for example AS_OF) that allows it to contain multiple data sets and the update process let alone the existing data and creates a new set of data.
If your database is about 300 lines you can consider a table report and even use it to contain multiple data sets. Then, the reports can be written to query the data by using a value AS_OF that wraps and returns the appropriate data. You don't need a window of failure since the oldest data are still available (but can be removed when you no longer need.
If you need a set of data, you can use a partitioned table work (with only one partition) to collect the new set of data, then a SWAP PARTITION to 'swap' in the new data. Only, this "Exchange" takes a fraction of a second and avoids a window of failure. Once the swap done no matter what user query will get new data.
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(1 = 1)
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(
col1,
col2,
COL3
)
values
(
: COL1,.
: COL2.
: COL3
)
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Thanks in advance.
Find a work around the error of generals limit exceeded GC:
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$ODI_HOME/oracledi/client/odi/bin/odi.conf
AddVMOption - XX: MaxPermSize = NNNNM
$$ODI_HOME/oracledi/client/ide/bin/ide.conf
AddVMOption - XmxNNNNM
AddVMOption - XmsNNNNM
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-
Need for SQL query to get the result.
Region
Month Trx type Summary of the resolution AMERICAS -13 may Adjustments Fix EMEA -13 may Adjustments Incorrect AMERICAS -13 may Credit memo Incorrect EMEA -13 may Invoice Fix AMERICAS -13 may Credit memo Fix OFD -13 may Adjustments Fix AMERICAS -13 may Invoice Incorrect DVL -13 may Adjustments Fix DVL -13 may Adjustments Fix OFD -13 may Adjustments Fix Above my Table and here is the result required. Similarly for other regions as well. Can someone help me with the SQL query?
Region Summary of the resolution Setting Credit memo Invoice Total general AMERICAS Fix 1 1 2 Incorrect 0 1 1 2 Like this?
SQL > select * from transaction_audit;
MTH TRX_TYPE REGION BOARD
-------- ------ ----------- ---------
AMERICAS-13 may SETTINGS CORRECT
EMEA-13 may INCORRECT ADJUSTMENT
AMERICAS-13 may CREDIT MEMO INCORRECT
EMEA-13 may INVOICE CORRECT
AMERICAS-13 may CREDIT MEMO CORRECT
OFD-13 may SETTINGS CORRECT
AMERICAS-13 may INVOICE INCORRECTE
LAD-13 may SETTINGS CORRECT
LAD-13 may SETTINGS CORRECT
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2, resolution_summary
3, count (decode (trx_type, "ADJUSTMENTS", trx_type)) adjustments
4, County (decode (trx_type, 'HAVING', trx_type)) credit_memo
5, County (decode (trx_type, "BILL", trx_type)) Bill
transaction_audit 6
Group 7
8 by region
9, resolution_summary
10 Decree
11 by region
12, resolution_summary
13.REGION TAKE ADJUSTMENTS CREDIT_MEMO INVOICE
-------- --------- ----------- ----------- ----------
CORRECT THE AMERICAS 1 1 0
0 1 1 INCORRECT AMERICAS
EMEA CORRECT 0 0 1
INCORRECT EMEA 1 0 0
DAL ADDRESS 2 0 0
OFD CORRECT 2 0 06 selected lines.
SQL >
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The IKM selector selection error: IKM SQL for Hyperion Planning
Hello
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SQL query for the mapping of a set of prizes to a group of classrooms
Hi all
I use Oracle database 11g Release 2.
I have the following data set:
Classrooms
ClassId ClassName ability group
------ ---------------------------------------------- -------------- -----------
Babbage/software Engg Lab 1 24 1
Basement 2 - block PG 63 1
3 1 56 1 class
Class 4 1 24 10
Class 5 1 24 11
Class 6 1 35 12
7 13 42 1 class
8 14 42 1 class
9 15 42 1 class
10 2 35 1 class
11 3 35 1 class
12 4 35 1 classroom
13 5 35 1 class
14 6 25 1 class
15 7 25 1 class
16 1 24 8 class
17 9 24 1 class
18 control Sys Lab 1 24
19 dig & Embd Sys Lab 20 1
20 PSD & Comm 20 1 Lab
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Farabi 22/Web Tech Lab 1 36
23 gen purpose Lab 40 1
Shirazi/24dB Tech Lab 1 36
ADV 25 elect Lab 30 2
26 16 42 2 class
27 17 49 2 class
28 18 56 2 class
29 19 42 2 class
30 20 49 2 class
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32 22 35 3 class
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BatchId BatchName force
--------------- ----------------------- --------------
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2 BIT - 12 28
3 BS (CS)-1 35
4 BS (CS) 78-2
5 BE (SE)-1 69
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13 BEE-4 157
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Any response will be appreciated.
The SQL Scripts to generate the required tables and populate data is less to:
CREATE TABLE classrooms (ClassId NUMBER, ClassName VARCHAR2 (50), capacity NUMBER, group NUMBER);
INSERT INTO the classrooms of the VALUES (1, "Babbage/software Engg Lab', 24, 1");
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INSERT INTO the classrooms of the VALUES (3, '1 class room', 56, 1);
INSERT INTO the classrooms of the VALUES (4, '10 class room', 24, 1);
INSERT INTO the classrooms of the VALUES (5, '11 class room', 24, 1);
INSERT INTO the classrooms of the VALUES (6, 'class room 12', 35, 1);
INSERT INTO the classrooms of the VALUES (7, 'class room 13', 42, 1);
INSERT INTO the classrooms of the VALUES (8, 'class room 14', 42, 1);
INSERT INTO the classrooms of the VALUES (9, '15 'class, 42, 1);
INSERT INTO the classrooms of the VALUES (10, 'class 2', 35, 1);
INSERT INTO the classrooms of the VALUES (11, 'class room 3', 35, 1);
INSERT INTO the classrooms of the VALUES (12, 'class room 4', 35, 1);
INSERT INTO the classrooms of the VALUES (13, 'class room 5', 35, 1);
INSERT INTO the classrooms of the VALUES (14, 'class room 6', 25, 1);
INSERT INTO the classrooms of the VALUES (15, '7 class room', 25, 1);
INSERT INTO the classrooms of the VALUES (16, 'class Room 8', 24, 1);
INSERT INTO the classrooms of the VALUES (17, 'class room 9', 24, 1);
INSERT INTO the classrooms of the VALUES (18, 'Control Sys Lab', 24, 1);
INSERT INTO the classrooms of the VALUES (19, 'Dig & Embd Sys Lab', 20, 1);
INSERT INTO the classrooms of the VALUES (20, 'DSP & Comm Lab', 20, 1);
INSERT INTO the classrooms of the VALUES (21, 'system ELECTROMECHANICAL Lab', 28, 1);
INSERT INTO the classrooms of the VALUES (22, ' Farabi/Web Tech Lab', 36, 1);
INSERT INTO the classrooms of the VALUES (23, 'Gen purpose Lab', 40, 1);
INSERT INTO the classrooms of the VALUES (24, ' Shirazi/DB Tech Lab', 36, 1);
INSERT INTO the classrooms of the VALUES (25, 'Elected Adv Lab', 30, 2);
INSERT INTO the classrooms of the VALUES (26, 'class room 16', 42, 2);
INSERT INTO the classrooms of the VALUES (27, 'class room 17', 49, 2);
INSERT INTO the classrooms of the VALUES (28, '18 'class, 56, 2);
INSERT INTO the classrooms of the VALUES (29, '19 'class, 42, 2);
INSERT INTO the classrooms of the VALUES (30, 'class room 20', 49, 2);
INSERT INTO the classrooms of the VALUES (31, 'class room 21', 35, 3);
INSERT INTO the classrooms of the VALUES (32, 'room 22', 35, 3);
INSERT INTO the classrooms of the VALUES (33, 'MDA Lab', 20, 3);
CREATE TABLE DegreeBatches (BatchId NUMBER, BatchName VARCHAR2 (50), membership NUMBER);
INSERT INTO DegreeBatches VALUES(1,'BIT-11',79);
INSERT INTO DegreeBatches VALUES(2,'BIT-12',28);
INSERT INTO DegreeBatches VALUES (3, 'BS (CS) - 1', 35);
INSERT INTO DegreeBatches VALUES (4, 'BS (CS) - 2', 78);
INSERT INTO DegreeBatches VALUES (5,'BE (SE) - 1', 69);
INSERT INTO DegreeBatches VALUES (6,'BE (SE) - 2', 84);
INSERT INTO DegreeBatches VALUES (7,'BE (SE) - 3', 64);
INSERT INTO DegreeBatches VALUES(8,'BICSE-7',84);
INSERT INTO DegreeBatches VALUES(9,'BICSE-8',43);
INSERT INTO DegreeBatches VALUES(10,'BEE-1',112);
INSERT INTO DegreeBatches VALUES(11,'BEE-2',151);
INSERT INTO DegreeBatches VALUES(12,'BEE-3',157);
INSERT INTO DegreeBatches VALUES(13,'BEE-4',157);
Best regards
Bilal
Published by: Bilal on December 27, 2012 09:52
Published by: Bilal on December 27, 2012 10:07Bilal, thanks for the nice problem! Another possibility to double check is to write a small PL/SQL function that returns 1 if a duplicate id is found, then equate to 0: "NUMBER of RETURN of Duplicate_Token_Found (p_str_main in VARCHAR2, p_str_trial VARCHAR2). It should analyze the second string and could use p_str_main LIKE '%', | l_id | ', %' for each id. In any case, the query complete (without that) is given below:
Solution with names SQL> WITH rsf_itm (con_id, max_weight, nxt_id, lev, tot_weight, tot_profit, path, root_id, lev_1_id) AS ( 2 SELECT c.id, 3 c.max_weight, 4 i.id, 5 0, 6 i.item_weight, 7 i.item_profit, 8 ',' || i.id || ',', 9 i.id, 10 0 11 FROM items i 12 CROSS JOIN containers c 13 UNION ALL 14 SELECT r.con_id, 15 r.max_weight, 16 i.id, 17 r.lev + 1, 18 r.tot_weight + i.item_weight, 19 r.tot_profit + i.item_profit, 20 r.path || i.id || ',', 21 r.root_id, 22 CASE WHEN r.lev = 0 THEN i.id ELSE r.nxt_id END 23 FROM rsf_itm r 24 JOIN items i 25 ON i.id > r.nxt_id 26 AND r.tot_weight + i.item_weight <= r.max_weight 27 ORDER BY 1, 2 28 ) SEARCH DEPTH FIRST BY nxt_id SET line_no 29 , rsf_con (nxt_con_id, nxt_line_no, con_path, itm_path, tot_weight, tot_profit, lev) AS ( 30 SELECT con_id, 31 line_no, 32 To_Char(con_id), 33 ':' || con_id || '-' || (lev + 1) || ':' || path, 34 tot_weight, 35 tot_profit, 36 0 37 FROM rsf_itm 38 UNION ALL 39 SELECT r_i.con_id, 40 r_i.line_no, 41 r_c.con_path || ',' || r_i.con_id, 42 r_c.itm_path || ':' || r_i.con_id || '-' || (r_i.lev + 1) || ':' || r_i.path, 43 r_c.tot_weight + r_i.tot_weight, 44 r_c.tot_profit + r_i.tot_profit, 45 r_c.lev + 1 46 FROM rsf_con r_c 47 JOIN rsf_itm r_i 48 ON r_i.con_id > r_c.nxt_con_id 49 WHERE r_c.itm_path NOT LIKE '%,' || r_i.root_id || ',%' 50 AND r_c.itm_path NOT LIKE '%,' || r_i.lev_1_id || ',%' 51 AND r_c.itm_path NOT LIKE '%,' || r_i.nxt_id || ',%' 52 ) 53 , paths_ranked AS ( 54 SELECT itm_path || ':' itm_path, tot_weight, tot_profit, lev + 1 n_cons, 55 Rank () OVER (ORDER BY tot_profit DESC) rnk, 56 Row_Number () OVER (ORDER BY tot_profit DESC) sol_id 57 FROM rsf_con 58 ), best_paths AS ( 59 SELECT itm_path, tot_weight, tot_profit, n_cons, sol_id 60 FROM paths_ranked 61 WHERE rnk = 1 62 ), row_gen AS ( 63 SELECT LEVEL lev 64 FROM DUAL 65 CONNECT BY LEVEL <= (SELECT Count(*) FROM items) 66 ), con_v AS ( 67 SELECT b.itm_path, r.lev con_ind, b.sol_id, b.tot_weight, b.tot_profit, 68 Substr (b.itm_path, Instr (b.itm_path, ':', 1, 2*r.lev - 1) + 1, 69 Instr (b.itm_path, ':', 1, 2*r.lev) - Instr (b.itm_path, ':', 1, 2*r.lev - 1) - 1) 70 con_nit_id, 71 Substr (b.itm_path, Instr (b.itm_path, ':', 1, 2*r.lev) + 1, 72 Instr (b.itm_path, ':', 1, 2*r.lev + 1) - Instr (b.itm_path, ':', 1, 2*r.lev) - 1) 73 itm_str 74 FROM best_paths b 75 JOIN row_gen r 76 ON r.lev <= b.n_cons 77 ), con_split AS ( 78 SELECT itm_path, con_ind, sol_id, tot_weight, tot_profit, 79 Substr (con_nit_id, 1, Instr (con_nit_id, '-', 1) - 1) con_id, 80 Substr (con_nit_id, Instr (con_nit_id, '-', 1) + 1) n_items, 81 itm_str 82 FROM con_v 83 ), itm_v AS ( 84 SELECT c.itm_path, c.con_ind, c.sol_id, c.con_id, c.tot_weight, c.tot_profit, 85 Substr (c.itm_str, Instr (c.itm_str, ',', 1, r.lev) + 1, 86 Instr (c.itm_str, ',', 1, r.lev + 1) - Instr (c.itm_str, ',', 1, r.lev) - 1) 87 itm_id 88 FROM con_split c 89 JOIN row_gen r 90 ON r.lev <= c.n_items 91 ) 92 SELECT v.sol_id, 93 v.tot_weight s_wt, v.tot_profit s_pr, c.id c_id, c.name c_name, c.max_weight m_wt, 94 Sum (i.item_weight) OVER (PARTITION BY v.sol_id, c.id) c_wt, 95 i.id i_id, i.name i_name, i.item_weight i_wt, i.item_profit i_pr 96 FROM itm_v v 97 JOIN containers c 98 ON c.id = To_Number (v.con_id) 99 JOIN items i 100 ON i.id = To_Number (v.itm_id) 101 ORDER BY sol_id, con_id, itm_id 102 / SOL_ID S_WT S_PR C_ID C_NAME M_WT C_WT I_ID I_NAME I_WT I_PR ---------- ---- ---- ----- --------------- ---- ---- ----- ---------- ---- ---- 1 255 255 1 SEECS UG Block 100 100 1 BIT-10 35 35 2 BIT-11 40 40 6 BICSE-7 25 25 2 IAEC Building 70 70 4 BSCS-3 40 40 7 BESE-3 30 30 3 RIMMS Building 90 85 3 BSCS-2 35 35 5 BEE-4 50 50 2 255 255 1 SEECS UG Block 100 95 4 BSCS-3 40 40 6 BICSE-7 25 25 7 BESE-3 30 30 2 IAEC Building 70 70 1 BIT-10 35 35 3 BSCS-2 35 35 3 RIMMS Building 90 90 2 BIT-11 40 40 5 BEE-4 50 50 3 255 255 1 SEECS UG Block 100 100 3 BSCS-2 35 35 4 BSCS-3 40 40 6 BICSE-7 25 25 2 IAEC Building 70 65 1 BIT-10 35 35 7 BESE-3 30 30 3 RIMMS Building 90 90 2 BIT-11 40 40 5 BEE-4 50 50 4 255 255 1 SEECS UG Block 100 100 3 BSCS-2 35 35 4 BSCS-3 40 40 6 BICSE-7 25 25 2 IAEC Building 70 70 2 BIT-11 40 40 7 BESE-3 30 30 3 RIMMS Building 90 85 1 BIT-10 35 35 5 BEE-4 50 50 5 255 255 1 SEECS UG Block 100 95 2 BIT-11 40 40 6 BICSE-7 25 25 7 BESE-3 30 30 2 IAEC Building 70 70 1 BIT-10 35 35 3 BSCS-2 35 35 3 RIMMS Building 90 90 4 BSCS-3 40 40 5 BEE-4 50 50 6 255 255 1 SEECS UG Block 100 100 2 BIT-11 40 40 3 BSCS-2 35 35 6 BICSE-7 25 25 2 IAEC Building 70 65 1 BIT-10 35 35 7 BESE-3 30 30 3 RIMMS Building 90 90 4 BSCS-3 40 40 5 BEE-4 50 50 7 255 255 1 SEECS UG Block 100 100 2 BIT-11 40 40 3 BSCS-2 35 35 6 BICSE-7 25 25 2 IAEC Building 70 70 4 BSCS-3 40 40 7 BESE-3 30 30 3 RIMMS Building 90 85 1 BIT-10 35 35 5 BEE-4 50 50 8 255 255 1 SEECS UG Block 100 100 1 BIT-10 35 35 4 BSCS-3 40 40 6 BICSE-7 25 25 2 IAEC Building 70 70 2 BIT-11 40 40 7 BESE-3 30 30 3 RIMMS Building 90 85 3 BSCS-2 35 35 5 BEE-4 50 50 9 255 255 1 SEECS UG Block 100 100 1 BIT-10 35 35 4 BSCS-3 40 40 6 BICSE-7 25 25 2 IAEC Building 70 65 3 BSCS-2 35 35 7 BESE-3 30 30 3 RIMMS Building 90 90 2 BIT-11 40 40 5 BEE-4 50 50 10 255 255 1 SEECS UG Block 100 100 1 BIT-10 35 35 3 BSCS-2 35 35 7 BESE-3 30 30 2 IAEC Building 70 65 2 BIT-11 40 40 6 BICSE-7 25 25 3 RIMMS Building 90 90 4 BSCS-3 40 40 5 BEE-4 50 50 11 255 255 1 SEECS UG Block 100 100 1 BIT-10 35 35 3 BSCS-2 35 35 7 BESE-3 30 30 2 IAEC Building 70 65 4 BSCS-3 40 40 6 BICSE-7 25 25 3 RIMMS Building 90 90 2 BIT-11 40 40 5 BEE-4 50 50 12 255 255 1 SEECS UG Block 100 95 1 BIT-10 35 35 3 BSCS-2 35 35 6 BICSE-7 25 25 2 IAEC Building 70 70 2 BIT-11 40 40 7 BESE-3 30 30 3 RIMMS Building 90 90 4 BSCS-3 40 40 5 BEE-4 50 50 13 255 255 1 SEECS UG Block 100 95 1 BIT-10 35 35 3 BSCS-2 35 35 6 BICSE-7 25 25 2 IAEC Building 70 70 4 BSCS-3 40 40 7 BESE-3 30 30 3 RIMMS Building 90 90 2 BIT-11 40 40 5 BEE-4 50 50 14 255 255 1 SEECS UG Block 100 100 1 BIT-10 35 35 2 BIT-11 40 40 6 BICSE-7 25 25 2 IAEC Building 70 65 3 BSCS-2 35 35 7 BESE-3 30 30 3 RIMMS Building 90 90 4 BSCS-3 40 40 5 BEE-4 50 50 98 rows selected. Elapsed: 00:00:01.42
Published by: BrendanP on January 20, 2013 11:25
I found the need to deduplicate regular expression:AND RegExp_Instr (r_c.itm_path | r_i.path, ',(\d+),.*?,\1,') = 0)
HISTORY_TABLE
ITEM_CODE | BAT_NO |
TXN_CODE
DOC_NO
UPDT_DT
I1
B1
T1
1234
JANUARY 3, 2015
I1
B20
T20
4567
MARCH 3, 2015
I1
B30
T30
7890
FEBRUARY 5, 2015
I2
B40
T20
1234
JANUARY 1, 2015
TRANSACTION
TXN_CODE | TXN_TYPE |
T1 | IN |
T20 |
OFF
T30
ALL THE
T50
IN
T80
IN
T90
IN
T60
ALL THE
T70
ALL THE
T40
ALL THE
IN_TABLE_HEAD_1
H1_SYS_ID (primary key) | TXN_CODE | DOC_NO |
DOC_DATE
H1ID1
T1
1234
JANUARY 1, 2015
H1ID2
T70
1234
FEBRUARY 1, 2015
IN_TABLE_ITEM_1
I1_SYS_ID |
H1_SYS_ID
(foreign key referencing H1_SYS_ID in IN_TABLE_HEAD_1)
ITEM_CODE
I1ID1
H1ID1
I1
I1ID2
H1ID1
I100
I1ID3
H1ID2
I3
IN_TABLE_BATCH_1
B1_SYS_ID | TXN_CODE DOC_NO (now in IN_TABLE_HEAD_1) | BAT_NO |
B1ID1
T1
1234
B1 / can be empty
B1ID2
T70
1234
B70
IN_TABLE_HEAD_2
H2_SYS_ID (primary key) | TXN_CODE |
DOC_NO
DOC_DATE
H2ID1
T30
4567
FEBRUARY 3, 2015
H2ID2
T60
1234
JANUARY 3, 2015
IN_TABLE_ITEM_2
I2_SYS_ID | H2_SYS_ID (foreign key referencing H2_SYS_ID in IN_TABLE_HEAD_2) | ITEM_CODE |
I2ID1 | H2ID1 |
I1
I2ID2
H2ID1
I200
I2ID3
H2ID2
I2
IN_TABLE_BATCH_2
B2_SYS_ID |
I2_SYS_ID
(foreign key referencing I2_SYS_ID in IN_TABLE_ITEM_2)
BAT_NO
B2ID1
I2ID1
B30 / null
B2ID2
I2ID2
B90
B2ID2
I2ID3
B60
IN_TABLE_HEAD_3
H3_SYS_ID (primary key) | TXN_CODE | DOC_NO | DOC_DATE |
H3ID1 |
T50
1234
JANUARY 2, 2015
H3ID2
T80
1234
JANUARY 3, 2015
H3ID3
T90
1234
JANUARY 4, 2015
H3ID4
T40
1234
AUGUST 5, 2015
IN_TABLE_ITEM_3
I3_SYS_ID |
H3_SYS_ID
(foreign key referencing H3_SYS_ID in IN_TABLE_HEAD_3)
ITEM_CODE
BAT_NO
I3ID1
H31D1
I2
B50
I3ID2
H3ID2
I4
B40
I3ID3
H3ID3
I4
I3ID4
H3ID4
I6
There is no IN_TABLE_BATCH_3
Please find below the expected results.
OUTPUT
ITEM_CODE | BAT_NO | TXN_CODE | DOC_NO |
BOE_DT
BATCH_YN
I1
B1
T1
1234
JANUARY 3, 2015
THERE
I1
B30
T30
7890
FEBRUARY 5, 2015
N
I2
B60
T60
1234
JANUARY 3, 2015
N
I3
B70
T70
1234
FEBRUARY 1, 2015
THERE
I4
T90
1234
JANUARY 4, 2015
N
I6
T40
1234
AUGUST 5, 2015
N
Controls database to create the tables above and insert the records.
CREATE TABLE stock_table()item_code VARCHAR2()80),bat_no VARCHAR2()80),txn_code VARCHAR2()80),
doc_no VARCHAR2 (80), boe_dt DATE );
INSERT EN stock_table
VALUES ('I1', 'B1', '', '', '');
INSERT EN stock_table
VALUES ('I1', '', '', '', '');
INSERT IN stock_table
VALUES ('I2', '', '', '', '');
INSERT EN stock_table
VALUES ('I3', 'B70', '', '', '');
INSERT EN stock_table
VALUES ('I4', 'B80', '', '', '');
INSERT EN stock_table
VALUES ('I5', 'B90', 'T102', '1234', '02-JUL-2015');
INSERT EN stock_table
VALUES ('I6', 'B100', '', '', '');
SELECT *
FROM stock_table
CREATE TABLE history_table()item_code VARCHAR2()80),bat_no VARCHAR2()80),txn_code VARCHAR2()80),
doc_no VARCHAR2 (80), updt_dt DATE );
INSERT IN history_table
VALUES ('I1', 'B1', 'T1', '1234', '03-JAN-2015');
INSERT IN history_table
VALUES ('I1', 'B20', 'T20', '4567', '03-MAR-2015');
INSERT IN history_table
VALUES ('I1', 'B30', 'T30', '7890', '05-FEB-2015');
INSERT IN history_table
VALUES ('I2', 'B40', 'T20', '1234', '01-JAN-2015');
SELECT *
FROM history_table
CREATE TABLE transaction1()txn_code VARCHAR()80),txn_type VARCHAR()80));
INSERT INTO transaction1
VALUES ('T1', 'IN');
INSERT INTO transaction1
VALUES ('T20', 'OUT');
INSERT INTO transaction1
VALUES ('T30', 'ALL');
INSERT INTO transaction1
VALUES ('T40', 'ALL');
INSERT INTO transaction1
VALUES ('T50', 'IN');
INSERT INTO transaction1
VALUES ('T60', 'ALL');
INSERT INTO transaction1
VALUES ('T70', 'ALL');
INSERT INTO transaction1
VALUES ('T80', 'IN');
INSERT INTO transaction1
VALUES ('T90', 'IN');
SELECT *
FROM transaction1
CREATE TABLE in_table_head_1()h1_sys_id VARCHAR2()80) PRIMARY KEY,txn_code VARCHAR2()80),
doc_no VARCHAR2 (80), doc_dt DATE );
CREATE TABLE in_table_head_2()h2_sys_id VARCHAR2()80) PRIMARY KEY,txn_code VARCHAR2()80),
doc_no VARCHAR2 (80), doc_dt DATE );
CREATE TABLE in_table_head_3()h3_sys_id VARCHAR2()80) PRIMARY KEY,txn_code VARCHAR2()80),
doc_no VARCHAR2 (80), doc_dt DATE );
INSERT IN in_table_head_1
VALUES ('H1ID1', 'T1', '1234', '01-JAN-2015');
INSERT IN in_table_head_1
VALUES ('H1ID2', 'T70', '1234', '01-FEB-2015');
INSERT IN in_table_head_2
VALUES ('H2ID1', 'T30', '4567', '03-FEB-2015');
INSERT IN in_table_head_2
VALUES ('H2ID2', 'T60', '1234', '03-JAN-2015');
INSERT IN in_table_head_3
VALUES ('H3ID1', 'T50', '1234', '02-JAN-2015');
INSERT IN in_table_head_3
VALUES ('H3ID2', 'T80', '1234', '03-JAN-2015');
INSERT IN in_table_head_3
VALUES ('H3ID3', 'T90', '1234', '05-JAN-2015');
INSERT IN in_table_head_3
VALUES ('H3ID4', 'T40', '1234', '05-AUG-2015');
CREATE TABLE in_table_item_1()i1_sys_id VARCHAR2()80) PRIMARY KEY,
h1_sys_id VARCHAR2 (80) REFERENCES in_table_head_1()h1_sys_id),item_code VARCHAR2()80));
CREATE TABLE in_table_item_2()i2_sys_id VARCHAR2()80) PRIMARY KEY,
h2_sys_id VARCHAR2 (80) REFERENCES in_table_head_2()h2_sys_id),item_code VARCHAR2()80));
CREATE TABLE in_table_item_3(i3_sys_id VARCHAR2(80) PRIMARY KEY,
h3_sys_id VARCHAR2 (80) REFERENCES in_table_head_3()h3_sys_id),item_code VARCHAR2()80),
bat_no VARCHAR2 (80));
INSERT IN in_table_item_1
VALUES ('I1ID1', 'H1ID1', 'I1');
INSERT IN in_table_item_1
VALUES ('I1ID2', 'H1ID1', 'I100');
INSERT IN in_table_item_1
VALUES ('I1ID3', 'H1ID2', 'I3');
INSERT IN in_table_item_2
VALUES ('I2ID1', 'H2ID1', 'I1');
INSERT IN in_table_item_2
VALUES ('I2ID2', 'H2ID1', 'I200');
INSERT IN in_table_item_2
VALUES ('I2ID3', 'H2ID2', 'I2');
INSERT IN in_table_item_3
VALUES ('I3ID1', 'H3ID1', 'I2','B50');
INSERT IN in_table_item_3
VALUES ('I3ID2', 'H3ID2', 'I4','B40');
INSERT IN in_table_item_3
VALUES ('I3ID3', 'H3ID3', 'I4','');
INSERT IN in_table_item_3
VALUES ('I3ID4', 'H3ID4', 'I6','');
SELECT *
FROM in_table_item_1
SELECT *
FROM in_table_item_2
SELECT *
FROM in_table_item_3
CREATE TABLE in_table_batch_1()b1_sys_id VARCHAR2()80) PRIMARY KEY,
txn_code VARCHAR2 (80), doc_no VARCHAR2 (80), bat_no VARCHAR2 (80));
CREATE TABLE in_table_batch_2()b2_sys_id VARCHAR2()80) PRIMARY KEY,
i2_sys_id VARCHAR2 (80) REFERENCES in_table_item_2()i2_sys_id),bat_no VARCHAR2()80));
INSERT IN in_table_batch_1
VALUES ('B1ID1', 'T1', '1234', 'B1');
INSERT IN in_table_batch_1
VALUES ('B1ID2', 'T70', '1234', 'B70');
INSERT IN in_table_batch_2
VALUES ('B2ID1', 'I2ID1', 'B30');
INSERT IN in_table_batch_2
VALUES ('B2ID2', 'I2ID2', 'B90');
INSERT IN in_table_batch_2
VALUES ('B2ID3', 'I2ID3', 'B60');
Please advise a solution for the same.
Thank you and best regards,
Séverine Suresh
very forced (question subfactoring used to allow easy testing/verification - could work with these test data only)
with
case_1 as
(select s.item_code,
s.bat_no,
h.txn_code,
h.doc_no,
h.updt_dt boe_dt,
cases where s.bat_no = h.bat_no then 'Y' else ' n end batch_yn.
cases where h.txn_code is not null
and h.doc_no is not null
and h.updt_dt is not null
then 'case 1' '.
end refers_to
from (select item_code, bat_no, txn_code, doc_no, boe_dt
of w_stock_table
where bat_no is null
or txn_code is null
or doc_no is null
or boe_dt is null
) s
left outer join
w_history_table h
On s.item_code = h.item_code
and s.bat_no = h.bat_no
and exists (select null
of w_transaction1
where txn_code = nvl (s.txn_code, h.txn_code)
and txn_type in ('IN', 'ALL')
)
),
case_2 as
(select s.item_code,
NVL (s.bat_no, h.bat_no) bat_no.
NVL (s.txn_code, h.txn_code) txn_code.
NVL (s.doc_no, h.doc_no) doc_no.
NVL (s.boe_dt, h.updt_dt) updt_dt.
cases where s.bat_no = h.bat_no then 'Y' else ' n end batch_yn.
cases where h.txn_code is not null
and h.doc_no is not null
and h.updt_dt is not null
then 'case 2'.
end refers_to
from (select item_code, bat_no, txn_code, doc_no, boe_dt
of case_1
where refers_to is null
) s
left outer join
w_history_table h
On s.item_code = h.item_code
and exists (select null
of w_transaction1
where txn_code = nvl (s.txn_code, h.txn_code)
and txn_type in ('IN', 'ALL')
)
and not exists (select null
of case_1
where item_code = h.item_code
and bat_no = h.bat_no
and txn_code = h.txn_code
and doc_no = h.doc_no
and updt_dt = h.updt_dt
)
),
case_31 as
(select s1.item_code,
NVL (S1.bat_no, W1.bat_no) bat_no.
NVL (S1.txn_code, W1.txn_code) txn_code.
NVL (S1.doc_no, W1.doc_no) doc_no.
NVL (S1.updt_dt, W1.doc_dt) updt_dt.
cases where s1.bat_no = w1.bat_no then 'Y' else ' n end batch_yn.
cases where w1.txn_code is not null
and w1.doc_no is not null
and w1.doc_dt is not null
then "case 31'.
end refers_to
from (select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn, refers_to
of case_2
where refers_to is null
) s1
left outer join
(select i1.item_code, h1.txn_code, h1.doc_no, h1.doc_dt, b1.bat_no
of w_in_table_item_1 i1
inner join
w_in_table_head_1 h1
On i1.h1_sys_id = h1.h1_sys_id
inner join
w_in_table_batch_1 b1
On h1.txn_code = b1.txn_code
and h1.doc_no = b1.doc_no
) w1
On s1.item_code = w1.item_code
),
case_32 as
(select s2.item_code,
NVL (S2.bat_no, W2.bat_no) bat_no.
NVL (S2.txn_code, W2.txn_code) txn_code.
NVL (S2.doc_no, W2.doc_no) doc_no.
NVL (S2.updt_dt, W2.doc_dt) updt_dt.
cases where s2.bat_no = w2.bat_no then 'Y' else ' n end batch_yn.
cases where w2.txn_code is not null
and w2.doc_no is not null
and w2.doc_dt is not null
then "case 32'.
end refers_to
from (select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn, refers_to
of case_2
where refers_to is null
) s2
left outer join
(select i2.item_code, h2.txn_code, h2.doc_no, h2.doc_dt, b2.bat_no
of w_in_table_item_2 i2
inner join
w_in_table_head_2 h2
On i2.h2_sys_id = h2.h2_sys_id
inner join
w_in_table_batch_2 b2
On i2.i2_sys_id = b2.i2_sys_id
) w2
On s2.item_code = w2.item_code
),
case_33 as
(select s3.item_code,
w3.bat_no,
NVL (S3.txn_code, w3.txn_code) txn_code.
NVL (S3.doc_no, w3.doc_no) doc_no.
NVL (S3.updt_dt, w3.doc_dt) updt_dt.
cases where s3.bat_no = w3.bat_no then 'Y' else ' n end batch_yn.
cases where w3.txn_code is not null
and w3.doc_no is not null
and w3.doc_dt is not null
then "case 33'.
end refers_to
from (select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn, refers_to
of case_2
where refers_to is null
) s3
left outer join
(select i3.item_code, h3.txn_code, h3.doc_no, h3.doc_dt, i3.bat_no
of w_in_table_item_3 i3
inner join
w_in_table_head_3 h3
On i3.h3_sys_id = h3.h3_sys_id
) w3
On s3.item_code = w3.item_code
)
Select item_code, bat_no, txn_code, doc_no, boe_dt, batch_yn
of case_1
where refers_to is not null
Union of all the
Select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn
of case_2
where refers_to is not null
Union of all the
Select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn
from (select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn,
ROW_NUMBER() over (partition by item_code of updt_dt desc order) rn
from (select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn
of case_31
where refers_to is not null
Union of all the
Select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn
of case_32
where refers_to is not null
Union of all the
Select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn
of case_33
where refers_to is not null
)
)
where rn = 1
ITEM_CODE | BAT_NO | TXN_CODE | DOC_NO | BOE_DT | BATCH_YN |
---|---|---|---|---|---|
I1 | B1 | T1 | 1234 | JANUARY 3, 2015 | THERE |
I1 | B30 | T30 | 7890 | FEBRUARY 5, 2015 | N |
I2 | B60 | T60 | 1234 | JANUARY 3, 2015 | N |
I3 | B70 | T70 | 1234 | FEBRUARY 1, 2015 | THERE |
I4 | - | T90 | 1234 | JANUARY 5, 2015 | N |
I6 | - | T40 | 1234 | AUGUST 5, 2015 | N |
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